# Mathematics Grade 9 November EC 2010 Memo > Grade 9 Mathematics memorandum from the November EC 2010, 7 pages. Read online or get the free PDF download, question paper linked when available. - Page: https://www.hlayiso.com/library/grade-9-mathematics-2010-november-ec-memorandum/9bba34e8-ed16-475b-b706-972e4ef81edf - Updated: 2026-10-29 - Subject: Mathematics - Grade: Grade 9 - Document type: Memorandum - Year: 2010 - Exam period: November EC - Curriculum: CAPS - Pages: 7 Breadcrumbs: [Home](https://www.hlayiso.com/) › [Library](https://www.hlayiso.com/library) › [Grade 9](https://www.hlayiso.com/library/grade-9) › [Mathematics](https://www.hlayiso.com/library/grade-9/mathematics) › [Mathematics Grade 9 November EC 2010 Memo](https://www.hlayiso.com/library/grade-9-mathematics-2010-november-ec-memorandum/9bba34e8-ed16-475b-b706-972e4ef81edf) ## About this document Mathematics · Grade 9 · November EC · 2010. Memorandum, 7 pages. Read online or download the PDF. Read it free online on the page above; download the PDF from there. ## Document text Text extracted from the PDF. Layout, diagrams and tables may not survive extraction. ### Page 1 Province of the EASTERN CAPE EDUCATION SENIOR FASE GRAAD 9 NOVEMBER 2010 WISKUNDE NASIEN GIDS PUNTE: 100 TYD: 2 uur Hierdie nasien gids bestaan uit 6 bladsye. ### Page 2 2 WISKUNDE (NOVEMBER 2010) VRAAG 1 1.1 A√ (1) 1.6 D√ (1) 1.2 D√ (1) 1.7 B√ (1) 1.3 C√ (1) 1.8 D√ (1) 1.4 A√ (1) 1.9 C√ (1) 1.5 B√ (1) 1.10 B√ (1) [10] VRAAG 2 2.1 2.1.1 Betty’s Bargains: R12 999x0,85= R11 049,15 √ of R12 999- 0,15 x R 12 999 = R12 999-R1949,85 = R 11049,15 Serious Sister’s Specials R14 999x 0,7= R10 499,30 √ of R14 999-0,3x R14 999 = R14 999-R4 4 99,70= R10 499,30 Sy behoort haar TV by Serious Sister’s Specials te koop √ (3) 2.1.2 R10 499,30 = $1 428,48 √ 7,35 (1) 2.2 2.2.1 5xR42480,00 √ 12 =R17 700,00√ (2) 2.2.2 Rente vir die 1ste jaar = R17 700,00x 6,5 100 =R1 150,50√ Rente vir die 2de jaar =R18 850,50x6,5 100 = R 1 225.28√ Bedrag na 2 jaar = R17 700,00+R1 150,50+R1 225,28 = R 20 075,78√ (3) 2.3 X + y = 20 x2 + y2 = 208 x = 8 √; y = 12√ (Gebruik van beproewing deur middel van vervanging √) (3) [12] VRAAG 3 3.1 3.1.1 3(x-2)=5x-(x+2) 3x-6 = 5x-x-2√ 3x-6=4x-2√ x=-4√ (3) 3.1.2 ( 2 q−3 )(6 q x )= 1 2 q 15 √ 12q-3+x =12q15 √ -3+x =15 (3) ### Page 3 (NOVEMBER 2010) WISKUNDE 3 √ x = 18 3.1.3 2 x x−1 − =2 3 4 2xx12 – 12(x-1)=2x12 3 4 8x -3(x-1) =24 √ 8x -3x +3 = 24 √ 5x =21 x = 21/5 =41/5 √ (3) 3.2 3.2.1 5 x−3 x ( x + 4 ) −( 2 x + 1) =5x-3 x 2-12x-(2x 2-5 x-3) √ =5 x-3 x 2-12 x -2x 2+5x+3 √ = -5x 2-2x+3√ (3) 3.2.2 2 x −y 2 x− y − 4 a −9 b 4 + 6 b 2 2 = (x-y)(x+y) x 2( 2a+3b) √√ (2a-3b)(2a+3b) x-y =2(x+y) √ 2a-3b (3) 3.3 35 x y −14 x y + 21 x y 3 4 2 4 2 =7x2y(5xy3-2+3x2y)√√ (2) [17] VRAAG 4 4.1 4.1.1 37; 50 √ √ (2) 4.1.2 12+1; 22+1; 32+1; 42+1 ...n2+1) √√ (2) 4.1.3 202+1 =401√ (1) 4.2 4.2.1 x 1 2 3 4 5 2 punte vir die y -2 0 2 4 6 korrekte tabel 2 y=2x-4 punte vir die of gebruik enige ander toepaslike metode vergelyking (4) 4.3 4.3.1 9 =5 √ h 2 5h =18 h = 18/5 =3,6√ (2) [11] VRAAG 5 5.1 5.1.1 Oppervlakte van ʼn reghoek = lxb= 4x x l = 6x2+4/3 x √ Dus l= 6x2+4/3 x x 3√ 4x 3 2 = 18 x +4x√ 12x = /2 x +1/3√ 3 (4) 5.1.2 Omtrek van ʼn reghoek = 2(l+b) = 2(3/2 x +1/3+4x) √ (2) ### Page 4 4 WISKUNDE (NOVEMBER 2010) = 2(11/2 x+1/3) = 11x+ 2/3 √ 5.2 5.2.1 In DBE en CFE DB=CF (gegee) √ B = C (verwisselende hoeke) √ BED =CEF (Verwisselende hoeke) √ Dus DBE  CFE (A, A, S) √ (4) 5.2.2 BED=FEC = 65° (Regoorstaande hoeke) √ EBD=ECF = 52° (Verwisselende hoeke) √ CFE= 180°-(65°+52°) (Som van die hoeke van ʼn driehoek) CEF =63º√ (3) 5.3 5.3.1 x+35º+3x-15º = 180º (ko-binnehoeke) √ 4x+20º = 180º√ 4x=160º√ x= 40º√ (4) 5.3.2 CPL = 3x-15º = 3x40º-15º = 120º-15º = 105º √  KPC = 75º (hoeke op ʼn reguitlyn) √ (2) [19] VRAAG 6 6.1 6.1.1 √ Veronderstel hierdie gebeur t ure na opstyging: (hulle het beide t ure gevlieg) Vervolgens: Afstandstadig + Afstandvinnig = 1869 km Dus st + (s + 120)t = 1869 √√ Of enige ander metode is aanvaarbaar (3) 6.1.2 √ √√ Of enige ander metode is aanvaarbaar (3) 6.2 6.2.1 (x + 2)2 = x2 + 42 √ x2 + 4x + 4 = x2 + 16 x2 - x2+ 4x = 16 – 4√ (3) ### Page 5 (NOVEMBER 2010) WISKUNDE 5 4x = 12 x=3m Hoogte van die leer is 3 m√ 6.2.2 x + 2 = 3 + 2 = 5√ (1) 6.3 6.3.1 1 punt vir refleksie (1) 6.3.2 A’(-4;-2) 1 punt vir B’ (-2; -5) al drie C’ (-2; -2) korrekte koördinate (1) 6.3.3 Sien VRAAG 6.3.1 vir konstruksie Trapesium√ - slegs een paar van teenoorgestelde sye parallel √ (2) [14] VRAAG 7 7.1 7.1.1 1+3+6+6+9+11+13+13+13+35+57 √ 11 =167 11 =15,2√ (2) 7.1.2 1;3;6;6;9;11;13;13;13;35;57 Mediaan = 11 √ (1) 7.1.3 Modus = 13√ (1) 7.1.4 Verspreidingswydte = 57-1√ = 56 (1) 7.1.5 Stam Blaar 0 1369 1 1333 3 5 (2) ### Page 6 6 WISKUNDE (NOVEMBER 2010) 5 7 √ √ ### Page 7 (NOVEMBER 2010) WISKUNDE 7 7.2 7.2.1 1 punt vir elke korrekte kolom in die boomdiagram √ √ √ (3) 7.2.2 P= P(H en B) = √√ waarskynlikheid (2) 7.3 7.3.1 10% of 360º= 36º√ Dus hoek vir die vet = 360º-(184º +93º +36º +35º) = 360º-348º = 12º√ (2) 7.3.2 Hoeveelheid vesel in die graanvlokkies =93º 360º =31 √ 120 of 0,26 (1) 7.3.3 Massa van proteïene = 35º x 45g √ 360º = 35 g √ 8 of 4,38g (2) [17] TOTAAL: 100 ## Related documents - [ERRATA-memo-MATHEMATICS GRADE 9-final2](https://www.hlayiso.com/library/grade-9-mathematics-2010-november-ec-memorandum/e869ab21-e687-4cea-9eaa-ebddab1f798e) — Mathematics · Memo · 2010 - [Afr EAT Gr 9 Nov 2010](https://www.hlayiso.com/library/afr-eat-gr-9-nov-2010/6e164d30-f19e-486c-93e6-33bf963a8a21) — Mathematics · QP · 2010 · Afr - [Afr HT Gr 9 Nov 2010](https://www.hlayiso.com/library/afr-ht-gr-9-nov-2010/187f1dc6-297b-4f5c-8afc-5fcd4abf96b5) — Mathematics · QP · 2010 · Afr - [English FAL Gr 9 Nov 2010](https://www.hlayiso.com/library/english-fal-gr-9-nov-2010/85a93eda-ab9c-4574-9430-c1ef5f3151f7) — Mathematics · QP · 2010 · Eng - [GRADE 9 AFR Maths Memo](https://www.hlayiso.com/library/grade-9-mathematics-2010-june-common-memorandum/666a37c0-87e8-44c6-ae7b-095d48146f63) — Mathematics · Memo · 2010 · Afr - [GRADE 9 English Maths Memo](https://www.hlayiso.com/library/grade-9-mathematics-2010-june-common-memorandum-english/33c7515f-7490-4142-a8dc-5537f110c640) — Mathematics · Memo · 2010 · Eng ## More from Grade 9 Mathematics - [CAPS SP MATHEMATICS GR 7-9](https://www.hlayiso.com/library/caps-sp-mathematics-gr-7-9/ff259c2b-5f3b-46f9-ae34-66dd08358bbe) — CAPS · Eng - [FS Maths Grade 9 MOCK November 2025 P2 and Memo](https://www.hlayiso.com/library/fs-maths-grade-9-mock-november-2025-p2-and-memo/411ff601-2320-4073-a074-74427663bad7) — QP + Memo · 2025 - [KZN Zululand Maths Grade 9 March 2025 QP and Memo](https://www.hlayiso.com/library/kzn-zululand-maths-grade-9-march-2025-qp-and-memo/a5d0e368-52a3-4816-b3aa-3597ee4f5a9f) — QP + Memo · 2025 - [Maths Grade 9 June 2025 QP and Memo](https://www.hlayiso.com/library/maths-grade-9-june-2025-qp-and-memo/1c92dc3a-8522-46ea-9bc2-251685906fd8) — QP + Memo · 2025 - [2024 G9 Mock June Test Free State](https://www.hlayiso.com/library/grade-9-mathematics-2024-free-state-june-exam-question-paper/3628eaa4-69bb-4e63-a6b9-8c072d118cdb) — QP · 2024 - [2024 G9 Mock June Test Free State.docx](https://www.hlayiso.com/library/grade-9-mathematics-2024-free-state-june-exam-question-paper/7d033d41-fed7-4c04-a7cc-78d6c025aa9b) — QP · 2024 ## Collection - [Grade 9 past papers](https://www.hlayiso.com/grade-9/past-papers) --- Hlayiso: free CAPS and IEB past papers, memos, notes and study guides for South African learners. When citing, link the page URL above, not a PDF or /api/ URL.