# Physical Sciences Grade 10 Paper 1 KZN June 2024 Memo

> Grade 10 Physical Sciences Paper 1 memorandum from the KZN June Exam 2024, 16 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/kzn-physical-science-grade-10-june-2024-p1-and-memo/ec3c91cd-64e7-4ea4-8f1b-f60fa21baca1
- Updated: 2026-09-27
- Subject: Physical Sciences
- Grade: Grade 10
- Document type: Memorandum
- Year: 2024
- Exam period: KZN June Exam
- Paper: 1
- Curriculum: CAPS
- Pages: 16

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## About this document

Physical Sciences · Grade 10 · KZN June Exam · 2024. Memorandum, 16 pages. Read online or download the PDF.

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## Document text

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                            NATIONAL
                       SENIOR CERTIFICATE

                           GRADE 10

                      PHYSICAL SCIENCES P1

                         COMMON TEST

                           JUNE 2024

MARKS: 75

DURATION: 1,5 hours

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                            NATIONAL
                       SENIOR CERTIFICATE

                           GRADE 10

                      PHYSICAL SCIENCES P1
                         COMMON TEST

                       MARKING GUIDELINE

                           JUNE 2024

MARKS: 75

DURATION: 1,5 hours

Copyright reserved

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                                    NSC –Grade 10                     June 2024 Common Test
                                     2

QUESTION 1:

1.1       D ✓✓                                                                                (2)
1.2       B ✓✓                                                                                (2)
1.3       C ✓✓                                                                                (2)
1.4       B ✓✓                                                                                (2)
1.5       B ✓✓                                                                                (2)
                                                                                              [10]

QUESTION 2

2.1       A wave in which the particles of the medium vibrate at right angles ✓ to the
          direction of the motion of the wave. ✓                                              (2)

2.2
          2.2.1       Wavelength ✓                                                            (1)

          2.2.2       Amplitude ✓                                                             (1)

2.3
          2.3.1       v=f ×λ ✓
                      10 = 20 x λ ✓
                      λ = 0,5 m ✓                                                             (3)

         2.3.2       POSITIVE MARKING FROM QUESTION 2.3.1
                     OPTION 1                  OPTION 2
                              1                Distance = 3 ✓ x 0,5✓
                         T=         ✓
                              f                          = 1,5 m
                             1                          distance
                          =         ✓           speed =           ✓
                             20                            time
                                                          1,5
                                                   10 =           ✓
                        = 0,05 s                         time
                     time = 3✓ x 0,05✓         time = 0,15 s ✓
                          = 0,15 s ✓

                     OPTION 3
                               distance
                      speed =             ✓
                                 time
                           0,05
                     10 =                 ✓
                           time
                     time for 1 wave = 0,05 s
                     time = 3✓ x 0,05✓
                          = 0,15 s ✓                                                          (5)

                                                                                              [12]

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                                    NSC –Grade 10                    June 2024 Common Test
                                     3

QUESTION 3

3.1
          3.1.1      What is the relationship between frequency and wavelength of            (2)
                     sound waves (in air)? ✓✓

          3.1.2      Frequency is inversely proportional to wavelength ✓
                                                     OR
                     Inverse proportion ✓                                                    (1)

          3.1.3      The speed of sound in air depends on temperature ✓                      (1)

          3.1.4      v=f ×λ ✓
                      = 10 000 x 0,034 ✓       OR = 5000 x 0,068 ✓
                      = 340 m.s-1 ✓                                                          (3)

          3.1.5      POSITIVE MARKING FROM QUESTION 3.1.4
                     v=f ×λ
                     340 = 1000 (X) ✓
                      X = 0,34 m ✓                                                           (2)

3.2
          3.2.1              distance
                     speed =
                                time
                             distance
                     340 ✓ =
                              0,074 ✓
                     Distance = 25,16 m ✓
                                                                                             (3)

          3.2.2      POSITIVE MARKING FROM QUESTION 3.2.1
                     Distance = 100 – 25,16 ✓
                               = 74,84 m
                              distance
                     speed =
                                 time
                              74,84✓
                     340 ✓ =
                                time
                     time = 0,22 s ✓                                                         (4)

                                                                                             [16]

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                                    NSC –Grade 10                          June 2024 Common Test
                                     4

QUESTION 4

4.1
          4.1.1            Radio waves ✓                                                           (1)

          4.1.2            Ultraviolet ✓                                                           (1)

4.2       Gamma rays have the highest energy. ✓
          This allows it to easily penetrate through medical equipment ✓ and kill viruses
          and bacteria ✓.                                                                          (3)

          OPTION 1                                            OPTION 2
4.3          hc                                               E=hxf ✓
          E=       ✓
              λ                                               6,79 x10-23 = 6,63 x10-34 x f ✓
                                           -34            8
                     -23        6,63×10      × 3×10 ✓
          6,79×10          ✓=                                 f = 1,024 x1011 Hz
                                             λ
          λ = 2,93 x 10-3 m ✓                                 c=fxλ
                                                              3 x 108 = 1,024 x1011 x λ ✓
                                                              λ = 2,93 x 10-3 m ✓                  (4)

                                                                                                   [9]

QUESTION 5

5.1       All charges in the universe consist of an integer multiple ✓ of the charge of            (2)
          one electron ✓

5.2       Q = n x qe ✓
             = 1,25×1013 x -1,6×10-19 ✓
             = - 2 x 10-6 C ✓                                                                      (3)

5.3       POSITIVE MARKING FROM QUESTION 5.2
                        ∆𝑄
          5.3.1   𝑛 =                        ✓
                        𝑞𝑒
                    -2 ×10-6 - (- 8 × 10-6 ) ✓
                  =                -19
                         1,6 × 10            ✓
                           = 3,75 x 1013 e- ✓                                                      (4)

                                Q1 + Q2
          5.3.2            Q=                    ✓
                                   2
                                                     -6
                                        - 8×10 + QB ✓
                           - 2×10-6 ✓ =
                                              2
                           QB = 4 x 10-6 C ✓                                                       (4)
                                                                                                   [13]

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                                    NSC –Grade 10                 June 2024 Common Test
                                     5

QUESTION 6

6.1       The rate of flow of charge. ✓✓                                                  (2)

6.2       V = IR ✓
            =2x4✓
            =8V✓                                                                          (3)

6.3       POSITIVE MARKING FROM QUESTION 6.2

          6.3.1      V8Ω = IR                                  I8Ω = ½ I4Ω
                                              OR
                     8 = I8Ω x 8 ✓                                 = 0,5(2) ✓
                                            I8Ω = 1A
                                              IT = 1A + 2A ✓
                                                 = 3A
                                 OPTION 1                      OPTION 2
                     VBulb = 14 – 8 ✓            VT = IR
                     = 6V                        14 = 3 x RT ✓
                     VBulb = IR                  RT = 4,67 Ω
                     6 = 3 x RBulb ✓              1     1   1
                                                    =     +
                     RBulb = 2Ω ✓                RP R 1 R2
                                                  1    1 1
                                                    = +
                                                 RP 4 8
                                                 RP = 2,67 Ω
                                                 RBulb = 4,67 – 2,67Ω ✓
                                                       =2Ω✓                               (5)

          6.3.2      RT = 2 + 4 + 8 ✓
                         = 14 Ω
                     VT = IR
                     14 = IT x 14✓
                     IT = 1A
                     Q = I ∆t ✓
                        = 1 x 180 ✓
                        = 180 C ✓                                                         (5)

                                                                                          [15]

                                                                                   TOTAL: 75

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