# Technical Mathematics Grade 12 P1 Gauteng Mock 2023 Addendum

> Grade 12 Technical Mathematics Paper 1 addendum from the Gauteng Mock Exam 2023 (Afrikaans), 2 pages. Read online or get the free PDF download.

- Page: https://www.hlayiso.com/library/grade-12-technical-mathematics-2023-gauteng-mock-exam-addendum-paper-1-afrikaans/81d10ba5-d0c4-43e7-8fff-6e814bba3ce5
- Updated: 2026-09-28
- Subject: Technical Mathematics
- Grade: Grade 12
- Language: Afrikaans
- Document type: Addendum
- Year: 2023
- Exam period: Gauteng Mock Exam
- Paper: 1
- Curriculum: CAPS
- Pages: 2

Breadcrumbs: [Home](https://www.hlayiso.com/) › [Library](https://www.hlayiso.com/library) › [Grade 12](https://www.hlayiso.com/library/grade-12) › [Technical Mathematics](https://www.hlayiso.com/library/grade-12/technical-mathematics) › [Technical Mathematics Grade 12 P1 Gauteng Mock 2023 Addendum](https://www.hlayiso.com/library/grade-12-technical-mathematics-2023-gauteng-mock-exam-addendum-paper-1-afrikaans/81d10ba5-d0c4-43e7-8fff-6e814bba3ce5)

## About this document

Technical Mathematics · Grade 12 · Gauteng Mock Exam · 2023 · Afrikaans. Addendum, 2 pages. Read online or download the PDF.

Read it free online on the page above; download the PDF from there.

## Document text

Text extracted from the PDF. Layout, diagrams and tables may not survive extraction.

### Page 1

ADDENDUM
             TECHNICAL MATHEMATICS/TEGNIESE WISKUNDE
                   Prelimanary Examination / Voorbereidende Eksamen

                      Paper / Vraestel 1              September 2023
            FINAL MARKING GUIDELINES (ADDITIONAL NOTES)
              FINALE NASIENRIGL YNE (ADDISIONELE NOTAS)

ITEM                                             DESCRIPTION/BESKRWING

NPU and NPR is valid for all questions where applicable / NPU en NPR
is geldig op alle vrae waar van toepassing.

           After factorizing, the bracket has to be a quadratic expression in order to CA the answer.
  1.1.2    Nadat daar gefaktoriseer is, moet die uitdruikking in die hakkie kwadraties wees om die CA vir die
           antwoorde te doen.
           Accept the following as an answer: / Aanvaar die volgende as ‘n antwoord:
  1.1.4

           𝑧̅𝑇 = −2 + 𝑖
  3.1.2    It the learner changed the -2 to 2 and kept −𝑖 then the learner gets 0 for the answer.
           Indien die leerder die -2 na 2 toe verander het en die −𝑖 gehou het, kry die leerder 0 vir die antwoord.
           No penalty if the calculation is not shown/ indicated.
  4.1.3    Geen straf as die bewerking nie gewys word nie.

          Only ONE point if intersection.
   5.5    Slegs EEN punt waar hulle sny.

          Accept the following due to an error on the information sheet:
          Aanvaar die volgende as gevolg van ‘n fout op die inligtingsblad.
          𝐴 = 𝑃(1 + 𝑖)2                  ✓F               A
                         0,092 2
          = 3 400 (1 + 365 )                ✓ SF            A
                                              0,092
          = 𝑅3 401,71                       ✓               A
                                               365
          = 𝑅3 402                          ✓ R3 402        CA
 6.2.1
          OR / OF
          𝐴 = 𝑃(1 + 𝑖)2                     ✓F              A
                         0,092 2
          = 3 400 (1 +     2
                               )            ✓ SF            A
                                             0,092
          = 3 719,9944                      ✓ 2            A
          = 𝑅3 720                       ✓ R3 402         CA
          (4)
          Accept the following due to an error on the information sheet:
          Aanvaar die volgende as gevolg van ‘n fout op die inligtingsblad.
 6.3      𝐴 = 𝑃(1 + 𝐼)2
                               0,125 2                          0,125
             = 20 000 (1 +          )                       ✓                       A
                                12                             12
             = 20 418,836                                   ✓ 20 418,836            CA

### Page 2

𝐴 = 𝑃(1 + 𝑖)2                                          ✓ SF                  CA
                            0,098 2                              0,098
           = 20 418,836 (1 + 4 )                                ✓ 4                   A
          = R21 431,62                                          ✓ 21 431,62           CA
         OR/OF
                           12,5   2         9,8   2
                                                          0,125
                           100
         𝐴 = 20 000 (1 + 12 ) . (1 + 4 )    100
                                                      ✓    12
                                                                                      A
         𝐴 = 𝑅21 431,62
                                                      ✓M                              A
                                                        9,8

                                                      ✓ 4
                                                        100
                                                                                      A
                                                      ✓M                              A
                                                      ✓ 21 431,62                     CA
         OR / OF
         𝐴 = 𝑃(1 + 𝐼)2
                           0,125 2                                0,125
           = 20 000 (1 +     2
                                )                               ✓ 2                   A
           = 22 578,125                                         ✓ 22 578,125          CA
         𝐴 = 𝑃(1 + 𝑖)2                                          ✓ SF                  CA
                                  0,098 2                         0,098
           = 20 418,836 (1 +        2
                                       )                        ✓ 2                   A
           = R24 844,99                                         ✓ 24 844,99           CA

         OR/OF
                           12,5   2         9,8   2
                                                          0,125
                           100
         𝐴 = 20 000 (1 + 2 ) . (1 + 2 )     100
                                                      ✓     2
                                                                               A ✓M            A
                                                          9,8

         𝐴 = R24 844,99                          ✓ 100
                                                     2
                                                                         A
                                                 ✓M                      A
                                                 ✓ 24 844,99             CA
         When marking first principles, as soon as a learner makes a second mistake, you stop marking and do
         not allocate any further marks. ONLY in Question 7.1.
 7.1     Wanneer ons eerste beginsels merk, hou ons op merk sodra die leerder ‘n tweede fout maak en dus
         gee ons nie verder punte nie. SLEGS in Vraaf 7.1.
                                        3
         If the learner only writes 𝑥 = 2, you may award full marks.
 7.4                                    3
          Indien die leerder slegs 𝑥 = 2 skryf, mag jy volpunte toeken.
         ✓ – 8𝑙𝑛𝑥 + 𝑐
         If a learner omits the c in this question, DO NOT penalise the learner.
10.1.2
         Indien die leerder die c weglaat in hierdie vraag, MOET die leerder NIE gepenaliseer word
         NIE.
 DATE APPROVED/DATUM GOEDGEKEUR                                        8 SEPTEMBER 2023
  EXTERNAL/EKSTERNE MODERATORS/E                                INTERNAL /INTERNE MODERATORS/E
    Name            Signature                                       Name           Signature

                                                                  HJ Swart

## Related documents

- [TECH MATHS P1 GR12 MEMO SEPT2023 Afrikaans+English](https://www.hlayiso.com/library/tech-maths-p1-gr12-memo-sept2023-afrikaans-english/514ee9ac-c663-4a12-98a5-11a8324a8f69) — Technical Mathematics · Memo · 2023 · Afr
- [Gr12 Technical Mathematics P1 (English and Afrikaans) 2021 Preparatory Possible Answers](https://www.hlayiso.com/library/gr12-technical-mathematics-p1-english-and-afrikaans-2021-preparatory-possible-answers/f02d5a55-02e7-417c-934a-f7c242038cd1) — Technical Mathematics · Memo · 2021 · Afr
- [TECH MATH P1 (Afrikaans) 2020 Preparatory Question Paper](https://www.hlayiso.com/library/grade-12-technical-mathematics-2020-gauteng-mock-exam-question-paper-paper-1-afrikaans/4db5d254-38dc-45e5-8168-ec90c5980f35) — Technical Mathematics · QP · 2020 · Afr
- [Tech MATH P1 (Afrikaans) X10 2019 Preparatory Examination Question Paper](https://www.hlayiso.com/library/tech-math-p1-afrikaans-x10-2019-preparatory-examination-question-paper/b99bda7d-3d00-4105-af34-1832591135a2) — Technical Mathematics · QP · 2019 · Afr
- [Grade 12 NSC Technical Mathematics P1 X5 Afrikaans Preparatory 2018 Question Paper](https://www.hlayiso.com/library/grade-12-nsc-technical-mathematics-p1-x5-afrikaans-preparatory-2018-question-paper/837c74de-a69a-41f0-93da-58d591494f8e) — Technical Mathematics · QP · 2018 · Afr
- [Tech MATH P2 (English and Afrikaans) X10 2019 Preparatory Examination Answer book](https://www.hlayiso.com/library/tech-math-p2-english-and-afrikaans-x10-2019-preparatory-examination-answer-book/35283687-efdb-40c5-a5e3-383bee3f78ba) — Technical Mathematics · Addendum · 2019 · Afr

## More from Grade 12 Technical Mathematics

- [Tech Maths P2 Memo A E watermark](https://www.hlayiso.com/library/tech-maths-p2-memo-a-e-watermark/854cae30-bff5-40b9-b49c-230b61df8d6f) — Memo · 2025
- [TECH MATHS P2 GR12 MEMO SEPT2025 Eng&Afr watermark](https://www.hlayiso.com/library/tech-maths-p2-gr12-memo-sept2025-eng-afr-watermark/5ff2a74b-0f46-49ba-be61-1ee972913d66) — Memo · 2025 · Eng
- [Gr 12 Technical Mathematics P2 (Afrikaans) 2025 Question Paper X05](https://www.hlayiso.com/library/grade-12-technical-mathematics-2025-gauteng-mock-exam-question-paper-paper-2-afrikaans/673174da-3296-4dd9-b0ed-c262fb1d1c63) — QP · 2025 · Afr
- [Technical Mathematics P1 Nov 2025 MG Afr & Eng](https://www.hlayiso.com/library/grade-12-technical-mathematics-2025-nsc-november-exam-memorandum-paper-1-afrikaans/46f4840a-7f39-4e8c-88d1-8beab76147dc) — Memo · 2025 · Afr
- [Technical Mathematics P2 Nov 2025 MG Afr & Eng](https://www.hlayiso.com/library/grade-12-technical-mathematics-2025-nsc-november-exam-memorandum-paper-2-afrikaans/4cc6dcbf-4367-429e-8ac9-2049f03eecb9) — Memo · 2025 · Afr
- [Technical Mathematics P1 Nov 2025 Afr](https://www.hlayiso.com/library/grade-12-technical-mathematics-2025-nsc-november-exam-question-paper-paper-1/00c4af24-67df-4872-a5e8-a2928fb0fe99) — QP · 2025 · Afr

## Collection

- [Grade 12 past papers](https://www.hlayiso.com/grade-12/past-papers)

---

Hlayiso: free CAPS and IEB past papers, memos, notes and study guides for South African learners. When citing, link the page URL above, not a PDF or /api/ URL.
