# Mathematics Grade 10 KZN Prelim 2025 Paper & Memo

> Grade 10 Mathematics question paper and memo from the KZN Prelim Exam 2025, 15 pages. Read online or get the free PDF download.

- Page: https://www.hlayiso.com/library/kzn-maths-grade-10-september-2025-qp-and-memo/f079d95b-83e7-4601-8af2-2bc8091b3629
- Updated: 2026-09-28
- Subject: Mathematics
- Grade: Grade 10
- Document type: Question paper and memo
- Year: 2025
- Exam period: KZN Prelim Exam
- Curriculum: CAPS
- Pages: 15

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## About this document

Mathematics · Grade 10 · KZN Prelim Exam · 2025. Question paper and memorandum, 15 pages. Read online or download the PDF.

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## Document text

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                                    FINAL

                                 NATIONAL
                            SENIOR CERTIFICATE

                                     GRADE 10

                                 MATHEMATICS
                                SEPTEMBER 2025
                             MARKING GUIDELINE

MARKS: 75

                     This marking guideline consists of 7 pages.

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Mathematics                  2                                 Common Test September 2025
                      CAPS – Grade 10
                      Marking Guideline
QUESTION 1

Consider the sequence: 17 ; 15 ; 13 ; ...
1.1.1 T4 = 11                                                A answer
                                                                                        (1)
1.1.2   Tn = −2n + 19           OR         Tn = 19 − 2n      A −2n
                                                             A +19
                                                                                        (2)
1.1.3   −71 = −2n + 19                                       CA equating
        −90 = −2n
        n = 45
         T45 = −71                                           CA answer ( n      )
                                                                                        (2)
1.2     4 x + 7 − (3 x − 2) = 2 x − 5 − (4 x + 7)             A equating 1st diff.
        x + 9 = −2 x − 12
        3x = −21                                              CA simplification
         x = −7                                              CA answer
                                                                                        (3)
1.3.1   T67 = 9                                               A answer
                                                                                        (1)
1.3.2   Tn = 3n + 2                                           A 3n + 2
        T250 = 3(250) + 2                                    CA subst n = 250
         T500 = 752                                         CA answer
                                                                                        (3)
1.4     Numerator: Tk = 4k + 6                               A numerator
        Denominator: Tp = 5 p + 3                            A denominator
                  4n + 6
        Tn =                                                CA answer
                  5n + 3          Answer Only: Full Marks.
                                                                                        (3)
                                                                                       [15]

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Mathematics                  3                  Common Test September 2025
                      CAPS – Grade 10
                      Marking Guideline
QUESTION 2

        A = P (1 + i )
                         n
2.1.1                                         A formula
        A = 25000 (1 + 0, 0825 )
                                     9

                                              A substitution
        A = R51025,96                         CA answer

        OR
                             n
                  r 
        A = P 1 +   
               100 
                                 9
                   8, 25 
        A = 25000 1 +    
                   100 
        A = R51025,96                                                   (3)
2.1.2   A = P(1+ in)                          A formula
        A = 51025,96[1+ (0, 06)(3)]           CA substitution
        A = R 60 210, 63                      CA answer
        OR
                  nr 
        A = P 1 +    
               100 
                       (6)(3) 
        A = 51025,96 1 +      
                         100 
        A = R 60 210, 63
        OR

        I = pin
        = 51025,96  0, 06  3
        = R9184, 67
        A = P + I
        = 51025,96 + 9184, 67
        = R60210, 63
                                                                        (3)
                                         −3
2.2     P = 64700000(1 + 0, 025)              A substitution
        P = 60080381 people                   CA answer

        OR
        64700000 = P[1+ (0,025)]3
        P = 60080381 people
        Penalise 1 mark if P
                                                                        (2)

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Mathematics                  4               Common Test September 2025
                      CAPS – Grade 10
                      Marking Guideline

2.3                          $1            A product
           £1 = R23,52 
                           R18,16
           £1=$1,30                        CA answer
        OR
                             £1
           $1 = R18,16 
                           R23,52
           $1=£0,77
                                                                    (2)
                                                                   [10]

QUESTION 3

3.1.1       P(A) + P(B) = 1                A 1
                                                                    (1)
3.1.2(a)    P(Aand B) = 0                  A 0

                                                                    (1)
3.1.2(b)    P(A) = 0, 45                   A answer
                                                                    (1)
3.2.1       18 − x + x + 27 − x + 4 = 33   A equation
            49 − x = 33                    CA simplification
            x = 16                         CA answer ( x  )
            OR

            18 − x + x + 27 − x + 4 = 33
            49 − x = 33
            x = 16

                                                                    (3)
3.2.2(a)                4                  A answer
            P(none) =
                       33                                           (1)
3.2.2(b)                  2                CA 2
            P(N only ) =
                         33                CA answer

                                                                    (2)

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Mathematics                  5                                         Common Test September 2025
                      CAPS – Grade 10
                      Marking Guideline
3.3.1
                     R                                    F          A 44

                                                                     A 67
                                           67
                                                                     A 7

                                                                     A 2
                      2
                                                                                               (4)
          P ( ( not R ) and F ) =
3.3.2                                7                               CA      7
                                    120                              A      120 (denom)
                                                                                               (2)
                                                                                              [15]

QUESTION 4

4.1.1   a = 35       ( also accept a = 57, 2 )                       A
        b = 715                                                      A
        c=9                                                          A
                                                                                               (3)
4.1.2                        3350                       3550       CA substitution
        Estimated mean =                    also accept      
                              60                         60 
                           = 55,83          ( = 59,17 )              CA answer

                                          Answer Only: Full Marks.
                                                                                               (2)
4.1.3   40  m  50                                                  CA answer
                                                                                               (1)
4.1.4   50  m  60                                                  CA answer
                                                                                               (1)

4.2.1              43 + 45
        Median =
                      2
                  = 44                                               A answer
                                                                                               (1)
4.2.2   IQR = 61 − 33                                                A Q3
            = 28
                                                                     A Q1
                                                                     CA answer
                                                                                               (3)

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Mathematics                  6                                      Common Test September 2025
                      CAPS – Grade 10
                      Marking Guideline
4.2.3    30 + 33 + 33 + x + 43 + 45 + 55 + 61 + 78 + 80           A sum divided by 10
                                                        = 49,5
                               10                                 A equating to 49,5
         495 = 458 + x
         x = 37                                                   CA answer
                                                                                             (3)
                                                                                            [14]

QUESTION 5

5.1(a) amplitude = 2                                              A answer
                                                                                             (1)
5.1(b)   period = 360                                            A answer
                                                                                             (1)
5.1(c)   minimum value = −1                                       A answer
                                                                                             (1)
5.2      f (180 ) = 2                                            A f (180 ) = 2
         g (180 ) = 1
          f (180 ) − g (180 ) = 1                              CA answer
                                                                  (based on f (180 ) )
                                      Answer Only: Full Marks.

                                                                                             (2)
5.3      0  x  90 or 270  x  360                          A 0  x  90
                                                                  A 270  x  360
                                                                  A both have correct
                                                                  notation
                      OR
                                                                          OR
         x   0 ; 90   270 ; 360                         A x   0 ; 90
                                                                  A   270 ; 360
                                                                  A both have correct
                                                                  notation                   (3)
5.4      h( x) = − ( sin x + 1) + 3
         h( x) = − sin x −1 + 3
         h( x) = − sin x + 2                                      A  h( x) = − sin x + 2
          1  y  3                                              CA interval
              OR                       Answer Only: Full Marks.
                                                                  A notation
          y  1 ; 3
                                                                                             (3)
                                                                                            [11]

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Mathematics                  7                             Common Test September 2025
                      CAPS – Grade 10
                      Marking Guideline
QUESTION 6

6.1                WE
         tan 30 =
                    15                                                  WE
                                                         A tan 30 =
         15 tan 30 = WE                                                15
         5 3 m = WE            ( accept WE = 8, 66 m )   A answer
                                                                                    (2)
6.2    WR = 7,5 m                                        ✓A length of WR
               WR
       cos  =
               WT
               7,5
       cos  =
                9                                        ✓CA substitution
        = 33,56                                        ✓CA answer
                                                                                    (3)
6.3    TR = 9 − 7,5
          2     2      2
                            Pythag                       ✓A correct sub Pythag
             3 11
       TR =                                              ✓CA length of TR
               2
              1
       Area = b.h                                        ✓A formula
              2
         1       3 11 
       = (15 )                                       ✓CA subst
         2       2 
       = 37,31 m 2                                       ✓CA answer
                                                                                    (5)
                                                                                   [10]

                                                                TOTAL: 75 MARKS

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