# Physical Sciences Grade 12 KZN March 2023 Paper & Memo

> Grade 12 Physical Sciences question paper and memo from the KZN March 2023, 23 pages. Read online or get the free PDF download.

- Page: https://www.hlayiso.com/library/kzn-physical-sciences-grade-12-march-2023-qp-and-memo/5108eb70-783f-4cd6-aa50-16f453fb99f5
- Updated: 2026-09-27
- Subject: Physical Sciences
- Grade: Grade 12
- Document type: Question paper and memo
- Year: 2023
- Exam period: KZN March
- Curriculum: CAPS
- Pages: 23

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## About this document

Physical Sciences · Grade 12 · KZN March · 2023. Question paper and memorandum, 23 pages. Read online or download the PDF.

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## Document text

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### Page 1

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Ae

Seeeseseeest

P
cy
.
"
cy
cy
1”
1"
a"
ry
1.
1.
cy
is
»

100

TIME : 24Hours

This question paper consists of 10 pages and 3 data sheets.

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Physi March 2023 Common Test

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INSTRUCTIONS AND INFORMATION
a Write your NAME in the appropriate spaces on the ANSWER BOOK.

Zs This question paper consists of SEVEN questions. Answer ALL the questions
in the AREER BOOK.

3. Start EACH question on a NEW page in the ANSWER BOOK.

4. Number the answers correctly according to the numbering system used in this
question paper.

5. Leave ONE line between two subquestions, for example between
QUESTION 2.1 and QUESTION 2.2.

6. You may use a non-programmable calculator.

a, You may use appropriate mathematical instruments.

8. Show ALL formulae and substitutions in ALL calculations.

9. Round off your final numerical answers to a minimum of TWO decimal places.

10. Give brief motivations, discussions et cetera where required.

1. You are advised to use the attached DATA SHEETS.

12. Write neatly and legibly.

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QUESTION 1: MULTIPLE-CHOICE QUESTIONS

Various options are provided as possible answers to the following questions.
Choose the answer and write only the letter (A-D) next to the question number (1.1-1.10)
in the ANSWER BOOK, for example 1.11 D.

1.1 A bodys les along a frictionless horizontal surface at CONSTANT VELOCITY.
For which ONE of the following pairs are the magnitudes of both physical
quantities ZERO?

A __ Displacement and momentum.
Acceleration and momentum.

Displacement and net force.

Acceleration and net force. (2)

1.2 A satellite orbits the Earth at a point X, where the gravitational force is a
quarter (% ) of the gravitational force it experiences on the surface of the Earth.

X

©) _ satellite

Earth

If the radius of the Earth is R, then the height of the satellite ABOVE THE
SURFACE of the Earth will be...

A 4R
2R
R

%R (2)

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: , . ‘ch 2023 Common Test
Physical Besiftoaded from Stanmorespysics.com

1.3

1.4

1.5

1.6

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A girl standing in a lift observes a 10N mass piece suspended from a spring
balance that is fixed to the roof of the lift. She sees that the reading on the
spring balance is GREATER than 10N for a short time interval. During this time
interval the lift is....

Ln
Bm at constant velocity.

C accelerating upwards.

D accelerating downwards. (2)

A ball of mass m hits a wall at a speed of v and rebounds in a straight line
in the opposite direction with the same speed.

The magnitude of the change in momentum of the ball will be...

A Oo

B 2mv

Cc ‘’mv

D mv (2)

A ball is thrown vertically upwards. Which ONE of the following physical
quantities has a NON-ZERO value at the instant the ball changes direction?

A __ Acceleration
B__ Kinetic energy
C Momentum

D Velocity (2)

The molecular formula of an organic compound is C4H100. Which ONE of the
following is the FUNCTIONAL GROUP of the organic compound?

A __ Formyl group
Hydroxyl group

Carboxyl group

0 9O BB

Carbonyl group (2)

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17. A FUNCTIONAL ISOMER of ethyl propanoate is .. .

A

1.8 Which ONE of the following is the EMPIRICAL FORMULA of

C4HgCHO.

‘GH3(CH2)3CHO.

2 — methylpentane?

March 2023 Common Test

(2)

(2)

A CsH7

Bo CeHta

CC CeHi2

D- CsHe

1.9 Which ONE of the following represents a product of the thermal cracking of

butane?

A C2H2

B  C2Ha

C CaHe

D = C4Hi0

1.10 Consider the structural formula of an organic compound given below:

H H fe} H
| | i} |
H =|" = Cm C=} 0 +
I | !
H H H

This compound is the product of the reaction between . . .

A

ethanol and propanoic acid.
propanol and propanic acid.
ethanol and ethanoic acid.

propanol and ethanoic acid.

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H
|
Cc
I
H

)

kb

(2)
[20]

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QUESTION 2 (Start on a new page.)

A force of magnitude F is applied at an angle @ with the horizontal to a box of

mass 60 kg placed on the floor. With force F applied, the magnitude of the maximum
static frictional force between the floor and the box is 140 N . The coefficient of static
friction between ttiebox and the floor is 0,3.

The applied force-daes not cause the box to lift off the floor.

2.1
2.2
2.3

2.4

ae
------ 2) 60kg

Define normal force.
Draw the free body diagram showing all forces acting on the box.

Calculate the magnitude of the normal force when the static frictional force
is at its maximum.

Determine the angle 6

QUESTION 3 (Start on a new page.)

A ball of mass 0,5 kg is projected vertically downwards from a height of 1,8 m with an
initial velocity of 2 m.s*'. The ball hits the ground and bounces two times.

The position — time graph for the motion of the ball from the instant it is projected until
it hits the ground after the second bounce is shown below. Ignore the effects of friction.

Position (m)

3.1

3.2

Sopyright reserved

Write down the maximum vertical height reached by the ball after the SECOND
bounce? =

The ball strikes the ground with a speed of 6,27 m.s* and is in; eantact with the
ground for 0,2 s during the first bounce. i

3.2.1 Calculate the time t1 as indicated on the graph.

3.2.2 Determine the velocity with which the ball leaves the ground after the first
bounce.

3.2.3 Calculate the magnitude of the force exerted by the ground on the ball
during the first bounce.

March 2023 Common Test

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3.3 Draw a velocity — time graph for the motion of the ball from the time that it is
projected to the time it rebounds to a height of 0.9 m.

Clearly show the following on your graph:

° Theé+time when the ball hits the ground

° The;velocity of the ball when it hits the ground

° The ivelocity of the ball when it rebounds off the ground.

QUESTION 4 (Start on a new page.)

Two balls, A and B, of mass 250 g and 300 g respectively collide head-on. Before the
collision, ball A was moving at a velocity of 4 m.s“ to the right and ball B at 6 m.s* to
the left. After the collision ball A moved to the left with a velocity of 2 m.s7'.

Before collision

4m.s1
6 m.s*

—> ee

A G9) :

4.1 Explain what is meant by an isolated system in Physics.
4.2 Calculate the velocity of ball B immediately after the collision.

4.3. Is the collision between the ball A and ball B ELASTIC OR INELASTIC? Show
how you arrived at the answer by means of a calculation.

(3)
[16]

(2)
(4)

(5)
[11]

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QUESTION 5 (Start on a new page.)
Consider the letters A to E in the table below:

A
H
|
H — C —H
ie |
i inet ai Sate Wipe
|
H H | H H
H — C —H
|
H
C4H100
CHsCCCH2CH3
but - 2- ene
E
H H fe}
| | ll
H —C —cC —C —OW—H
|
HW
H — C — H
|
H
e H H H H H H
| | | | | |
Rta Srdlmaiiuiieee Lalas s
H H H H H I

Use the information in the table to answer the questions that follow.

J

5.1. Write down the: iz

==]

5.1.1 IUPAC name of compound A. rata (3)

5.1.2 _ Letter that represents a compound that belongs to the same homologous
series as ethyne.

(1)

5.1.3 NAME of the functional group of compound E. (1)
5.1.4 General formula of the homologous series to which compound A belongs. (1)
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5.2

5.3

5.4

5.5

Compound B represents a TERTIARY alcohol. Write down the structural
formula of compound B.

Compound D has CHAIN and POSITIONAL isomers.
positional isomer

@ down the IUPAC NAME of the POSITIONAL isomer of compound D
5.3.3 Write. down the structural formula of a CHAIN isomer of compound D
ls compound C saturated or unsaturated? Give a reason for the answer

Compound F undergoes complete combustion. Write a balanced equation using
MOLECULAR FORMULAE to represent the reaction that takes place.

QUESTION 6 (Start on a new page.)

The table below shows the results obtained during a practical investigation. Two
experiments were conducted to determine the BOILING POINTS of compounds under
the same conditions.

Experiment Compound Molecular Mass (g.mol) | Boiling Point
(°C)
1 A_- | CH3COOH 60,5 11,8
B__| CHs(CHz)20OOH 88,1 163
2 C_ | CHsCH2CH2OH 60,1 97
D | CHs(CH2)3CH20H 88,1 137
6.1 Define boiling point.
6.2 Apart from the conditions for determining boiling points, state the controlled
variable for experiment 1.
6.3 Write down the general conclusion for this investigation.
6.4. Which compound will have the highest vapour pressure?
6.5 The boiling points of compounds B and D are compared.

Copyright reserved

6.5.1 Write down the independent variable for this comparison.
6.5.2 Fully explain the difference in the boiling points of the twé'eompounds.

March 2023 Common Test

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(2)

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QUESTION 7 (Start on a new page.)

In the flow diagram below I, Il and Ill represent organic reactions. P and Q are different

organic compounds. Q is the major organic product.

7.1 Name the TYPE of substitution reaction represented by reaction I.
7.2 Write down the STRUCTURAL formula for compound Q.
7.3 Name the inorganic reagent used in reaction III
7.4 Write down the type of reaction represented by reaction Ill
7.5 The same INORGANIC reagent is used in reactions I and II.

Write down

7.5.1. The NAME or FORMULA of the inorganic reagent used.

7.5.2 ONE difference between the inorganic reagent used in reactions | and Il.
7.6 Write down the IUPAC name of:

7.6.1 Compound P

7.6.2 The organic product of reaction III

TOTAL MARKS:
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COMPOUND Q + KBr + H20

CHsCH2CHOHCH3

March 2023 Common Test

(1)
(2)
(1)
(1)

(1)
(2)

(2)

(2)
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[100]

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DATA FOR PHYSICAL SCIENCES (PHYSICS) GRADE 12

GEGEWENS VIR FISIESE WETENSKAPPE (FISIKA) GRAAD 12
TABLE 1: PHYSICAL CONSTANTS/TABEL 1: FISIESE KONSTANTES

March 2023 Common Test

NAME/NAAM SYMBOL/SIMBOOL VALUE/WAARDE
Acceleration dué-to gravity 5
ekragver Mulling 9g 9,8 m-s
Universal gravitational constant G 6,67 x 101 N.m2.kg?
MOTIONIBEWEGING
VA =Vitadt Ax =viAt+ daat? orfof Ay =vAt+Jadt?

vi" = Vi? +2aAx orlof v,? =v? +2ady | Ax= (424) At orlofAy = (“ea

K=E, =p mv?

FORCE/KRAG
Fret = Ma : p=mv
FieAt =Ap=mv, —my, Fy =mg
F= SOR;
r
f°" =y,N f, = HN

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March 2023 Common Test

DATA FOR PHYSICAL SCIENCES GRADE 12

CHEMISTRY
TABLE 1: PHYSICAL CONSTANTS:
NAME/NAAM paal SYMBOL/SIMBOOL VALUE/WAARDE
Standard pressure) > ° 5
Standaarddruk Fi P 1,013 x10"
Molar gas volume-at STP act
Molére gasvolume by STD Vm 22.4 anit
Standard temperature
Standaardtemperatuur 7 273K
Charge on electron 19
Lading op electron E “1,6 x10C
Avogadro's constant 23 malt
Avogadro-konstante Na 6,02 x 10*° mol
TABLE 2: FORMULAE
m N
n=— n=—
M Na
n m eave
ty] or/of cmay ON
Ce a ne = +)
CV, M PH = -log[H30*]
Kw = [H30*][OH7] = 1 x 10-4 at/by 298 K

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13

NSC

TABLE 3: THE PERIODIC TABLE OF ELEMENTS

March 2023 Common Test

1 2 3 4 5 6 7 8 9 10 «11 12 13 14 #15 16 #4917 + «618
(I) (Il) (y= (IV) (VY) (VI) (VN) s(VII)
Atomic number
1 KEY 2
= H | He
: 29 4
3 4 Electronegativity | ., Symbol 5 6 7 8 9 10
2 Li |% Be cao d ie eBIcSNISO Ne
7 9 : 11 12| 14| 16] 19/| 20
1 12 13| 14| 15| 16! «+17/ «418
& Na|= Mg Approximate relative atomic mass “Ae\? SiG P13 S |¢Ce!| Ar
23 24 27 | 28| 31/ 32/| 35,5| 40
19 20 21 22| 23] 24] 25| 26] 27| 28) 29| 30| 31| 32] 33] 34/] 35/ 36
@ K |2 Cal? Sc |Z Ti |? © Cr |2Mn|2 Fe |% Co|2 Ni |2 Cu |2 Zn |2 Ga|2 Ge |S As |S Se |§ Br| Kr
39 40 45 | 48 | 54 52| 55| 56| 59/| 59| 635] 65| 7o| 73| 75| 79| 80| 84
37 38 39 | 401 411 421 #43/| #44/ «45| #46| 47! #48| 49] So; 51] 52/ 53] 54
2 Rb? Sr i|% Y [Zr] Nb|2Mo/2? Te |S Ru|& Rh|s Pd |2 Ag |= Cd|= In |2 Sn |2 Sb|& Te |G | | Xe
86 88 s9 | 91| 92] 96 101| 103} 106| 108] 112| 115| 119| 122| 128| 127| 131
55 56 57 |. 72| 73| 741 +#»75| +#»+76| +#+77| ~«78;| «+79| 8o| 81| 82| 83] 84] 85| 86
Cs |2 Bal La|? Hf} Ta} W/ Re| Os| Ir| Pt} Au| Hg/2 Te |2 Pb|2 Bi |S Po|& At) Rn
133| 137| 139] 179] 181| 184| 186| 190| 192| 195| 197| 201| 204| 207| 209
87 88 89
n o
o Fr |e sa Ac 58] 59 | 60 | 61 | 62 | 63 | 64 | 65 | 66 | 67 | 68 | 69 | 70 | 71
Ce | Pr | Nd | Pm| Sm} Eu | Gd J_Tb | Dy | Ho | Er | Tm| Yb | Lu
140 | 141 | 144 150 | 152 | 15717159 | 163 | 165 | 167 | 169 | 173 | 175
90 | 91 | 92 | 93 | 94 | 95 | 9641 97 | 98 | 99 | 100 | 101 | 102 | 103
Th | Pa | U | Np | Pu | Am| Cm] Bk | Cf | Es | Fm | Md | No} Lr
232 238

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education

Department:
Education
PROVINCE OF KWAZULU-NATAL

NATIONAL
SENIOR CERTIFICATE

This Marking Guideline consists of 10 pages.

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NSC - MARKING GUIDELINE

QUESTION 1: MULTIPLE-CHOICE QUESTIONS

1.1 Dvv
1.2 Cv.
1.3 Cv

1.4 BYv
15 AvY
1.6 BYv
1.7 Cyvv
1.8 AVY
1.9 BYv
1.10 AVY

[20]

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NSC - MARKING GUIDELINE

QUESTION 2 (Start on a new page.)

2.1 Normal force is the force or component of a force which a surface exerts on an
object with which it is in contact, and which is perpendicular to the surface.v ¥ (2)

ter

OO]

2.2

fv

WY

Accept the following symbols
N Normal Force/Normal/Fn

f Static friction/ fs

Ww Weight/Fw /Gravitational force/fg
F Force applied/Fa

Notes
e Mark is awarded for label and arrow.

e Do not penalize for length of the arrows.
e Deduct 1 mark or any additional force.
e If force(s) do not make contact with body/dot:Max:3/4
e lf arrows missing but labels are there: Max: 3/4 (4)
230° f™=uNV
140 =0,3N ¥
N = 466,67N ¥
(3)
2.4 POSITIVE MARKING FROM 2.3
F, =f," =140NV
N=F,-F,
466,67 =(60)(9,8)—F, ¥
F, =121,33N
tand=—=
tang — 12433 V
0=40.91V¥
(4)
[13]

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NSC - MARKING GUIDELINE

QUESTION 3 (Start on a new page.)

3.1
3.2.1

0,5 mv

oprah) OPSIE 1
Upwards positive
=

Ht
vy, = v,tadtv

~6,27v = -2 + (-9,8)Atv
At = 044sv

Downwards positive

V, = v, tadtv

6,27V =2 + (9,8)Atv
At=0,44sv

OPTION 2/OPSIE 2
Upwards positive

Ay = vAt+ % aAt’ v
-1,8 V= (-2)At+ % (-9,8)At V

At =_DENb* =4ac
2a
we2tvey -4(4.9)(-1.8)
2(4.9)
=0,44sv

Downwards positive
Ay =vAt+ % alt v

1,8 V= (2)At+ % (9,8)At ¥

aa=2et Vb’ —4ac
2a
aewt (-2)’ -4(4.9)(-1.8)
2(4.9)
=0,44sv

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March 2023 Common Test

(1)

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3.2.2

3.2.3

NSC - MARKING GUIDELINE

OPTION 3
ay - VAM) ary
2

Lev (2+6,27))
, 2

At = sv

fe positive:

ve = vy, + 2aly VY
O° =v, + 2(-9,8)(0,9)¥
V,= 4.2 m:s” upwards ¥

Atv

Downwards positive:
ve = v, + 2ahy Vv

2 2
0 =v, + 2(9,8)(0,9) ¥
V,= 4.2 m:s” ¥ upwards¥

Upwards positive:

March 2023 Common Test

F. At = mAv
E (0:2) = (0,5)[(4,2 ~ (-6,27

Y for either equation

F,9:= 26,175 N

Fret = F-Fg

26,1755 = F - (0,5)(9,8) ¥
F = 31,075 NV

Downwards positive:

F_ At = mAv ¥
F et (0.2) = (0 5) (azo 6 27) “——

F set = -26,175 N Y for either equation
F 9 = 26,175 N a
Fret Fg -

- 26,1755 = (0,5)(9,8) - FY
F = 31,075 NY

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NSC - MARKING GUIDELINE

3.5 Upwards positive:

t(s)

-6,.27

Downwards positive:

t(s)

Criteria for graph Marks
2 straight discontinuous parallel lines, one above and one below v
the time axis

First part of the graph starts at v = 2 ms at t=0s and extends

4 v
until v=6,27 m:s_att=0,44s.
Second part of graph starts at v = 4,2 ms att = 0,64 s until y,
v=Oms..
(3)
[16]

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NSC - MARKING GUIDELINE

QUESTION 4 (Start on a new page.)

4.1

4.2

4.3

A system on which the net external force is zero.v¥ ¥

Right a: itive:
rp=2

Any
ApA = onev

MY, +MgV;, = MV, + MpVy,
(0, 25)(4) + (0, 3)(—6) = (0, 25)(—2) + (0, 3)(v he \¥v
v,, =—1m.s*

v,, =1m.s* to the left

Left as Positive:

2p,= Zp,
ApA = - ApB

M,V,, +M,V,, =M,V;,, +MzV/,

Any
onev

(0, 25)(—4) + (0, 3)(6) = (0, 25)(2) +(0,3)(v, )¥¥
v,, =1m.s*
v,, =1m.s* to the leftY

1
v, > +—m,v,° 4%
in 15 MBVin

(0,25)(4)° + ; (0,3)(-6)° ¥

1
ZEk iwefore) ama

Nle

1
CE atten = 2 a

#ZE

ZEk (before)

Kaen)”
-. INELASTICY

NOTE: If starts with 2Ek gooe= ZEk cate) maximum

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March 2023 Common Test

2/5

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NSC - MARKING GUIDELINE

QUESTION 5

5.1.1

5.1.2
5.1.3
5.1.4
5.2

5.3.1

5.3.2

4,5 — dimethylv hex — 2 —- Venev

Marking criteria:

Cv
carboxyl v
CnHan ¥
H
|
H Oo H
| | |
H—C—C—C—H
| |
H | H
H—C —H
|
H

Marking criteria:
¢ Correct functional group: %

e Whole structure correct: x

Organic molecules with the same molecular formula but different positions of
the side chains/substituents/functional groups on the parent chain vv

but - 1- ene v

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March 2023 Common Test

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NSC - MARKING GUIDELINE

5.3.3
i - ia
=cC—_—H Marking criteria:
e 3 carbons in parent chain with the
double bondY
—H e Methyl group as a substituent
5.4 Unsaturatedv
There multiple bonds between C atoms in the hydrocarbon chain/triple bond
between C atoms in the hydrocarbon chain. v
5.5 2CeHia + 1902 — 12COz2 + 14H20
Reactants ¥ Productsv Balancing Vv
QUESTION 6
6.1 The temperature at which the vapour pressure equals atmospheric (external)
pressure. vv (2 or 0)
6.2 Compounds have the same functional group/belong to the same homologous
seriesY
6.3 As the length of the carbon chain/molecular mass increases the boiling point
increases for the same functional group/homologous seriesv Vv
6.4 AY
6.5.1 Type of functional group/organic compound/homologous series. ¥
6.5.2

e Bhas 2 sites for hydrogen bondingY and
e therefore has stronger intermolecular forcesY
That require more energy to overcome. v
OR
D has only 1 site for hydrogen bondingY and
therefore has weaker intermolecular forcesY
That require less energy to overcome.

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March 2023 Common Test

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Test
NSC - MARKING GUIDELINE
QUESTION 7
71 hydrolysisY
H H H H
| | | |
H— C — C = €C — C —H
| |
H H
Double bond between the second and third
carbon atomsv
Whole structure correct’
7.3 Water(H20)/sulphuric acidH2SO«/phosphoric acidHsPO4/
hydrogen chloride(HCl) v
74 Addition/hydration V
7.5.1 Potassium hydroxide/KOH ¥
7.5.2. KOH in reaction | is dilute. ¥
KOH in reaction Il is concentrated. v
7.6.1 2-bromov butanev
7.6.2 ButanY -2-olv

TOTAL MARKS:

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March 2023 Common

(1)

(2)

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(2)

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