# Mathematics Grade 11 KZN Prelim 2025 Paper & Memo

> Grade 11 Mathematics question paper and memo from the KZN Prelim Exam 2025, 16 pages. Read online or get the free PDF download.

- Page: https://www.hlayiso.com/library/kzn-maths-grade-11-september-2025-qp-and-memo/286df67f-6841-434e-9245-e0e951632580
- Updated: 2026-09-27
- Subject: Mathematics
- Grade: Grade 11
- Document type: Question paper and memo
- Year: 2025
- Exam period: KZN Prelim Exam
- Curriculum: CAPS
- Pages: 16

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## About this document

Mathematics · Grade 11 · KZN Prelim Exam · 2025. Question paper and memorandum, 16 pages. Read online or download the PDF.

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## Document text

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### Page 1

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KWAZULU-NATAL PROVINCE

EDUCATION
REPUBLIC OF SOUTH AFRICA

NATIONAL

1% hours

This question paper consists of 7 pages and 2 DIAGRAM SHEETS.

Copyright reserved Please Turn Over

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Grade 1

INSTRUCTIONS AND INFORMATION

Read the following instructions carefully before answering the questions.

1.

2.

This question paper consists of 5 questions.
Answer ALL the questions.

Number the answers correctly and according to the numbering system used in this
question paper.

Clearly show ALL calculations, diagrams, graphs, etc. which you have used in
determining your answers.

Answers only will NOT necessarily be awarded full marks.

You may use an appro
graphical), unless s

lator (non-programmable and non-

If necessary, round off ans\ TWO decimal places, unless stated otherwise.

TWO DIAGRAM SHEETS fo ON 3.2.2, QUESTION 3.2.4,

QUESTION 5.1 and QUE attached at the end of this question paper.
Detach the DIAGRAM SHEETS and hand them in together with your ANSWER
BOOK.

Diagrams are NOT necessarily drawn to scale.

Write neatly and legibly.

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Grade 1

QUESTION 1

1.1

1.2

1.3

1.4

15

A’school bought a brand-new data projector for R20 000. The value of the machine
depreciated annually at the rate of 13% per annum, on a reducing balance.

1-1-1 — Calculate the book value of the data projector 7 years after it was bought. (2)

1.1.2. The exchange rate between America ($) and South Africa (R ) was
$1 =R18,45. Calculate the book value of the data projector 7 years after it was

bought in American dollars. (2)

An investment earns interest a p.a., compounded quarterly. Calculate

the effective interest rate (3)

The value of a flat increases a e rate of 12% per annum on a straight-line

basis. Calculate the current f it will be valued at R500 050 in 60

months’ time. (2)

Three years ago, the selling price of a dozen of eggs was R16,25. The selling price of a

dozen of eggs is currently R18,00. Calculate the average yearly inflation rate at which

the price of eggs increased over the three years. (4)

Mr Mavundla invested R12 000 in an account that earned interest at the rate of 11,35%

p.a.. He had forgotten what the compounding period of the investment was. After 20

unequal amounts of interest were added to the original investment, the accumulated

amount was R36 193,15. How many years did it take for the original investment to

accumulate to R36 193,15? (5)
[18]
(2)

iven that events A and B are mutually exclusive. (3)

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rade |

2:2

A SuEICY was conducted among 140 workers about the category of salary they earned
i ey worked. The results are summarised in the

Moderate Bad
: : Total
environment | environment
15 17 55
3 Pp 60
12 9 25
30 61 140
Write down the values of m and p. (2)

2.2.2 Calculate the prob electing a worker from this group who
worked in a good ose salary was in the
R25 000 < x < R40 000 cate (1)

2.2.3. Are the events worki rate environment and earning a salary above
R40 000 independent? Fustif ir answer with relevant calculations. (4)

2.3. Mr Van der Merwe rolls an ordinary fair dice in a game.
The rules are as follows:
e if number | is rolled, he wins;
e  ifnumber 2 or 3 is rolled, he loses;
e if number 4,5 or 6 is rolled, he rolls again.

If Mr Van der Merwe rolls again and:
e anumber from | to 4 is rolled, he loses;

e number 5 or 6 is rolled, he wins.

The game stops when Mr Van der Merwe wins or loses.

2.3.1 Represent the above information in a tree diagram. Show the probabilities
associated with each branch and the outcomes of this game. (4)

2.3.2 Write down the probability that Mr Van der Merwe wins on the first roll of the

dice. q)

2.3.3 Calculate the probability that Mr Van der Merwe will lose at this game.
Write your answer as a percentage. (3)
[20]

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Grade 1

QUESTION 3

ca!

3.2

The table below shows the number of learners who participated in a Maths Olympiad at
a school over the past 9 years.

5 8 15 20 25 27 31 36 75
3.1.1 Calculate the mean of the data. (2)
3.1.2 Write down the standard deviation of the data. dd)

of learners who participated in the Maths

3.1.3. For how many years wa
1 ation below the mean? (2)

tbe number

)f learners waited one afternoon before
orded. The information was summarised

The amount of time, in mi
they were helped by a schoo
in the frequency table below.

3.2.1 Write down the modal class of the data. (dd)

3.2.2 Complete the cumulative frequency column of the table provided in DIAGRAM

SHEET 1. (2)
3.2.3. Write down the total number of learners who waited to be helped by the librarian ()
that afternoon.
3.2.4 On the grid provided in DIAGRAM SHEET 1, draw the cumulative frequency
graph (ogive) of the data. (3)
3.2.5 Use your graph to estimate the interquartile range of the data. (3)
[15]

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le 1
QUESTION 4.

In the diagram below, the graphs of f(x)=sinbx+gq and g(x) =cos(x+p) are shown for the
interval 90° < x <180°.

4
z= oN
15
re
— 7
LZ,
-° 60° oe Yea?
055 r
4.1 Write down the amplitude of f ()
4.2 Write down the period of g. (1)
43 Write down the values of b, q and p. (3)

44 Determine the value(s) of x in the interval —90° < x <180° for which:
4.4.1 x.g(x) 20. (2)
44.2  — f(x)—sin30°= g(x)+1 (3)
45 Given that A(x)=g(x+k), determine the value(s) of k in the interval
—90° <k <180°where h(x) =sin(—x). (2)

[12]
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le 1

QUESTIONS

5.1 Inthe diagram below, AABC is sketched. B is an acute angle.

A

sinB _ sinC

Use the sketch provided on D! 2 to prove that = (5)
e
5.2 In the diagram below, AB is a vertical pole. The angle of elevation from C to the top of
the pole is @ and the angle of elevation from M to the top of the pole is @.
CM is x metres.
B
x ain a@.sin@ (5)
sin(O-a)
[10]

TOTAL: 75 MARKS

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TEAR OFF

matPewnloaded from Stanmorephysics.com September 2025 Test
Grade 1
NAME:
DIAGRAM SHEET 1
QUESTION 3.2.2
Time waiting Number of | Cumulative
(in minutes) learners frequency
O<x<4 6
4<x<8 12
20
16
6
QUESTION 3.2.4

10 ll 12

Time waiting (in minutes)

14 15 16 17 18 19 20

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September 2025 Test

Grade 1

matPawnloaded from Stanmorephysics.com

DIAGRAM SHEET 2
QUESTION 5.1
QUESTION 5.2

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AHO YUVAL

### Page 10

NATIONAL
SENIOR CERTIFICATE

MARKS: 75

These marking guidelines consist of 7 pages.

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Grade 11 CAPS — Marking Guidelines
QUESTION 1
1.1.1 | A=P(1-i)" B/D incorrect formula
A=20-000(1-0,1 3)’ vA correct subst. into correct formula
fal Only penalize here for
RG 45,10 incorrect rounding off. ¥CA answer Q)
1.1.2 | Vaiuein dotlars = 87 545.10 va Book value
R18,45/$1 18,45
=$408,95 | Answer only: Full marks ¥CA answer Q)
1.2 tig = ( + ba] YA correct formula
m
4
ltig = (: + 0, a vA correct substitution into formula
4
r=9,31% per annum ¥CA answer
G3)
13 | 4=P(+in)
500050= P(1+0,12x 5) vA correct subst. into correct formula
_ 500050
(1+0,12x 5)
P=R312531,25 B/D incorrect formula ¥CA answer
(2)
14 A=P(I+i)'
(red) ; VA P= 16,25; A= 18; n=3
18=16, 25(1 +i ) vA subst. into correct formula
. 18
i= te 25 ol YCA simplifying using ¥.....
im B/D incorrect formula and a
r=3,47% if A and P are swopped CA answer “)

vA correct subst. of A and P

vA correct subst. of i and exponent 20

¥CA simplification

¥CA value of compounding period
¥CA answer (5)

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Grade 11 CAPS — Marking Guidelines
QUESTION 2
2.1.1 | P(B)=1—P(not B)
=1-0,67 Agesier Galyt 2 vA subst. into correct rule
= 0,33 2 v A answer (2)

2.1.2 | P(A or B)= P(A) + P(B)—P(A and B)
0,57 = P(A) +.0,33 —0

P(A) = 0,24 B/D if P(A and B) #0

OR
P(A or B)= P(A) + P(B)
0,57 = P(A) + 0,33

¥ A correct rule
¥CA substitution
¥CA answer (3)

OR
v A correct rule

¥ CA substitution

P(A) = 0,24 ¥ CA answer (3)
2.2.1 |m=4 YA 4
p=35 VA 35 (2)
a2) | P=
140
11 ll
P= — vA — 1
70 70 qd)
2.2.3 | P(moderate and R40 000 < x3
3
vA — OR 0,09
35
P 30. 25
(moderate )xP (R40 000 < x < R65 000) VA ax
140 140 140 140
15 15
=—— OR 0,04 vA — OR 0,04
392 392
P( moderate and > R40 000) # P(moderate)xP(> R40 000)
..the events are NOT INDEPENDENT ¥CA conclusion (4)
2.3.1 1* roll 24 roll OUTCOMES
, ' vA both branches correct
Wins Wins
¥ A correct probabilities:
x Zor! i 3orl on I* roll
Loses, Loses 6 6 3 6 2
4 Loses Rolls Again & Loses | vA correct probabilities:

ree : : OR : : : OR ; on 2™ roll
: Wins Rolls Again & Wins | YA outcomes (4)
2.3.2 P(win on the first roll) == OR 0,17 OR 16,67% vA z (1)
2.3.3 | P(loses)= P(L) + P(Rolls Again and Loses) 5
P(loses)= 2 + exe vCA 6 OR ;

6

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September 2025 Test

Grade 11 CAPS arking Guidelines
11 3.4 1.2
moe ¥CA >x— OR=x=
P(loses) : oC as
P(loses)= 66,67% YCA answer (3)
[20]
QUESTION 3
31.1 | x22” F VA 242
9 Answer only: =
= 26,89 2 ¥CA answer
Note: CA only if
divided by 9
(2)
3.1.2 | o=19,56 VA 19,56 dl)
3.1.3 | ¥-o =26,89-19,56
= 7,33 (no. of learne on below the mean) YCA x-o
-. | year ¥CA answer (2)
3.2.1 | 8<x<12 v A answer qd)
8.2: - 7
Time waiting
(in minutes)
O0<x<4
1
2 an VA 6; 18
20 38
16 54
6 60 YCA 38; 54; 60
(2)
3.2.3 | 60 learners ¥CA answer (1)

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Grade 11 CAPS — Marking Guidelines

3.2.4
60
58 |
56
54 4
re! YCA points plotted
Pa a at upper limit
44
Es a ¥ A shape: smooth
= 38 curve
36
out v :
32 A grounding at
23 (0:0)
£ 26
5 24
2 2
20
18
16
14
12
10
8
6
>
ri Vv SS (3)
13. 14 15 16 17 18 19 20
e inutes)
3.2.5 | Q#7,5 YCA Q, =7,5 (accept 7 to 8)
Q, 13,5 YCA Q, =13,5 (accept 13 to 14)
IQR = 13,5-7,5
=é ¥CA answer (accept 6 to 7) (3)
[15]
QUESTION 4
4.1 | Amplitude of f =1 vA 1
da)
4.2 | Period of g =360° YA 360°
Q)
43 | b=2 VA b=2
q=l VA q=1
p=30° VA p=30°
GB)
44.1 | xe [oe ; 60°] OR 0°<x <60° v A critical values/endpoints
V :
If xe (0°; 60°) OR 0°<x <60°: 1 mark shnofation 6
4.4.2 | f(x)-sin30°= g(x)+1
1
ae a i vA sin30°= 3 OR 0,5
F(x) = g(x) +15 vA manipulation
*x=90° Also accept: x =34,4° or x=166,4° || vA answer
GB)

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Grade 11 CAPS — Marking Guidelines

September 2025 Test

45 | h(x)=sin(—x)
=Ssinx
~=cos(90°+x) YA cos(90°+x)
=cos(x+30°+60°) rs
1k =60° Answer only: — VA k=60°
p : 2
! Q)
[12]
QUESTION 5
5.1
Construction: Draw perpen YA construction
In AABD: sing =" vA ana
c
VA h=csinB
VA h=bsinC
FA csinB _ bsinC
be be
(5)

OR

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### Page 16

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Grade 11 CAPS — Marking Guidelines

September 2025 Test

A(ccosB ; csinB)

csinB

——

ry

B D Cc %

Construction: Draw perpendicular height AD.
In AABC: h=csinB

In AADC: sinC=4

csinB _ bsinC

be be

sinB_ sinC

—= ahimorephysics.com
b e

YA construction
YA y, orh=csinB

YA sinc at
b
YA h=bsinC
vA equating and + by be
(5)

52

sin(O—a)
_ _xsina
sin(@-a)

In AAMB: sind
AM

-. AB= AMxsin@
_ xsina.sinO
sin(@-a)

VA CAM=60-a@

¥ A correct subst. into sine
rule

TOTAL MARK: 75

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