# Mathematics Grade 8 Paper 1 November Mock 2026 Memo

> Grade 8 Mathematics Paper 1 memorandum from the November Mock Exam 2026, 7 pages. Read online or get the free PDF download, question paper linked when available.

- Page: https://www.hlayiso.com/library/grade-8-mathematics-2026-november-mock-exam-memorandum-paper-1/26e0c258-6372-42f6-9895-9055ab8859f8
- Updated: 2026-10-26
- Subject: Mathematics
- Grade: Grade 8
- Document type: Memorandum
- Year: 2026
- Exam period: November Mock Exam
- Paper: 1
- Publisher: Hlayiso
- Curriculum: CAPS
- Pages: 7

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## About this document

Mathematics · Grade 8 · November Mock Exam · 2026. Memorandum, 7 pages. Read online or download the PDF.

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## Document text

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### Page 1

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Mock
hlayiso mock exams
Practice Series:
Grade 8 Exam Preparation
WWW.HLAYISO.COM
SENIOR PHASE
END-OF-YEAR EXAMINATION
GRADE 8
MATHEMATICS P1
NOVEMBER 2026 (MOCK)
MARKING GUIDELINES
MARKS: 75
These marking guidelines consist of 7 pages.

### Page 2

Mathematics/P1
2
Senior Phase – Marking Guidelines
Hlayiso/Mock 2026
NOTE:
• If a learner answers a question TWICE, only mark the FIRST attempt.
• If a learner has crossed out an attempt and not redone the question, mark the crossed-out version.
• Consistent accuracy (CA) applies in ALL aspects of the marking guidelines. Stop marking at the
second calculation error.
• Accept correct alternative methods. Answers only: award full marks ONLY where the guideline
says so.
• Do not penalise learners if units are omitted in final answers, unless the question asks for them.
SECTION A
QUESTION 1
1.1
B (−7 is a negative integer; natural numbers are
1 ; 2 ; 3 ; ...)
✓B
(1)
1.2
A (3,6×105)
✓A
(1)
1.3
C (highest exponent is 5)
✓C
(1)
1.4
C (460×1,15 = R529)
✓C
(1)
1.5
C (cube numbers: 53 = 125)
✓C
(1)
[5]
SECTION B
QUESTION 2
2.1
150 = 2×3×5×5
150 = 2×3×52
✓prime factors
✓exponential form
(2)
2.2
HCF = 2×3 = 6
LCM = 23 ×3×52 ×7 = 4200
✓HCF = 6
✓LCM = 4200
(CA from 2.1)
(2)
2.3
=
√
25−(−4)+(−8)
= 5+4−8
= 1
✓
√
25 = 5
✓+4 and −8
✓answer
(3)
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### Page 3

Mathematics/P1
3
Senior Phase – Marking Guidelines
Hlayiso/Mock 2026
2.4
= 5
2 −6
12
= 5
2 −1
2
= 4
2 = 2
✓5
2
✓1
2 (multiplication first)
✓answer
(3)
[10]
QUESTION 3
3.1
Total parts = 2+3+4 = 9
One part = 1350
9
= R150
Ayanda: R300; Bheki: R450; Zola: R600
OR
2
9 ×1350 = R300,
3
9 ×1350 = R450,
4
9 ×1350 = R600
✓9 parts / R150
✓any two shares
✓all three shares
(3)
3.2
Time = distance
speed
= 270
90 = 3 hours
Arrival: 07:45+3 h = 10:45
✓3 hours
✓10:45 (CA)
(2)
3.3
SI = 6500×4×0,075
SI = R1950
Amount = 6500+1950 = R8450
OR A = 6500(1+4×0,075) = R8450
✓substitution
✓R1 950
✓R8 450 (CA)
(3)
[8]
QUESTION 4
4.1
= 4x6y2 ×3xy4
6x5y3
= 12x7y6
6x5y3
= 2x2y3
✓4x6y2
✓12x7y6 or coefficient 2
✓x2y3
(3)
4.2
= 7a4 −2a4
= 5a4
✓7a4 and 2a4
✓answer
(2)
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### Page 4

Mathematics/P1
4
Senior Phase – Marking Guidelines
Hlayiso/Mock 2026
4.3
= 34 ÷33 +1
= 3+1 = 4
OR 81÷27+1 = 4
✓34 ÷33 or 81÷27
✓answer
(2)
[7]
QUESTION 5
5.1.1
1
✓answer
(1)
5.1.2
−7
✓answer
(1)
5.1.3
= −5(−2)3 +3(−2)2 +(−2)−7
= −5(−8)+3(4)−2−7
= 40+12−2−7
= 43
✓substitution
✓40 and 12
✓answer
(3)
5.2.1
= 6a2 −3ab−2a2 −8ab
= 4a2 −11ab
✓6a2 −3ab
✓−2a2 −8ab
✓answer
(3)
5.2.2
= 12x3
4x −8x2
4x + 4x
4x
= 3x2 −2x+1
✓3x2 −2x
✓+1
(2)
5.2.3
(5p2 −3p+2)−(2p2 −p−6)
= 5p2 −3p+2−2p2 + p+6
= 3p2 −2p+8
✓correct order and signs
✓answer
(2)
[12]
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### Page 5

Mathematics/P1
5
Senior Phase – Marking Guidelines
Hlayiso/Mock 2026
QUESTION 6
6.1.1
5x−2x = 8+7
3x = 15
x = 5
✓3x = 15
✓answer
(2)
6.1.2
3x−12−2x−2 = 6
x−14 = 6
x = 20
✓3x−12
✓−2x−2
✓answer
(3)
6.1.3
×6: 2x+12 = 3x−6
12+6 = 3x−2x
x = 18
✓multiplying by LCD 6
✓2x+12 = 3x−6
✓answer
(3)
6.1.4
5x = 125
5x = 53
x = 3
✓5x = 125 or 53
✓answer
(2)
6.2
Kagiso: x
Lerato: x+6
(x+4)+(x+6+4) = 40
2x+14 = 40
x = 13
Lerato is 13+6 = 19 years old.
(Trial and improvement with a check: full marks)
✓equation
✓x = 13
✓19 years (CA)
(3)
[13]
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### Page 6

Mathematics/P1
6
Senior Phase – Marking Guidelines
Hlayiso/Mock 2026
QUESTION 7
7.1.1
p = 10
q = 12
✓p
✓q
(2)
7.1.2
Constant difference = 2
Tn = 2n+2
✓2n
✓+2
(2)
7.1.3
2n+2 = 64
2n = 62
n = 31 tables
✓equating to 64
✓31 tables (CA)
(2)
7.2.1
Constant difference = 3
y = 3x−4
✓3x
✓−4
(2)
7.2.2
a = 3(4)−4 = 8
b = 3(10)−4 = 26
✓a = 8
✓b = 26 (CA)
(2)
[10]
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### Page 7

Mathematics/P1
7
Senior Phase – Marking Guidelines
Hlayiso/Mock 2026
QUESTION 8
8.1.1
12 km
✓answer
(1)
8.1.2
From 08:45 to 09:30: 45 minutes
✓answer
(1)
8.1.3
Distance = 12 km; time = 09:30 to 10:30 = 1 hour
Speed = 12
1 = 12 km/h
✓12 km and 1 hour
✓12 km/h
(2)
8.1.4
To the park: the graph is steeper from A to B (12 km in
45 min = 16 km/h, compared to 12 km/h on the way
back).
✓to the park
with reason
(No mark for the answer
without a reason)
(1)
8.2.1
x
−1
0
1
2
3
y
−3
−1
1
3
5
✓any three correct
✓all five correct
(2)
8.2.2
x
y
(3 ; 5)
(−1 ; −3)
✓at least three points plotted
correctly
✓all five points plotted
correctly
✓straight line drawn
through the points
(CA from 8.2.1)
(3)
[10]
TOTAL: 75
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