# Physical Sciences Grade 12 KZN March Test 2026 Paper & Memo

> Grade 12 Physical Sciences question paper and memo from the KZN March Test 2026, 21 pages. Read online or get the free PDF download.

- Page: https://www.hlayiso.com/library/grade-12-physical-sciences-2026-kzn-march-test-question-paper-and-memorandum/42512194-7cb6-4f56-8301-2c9b9db0f48e
- Updated: 2026-09-28
- Subject: Physical Sciences
- Grade: Grade 12
- Document type: Question paper and memo
- Year: 2026
- Exam period: KZN March Test
- Curriculum: CAPS
- Pages: 21

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## About this document

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### Page 1

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KWAZULU-NATAL PROVINCE

EDUCATION
REPUBLIC OF SOUTH AFRICA

NATIONAL
SENIOR CERTIFICATE

GRADE 12

MARKS : 100

TIME : 2 Hours

This question paper consists of 10 pages and 4 data sheets

Copyright reserved Please turn over

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March 2026

INSTRUCTIONS AND INFORMATION

1.

10.

11.

This question paper consists of SEVEN questions. Answer ALL the questions in your
ANSWER BOOK.

Start EACH question on a NEW page in the ANSWER BOOK.

Number the answers correctly according to the numbering system used in this question
paper.

Leave ONE line between two sub questions, for example between QUESTION 2.1 and
QUESTION 2.2.

You may use a non-programmable calculator.
You may use appropriate mathematical instruments.

You are advised to use the atta

ed)D SHEETS.

Show ALL formulae an NS L calculations.

Round off your final numeri ers to. a minimum of TWO decimal places.

Give brief motivations, discu et cetera where required.

Write neatly and legibly.

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QUESTION 4

Four possible options are provided as answers to the following questions. Each question has only
ONE correct answer. Choose the correct answer and write the letter (A — D) next to the relevant
question number (1.1 — 1.6) on the answer sheet.

4.1

1.2

1.3

Which ONE of the following physical quantities is the rate of change of
momentum?

A Impulse
B_ Acceleration

C Power
D Force (2)

An object is dropped from thé top of a’tall/building. After time t, the object's
momentum is p. What will enema the object be after time 2t? Ignore
the effect of air friction. ;

A ‘’p

Bp

C 2p

D 3p (2)

A boy pushes a heavy box across a rough floor with a constant force of 250 N.
The box experiences a constant frictional force of 50 N while it is moving.

250N

ol aq

The magnitude of the force exerted by the box on the boy is ...

A 50N
B 200N
C 250N
D 300N (2)

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### Page 4

Physica ooo
fo]

1.4

1.5

1.6

Ce} 4 R March 2026
Wnloaded from Stanmorephysics.com

Consider the organic compounds (I to IV) shown below.

I: CH= C -CH2-CHs

I; [CH3— C = C — CH2—- CHs3

Ile | CH3 — C = C — CHs

IV: | CH3 - C = CH
Which of the compounds above are positional isomers?
A landll
Bland Ill
Cc landlv
D_Iland Ill (2)
In which one of the followi fernatives are the three compounds listed in
order of their increasing {a ssure?
A Pentanoic acid; Pentan = 1°
B_ Pentane; Pentan — 1 — C
C  Pentan — 1 - ol; Pentane; Pentanoic ac
D Pentan — 1 — ol; Pentanoic acid; Pentane (2)

An organic compound X has the molecular formula CaHsOz.

When X is heated with an excess of ethanol in the presence of concentrated
sulfuric acid, a sweet-smelling compound forms.

When Compound X reacts with sodium carbonate solution, carbon dioxide is
produced. Stanmorephysics

Which ONE of the following is the IUPAC name of compound X?

A Ethyl Ethanoate.

B_ Butanoic acid

C Butyl Ethanoate

D Ethyl Butanoate (2)

112]

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QUESTION 2

In the diagram below, two blocks, A and B, of mass 8 kg and 5 kg, respectively, are
connected by a light, inextensible string. The string is passed over a light, frictionless
pulley so that the blocks hang down as shown.

Initially, the blocks are held stationary at the same position above the floor. Each
block is 0, 3 m high.

ea
(0,3 m
1

4

A B
8 ka 5kg

Floor f
c aaa ]
ps as

The blocks start moving when they are released.
Ignore air friction when answering the questions below.

2.1. Draw a Free-body diagram of ALL the forces acting on block B. (2)
2.2 State Newton’s second law of motion in words. (2)
2.3 Calculate the blocks' acceleration after they are released. (4)

Block A touches the floor a second later after the release. The blocks come to rest
as shown below. downloaded Stanmorephysics

8kg

Floor
tr

2.4 Calculate the vertical distance d measured from the top of block A to the
bottom of block B at the instant block A touches the floor. (5)

[13]

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March 2026

Physical Sciences 6
NSC

QUESTION 3

A soft ball with a mass of 0,3 kg is projected vertically upwards from the roof of a 45m
tall building with velocity v. It hits the balcony below with a velocity of 29,36 m.s", and
bounces off with a velocity of 13,77 m.s“!. The balcony is 12 m above the ground, as
shown below. Ignore the effects of friction.

45m

Balcony
12m }

’ +} Ground

3.1 Define the term Projectile. (2)
3.2 Calculate:

3.2.1 The magnitude of the velocity v, with which the ball was thrown from the

roof of the building. (4)

3.2.2 The velocity with which the ball strikes the ground. (3)
It takes 8,2 s from the time the ball is released from the roof until it strikes the ground.
3.3 Calculate the NET FORCE that the balcony surface exerted on the ball. (7)

[16]

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Physical Sci .
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QUESTION 4

Car A of mass 900 kg is stationary at a traffic light when it is hit from behind by Car B,

of mass 1100 kg, travelling at 19 m-s” to the right. Immediately after the collision, Car
A moves to the right at 10 m:s“!. Stanmorephysics

Stationary

be’

Unknown velocity 10 ms?
a a

4.1 State the law of conservation of linear momentum in words. (2)
4.2 Calculate the velocity of car B immediately after the collision. (4)

4.3. “Modern cars are designed to partially crumple on impact. A crumple zone is a
specially designed part of a motor vehicle that is designed to deform or collapse
during a collision.”

Explain how crumple zones are used as a safety measure in motor vehicles. (2)

4.4 Determine, by means of a calculation, whether the collision between car A and
car B is ELASTIC or INELASTIC.

4.5 A traffic officer arrives at the accident scene and makes the following observation:
“In a head-on collision involving two cars of different masses, the risk of passenger
injury in the heavier car is lower than in the lighter car”.
Use Physics principles to explain the observations made by the traffic officer. (2)

[15]

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### Page 8

Physical Sciences 8 ‘ March 2026
jownloaded from Stanmorephysics.com
QUESTION 5 (Start on a new page)
The letters A to F in the table below represent six organic compounds.
H
eo wo
A fy i | i Ethy! propanoate
ae
H H | H H
| H H
H Cc Cc Cc
foo | |
H H
e—
H
E} Butane
5.1 Define homologous series. Stanmorephysics (2)
5.2. Towhich homologous series does compound B belong? (1)
5.3 Draw the structural formula of compound B. (3)
5.4 Write down the LETTER that represents the following:
5.4.1. Anunsaturated hydrocarbon. (1)
5.4.2 Acompound with the general formula CnH2n0. (1)
5.5 Write down:
5.5.1. The IUPAC name of compound A. (2)
5.5.2 The IUPAC name of compound D. (2)
5.5.3 The balanced equation, using MOLECULAR FORMULA, of the
complete combustion of compound E. (3)
[15]

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### Page 9

Physical Sciences March 2026

9 ‘
ownloaded from Stanmonegshysics.com
QUESTION 6 (Start on a new page)

The boiling points of various primary straight-chain alcohols are provided in the table
below.

Alcohol Boiling point (°C)
Methanol 65
Ethanol 78
Propan — 1 —ol 97
Butan — 1 -ol 118
Pentan — 1

6.1 Write down the NAME of the fu

6.2 Define the term boiling point. (2)
6.3. Which ONE of the alcohols mentioned above is the LEAST flammable at room
temperature?
Explain your answer by referring to vapour pressure and risk of ignition. (3)
6.4 Use the information in the table above to answer the following questions.
6.4.1. On the graph paper provided, draw a graph of Boiling point versus the
number of carbons in each alcohol. Stanmorephysics (4)
6.4.2 State the trend shown on the graph. (2)
6.4.3. Explain your answer in 6.4.2 by referring to the TYPE and STRENGTH of
the intermolecular forces involved. (3)
[15]

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### Page 10

Physical eweloaded from Stanmorefhysics.com Mare'2026

QUESTION 7 (Start on a new page)

7.1. The following equation represents the cracking of a hydrocarbon at high
temperature and pressure:
C11H24 > 2C2Ha + ¥ + CaHio
Draw the structural formula of compound Y.

(2)

7.2. The flow diagram below shows the preparation of different organic compounds
using compound P, which has the general formula CnHansz.

Reaction 1 Inorganic
Compound P cn 2-Chlorobutane | compound X

Compound Q y

(Major product) oreph| Compound R

7.2.1 Write down ONE reaction condition for Reaction 1. (1)

7.2.2 |s2-chlorobutane a PRIMARY, SECONDARY, or TERTIARY haloalkane?
Explain your answer. (2)

7.2.3. Write down the balanced equation, using STRUCTURAL FORMULAE for
Reaction 3. (4)

7.3. Reaction 2, in the flow diagram above, is an elimination reaction during which
the organic compound Q and TWO inorganic compounds are formed.

Write down:
7.3.1 The NAME of this type of elimination reaction. (1)
7.3.2 The IUPAC name of Compound Q. (2)

7.3.3 The FORMULA of EACH inorganic product formed during Reaction 2. (2)

[14]
TOTAL MARKS: [100]

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### Page 11

Physical Science:

Downloaded from Stanmorephysics.com

11

March 2026

DATA FOR PHYSICAL SCIENCES GRADE 12 PAPER 1 (PHYSICS)
GEGEWENS VIR FISIESE WETENSKAPPE GRAAD 12 VRAESTEL 1 (FISIKA)

TABLE 1: PHYSICAL CONSTANTS/TABEL 1: FISIESE KONSTANTES

NAME/NAAM SYMBOL/S/MBOOL VALUE/WAARDE
Acceleration due to gravity “g2
Swaartekragversnelling a sald
Speed of light in a vacuum 8 m-s-1
Spoed van lig in 'n vakuum ¢ 3,0 x 10" ms
Planck's constant -34 J.
Planck se konstante n scitadihiallida
Coulomb's constant 9 N-m2-C-2
Coulomb se konstante 3 a eRe
Charge on electron Lading “1,6 x 10°9-C
op elektron ~<o 4
Electron mass Elektronmassa * | 9,11 x 10°31 kg

TABLE 2: FORMULAE/TABEL 2: FORMULES

MOTION/BEWEGING

Vp = Vi + aAt

Ax = v,At~ at‘ orfof Ay =v At - :aAt®

Ap =mv, -mv,

5 - 7 {Vv +Ve ; iVosMe
v2 =v? +2aax orlof v.27 =v72+2ary | Ax=| 5 [At or/of Ay =! aa a At
\
FORCE/KRAG
Free =Ma p=mv
F.At =Ap w=mg

WORK, ENERGY AND POWERI/ARBEID, ENERGIE EN DRYWING

W =FAxcos 0 U=mgh orfof Ep =mgh
K my! oof E, =p" Wra = AK oof W,.. = AE,

AK=K,-K, offof AE, = Ey, - Ey,
“ P= Fy

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### Page 12

Physical $geprivaded from Stanmorephysics.com

March 2026

DATA FOR PHYSICAL SCIENCES GRADE 12

PAPER 2 (CHEMISTRY)

GEGEWENS VIR FISIESE WETENSKAPPE GRAAD 12

VRAESTEL 2 (CHEMIE)

TABLE 1: PHYSICAL CONSTANTS/TABEL 1: FISIESE KONSTANTES

NAME/NAAM SYMBOL/S/MBOOL VALUE/WAARDE
Standard pressure 5
Standaarddruk pe Latee 19° Fe
Molar gas volume at STP -
Molére gasvolume by STD Vm 22,4 dm?-mot"
Standard temperature 273K
Standaardtemperatuur

Charge on electron Lading 1,6x109C

op elektron

Avogadro's constant
Avogadro-konstante

6,02 x 1023 mol

n=m n=N
M Na
c= oof c= ™@ n=V
Vv MV Vin
CaVa= Na “
oe he pH = -log[Hs0*]

Kw = [H3O*][OH‘] = 1 x 10°4 at/by 298 K

or/of

or/of

Ecetie = Ecathodeo —Eanodeo /Eese! =Exatoseo —Eanodes

Ecetio = Ereductione— Eoxidatione/Eese! = Ereduksieo— Eoksidasies

Eceiie = Eoxidisinge agent — Ereducinge agent /Eose! =Eoksideermio dde! — Ereduseermié ddet

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### Page 13

Physifaoawistaaded from Stanmorephysics.com 14 March 2026
: NSC
_ TABLE 3: THE PERIODIC TABLE OF ELEMENTS
i iL 3: DIE PERIODIEKE TABEL VAN ELEMENTE
1 2 3 4 E) 6 7 8 9 10 11 12 13 14 15 16 17 18
(I) (Il) ; (my (ivy) (Vy) (ts
Atomic number
a KEY/SLEUTEL Atoomgetal A
av e
N
1 7 29 4
3 4 Electronegativity J Gy [Symbol 5 6 7 8 9 10
2 Li |Z Be Elektronegatiwiteit “| - ana Simbool s BIS = Nle0]$¢ Ne
7 9 ! 11 12 14 16 19 20
11 12 tT 13 14 15 16 17 18
3 Na/= Mg Approximate relative atomic mass 2AQI2 SiS P| S |3Ce! Ar
23 24 Benaderde relatiewe atoommassa 27 28 31 32 35,5 40
19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36
@ K |2 Ca/2 Sc /2 Ti |& 2 Cr |2Mn|2 Fe |2 Co|2 Ni |2 Cu|2 Zn |2 Ga|2 Ge |& As |S Se |S Br| Kr
39 40 45 48 51 52 55 56 59 59 63,5 65 70 73 75 79 80 84
37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54
oe Rbi2 Sri Y |= Zr} Nb|2 Mol? Te |S Ru/a Rh|& Pd |2 Ag |= Cd |= In 2 Sn/2 Sb|& Te /a | Xe
86 88 89 91 92 96 101 103 106 108 112 115 119 122 128 127 131
55 56 57 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86
S$ Cs/2 Ba| La|2 Hf} Ta] W| Re| Os} Ir| Pt] Au] Hg|2 T2/2Pb/2 Bi |S Pols At| Rn
133 137 139 179 181 184 186 190 192 195 197 201 204 207 209
87 88 89
nw oa
o Fr |e se Ac 58 59 60 61 62 63 64 65 66 67 68 69 70 71
Ce | Pr | Nd | Pm | Sm | Eu | Gd | Tb | Dy | Ho| Er | Tm| Yb | Lu
140 141 144 150 152 157 159 163 165 167 169 173 175
90 91 92 93 94 95 96 97 98 99 100 101 102 103
Th | Pa | U | Np} Pu | Am | Cm | Bk | Cf | Es | Fm | Md | No | Lr
232 238

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### Page 14

Prysictheipifoaded from Stanmorefhysics.com REN EBS

NOTE: Tear this page off and submit it with your answer booklet.

Learner's name:

6.4.1

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t f ,
} {
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H {
i i
aa 4 funfop— '
itt

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### Page 15

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KWAZULU-NATAL PROVINCE

EDUCATION
REPUBLIC OF SOUTH AFRICA

NATIONAL
SENIOR CERTIFICATE

GRADE 12

MARKS : 100

These marking guidelines consist of 7 pages.

Copyright reserved Please turn over

### Page 16

PhysicdDeuetebsaded from Stanmorephysics.com

QUESTION 1

1.1 bce

12 Cv

1.3 ¢6uae

14 Bvv

15 Avv

16 Bvv

QUESTION 2

24 Tv
Fg v

2.2 When a net force acts on an object,

2.3

2.4

Block A
Fnet=ma v
Fg-T=ma

8x9,8-T=8av....eqn 1.

a=2,26ms?v

POSITIVE MARKING FROM 2.3

Ay = viAt + % at? Vv
=0+%x2,26x 12 Vv
=1,13m

d=1,13+1,13 v-0,3v
=1,96mv

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T-Fg=ma
T-5x 9,8 = 5a v... eqn 2.

March 2026

e object will accelerate in the direction of

the net force with an acceleration that is directly proportional to the net force
vY and inversely proportional to the mass of the object. v

Please turn over

(2)
(2)
(2)
(2)
(2)
(2)
[12]

(2)

(2)

(4)

(5)
[13]

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PhysicdDeneeboaded from Stanmorephysics.com

QUESTION 3

3.1

3.2.1

3.2.2

3.3

An object that has been given an initial velocity and then moves under the
influence of the gravitational force only. vv”

Upward as positive

ve = vi? + 2ady ¥

(- 29,36)? v= vi? + 2 (- 9,8) (- 33)”
vi = 14, 67 m.s! ¥

Downward as positive

ve = vi? + 2aAy ¥

(29,36)? v= vi? + 2 (9,8) (33)
vi= 14,67 mst v

Upward as positive
vie = vit + 2aAy ¥

= (13, 77)? + 2(- 9.8 uth an
vi = 20, 61 m.s" downward

POSITIVE MARKING FRO!
Time |

Downward as positive

vi = vi? + Zady ¥

(- 13, 77)? + 2(9,8) (12)”
vi = 20, 61 m.s“', downward v

and 3.2.2

n the rou to the balcony

Upward as positive
Vr = vi + adt ¥
(-29, 36) = 14, 67 + (- 9,8) At ¥

Downward as positive
vr = vi + aAt ¥
(29, 36) = - 14, 67 + (9,8) At v

At=4,49s

At=4, 49s

Time from the balcony to the ground

Upward as positive

Downward as positive

Vr = vi t+ adt vi = vi + adt
(-20, 61) = 13, 77 + (- 9,8) At Vv (20, 61) = - 13, 77 + (9,8) At v
At=3,51s At=3, 51s

Contact time: 8,2 — (4, 49 + 3,51) V=0,2s

Fnet = ™@r-w
At
Fnet = smart a88e) y

Fnet = 64, 70 N, upward ¥

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March 2026

(2)

(4)

(3)

(7)
[16]

### Page 18

PhysicdDeuieteboaded from Stanmorephysics.com March 2026

QUESTION 4
4.1. The total linear momentum of an isolated system is conserved. v Vv (2)

4.2 > Pbefore = > Patter
Mavai+ MeVei = Mavar + MBVer
0 + (1100 x 19) v= (900 x 10) + 1100ver ¥

Vi = 10, 82 m.s"", to the right v (4)

4.3 Crumple zones increase the collision time” , which reduces the net
force V experienced by the cars. (2)

4.4 POSITIVE MARKING FROM 4.2

> Ek before = % mavait + a maver? v
=0+%x
= 198550 J

> Ek after = % mavar?+ %
=%x 900 x 1 «(10 82)? v
= 109389, 82 J

> Ekbefore # > Ekafter v

Collision is INELASTIC

(5)

4.5 Newton’s third law: Both cars experience equal force. ¥
Newton's second law: Acceleration is inversely proportional to the mass. v
Therefore, a heavier car experiences smaller acceleration than a lighter car. (2)

[15]

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### Page 19

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QUESTION 5
5.1. A series of organic compounds that can be described by the same general
formula. Vv (2)
5.2 Esters. v (1)
v v v
5:3 A XK
( \ Oo \

(3)
5.4.1 Fv (1)
54.2 Av (1)
v v
5.5.1 2-methylpentan-3-one (2)
v v
5.5.2 2-methylbutan-2-ol (2)
5.5.3 2CaH10 + 1302 ¥> 8CO2+10H20Y Bal. ¥ (3)
[15]

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### Page 20

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QUESTION 6

6.1. Hydroxyl (group) ~ (1)

6.2 The temperature at which the vapour pressure of a substance equals the
atmospheric pressure. vv (2)

6.3 e  Pentan-1-ol. ¥

e It has the lowest vapour pressure. ¥

e It produces fewer flammable vapours at room temperature, which reduces
the risk of ignition. v

(3)

6.4.1

Boiling Point vs Number of Carbon Atoms
(First Five Primary Alcohols)
140 =

130 7

120

110

Boiling point (*C)
”
§ 8 8

x
3

Number of carbon atoms
Marking criteria:

e Both axes correctly labelled with appropriate scale: ¥
e All five points plotted accurately: vv
e Graph with a positive gradient: v

(4)

6.4.2 The boiling point increases as the number of carbon atoms/chain length/surface

area/molecular mass increases. vv (2 or 0) (2)
6.4.3. As the number of carbon atoms increases,
the London/Dispersion forces ¥ get stronger. Vv

More energy is required to overcome the intermolecular forces. V (3)
[15]

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QUESTION 7
iv
Oh |
<1
H H (2)
7.2.1. Heat or Light ¥ (1)

7.2.2 Secondary. v
The carbon atom bonded to the halogen/Cl is attached to two other carbon atoms
(in the compound). ~

7.2.3

(2)

v vi v
tT, oo
H—C—C— C— C —H+ C—C— C—H+ K-Cl

| | | | ||

H H H H H H H (4)
7.3.1 Dehydrohalogenation. v (1)
7.3.2 But-2-ene vv (2 or 0) (2)
7.3.3 KClY and H20 v (2)

[14]

TOTAL MARKS: [100]

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- [Grade 12 past papers](https://www.hlayiso.com/grade-12/past-papers)

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