# Physical Sciences Grade 12 P1 Limpopo Mock 2023 Paper & Memo

> Grade 12 Physical Sciences Paper 1 question paper and memo from the Limpopo Mock Exam 2023, 24 pages. Read online or get the free PDF download.

- Page: https://www.hlayiso.com/library/grade-12-physical-sciences-2023-limpopo-mock-exam-question-paper-and-memorandum-paper-1/665ba202-a2dc-4998-a4e8-2b9e14c243df
- Updated: 2026-09-28
- Subject: Physical Sciences
- Grade: Grade 12
- Document type: Question paper and memo
- Year: 2023
- Exam period: Limpopo Mock Exam
- Paper: 1
- Curriculum: CAPS
- Pages: 24

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## About this document

Physical Sciences · Grade 12 · Limpopo Mock Exam · 2023. Question paper and memorandum, 24 pages. Read online or download the PDF.

Read it free online on the page above; download the PDF from there.

## Document text

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### Page 1

Downloaded from Stanmorephysics.com

NATIONAL
SENIOR CERTIFICATE

MARKS: 150
TIME: 3 hours

This question paper consists of 19 pages and 3-paged data sheets.

### Page 2

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QUESTION 4 (Start on a new _—

Various options are Provided as possible answers to the following questions. Choose
the answer and writ

fe only the letter (A-D) next to the question numbers (1.1 to 1.10) in
the ANSWER BOOK, e.g. 1.11 E. Each question has only ONE correct answer.

1 ONE of the following is the CORRECT term for the gravitational force
arth exerts on any object on or near its surface?

A Weight

B Friction

C Tension

D Compression (2)
1.2 The attfuck places a suitcase on the level dashboard in front of him.

He obser ;" € suitcase is sliding towards the windscreen. At this instant

the truckiS probably moving ...

A forward at constant velocity.

B backward and slowing down.

C forward and slowing down.

D backward at constant velocity. (2)

Copyright reserved Please turn over

### Page 3

4

Downloaded from Stanmorephysiggich one of the following combina,

1.3

1.4

sail ,
Astone is thrown vero acceleration and velocity one secong before

correctly represents HN?

reaching maximum height? _—
Assume that air resistance IS '9
VELOCITY
ACCELERATION
9,8 mos* upwards
f 9,8 mis* upwards
—
B 9,8 mos” downwards 9,8 mUs” upwards
Ds cpgedlalaenwmeenmenacs |
Cc 9,8 mus“ upwards 9,8 mos downwards
D 9,8 mus? downwards 9,8 mus* downwards .
a lower speed limit and the driver slows down the

A car approaches a road with
car. The two vectors pi and
respectively.

pr below represent its initial and final momenta

pr

pi er ee

Which ONE of the following vector diagrams CORRECTLY represents the
change in momentum (Ap) of the car?

+

A
5 =
c
D

_
()

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### Page 4

Physical Sciences/P4

5
Downloaded from Stanmoreph¥sics.com

1.5 Al ject i
i 's dropped from a height h above ground level, Which ONE of th
“ 9 graph BEST represents the relationship between its kinetic '
(Ex) and its height above ground level? li

B
ih Ex
0

LimpopoDoE/September 2023

h 0 h
C D
° . eo
0
h " h

(2)

1.6 How does the frequency and wavelength of a wave source change when it
moves towards the observer?

A The wavelength increases whilst the frequency decreases
B The wavelength decreases whilst the frequency increases
C The wavelength decreases whilst the frequency decreases

D The wavelength increases whilst the frequency increases

### Page 5

6
Downloaded from Stanmorephyslés.com
Qi and a negative point charge Qe of equal mn

Pn int charge A . gn;
PS pe on as shown in the diagram below. Tuga
are ne!
Qe
Qe enna O@---+-+~_

ox ™ Y en,
bboy halfway between Qx and Q2.

Which ONE of the following combinations gives the correct direction of the m
electric field due to the presence of the charges Qi and Q2 at positions x y and

Z respectively?
X ¥: ae
A Right Left 3 _ Right ~~
B Right Right : Left
Cc Left Right Right
2 Left Right Left
Bern 0

### Page 6

Physical Sciencesip4

Downloaded from Stanmorephysies.com LimpopoDoE/September 2023
1.8 In the given

Circuit di
IDENTICAL. cuit diagram below, the three light bulbs Li, L2 and Ls are

= PRE-€are readings on the ammeters in the circuit.

2)

tf
i)
C

a

Which ONE of the following mathematical equations is CORRECT?

A Y=X-Z
B X=3Y
Cc X=Y+Z

D X=Y-Z (2)

### Page 7

8
Dawaleedat! from Stanmore}ifysics.com

sents the output of an AC Generator. 7 ;
re: me generator after a Change his

below reP!
49  Thesolidline inthe graph output of the $4

dotted line represents
been made to the gene

rator.

——>
Times (s)

Which ONE of the following could be the change made to the generator?

A The number of turns on the coil was halved.

B The strength of the magnetic field was halved.
C The speed of rotation of the coil was halved,
D

The surface area of the Coil was doubled.

Q)

### Page 8

Physical Sciences/P4

Sei LimpopoDoE/September 2023
Downloaded from Stanmorephysics.com
10

The diagram below indicates an i
energy level diagram that i
the four energy levels in an atom. ° eae

4
| Es
8 - E2
fl ls |
2 Ei
y | P

Eo

Which ONE of the four energy transitions has the SHORTEST wavelength?

A P

B Q

Cc OR

D 6S (2)
[20]

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### Page 9

tart on a new page)

aussHge Ged from Stanmorgahssiieneduaiined at an angle of 30° to the

S|
k of mass 2 kg is
i oot as shown in the diagram below

ion px between the block and the plane is 0,20.

The coefficient of kinetic fricti

231.1 Define the term kinetic frictional force. (2)

2.12 Draw a labelled free-body diagram for the block whilst in motion. (3)

2.1.3. Calculate the acceleration of the block. (5)
2.2 In two adjacent buildings of the same size, the two walls nearest one another

are 7 m apart and the walls furthest from one another are 35 m apart, as the
diagram below illustrates.

Use an appropriate calculation to show thatthe gravitational fore thatthe vo

inner walls exert on each other is 25 times bigger than that of the two outer

walls on each other (i.e. Fatinner walls) = 25 x Fg(outer walls))

(14)

### Page 10

Physical Sciences/P1_ 5 1
Si

ol QrsRrAechefcR'D nab daRGrePhySics.com

A mountain climber throws two identical stones from a high cliff to a Pool of water which
is 50 m below the cliff. The first stone A is thrown vertically downwards with an initial
vertically downwards with a velocity of 2 mUs-'. After 1 s, the second stone is thrown an
unknown velocity, Both stones A and B reach the water surface of the pool at the same

time.

LimpopoDoE/September 2023

50m

Ve alew 7

S

= zy
Sg ba?

Pl

__Water surface

Neglect the effects of air resistance.
3.1 Explain what is meant by a projectile.
3.2 Calculate, by using THE EQUATIONS OF MOTION, the:

3.2.1. Time taken by stone A to hit the water

3.2.2 Time taken by stone B to hit the water
(1)

(3)

3.2.3 Initial velocity of stone B

### Page 11

12

Cc.
Downloaded from Stanmore fi SicS.com ,, ?
y: ‘fion-versus-time graphs for the motions
xes, Positions fr i
ao oa ane sae! that they are thrown until they hit the water
of the two stones
\ P ERENCE.
elisa SURFACE AS THE ZERO REF

i Ss:
show the values of the following on the graph
e at which the stones hit the water.

« Time at which stone B is thrown. . i
¢ Initial height of the stones above the water surface.

[14]
QUESTION 4 (Start on a new page)
A 0,005 kg bullet is fired horizontally into a 3 kg wooden block resting on a horizontal
. The bullet remains embedded in the block, which is observed to slide 0,25 m
ie surface before stopping.
lo the diagram below).
i + W E
|
| |
| \ .
Before collision After collision
The coefficient of kinetic friction between the block and surface is 0,20
Neglect the effects of air resistance.
41 Is frictional force an EXTERNAL FORCE or INTERNAL FORCE? (")
4.2 State the principle of conservation Of linear momentum j ords. 0
4.3 Calculate the:
4.3.1 Velocity of the block after the bullet has been embedded in it 0
4.3.2

Initial velocity of the bullet before Striking the block i
{it

### Page 12

13

. LimpopoDoE/September 2023
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QUESTION 5 (Start on a new page)

A pulley system with a mass piece is operated by an electric motor. It is used to lift a
load of 120 kg.vertically upwards at a constant speed, as shown in the diagram below.

Light frictionless pulley

125 kg |Load

{io kg |Mass piece

The load covers a distance of 6,8 m in 0,01 seconds.
Neglect all the effects of friction.
5.1 Define, in words, the term power as applied in Physics. (2)

5.2. Calculate the work done by the gravitational force on the load. (3)

§3 Determine the average power output required by the electric motor to lift the
load through 6,8 m in 0,01 seconds. (7)

[12]

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### Page 13

14
NSC

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QUESTION 6 (Start on anew page)

6.1

6.2

k radio awakens him/her with a steady and irritating
Hz One morning, it malfunctions and cannot be turneg

A physics learner's clo
drops the clock radio out of his/her fourth-story

sound of frequency 600
off. Inffrustration, the learner :

the ground.
Oo cron (a8 _ Ignore the effects of air resistance,

do! .
Assuréthe speed of sound is 343 mUs |
L
6.1.1 State the Doppler effect in words. (2)
6.1.2 Calculate the frequency that the learner hears just before the clock
radio strikes the ground. (6)

6.1.3 Explain the change in frequency observed by the learner with

reference to the speed of the clock radio. (3)
A helium line from the spectrum of the sun has a frequency of 6,20 x 10" Hz,
The frequencies of the same helium line from the Earth, which are observed in
the line emission spectrum of two stars, are:
Star X : 6,24 x 1014 Hz
Star Y : 6,04 x 1014 Hz
6.2.1. Which ONE of the stars (X or Y) has a red shift? (1)

6.2.2 In which direction Away from the Earth or Towards the Earth does

star X move? a

[13]

EEE)

### Page 14

15 LimpopoDoE/September 2023
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QUESTION 7 (Start on a new page)

71 A:small sphere X having a mass of 8 x 10? kg and a charge of +6 x 107 C
yangs vertically by a thin wire of negligible mass. When the charge Y
of -9.x.107 Cis brought closer to the sphere, the wire makes an angle 6 to the

vel hen brought to rest 0,15 m away from the charge Y, as shown in the
di below.
ir)
|
|
|
|
|
|
X Y
__--_045m__
“7AM +. State Coulomb’s Law in words. (2)

1 A .2° Draw a labelled free-body diagram for the sphere X when at rest. (3)

~ Calculate the::

7.1.3: Electrostatic force exerted by sphere X on charge Y (3)
744 : “Angle 6 shown in the diagram (4)
S7A.5° Tension in the wire (2)

7.2. Two.point'charges, Qs and Qe, with charges -16 X 107C and +4X 107C
- respectively, are placed 3 m apart as shown in the diagram below.

: |
‘ 7 |
P sm gm | Ent =O NOC"

The net electric field at point P due to the presence of theo point charges, is
ZERO. .

Determine the value of x, shown in the diagram. (5)
[19]

### Page 15

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QUESTION 8 (Start on a new page)

re conducting an experiment to determine the emf (e) ang

Grade 12 Physics learners a tery. They have access to an ammeter but do not haye 9

internal resistance (r) of a bat
voltmeter.

They setup. ircuit shown in the diagram below.

(4) (K)o40

82
8.1 Define the term emf of a battery. (2)
8.2 State the purpose of placing the switch next to the 8 Q resistor. (2)

The results of the experiment are shown in the table below.

AMMETER READING
Switch open 4A
Switch closed 6A

8.3 i
Use the results from the &xperiment to determine the: (use¢= I(R +r)

8.3.1 Internal resistance of the battery

(5)
8.3.2 emfofthe battery

(2)

### Page 16

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8.4

8.5

LimpopoDoE/September 2023

Calculate the:

8.4.1 Power dissipated in the battery when the switch is closed (2)

8.4.2 ac? Energy dissipated in the bulb in 6 minutes when the switch is open (3)

Ho © brightness of the bulb affected when the switch is opened? State
onl HTER, DIMMER or NO CHANGE.
Explain the answer. (3)

[19]

QUESTION 9 (Start on a new page)

The following diagrams show two types of generators

9.1

9.2

Diagram X Diagram Y

(1)

Write down the energy conversion which takes place in a generator.
Write down the type of generator represented by:
9.2.1 Diagram X

(1)
9.2.2 Diagram Y

### Page 17

Physi

9.3

9.4

18

| Sciences/P1 ;
ownloaded from Stanmoreiifysics.com

State the difference between the two generators by referring to the
components, shown in the diagrams, of which they consist. (
otential difference with root-mean-

The generator in diagram Y produces a p

square (' value of 220 V.

9.4.1 fine, in words, the term rms voltage. (2)
9.4.2 Calculate the peak (maximum) potential difference of the generator. (3)
9.4.3. Sketch a graph of potential difference-versus-time to indicate one full

rotation of the coil.

Clearly indicate the values of the following on the graph:

¢ The rms value
* The peak potential difference (3)
[13]

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QUESTION 10 (Start on a new Page)

Ina mi aay effect experiment, the maximum kinetic energy of the photoelectrons
ejected from a certain metal surface is 4,48 x 10-9 J. When the wavelength of the

incident light_is, increased by 50%, the maximum kinetic energy decreases
to 1.76 x 10°

10.1 Defi e term work function of a metal in words. (2)

10.2 Prove, by means of an appropriate calculation, that the work function of the
cathode is 3,68 x 10° J. ®)

10.3 Hence find the initial wavelength of incident light. (2)
10.4 How does EACH of the following affect the maximum kinetic energy of the

photoelectrons?
(State only INCREASES, DECREASES or REMAINS THE SAME).

10.4.1 Using incident light of shorter wavelength (1)

10.4.2 Using a photocathode with a higher work function (1)

10.4.3 Using incident light of greater intensity (1)
[13]

GRAND TOTAL: [150]

### Page 19

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NATIONAL SENIOR CERTIFICATE

These Errata marking guidelines consist of 6 pages.

Copyright reserved please turn over

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Douslcasiedirfirom Stanmorephysics.com Limpopo DoE/September 2023

Errata Marking Guidelines

QUESTION 1
1.10 Accept: letter S
QUESTION 2
2:14 The force fl ppose the motion” of a moving object relative to the surface.” (2)
212: Marks allocation
Fret = ma Any onev
mgsin@ - [x mgcos@ = m
(2)(9,8)(sin 30°)¥ — (0,20)(2)(9,8)(cos 30°) ¥= (2)-av
<a = 3,20259 m:s* (3,20 m-s)downhill¥ (2)
2.2 OPTION 1: OPTION 2:
: 35
Mark awarded for Factor tay= my
Gm4m = PY m
F g(inner walls) = ae 2 ~
; _ Gmym2 y
Fg(inner walls) = (2
Gm4m.
Fg(inner walls) = 1 ev
zt)
Gm4m.
Fog(inner walls) = = 2y
Zr
= 95 (Smim2
= 25 ( (nH? )
(4)

Copyright reserved

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Errata Marking Guidelines

QUESTION 3

orl Accept: An object upon which the only force acting is the gravitational force.

3.2.1 OPTION cal OPTION 3:
INO AT

_ (Ve Marks allocation:
Ay= 3

(ee + *)

(50) = At

-.At=2,997s or At = (3,00 s)

st = 2,997 s¥(3,00 s)

3.2.2 | POSITIVE MARKING FROM 3.2.1

At = 2,997 — 1 = 1,997 sv

At = 3,00 — 1 = 2,00 sv
3.2.3 POSITIVE MARKING FROM 3.2.2 FOR:
At=2,00s

Ay = viAt + 3a (At)?
50 = vi(2) + (9,8)(2)?

“Vi = 15,20 mst

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Errata Marking Guidelines

QUESTION 4
4.3.1
Marks allocation:
OPTION 1 OPTION 2:
Fret = ma Any onev’ f= uKN | ny onev
-fk = ma =yKmg
-uxN = ma (0,2)(0,005 + 3)v (9,8)

~(0,20)(0,005 + 3)v (9,8) =(0,005+3)av

“a =-1,96 m-s?

ve = vi2 + 2aAx¥

(0)? = vi? + 2(-1,96)(0,25) Vv

Vi = 0,98995 ms (0,99 m:s")¥

Fx = 5,8898 N, westwards

Wnet = AEKY

fkAxcos0 = ; m (v?-v?)

(5,8898)(0,25) v'cos180°= = (3,00) (0?-v?)v

Vi = 0,99 m:s"', eastwardsY

4.3.2

Marks allocation:

POSITIVE MARKING FROM 4.3.1

Xp, ==Zp,

MpVb,+MgVp,= (Mp - Mg) V1

ny oneY

(0,005)v, +(3)(0) = (0,005+3)(0,98995)”

Vp,= 594,96 m-s"' Eastwards. ¥

QUESTION 5

5.2 OPTION 1 and 2:

Consider m = 120 kg:

w = FAycos@

Any one¥
Ww = mgAycos@

= (120)(98)cos180°V
= -7996,80 Jv

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(6)

(4)

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Bowileadedpirom Stanmorephysics.com Limpopo DoE/September 2023

Errata Marking Guidelines

§:3
POSITIVE — 5.2
OPTION 2: an? OPTION 3: OPTION 4:
Consider mass = 120 kg: (m = 120 kg) Fnet = ma = 0
Fret = ma = 0 Wmotor+(120)(9,8)-(100)(9,8) = 0

Whet = AExY
Wmotor + 6664 - (8330) =0

Wmotor + Fmp + (-Fioad) = 0 ¥

Womotor+(125)(9,8)”—-(100)(9,8)¥=0

Fmotor = 196 N

Womotor = 1332,80 J Fmotor = 245 N Nae — A
6.8
pow _ ax ~ 0,01
At Vave = 77 = 680 m-s”
_ 1332,80 - 68 /
0,01 0,01 Pave = FVave
= 680 m-s? = (196)(680)
= 1332 80 W = 1332 80 W
Pave = FVave
= (245)(680)
= 166600 WY
QUESTION 6
6.1.2 OPTION 2: OPTION 3: OPTION 4:
For calculating vs: ve = vi + 2Zady FnetAt = Ap
' =(0)? + 2(9,8)(15,0 mg-At = m(Vj - VF)
ay= (“*)at (OF * 2081.0) | 6'8y1,7496) = vi -0
2, vi= 14 m-s* vi= 14 m-s™
Vi
15,0= (78) 1,7496)0
vi = 14 m-s"
6.1.3 Bullet 3:

Frequency heard by the listener decreases.

Copyright reserved

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Errata Marking Guidelines

QUESTION 7
7.1.3 k=9x10°

7.1.4 POSITIVEJMARKING FROM 7.1.3 OPTION 3:

lan

Fe w= mg
= (8 x 102)(9,8)
w= 0,764.N

Copyright reserved please turn over

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