# Mathematics Grade 3 Gauteng Provincial November 2022 Memo

> Grade 3 Mathematics memorandum from the Gauteng Provincial November Exam 2022 (isiXhosa), 6 pages. Read online or get the free PDF download, question paper linked when available.

- Page: https://www.hlayiso.com/library/grade-3-mathematics-2022-gauteng-provincial-november-exam-memorandum-isixhosa/679ada0e-5624-4058-893d-8771b60a8df1
- Updated: 2026-09-28
- Subject: Mathematics
- Grade: Grade 3
- Language: Isixhosa
- Document type: Memorandum
- Year: 2022
- Exam period: Gauteng Provincial November Exam
- Curriculum: CAPS
- Pages: 6

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## About this document

Mathematics · Grade 3 · Gauteng Provincial November Exam · 2022 · isixhosa. Memorandum, 6 pages. Read online or download the PDF.

Read it free online on the page above; download the PDF from there.

## Document text

Text extracted from the PDF. Layout, diagrams and tables may not survive extraction.

### Page 1

UHLOLO EPHONDWENI
                EYENKANGA 2023
                     IBANGA 3
              ISIKHOKELO SOKUMAKA

                 IMATHEMATIKA: ISIXHOSA

6 amaphepha

### Page 2

ISIKHOKELO SOKUMAKA         Ibanga 3 IMathematika

1    C                                                         1 inqaku

2    B                                                         1 inqaku

3    D                                                         1 inqaku

4    A                                                         1 inqaku

5    B                                                         1 inqaku

6    C                                                         1 inqaku

7    C                                                         1 inqaku

8    D                                                         1 inqaku

9    B                                                         1 inqaku

10   D                                                         1 inqaku

11   7:40 ekuseni Okanye imizuzu engamashumi amabini phambi     1 inqaku
     kwentsimbi yesibhozo 

12   iikota ezimbini                                           1 inqaku

13   ama 30 emizuzu                                            1 inqaku

14   IPentagoni                                                1 inqaku

15   IiKilomitha                                               1 inqaku

16   A     500                                                 1 inqaku ngempendulo
     B     1 500                                               nganye echanekileyo
                                                                (2 amanqaku)

17                                                                   1 inqaku
                            

                                              2

### Page 3

ISIKHOKELO SOKUMAKA   Ibanga 3 IMathematika

     Ulandelelwano olululo

18   706; 705; 701; 659; 607                                    1 inqaku
                                                                 ngolandelelwano
                                                                 olululo
                                                                 (1 inqaku)

19   A   B – Ityhubhu                                           1 inqaku
     B   C – Ikhowuni                                           ngempendulo
                                                                 nganye
                                                                 (2 amanqaku)

20   Isithathu sekota ukugcwala                                 1 inqaku

21   A   C3 okanye 3C                                           4 amanqaku
     B   D4 okanye 4D                                           1 ngempendulo
                                                                 nganye
     C   C2 okanye 2C                                           echanekileyo
     D   IPhiramidi                                             (4 amanqaku)

22   1   Bala zonke izikwere = 16                               1 inqaku
                                      Okanye                     ngempendulo
     2   Umqolo x ikholam = 16                                  nganye
                                                                 echanekileyo
                                      Okanye
                                                                 (2 amanqaku)
     3   4 x 4 = 16
     (Nokuba yeyiphi imethodi echanekileyo yamkelekile)

                                                 3

### Page 4

ISIKHOKELO SOKUMAKA               Ibanga 3 IMathematika

23   6 x 4 = 24                                                            1 inqaku
                                      Okanye                                ngempendulo
     12 + 12 = 24                                                           nganye
                                      Okanye                                echanekileyo
     24 amaqanda                                                           (2 amanqaku)
     (Nokuba yeyiphi imethodi echanekileyo yamkelekile)

24   360 ÷ 12 = 30 grams                                                   1 inqaku
     2 x 30 grams = 60 grams                                               ngempendulo
                                                                            nganye
     (Nokuba yeyiphi imethodi echanekileyo yokwahlula yamkelekile)
                                                                            echanekileyo
                                                                            (2 amanqaku)

25   USara mde kuno Jay nge 13 lwee cm                                     1 inqaku
     151 cm – 138 cm = 13 cm                                               ngempendulo
                                                                            nganye
                                                                            echanekileyo
                                                                            (2 amanqaku)

26   12 ÷ 4 = 3                                                            1 inqaku
                                      Okanye                                ngempendulo
     12 ÷ 3 = 4                                                             nganye
     Yamkela noba yeyiphi imethodi echanekileyo                             echanekileyo
                                                                            (1 inqaku)

27   5 x 6 = 30                                                            1 inqaku
     Zingama 30 izincamathelisi                                            ngemethodi
                                                                            echanekileyo, 1
     Yamkela noba yeyiphi imethodi echanekileyo
                                                                            inqaku
                                                                            ngempendulo
                                                                            nganye
                                                                            echanekileyo
                                                                            (2 amanqaku)

                                                  4

### Page 5

ISIKHOKELO SOKUMAKA             Ibanga 3 IMathematika

28   36 ÷ 3 = 12                                                           1 inqaku
                                                                            ngempendulo
                                                                            echanekileyo, 1
                                                                            inqaku
                                                                            ngokuqakatha
                                                                            okuchanekileyo
                                                                            (2 amanqaku)
                                            

           0     3      6      9     12    15   18   21    24   27   30   33    36      39
     Yamkela nokuba yeyiphi imethodi echanekileyo

29   8 x 4 = 32                                                            1 inqaku
                                                                            ngempendulo
     Usebenzise iilamuni ezingama 32 ukwenza ilemonadi                     echanekileyo, 1
                                                                            inqaku
                                                                            ngokuqakatha
                                                                            okuchanekileyo
                                                                            (2 amanqaku)

30   15 + 6 = 21                                                           1 inqaku
                                                                            ngemethodi
     Zingama 21 iiapile zizonke                                            echanekileyo, 1
                                                                            inqaku
                                                                            ngempendulo
                                                                            nganye
                                                                            echanekileyo
                                                                            (2 amanqaku)

31   242 + 353                                                              1 inqaku
                                                                            ngemethodi
     = (200 + 40 + 2) + (300 + 50 + 3)                                     echanekileyo, 1
     (200 + 300) (40 + 50) (2 + 3)                                          inqaku
     500 + 90 + 5                                                           ngempendulo
     595                                                                   nganye
                                                                            echanekileyo
                                                                            (2 amanqaku)

                                                 5

### Page 6

ISIKHOKELO SOKUMAKA    Ibanga 3 IMathematika

32   598 – 75 =                                                    1 inqaku
                                                                    ngemethodi
     = (500 and 90 and 8) – (70 and 5)                              echanekileyo, 1
       (500 – 0) (90 – 70) (8 – 5)                                  inqaku
     = 500 – 20 – 3                                                 ngempendulo
     = 523                                                         nganye
                                                                    echanekileyo
                                                                    (2 amanqaku)
     Yamkela nokuba yeyiphi imethodi echanekileyo

33   A    Incwadi ngezilwanyana                                    1 inqaku
     B    23                                                       ngempendulo
                                                                    nganye
     C    2 abafundi                                               echanekileyo
                                                                    (3 amanqaku)
                                                           ITOTALI: 50 amanqaku

                                                6

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