# Mathematics Grade 8 Paper 1 Eastern Cape November 2014 Memo

> Grade 8 Mathematics Paper 1 memorandum from the Eastern Cape November Exam 2014, 7 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/grade-8-mathematics-2014-eastern-cape-november-exam-memorandum-paper-1/e5fbd0c6-fe26-436c-80fd-340d1535b35d
- Updated: 2026-10-29
- Subject: Mathematics
- Grade: Grade 8
- Document type: Memorandum
- Year: 2014
- Exam period: Eastern Cape November Exam
- Paper: 1
- Curriculum: CAPS
- Pages: 7

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## About this document

Mathematics · Grade 8 · Eastern Cape November Exam · 2014. Memorandum, 7 pages. Read online or download the PDF.

Read it free online on the page above; download the PDF from there.

## Document text

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### Page 1

1

                    Overberg Education District

          GR 8

MODEL EKSAMEN/EXAM P 1

   WISKUNDE/MATHS

    NOVEMBER 2014

    MEMORANDUM

### Page 2

2

Ques/                   Calculations/Berekeninge                 Explanation if necessary/
 Vr                                                               Verduideliking indien
                                                                          nodig

VRAAG/QUESTION 1

1.1     (a)    81            A

        (b)    363          A

        (c)    81; 189; 450         A (all 3 correct)

        (d)    5A
                                                         (4)
1.2     2 678 879  A

                                                         (1)
                                                             1 A for each number in
1.3     30 + 8 ÷ 2 - 10 = 24                             (4)     correct position
1.4                   90
        - 20 (150 x -    + 10 )
                      45                                         1 M A -300
        = - 20 (-300 + 10)  MA                                  1 CA -290
        = -20 x -290  CA                                        1CA answer
        = 5 800      CA
                                                          (3)
1.5     4   80
          =
        5 100

         9   36
           =
        25 100

         6   60
           =
        10 100
                                                                 A 1 mark for each 2 correct
        3    15                                                  conversions
          =
        20 100
         A
                                                                 1 CA descending/dalende
              4             6    44         9   3   1
                        ;      ;       ;      ;   ;   CA
              5             10   100       25 20 100

                                                           (3)
                    5
1.6     1,123 x 10 = 112 300  A

        9,2 x 103 = 9 200  A

        Therefore 9,2 x 103 smallest/kleinste CA

### Page 3

3

Ques/               Calculations/Berekeninge               Explanation if necessary/
 Vr                                                         Verduideliking indien
                                                                    nodig

                                                     (3)

1.7      2 916

                 2 2916
                 2 1458
                 3 729
                 3 243              M                     1 M any method you have
                 3   81                                    taught!
                 3   27
                 3   9
                 3   3
                     1

         2 916 = 22 x 36          CA                      1 CA powers of prime no’s
                                                           Magte van priemfaktore
         √ 2 916 = 2 x 3 = 54 CA
                          3

                                                           1 CA antwoord
                                                    (3)

1.8.        0,5kg:250g

         = 500g:250g  C OR 0,5kg:0,25kg                   1 C conversion/omskakeling
         = 2:1  CA                                        1 CA simplification
                                                    (2)
1.9.             4                                         2A x correct numerator &
         750 x      A
                 3                                         denominator/teller &
                                                           noemer
         = R1 000 CA
                                                           1CA answer
                                                    (3)
1.10.1 Profit = R75           A
                                                     (1)
1.10.2   75                                                1 CA fraction with 250 D/N
             CA x 100  M
         250                                               1M x100

         = 30%  CA                                        1CA answer
                                                     (3)
1.11     2 800 x 0,2 x2

         = R1 120  A
         = Total amount payable/bedrag betaalbaar          1A interest amount/rente
         = 1 120 + 2 800                                   bedrag
         = R3 920  CA                                     1CA total amount/bedrag

### Page 4

4

Ques/                  Calculations/Berekeninge                            Explanation if necessary/
 Vr                                                                         Verduideliking indien
                                                                                    nodig
        Monyhly installments/paaiement
          3 920                                                        1CA ÷ 24
        =          CA
           24
                                                                       1CA answer
        = R163,33  CA                                         (4)

                                                                                                    [34]

VRAAG/QUESTION 2

2.1     -2 x – x 3 + 9 x 2 + 14( x 2 + 2)

        2.1.1     4 A                                               (1)

        2.1.2 -2(-2) – (-2)3 + 9(-2)2 +14((-2)2 +2)           SF             1SF substitution/stel in

                  =4 + 4 +36 + 84 CA
                                                                              1CA simplification/
                  = 132 CA                                                   Vereenvoudiging
                                                                      (3)
                                                                              1CA answer
2.2.1
                                   p 4 . q 4 . q 2 . p3
                                         q 6 . p6

                 A            A
                 7-6                                                          1A p correct
        =    p             .        q6 - 6
                                                                              1A q correct
        =   p CA
                                                                              1CA answer
                                                                      (3)
2.2.2              4   2       3    4
            (-8 x y )(5 x y )( -2 x )

         A A A                                                             1A for each item
        = 80 x 8 y6                                                           completely correct
                                                                              Vir elke item heeltemal
                                                                              korrek
                                                                      (3)

2.2.3       -5 (2x 2 + x – 20) + 12x 2+3 x
                A                                                            1A brackets correctly
        = -10x - 5 x + 100 + 12x 2+3 x
              2                                                               removed/
                                                                              Hakies korrek verwyder

### Page 5

5

Ques/               Calculations/Berekeninge                    Explanation if necessary/
 Vr                                                               Verduideliking indien
                                                                          nodig
        = 2 x 2 - 2 x + 100   CA                                 1CA 3 terms
                                                                   1CA correctly
                                                                   simplified
                                                              (3)

2.3.1   4 x +5=5 x - 9
            - x = - 14 A                                            1A both sides correct
             x = 14 CA                                              1CA answer
                                                              (2)

2.3.1                       5 ( x - 1 )−( 1 - 2 x ) = 8

        A         A
        5 x - 5 -1 + 2 x = 8                                         2A for both brackets
        7 x = 14 CA                                                 correctly removed
        x = 2 CA                                                    1CA for simplification
                                                                     1CA for answer

                                                              (4)
2.4     Let son be x                                                 ANY METHOD!!
        Then father = x + 25 
        In 5 years’time/oor 5 jaar                                   ENIGE METODE!!

        Son = x + 5
        Father = x + 30 

        Then/dan: 2( x + 5) = x + 30 
        2 x + 10 = x + 30

        x = son = 20 
                                                              (4)
2.5.1   13A                                                 (2)
2.5.2    N = 3p-2 A                                        (3)

2.5.3   N = 3 (100) – 2 SF                                          1 SF substitute/instel
         = 298 CA                                            (2)    1CA answer

2.6.1     6:00                                                (1)
2.6.2    7:30                                                  (1)
2.6.3     1h                                                   (2)
2.6.4      9:00                                                (1)

### Page 6

6

Ques/           Calculations/Berekeninge                              Explanation if necessary/
 Vr                                                                    Verduideliking indien
                                                                               nodig
2.7.1                                                                   1 mark for each two
            x    ―1           0            1                2       3   correct, plus 1 mark for
                                                                        last one correct
            y     -5         -3        -1                   1       3
                                                                          1 punt vir elke twee
                        CA                                             korrek, plus 1 punt vir
                                                                          die laaste 1 korrek

                                                                    (3)

2.7.2   ANNEXURE A/BYLAE A

                                                            (3;3)

                                                    (2;1)

                                           (1;-1)

                                  (0;-3)

                        (-1;-5)

### Page 7

7

Ques/              Calculations/Berekeninge                 Explanation if necessary/
 Vr                                                          Verduideliking indien
                                                                     nodig

        Scales on both x-and y- axes correct/ Skale vir beide x-en y-asse korrek A
        All 5 points plotted correctly/ Al 5 punte korrek geplot CA
        Join points for a straight line/Verbind punte vir reguitlyn CA             (3)
                                                                                    [41]
                                        TOTAL 75

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