# Physical Sciences Grade 12 Paper 1 MP Mock 2023 Paper & Memo

> Grade 12 Physical Sciences Paper 1 question paper and memo from the MP Mock Exam 2023, 36 pages. Read online or get the free PDF download.

- Page: https://www.hlayiso.com/library/grade-12-physical-sciences-2023-mp-mock-exam-question-paper-and-memorandum-paper-1/c2d03552-5382-4c06-841e-d94bf4d28ccf
- Updated: 2026-09-28
- Subject: Physical Sciences
- Grade: Grade 12
- Document type: Question paper and memo
- Year: 2023
- Exam period: MP Mock Exam
- Paper: 1
- Curriculum: CAPS
- Pages: 36

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## About this document

Physical Sciences · Grade 12 · MP Mock Exam · 2023. Question paper and memorandum, 36 pages. Read online or download the PDF.

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### Page 1

— — ——
a — —_——

+ education

DEPARTMENT: EDUCATION
MPUMALANGA PROVINCE

NATIONAL

MARKS: 150

TIME: 3 hours

This question paper consists of 21 pages including 3 information sheets.

Ploase tun aver

Copypngn reversed

—————— ———

### Page 2

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| Sci s/P °
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MDE/September 2023

INSTRUCTIONS AND INFORMATION

ue

2.

10.

Ns

12.

Write your name on the ANSWER BOOK.

This question paper consists of ELEVEN questions. Answer ALL the questions
in the WER BOOK.

Start H question on a NEW page in the ANSWER BOOK.

Nu lhe answers correctly according to the numbering system used in this
question paper.

Leave ONE line between two subquestions, e.g. between QUESTION 2.1 and
QUESTION 2.2.

You may use a non-programmable calculator.

You may use appropriate mathematical instruments.

Show ALL formulae and substitutions in ALL calculations.

Round off your FINAL numerical answer to a minimum of TWO decimal places.
Give brief motivations, discussions, etc. where required.

You are advised to use the attached DATA SHEETS.

Write neatly and legibly.

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Physical Sciences/P1 MDE/September 2023
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QUESTION 1: MULTIPLE CHOICE QUESTIONS

Various options are provided as possible answers to the following questions. Choose
the answer and write only the letter (A-D) next to the question number (1.1 to 1.10) in
the ANSWER BOOK, e.g. 1.11 D. Each question has only ONE correct answer.

11 Which O f the following groups of physical quantities are vectors?
A eration, speed and velocity
B Mass, distance and acceleration

Cc Acceleration, force and velocity
D Electric field, current and charge (2)

1.2 In which ONE of the following cases is the resultant force acting on an object
equal to zero?

A An object moving with constant acceleration.
B When the only force acting on the object is the gravitational force.

[o} An object undergoes equal displacements every second.

D An object moving with increasing acceleration. (2)
1.3 Which ONE of the examples stated below best describes weightlessness?
A An object accelerates downwards towards the Earth at an acceleration
of 9,8 m.s®.

B An object moving at a constant velocity upwards away from the
ground.

Cc An object moving at constant velocity downwards towards the ground.

D An object that is accelerated upwards away from the ground by a
constant applied force. (2)

Naas
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1.4 The graph below indicates the net force exerted on an object over a period of
time.
a

Fret (N)

At(s)

The area under the graph represents the .....of the object.
A momentum

B impulse

Cc rate of change of momentum

D acceleration (2)

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1.5 An object is dropped from a height, h, above the ground level. Ignore the effects
of air resistance.

Which ONE of the following graphs represents the relationship between kinetic
energy, Ex, and the height, h, above the ground the BEST?

Ex Ex

(2)

1.6 Which ONE of the following describes the effect of the Doppler shift on the
spectral lines if the star moves AWAY from the earth?

The spectral lines...

A shift to the red end of the spectrum.
B shift to the blue end of the spectrum.
Cc appear more dim.
D

show no change at all. (2)

, Piedad lin aver
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1.7. Two identical charges are placed a distance r from each other in a vacuum.
Charge Q1 experiences an electrostatic force F due to charge Qz. The charge on
Q2 and the distance between the charges is changed.

5

—_——=}
ae cS
CT Cast!
Which ONE of the following combinations will result in a force of 16 F exerted on
Qi?
Charge Q2 Distance r
A Ye Qa 2r
B 4Q2 Yer
[e} 2Q2 Yer
D 8Q2 2r
(2)

1.8 Three identical bulbs are connected to a cell with internal resistance.The switch
S is CLOSED as shown in the circuit diagram below.

Switch S is now opened.

Which ONE of the following gives the CORRECT changes observed on the
ammeter and voltmeter?

AMMETER READING VOLTMETER
READING
A Increases Increases
B Increases Decreases
Cc Decreases Decreases
D Decreases a Increases (2)

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1.9 In the graph below the solid curve shows how the emf produced by a simple

generator changes with time. The broken curve shows the output of the same
generator had been made to the generator.

Which change has been made to result in the broken curve?

A

B
c
D

Copyngi fevered

The number of windings in the coil is doubled.
The speed of rotation is doubled.
A split ring commutator is added.

The strength of the magnets is doubled. (2)

Pladoe Niet ower

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1.10 The diagram below shows the possible transitions of electrons between
ENERGY LEVELS (E: to Es) in an atom of a specific element.

Es

E;

Which transition will produce the line of the SHORTEST WAVELENGTH on the
emission spectrum of the element?

A Transition a
B_ Transition b
C_ Transition c

D_ Transition d (2)

[20]

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QUESTION 2 (Start on a new page.)

MDE/September 2023

Block A with mass 4 kg, that is at rest on a rough horizontal table, is connected to
another block B with mass 8 kg by a light inextensible string passing over a frictionless

pulley.

A force F; of itude 96 N is applied vertically upwards on block B as shown in the

diagram belo’

Fi=96N

8kg

A force Fz of magnitude 75 N is now applied at an angle of 25° with the horizontal on
block A and the block accelerates to the left. The kinetic frictional force on block A is

11,76 N. Ignore the effects of air friction.

2.1 State Newton's Second Law of Motion in words.
2.2 Draw a labelled free-body diagram for block A.
2.3 Calculate the magnitude of the:

2.3.1 Acceleration of block A

2.3.2 Tension in the rope connected to block A

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(2)
(5)

(5)
(2)
[14]

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QUESTION 3 (Start on a new page.)

The position-time graph for a ball thrown vertically downwards from the top of a 48 m

MDE/September 2023

high building is shown below. The ball bounces off the ground, reaching a maximum

(2)

(4)
(3)
(3)

height of 8 m.
Ignore the effe air resistance and the contact time with the ground. The graph is not
drawn to scal
E
c
2
=
Q
ok at eel cl renee alla em aebow
a
Time (s)
3.1 Explain what is meant by a projectile.
3.2 Calculate the speed with which the ball:
3.2.1 is thrown downwards
3.2.2 hits the ground
3.2.3. bounces upwards from the ground
3.3 Draw a velocity-time graph for the entire motion of the ball.

Indicate the following on your graph:

(i) initial wele which the ball was thrown

the ball hits the ground

ball to hits the ground

hich the ball bounces off the grou

(iii) time
(iv) the

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(4)
[16]

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QUESTION 4 (Start on a new page.)

MDE/September 2023

A tennis ball with a mass of 15,5 g strikes a stationary 8,45 kg block with a speed of
45 m:s"' and bounces straight back with a speed of 10,60 m-s‘'. The block moves
1,32 m to the right as indicated in the diagram below.

41 State the principle of conservation of linear momentum in words.
4.2 Calculate the magnitude of the:
4.2.1. Velocity of the block immediately after collision

4.2.2

Copyright reserved

Frictional force between the block and the table if the block moves

1,32 m before coming to rest

lz

Please tum over

(2)

(4)

(5)
{11}

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QUESTION 5 (Start on a new page.)

A child with a mass 50 kg on a board mass 3 kg slides from rest down a sand dune. The
sand dune has an angle of 30° with the horizontal and a height of 35 m.
The coefficient iction between the board and the sand is 0,45.

gat

c
5.1 Define the term non-concervative force. (2)
5.2 Draw a labelled free-body diagram for the child and the board at point B. (3)

5.3 Calculate the frictional force that the child and the board experience as they (3)
slide down the sand dune.

5.4 State the work-energy theorem in words. (2)
5.5 Calculate the final velocity that the child and board have when they reach (5)
point B.
[15]

Cap yng teverved Plgase tun aver

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QUESTION 6 (Start on a new page.)

A siren of a stationary train emits sound waves of a constant frequency of 780 Hz. A
person in a car with a detector accelerates constantly from rest at point X towards the
train. Take the speed of sound in air as 340 m:s"'.

—_—
—® —@e
; 83,11 m _____Y
6.1 Name the phenomenon that was observed by the listener. (1)
6.2 Calculate the wavelength of the emitted sound waves. (2)
6.3 Explain why the observed frequency is higher than the emitted frequency. (2)

At point Y, 83,11 m from point X, the person in the car measures an observed
frequency of 850 Hz.

6.4 Calculate the:

6.4.1 speed of the car at point Y (5)
6.4.2 acceleration of the car (3)
[13]

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QUESTION 7 (Start on a new page.)

Sphere N, with charge -30 UC, is placed on an isolated stand. Sphere M, with charge
-20 uC hangs on an inextensible string from a horizontal beam and is a distance of 80 cm
from sphere shown in the diagram below.

7.1. State Coulomb's Law in words. (2)
7.2 Drawa labelled free-body diagram for sphere M. (3)

7.3 Calculate the magnitude of the:

7.3.1 electrostatic force between the two spheres (3)
7.3.2 tension T in the string if the mass of sphere Mis 90 g (4)
[12]

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QUESTION 8 (Start on a new page.)

Two small spheres, A with a charge of +5 nC and B with a charge of-4 nC respectively,
are placed a certain distance from each other in a vacuum as shown in the diagram
below.

A
+5 nC -4nCc
8.1 Define the term electric field in words. (2)
8.2 Draw the electric field pattern between spheres A and B. (3)

P is a point LEFT of spheres A and B. Point P is at a distance r from sphere A and
sphere A is at a distance 3r from sphere B as shown in the diagram below. The net
electric field at point P is 4128 N-C*' west.

N
P B
ee ae | nk ce ry wel> E
+5 nC -4nc S
8.3 Calculate the value of r. (6)

(14)

,
Copying (euerved Plodae lun ower

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NSC
QUESTION 9 (Start on a new page.)
A battery with an internal resistance of 0,5 Q and emf (€) of 24 V is connected to four
resistors , a closed switch, a high resistance voltmeter(V) with 22,3 V and ammeter of
negligible resi ce, as shown in the diagram below.

The resistan the connecting wires must be ignored.

Ss
30
9.4 Explain the term emf of 24 V with reference to work done. (2)
9.2 Calculate the:
9.2.1 Current in the 3 Q resistor (3)
9.2.2 Power dissipated in the 18 Q resistor (5)
9.2.3 Current in resistor R (4)

Resistor R_ is removed from the circuit.

9.3 Will the power dissipated in the 18 Q resistor INCREASE, DECREASE or
REMAIN THE SAME? Explain the answer. (3)

(17)

Copyngil teberved Vischoet TH wens

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QUESTION 10 (Start on a new page.)

MDE/September 2023

The simplified diagram below represents an alternating current (AC) generator.

10.1 Write down the energy conversion that occurs in an AC generator. (2)

10.2 Which structural change must be done to the components of the AC generator (1)
to change it into a DC generator?

A3 Q resistor is connected to the AC generator.

10.3 Calculate the maximum current that flows through the resistor if the resistor has
an average power of 100 W. (5)

(8]

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QUESTION 11 (Start on a new page.)

Learners conduct an experiment to investigate the photoelectric effect.Metal disc M is
irradiated with three light sources of different wavelengths and the results obtained are

noted in the ew

Light length | Emission of photoelectrons
source ‘8 m)
A 77480 Photoelectrons emitted that move away from metal
B 620 No photoelectrons emitted
¢ 570 Photoelectrons emitted and do NOT move away from metal
141.1 Define the term work function in words. (2)

11.2 Explain why light source A releases photoelectrons from the metal disc M, but not
light source B. (2)

11.3. Calculate the:
11.3.1 Work function of metal M (3)

11.3.2 Speed with which the photoelectrons are moving if metal disc M is (5)
irradiated with light source A

11.4 Light source Ais BLUE light and light source B is ORANGE light. Which colour of
light is light source C? Choose between VIOLET, GREEN or RED. (1)

[13]

TOTAL:150

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Physical Sciences/P1

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19

MDE/September 2023

DATA FOR PHYSICAL SCIENCES GRADE 12

PAPER 1 (PHYSICS)

GEGEWENS VIR FISIESE WETENSKAPPE GRAAD 12

VRAESTEL 1 (FISIKA)

TABLE 1: PaeaPAL CONSTANTS/TABEL 1: FISIESE KONSTANTES

NAME/NAAM SYMBOL/SIMBOOL | VALUE/WAARDE
Unherooe iraviasiohonstan Rar nto Nae ha"
Cocke bs wrestle : Serene
bedi co. menen : =e
oatmeal Me 9,11 x 10°" kg
Padlus van die Aarde Pe sala

Lagi fopetved

Mleoe lit aver

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Physical WiaaeY from Stanmorepitysics.com MDE/September 2023

TABLE 2: FORMULAE/TABEL 2: FORMULES

MOTION/BEWEGING

vy =v, +aapaal Ax=v,At+tadt® or/of Ay =v At+taat?

. v, +V itv,
at we +2 oot v? =v! + 2aty Ax = ( 1 +a or/of Ay = (“st 2 seat

FORCE/KRAG

Fret = Ma p=mv
iO =pN f,_ =1,N
F,,At=Ap
w=mg
Ap =mv, — mv,
F= ot oof =F= qe g -a4 or/of g wigs.

5 r

WORK, ENERGY AND POWER/ARBEID, ENERGIE EN DRYWING

W-=Faxcos@ U=mgh oof E,=mgh
Wrer =AK —orfof Wye, = AE,

K=3mv? oof =E, =3mv
AK=K,-K, Orof AE, =E,, -E,
Ww
W,. =AK+AU or/of W,, = AE, + AE, pas
Pos = FV sve / Poemis * FV cemis

WAVES, SOUND AND LIGHT/GOLWE, KLANK EN LIG

vat, Ts

—i4

viv,
viv,

{, oof {,=~2“44, |E=ht orf Eq
vt

b

f,=

E=W, +E yay) offof E = W, +K,,,, where/waar

unas) mae ka mas

E=ht and/en W, =hf, and/en E - Snvi or/of K,. = ala

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Physical Sciences/P1

21

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ELECTROSTATICS/ELEKTROSTATIKA

ve
q Fevey

n=

n= 2 =
e

Q

ELECTRIC CIRCUITS/ELEKTRIESE STROOMBANE

emf (£) = I(R+1)

R=~
emk (£) = I(R +r)
R, =R, +R, +
R, R, R,
w-Vq Paw
At
W-VIAt
P=VI
W=FPRAt
vi P =I'R
=-— 2
= po
R

ALTERNATING CURRENT/WISSELSTROOM

I , Pee =Veslims Poems = Var Ly
Jing = / Vgk = maks
v2 2 TPA! Pr = ER
V, V,
Ving == / Vi, =—ms. 2 2
2 mb Pet iP -

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MDE/September 2023

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education

DEPARTMENT: EDUCATION
MPUMALANGA PROVINCE

NATIONAL
SENIOR CERTIFICATE
NASIONALE
SENIOR SERTIFIKAAT

GRADE/GRAAD 12

PHYSICAL SCIENCES: PHYSICS (P1)
FISIESE WETENSKAPPE: FISIKA (V1)

SEPTEMBER 2023

MARKING GUIDELINES/NASIENRIGLYNE

MARKS/PUNTE: 150

These marking guideline consists of 14 pages

Hierdie nasienriglyne bestaan uit 14 bladsye

Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

### Page 23

Physoowiealeondad wheekapstanmorephysics.com ——_ mpu/september 2023

NSC/NSS-Marking Guideline/Nasienriglyn

QUESTION 1 / VRAAG 1

11. Cvv (2)
12 Cvv (2)
13° Avv (2)
14. BYv (2)
15 Dvv (2)
16 Avy (2)
17 Byv (2)
18 Cvv (2)
19 BYv (2)
1.10 Dvv (2)

[20]

Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

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Physluosaalegrdiad weteerapstanmorephysics. com MPU/September 2023

NSC/NSS-Marking Guideline/Nasienriglyn

QUESTION 2/ VRAAG 2

2A

22

Copyright reserved/Kopiereg voorbehou

Marking criteria/Nasienkriteria

If any one of the underlined key words/phrases in the correct context is omitted,
deduct 1 mark. /indien enige van die onderstreepte sleutelwoorde/frases in die
korrektejkonteks uitgelaat is, trek 1 punt af.

When a netforce acts on an object, the object will accelerate in the direction of
Sand the acceleration is directly proportional to the resultant/net force

'sély proportional to the mass of the object. vv

Wanneee-n resulterende/netto krag op 'n voorwerp inwerk, versnel die voorwerp
in die rigting van die krag teen 'n versnelling direk eweredig aan die
resultante/netto_krag en omgekeerd eweredig aan die massa van die voorwerp.
OR/OF

The resultant/net force acting on an object is equal to the rate of change of
momentum of the object. (2 or 0)

Die resulterende/netto krag wat op ‘n voorwerp inwerk is gelyk aan die tempo
van verandering van momentum. (2 of 0)

Fv a

Tv

fv

wv

Accepted labels / Aanvaarde benoemings

w Fg / Fw/ force of earth on block / weight / mg / gravitational force /
VALUE

F Fapplied / Fa / Applied force

T Tension in rope / Fr

F Firiction / Fr / frictional force /

N Normal force / Fn

Notes/Aantekeninge:
e Mark awarded for label and arrow.
e Any additional forces: deduct 1 mark: max She

e No labels: deduct 1 mark: max4/.
e If everything correct, but no arrows: deduct 1 mark: 4/,
e Force(s) not touching object: deduct 1 mark: max 4/5
e Ignore relative sizes of the vectors

(2)

(5)

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Physlosatalegndiad whteesxapstanmorephysics.com

2.3.1

2.3.2

NSC/NSS-Marking Guideline/Nasienriglyn

MPU/September 2023

Marking criteria/Nasienkriteria:
e Formula for block A or block B ¥

e Substitution of Fnet for block A v
e Substitusion of Fnet for block B v

For Block B:

Fnet =. mat, Fnet = ma
eS noe a anyone fee) = ma
(75)cos25 —T — 11,76 Vv = 4a v 18,4 + T-96 v= 8a
56,21 -T =4a T -17,6=8a

T =-4a +56,21 T=8a+17,6

- -4a + 56,21 = 8a+ 17,6
12a = 38,61
a=3,22ms?v

POSITIVE MARKING FROM QUESTION 2.3.1
Marking criteria/Nasienkriteria:
e Substitution to calculate T ¥

e Answer v

For Block A: For Block B:

T = -4a +56,21 T =8a+ 17,6
= (-4)(3,22) + 56,21 v = (8)(3,22) + 17,6
= 43,33 NV = 43,36 N

QUESTION 3/ VRAAG 3

3.1

3.2.1

Copyright reserved/Kopiereg voorbehou

An object which has been given an initial velocity and then it moves under the

influence of the gravitational force only. ¥ Y (2 or 0)

'n Voorwerp waaraan 'n beginsnelheid gegee is en wat dan slegs onder die

invioed van die gravitasiekrag beweeg. (2 or 0)

Upwards positive/ Downwards positive/
Opwaarts positief: Afwaarts positief:
Ay = viAt + Yalt? v Ay = viAt + “alt

-48 v = vi(2,8) + % (-9,8)(2.8)? v
vi = -3,42
vi = 3,42 m-s? v

(5)

(2)
[14]

(2)

(4)

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MPU/September 2023

NSC/NSS-Marking Guideline/Nasienriglyn

3.2.2 | POSITIVE MARKING FROM QUESTION 3.2.1
POSITIEWE NASIEN VANAF VRAAG 3.2.1

Upwards Positive/
Opwaarts positief

OPTION 1

Upwards Positive/ Downwards Positive/
Opwaarts-positief Afwaarts positief

Vr = vi taAby v= vi ta At ¥

ve = -3 vr = 3,42 + (9,8)(2,8) Vv
v= -30,86)m-s"!

Vr = 30,861m-s! Vv vr = 30,86 ms? ¥
OPTION 2

Downwards Positive/
Afwaarts positief

ve = vi? + 2a Ay ¥

ve? = (3,42)? + 2(9,8)(48) ¥
vi = 30,86 m-s? v

OPTION 3

Upwards Positive/

Opwaarts positief
+y;

Ax= ele Atv

- 3,42
-48= —_— 2,8 V

vr = -30,87 m-s*
vr = 30,87 ms? v

Downwards Positive/
Afwaarts positief

VEtV;
( f ) at

+ 3,42
4g= 34), 3 v

vr = 30,87 m-s? ¥

OPTION 4
(Em)a = (Em)B

Anyone Vv

(mgh + Yamv2)a = (mgh +% mv2)e Enige een

m(9,8)(48) + % m(3,42)? = 0 + “mv? ¥

v = 30.86 mst v

9,8)(2,9) = vi— 3,42 v
v = 30.86 ms? v

OPTION 5

Fret At = Ap

Fret-At = mvs — mvi Anyone ¥
mgAt = mvr— mvi Enige een
gAt= w—-vi

(3)

3.2.3 | Upwards positive /
Opwaarts positief
ve = vi? + 2a Ay ¥
0 = vi? + 2(-9,8)(8)”
vi= 12,52 m-s'¥

Downwards posi
Afwaarts positie’
ve = vi2 + 2a Ay
0 = v2 + 2(9,8)(-8):
vi= 12,52 m-s1v

(3)

Copyright reserved/Kopiereg voorbehou

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Physoowienlegndad wheekapstanmorephysics.com —— mpu/september 2023

NSC/NSS-Marking Guideline/Nasienriglyn
3.3. | Marking criteria/Nasienkriteria:
e Initial velocity with which the ball was thrown (3.2.1) “

e Beginsnelheid waarmee bal gegooi is

e Final velocity with which the ball hit the ground (3.2.2) Vv

e Ejndsnelheid waarmee die bal die grond tref

° Time taken to hit the ground (2,8 s)”

¢ Tydjom die grond te tref (2,8 s)

. The velocity with which the ball bounces off the ground — line parallel to
“other line (3.2.3) v

e Die snelheid waarmee die bal van die grond as bons — lyn parallel met

ander lyn
POSITIVE MARKING FROM/POSITIEWE MERK VANAF 3.2.1., 3.2.2 & 3.2.3

UPWARDS POSITIVE/OPWAARTS POSITIEF

12,52 /------------------

At (s)

V (ms)

-3,42

-30,86

DOWNWARDS POSITIVE/AFWAARTS POSITIEF

30,86

3,42

V (m-s*)
i=}

-12,52

‘ (4)
[16]

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NSC/NSS-Marking Guideline/Nasienriglyn
QUESTION 4/ VRAAG 4

4.1 Marking criteria/Nasienkriteria

If any one of the underlined key words/phrases in the correct context is
omitted, deduct 1 mark. /Indien enige van die onderstreepte
sleutelwoorde/frases in die korrekte konteks uitgelaat is, trek 1 punt af.

The total{linear) momentum of an isolated/closed system remains constant/is

Die totaléi(lineére) momentum in 'n geisoleerde sisteem bly konstant/behoue.
= (2)

4.2.1 | TAKE TO THE LEFT AS POSITIVE/NEEM LINKS AS POSITIEF
Zpi = Zpr

(mvi)1 + (mvi)2 = (mvs)1 + (mvs)2

(0,015)(-45) + (8,45)(0) v = (0,015)(10,60) + (8,45)(vr) v

v=-0,10 ms

v=0,10 mst ¥

TAKE TO THE RIGHT AS POSITIVE/NEEM REGS AS POSITIEF
Zpi = Zpr

(mvi)1 + (mvi)2 = (mve)1 + (mve)2

(0,015)(45) + (8,45)(0) v = (0,015)(-10,60) + (8,45)(vs) ¥

v= 0,10 ms? ¥ (4)

} v Any one/enige een

v Any one/enige een

4.2.2 | POSITIVE MARKING FROM QUESTION 4.2.1
OPTION 1

ve = vit + 2a Ay

02 v= (0.10)? + 2(a)(1,32)¥

a =-0,00378 m-s? (a= -3,79 x10 m-s*)

Fret = mav

f = (8,45)( - 0,00378) v

f=0,03 Nv

POSITIVE MARKING FROM QUESTION 4.2.1
OPTION 2

ve = vi? + 2a Ay

0? = (0.10)? + 2(a)(1,32)”

a =-0,00378 m:s? (a= -3,79 x10 m-s*)

ve =vita At
0 = 0,10 + (- 0,00378) At
At = 26,39 sv

Fret-At = mv — mvi ¥

(26.39) = (8,45)(0) — (8,45)(0,10) v
f=-0,03N

f =0,03 Nv

(5)
[11]

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Physlowatalemndiad whteexapstanmorephysics.com

NSC/NSS-Marking Guideline/Nasienriglyn

QUESTION 5/ VRAAG 5

5.1

5.2

5.3

5.4

5.5

Copyright reserved/Kopiereg voorbehou

MPU/September 2023

Marking criteria/Nasienkriteria

If any one of the underlined key words/phrases in the correct context is
omitted, deduct 1 mark. /Indien enige van die onderstreepte
sleutelwgorde/frases in die korrekte konteks uitgelaat is, trek 1 punt af.

A force forwhich the work done in moving an object between two points
depends‘on the path takenv v

‘n Krag-waarvoor die arbeid verrig om 'n_voorwerp tussen twee punte te
beweeg, afhanklik is van die roete wat gevolg word.

Nv
fv

wv

Accepted labels / Aanvaarde benoemings

w Fg / Fw/ force of earth on block / weight / mg / gravitational force /

f Firiction / Fr / frictional force

N Normal force / Fn

fk = pxN ¥ N= Fot
= (0,45)(449,81) v = (53)(9,8)cos30°
= 202,42 Nv = 449,81 N

Marking criteria/Nasienkriteria

If any one of the underlined key words/phrases in the correct context is
omitted, deduct 1 mark. /Indien enige van die onderstreepte
sleutelwoorde/frases in die korrekte konteks uitgelaat is, trek 1 punt af.

The net work done on an object is equal to the change in kinetic energy of the

object. vv

Die netto arbeid verrig op 'n voorwerp is gelyk aan die verandering in kinetiese
energie van die voorwerp OF die arbeid verrig op die voorwerp deur 'n netto

krag is gelyk aan die verandering in kinetiese energie van die voorwerp.
POSITIVE MARKING FROM Q5.3

OPTION 1
Whet = AEx
fAxcosQ + NAxcosO + FgAxcosO = Yamvi*? — Ymvi2 ¢
(202,42)(35)cos180°V + 0 + (53)(9.8)(35)cos60° Vv = %4(53)v"? VY —0
ve = 8,70 mst ¥

(2)

(3)

(3)

(2)

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NSC/NSS-Marking Guideline/Nasienriglyn

OPTION 2

Whe = AEk + AEp } Any one Y

fAx cosO= [Yamvi* — Yamvi? ]+ [mghr— mghi]

(202,42)(35)cos180°v = [74(53) vi v— 0] +[(53)(9,8)(17,5) — (53)(9,8)(35)1”

v= 8,70m-s" ¥ (5)
[15]

QUESTION 6 G6

6.1 Doppler effect / effek (1)

6.2 v=fA
340 = 780A Vv
A=0,44mv

(2)

6.3. Waves in front of source are more compact/ wavelength decreases Vv
More waves per second reaches the listener v

Golwe voor die bron is meer kompak/ golflengte neem af
Meer golwe per sekonde bereik die luisteraar

(2)
6.4.1
VEVL v
ape as =—_
f= aagis” OR f= cfs
340 + vy
v=( ———_ Vv v
850 34040 780
v_ = 30,51 ms! ¥ (5)
6.4.2 vi = vit + 2aAy Vv
(30,51) = 0? + 2a (83,11) ¥
a=5,60 ms? v
(3)

[13]

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NSC/NSS-Marking Guideline/Nasienriglyn

QUESTION 7 / VRAAG 7

Tal

7.2

Copyright reserved/Kopiereg voorbehou

Marking criteria/Nasienkriteria

If any one of the underlined key words/phrases in the correct context is
omitted, deduct 1 mark. /indien enige van die onderstreepte
sleuteloGrde/frases in die korrekte konteks uitgelaat is, trek 1 punt af.

Not itmasses used ( %, )

The magnitude of the electrostatic force exerted by one point charge (Q,) on
another point charge (Q,) is directly proportional to the product of the

magnitudes of the charges Y and inversely proportional to the square of the
distance (r) between them v

Die grootte van die elektrostatiese krag wat een puntlading (Q,) op 'n ander

puntlading (Q,) uitoefen, is direk eweredig aan die produk van die groottes van

die ladings v en omgekeerd eweredig aan die kwadraat van die afstand (r)
tussen hulle. ¥

Tv

Fe v
Fg v
Accepted labels / Aanvaarde benoemings
Ww Fg / Fw/ force of earth on block / weight / mg / gravitational force / 0,392
N
Fe Electrostatic force
T Tension in rope / Fr

Notes/Aantekeninge:
e Any additional forces: deduct 1 mark: max 2/5

¢ No labels: deduct 1 mark: max 2h,
* No arrows: 9/,

e Force(s) not touching object: deduct 1 mark: max 2/3
e Ignore relative sizes of the vectors

(2)

(3)

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NSC/NSS-Marking Guideline/Nasienriglyn

7334 R= rev

_(ox0?) (30 x 10°) 20 x 10°)

agp O87
F=8 al (8,4375 N)
7.3.2 | Fg = —
= (0,09)(9,8)
= 0,882 Nv

T2=Fe2 + Fg? v
= (8,44)? + (0,882 v
T=8,49NV

QUESTION 8 / VRAAG 8

8.1 Marking criteria/Nasienriglyne:
-1 mark for each of the 3 key words omitted in the correct context.
-1 punt vir elk van die 3 sleutelwoorde weggelaat in die korrekte konteks.

The electric field is an area in space where an electric charge experiences a

force. vv
Die elektriese veld is ‘n gebied in die ruimte waarin ‘n elektriese lading ‘n krag
ondervind
8.2
Criteria for sketch/Kriteria vir skets Marks/Punte
Correct shape as shown. v
Korrekte vorm soos getoon. 1
Direction away from positive to negative. v
Rigting weg van positief na negatief.
Field lines start on spheres and do not cross for correct al v
diagram.
Veldlyne begin op elke sfeer en kruis nie vir korrekte diagram.

(3)

(4)
[12]

(2)

(3)

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NSC/NSS-Marking Guideline/Nasienriglyn

83 | Ene =E, + E>
Enet = “2 - "ev (Mark for/Punt vir ~)

9 9 9 -9
CRD 9x107)(5x10 dy _ vy Gxi0 )(4x10 dy

1 (4r)?
4128 = —
= 72 Tort
r =0,10m¥ (6)
[11]
QUESTION 9/ VRAAG 9
9.1 24 Joule” per unit coulomb charge work done. ¥
Arbeid van 24 Joule per eenheid coulomb lading (2)
2. lost V
9.2.1 = es y
I= 24-223
0,5
=3,4 AY
(3)
9.2.2 | POSITIVE MARKING FROM Q9.2.1
V30=IR Paen= ve re
= 3,4(3) ¥ 180° R
=10,2V (12.17
Pagn=— 3
Vi = 22,3- 10,2 v _ 18
=12,1V = 8,314 W¥ (5)
9.2.3 POSITIVE MARKING FROM Q9.2.1 & Q9.2.2
Vv Vv
loo= RY hen=R
- 12,1 y - 124
18
=2,02A =0,67A
IR = ltot - Ten - ga
= 3,4 — 2,02 -0,67
=0,71AV (4)

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NSC/NSS-Marking Guideline/Nasienriglyn
9.3 Increase ¥
R (18Q) remains constant, Viincreases v
Current in circuit decreases

P=zVv

QUESTION 10/VRAAG 10

10.1. Kinetic/mechanical energy TO electrical energyY V
Kinetiese/meganiese energie NA elektriese energie

10.2 — Slip rings (AC) and split rings (DC)”
Sleepringe (WS) en splitringe (GS)

(3)
[17]

(2)

(1)

10.3 {OPTION 4 OPTION 2
Pave= Fak v Pave= sR v
100= I245(3)”

Tmax
v= v v
lime = 577A ava

Imax = 8,16AY
Tax v

lee =
rms V2
577 = Tmax v

Imax = 8,16AY

(5)

QUESTION 11 / VRAAG 11

11.1 Marking criteria/Nasienkriteria

If any one of the underlined key words/phrases in the correct context is
omitted, deduct 1 mark. /Indien enige van die onderstreepte
sleutelwoorde/frases in die korrekte konteks uitgelaat is, trek 1 punt af.

The minimum energy that an electron in the metal needs to be emitted from
the metal surface. vv

Die minimum energie benodig om 'n elektron uit die opperviak van 'n metaal
vry te stel..

11.2. Light source A — higher frequency than fo ~
OR Light source B — lower frequency than fo

Ligbron A — hoér frekwensie as fo i
OF Ligbron B — laer frekwensie as fo fact
Wavelength 4 7

Golflengte a F

[8]

(2)

(2)

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MPU/September 2023

NSC/NSS-Marking Guideline/Nasienriglyn

11.3.1

(3)
11.3.2 | POSITIVE MARKING FROM 11.3.1
E = Wot Ex(max)”
“ = Wo + “mv?
334 8,
WY =(3,489x107)v + %4(9,11%10°" yvev
10°m-st v (5)
11.4 Green/Groenv (1)
[13]

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TOTALITOTAAL: 150

### Page 36

Downloaded from Stanmorephysics.com

education

)
DEPARTMENT: EDUCATION
MPUMALANGA PROVINCE

ERRATA PHYISCAL SCIENCES 2023 GRADE 12 TRIAL PAPER 1

Question | Correction
1.5 Answer is A
55) Q5.5 should not be marked; statement was in complete.

BASED ON Q5.5 ABOVE THE TOTAL OF THE PAPER IS NOW 145 MARKS

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