# Life Sciences Grade 12 Paper 2 GP Prelim 2023 Memo (English)

> Grade 12 Life Sciences Paper 2 memorandum from the GP Prelim 2023 (English), 14 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/life-sciences-p2-english-memo/e3c2f95a-3d14-499a-b6c2-508945930b0d
- Updated: 2026-09-27
- Subject: Life Sciences
- Grade: Grade 12
- Language: English
- Document type: Memorandum
- Year: 2023
- Exam period: GP Prelim
- Paper: 2
- Curriculum: CAPS
- Pages: 14

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## About this document

Life Sciences · Grade 12 · GP Prelim · 2023 · English. Memorandum, 14 pages. Read online or download the PDF.

Read it free online on the page above; download the PDF from there.

## Matching paper and memo

- [Life Sciences P2 (English) QP](https://www.hlayiso.com/library/life-sciences-p2-english-qp/bb04c5c6-158b-47c6-b2ca-a195e96e93ef) — QP · 2023 · Eng

## Document text

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          PREPARATORY EXAMINATION
                                      2023
                  MARKING GUIDELINES

                    LIFE SCIENCES (PAPER 2) (10832)

 14 pages

Please note, the paper is out of 148 not 150. Change the raw mark total on SASAMS from
150 to 148.

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     PRINCIPLES RELATED TO MARKING LIFE SCIENCES

1.   If more information than marks allocated is given
     Stop marking when maximum marks are reached and put a wavy line and 'max' in
     the right-hand margin.

2.   If, for example, three reasons are required, and five are given
     Mark the first three irrespective of whether all or some are correct/incorrect.

3.   If the whole process is given when only part of it is required
     Read all and credit relevant parts.

4.   If comparisons are asked for, and descriptions are given
     Accept if differences/similarities are clear.

5.   If tabulation is required, but paragraphs are given
     Candidates will lose marks for not tabulating.

6.   If diagrams are given with annotations when descriptions are required
     Candidates will lose marks.

7.   If flow charts are given instead of descriptions
     Candidates will lose marks.

8.   If the sequence is muddled and links do not make sense
      Where sequence and links are correct, credit. Where sequence and links are
      incorrect, do not credit. If the sequence and links become correct again, resume
      credit.

9.   Non-recognised abbreviations
     Accept if first defined in the answer. If not defined, do not credit the unrecognised
     abbreviation but credit the rest of the answer if correct.

10. Wrong numbering
    If the answer fits into the correct sequence of questions but the wrong number is
    given, it is acceptable.

11. If the language used changes the intended meaning
    Do not accept.

12. Spelling errors
    If recognisable, accept it provided it does not mean something else in Life
    Sciences or if it is out of context.

13. If common names are given in terminology.
    Accept, provided it was accepted at the memo discussion meeting.

                                                 2

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14.   If only the letter is asked for and only a name is given (and vice versa)
      Do not credit.

15.   If units are not given in measurements
      Candidates will lose marks. Memorandum will allocate marks for units separately.

16.   Be sensitive to the sense of an answer, which may be stated differently.

17.   Caption
      All illustrations (diagrams, graphs, tables, etc.) must have a caption.

18.   Code-switching of official languages (terms and concepts)
      A word or two that appears in any official language other than the learners'
      assessment language used to the greatest extent in his/her answers should be
      credited if it is correct. This applies to all official languages. A marker that is
      proficient in the relevant official language should be consulted.

19.   Changes to marking guidelines
      No changes must be made to the marking guidelines without consulting the
      Provincial Internal Moderator.

                                                 3

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SECTION A

QUESTION 1

1.1 1.1.1    C 

    1.1.2    C 

    1.1.3    C 

    1.1.4    D 

    1.1.5    A 

    1.1.6    D 

    1.1.7    B 

    1.1.8    B 

    1.1.9    D 

    1.1.10   B                                   (10 x 2)   (20)

1.2 1.2.1    Haploid ✓

    1.2.2    Stem cells ✓/Meristematic

    1.2.3    Prognathism ✓/prognathous

    1.2.4    Genetically modified ✓ organism

    1.2.5    Incomplete dominance ✓

    1.2.6    Chimpanzee ✓

    1.2.7    Colour-blindness ✓

    1.2.8    Genome ✓                              (8 x 1)     (8)

1.3 1.3.1    Only A ✓✓                                         (2)

    1.3.2    Only B ✓✓                                         (2)

    1.3.3    Only B ✓✓                                        (2)
                                                              (6)

                                               4

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1.4 1.4.1     (a)   D ✓ foramen magnum ✓                                  (2)
              (b)   C ✓ pelvis ✓/pelvic girdle                            (2)

      1.4.2   (a)   C – shaped ✓                                          (1)
              (b)   S – shaped ✓                                          (1)

      1.4.3   (a)   Quadrupedal ✓/quadrupedalism                          (1)
              (b)   Bipedal✓/bipedalism                                   (1)
                                                                          (8)

1.5   1.5.1   Dihybrid ✓cross                                             (1)

      1.5.2   (a)   aall ✓✓/llaa                                          (2)
              (b)   AL, Al, aL, al ✓✓/LA, lA, La, la                      (2)

      1.5.3   Complete dominance ✓                                        (1)

      1.5.4   25 ✓✓%                                                      (2)
                                                                          (8)

                                                       TOTAL SECTION A:   50

                                                  5

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SECTION B

QUESTION 2

2.1 2.1.1   (a) adenine ✓/A                                                                 (1)
            (b) deoxyribose ✓sugar                                                          (1)
            (c) phosphate ✓                                                                 (1)

    2.1.2   Strand X ✓/X                                                                    (1)

    2.1.3   Uracil is present ✓
            (Mark first ONE only)                                                           (1)

    2.1.4   -    The double helix DNA unwinds. ✓
            -    The double-stranded DNA unzips ✓/weak hydrogen bonds break to
                 form two separate strands.
            -    One strand is used as a template ✓
            -    to form mRNA ✓
            -    using free RNA nucleotides from the nucleoplasm. ✓
            -    The mRNA is complementary to the DNA. ✓
            -    mRNA now has the coded message for protein synthesis. ✓      Any           (5)

    2.1.5   DNA is too large to leave the nucleus ✓/fit through the nuclear pore, but
            the single stranded mRNA is small enough to leave the nucleus/fit through
            the nuclear pore
            to carry the coded message for protein synthesis from the DNA. ✓

            OR

            Transcription is important because it is the main point at which the cell
            regulates ✓
            which proteins are to be produced and at what rate. ✓

            OR

            Transcription makes the mRNA which will contain the code from the
            DNA ✓
            which the cell/ribosome will then read to produce new protein molecules✓
            /for the process of translation.
            (Mark first ONE only)                                                           (2)
                                                                                           (12)

                                                6

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2.2 2.2.1   -     A child inherits the DNA ✓
            -     from both their father and their mother. ✓                                  (2)

            OR

            -     All the DNA bands/black bands/bars of the child ✓
            -     will match the mother and the father. ✓

            OR

            -     A child’s DNA profile/black bands/bars must be compared ✓
            -     with both parents. ✓

            OR

            There is no other scientific test ✓✓ to determine paternity.

    2.2.2   (a)     Woman Y’s child✓/Child Y                                                  (1)

            (b)     -    Five of the DNA bands/black bands/bars of child Y ✓match the
                         black bands/bars of woman Y. ✓
                    -    All / four of the remaining the DNA bands/ black bands/bars of
                         child Y match Mr Megabucks. ✓/the remaining bands of Child Y
                         match Mr Megabucks.

                    OR

                    DNA bands/black bands/bars of the child Y ✓ match both the DNA
                    bands/black bands/bars of Woman Y ✓ and Mr Megabucks. ✓                   (3)

    2.2.3   Skin ✓/blood/saliva/cheek cells/hair follicles (with roots) /semen/ nails
            (If hair is given as an example, it MUST include the term FOLLICLE to get
            a mark.                                                                           (1)
                                                                                              (7)

2.3 2.3.1   Metaphase II ✓/2                                                                  (1)

    2.3.2   (a)     4 ✓/four                                                                  (1)
            (b)     2 ✓/two                                                                   (1)

    2.3.3   (a)     chromosome ✓                                                              (1)
            (b)     pulls chromatids/chromosomes to opposite poles ✓                          (1)

                                                  7

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2.3.4   -   During prophase I ✓
        -   homologous chromosomes lie next to each other ✓
        -   chromatids from each homologous chromosome/non-sister
            chromatids overlap ✓and touch each other
        -   at a point called the chiasma ✓(plural: chiasmata)
        -   Chromatid exchange genetic material ✓
                                                                       Any    (4)

2.3.5                 Diagram showing a cell in anaphase II

                                               Centriole/centrosome

                                               cytoplasm

                                               centromere

                                               chromatid/daughter
                                               chromosome /chromosome

                                               spindle fibre

                                               cell membrane

        Diagram rubric:                                               Mark
        C    Caption including Anaphase II/2                           1
        P    Diagram – Position of chromosomes:                        1
             One large and one small unreplicated Chromosomes
                /chromatids/daughter chromosomes pulled to
                opposite poles
             - Showing a clear gap between chromatids at the
                equator of the cell.
        S    Diagram – Shading:                                        1
             Correct shading of all chromatids/daughter
             chromosomes /Unreplicated chromosomes
        L    Any two correct labels                                    2
                                                                       5      (5)
                                                                             (14)

                                        8

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2.4 2.4.1   4 ✓/four                                                                        (1)

    2.4.2   3 ✓/three                                                                       (1)

    2.4.3   P1 Phenotype FH/hypercholesterolemia x without FH/ hypercholesterolemia 
               Genotype                 Tt         x             tt       ✓
                Meiosis
                Gametes                  T,    t         x        t,   t✓

                Fertilisation

            F1 Genotype                  Tt         Tt       tt        tt ✓

            F1 Phenotype 2 with FH/hypercholesterolemia: 2 Without FH/
            hypercholesterolemia  (accept simplified ratio)

            Probability: 50%*✓ of having a child without FH/hypercholesterolemia
            (*Compulsory mark)
            P1 and F1 ✓
            Meiosis and fertilisation ✓
                                                              *Compulsory 1 + Any 5

                                                     OR

            P1
            Phenotype FH/hypercholesterolemia x without FH/hypercholesterolemia 
            Genotype                       Tt        x           tt ✓
                                     Gamete           T            t
            Meiosis
                                         t            Tt           tt
                                         t            Tt           tt
            Fertilisation
                                    1 mark for correct gametes 
                                    1 mark for correct genotypes 

            F1 Genotype             Tt  Tt    tt      tt ✓
            F1 Phenotype 2 FH/ hypercholesterolemia: 2 without FH/
            hypercholesterolemia  (accept simplified ratio)
            Probability: 50% *✓ of having a child without FH/hypercholesterolemia
            (*Compulsory mark)
            P1 and F1 ✓
            Meiosis and fertilisation ✓
                                                              * Compulsory 1 + Any 5        (6)
                                                                                            (8)

                                                     9

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2.5 2.5.1   Number of lactose intolerant people in country B

                 12                     12
            =       ✓ x 190 ✓million OR           ✓ x 190 000 000 ✓
                100                     100

            = 22,8 million ✓   or 22 800 000 ✓                                         (3)

    2.5.2   E✓                                                                         (1)

    2.5.3   Smallest sample size ✓
            only tested 20 people ✓                                             Any
                                                                                       (1)

    2.5.4   -  Test on the same number of people/same sample percentage in each
               country ✓
            - Use the same lactose intolerance test on every person ✓
            - Test each person at the same time of the day ✓
            - All people should consume the same diet ✓
            - Same time frame for testing in each country ✓
            - Same amount of milk drunk each day ✓
            - Same source of milk used ✓
            (Mark first TWO only)                                                      (2)

    2.5.5   -  Decide on which people to select ✓/sample size for the investigation
            -  Ask permission from participants✓ / ethics committee/ hospitals
            -  Decide which countries consume milk to include ✓in the investigation
            -  Decide on a venue to conduct the tests ✓
            -  Decide on a testing method ✓
            -  Decide a method to record results ✓
            -  Decide on the type of diet all participants need to follow ✓
            -  Decide on which hospitals to consult, gather and use data which they
               can provide ✓
            (Mark first TWO only)
            (Do not accept controlled variables)                                       (2)
                                                                                       (9)
                                                                                      [50]

                                             10

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QUESTION 3

3.1   3.1.1    Cross/Mate/breed East Friesian ✓ sheep for bare backsides ✓ and
               Cheviot ✓ sheep for bare legs ✓

               Select offspring with both bare legs and backsides ✓/have the same
               characteristics as both parents.

               Continue this process for many generations✓/the process is repeated for
               many generations/offspring can be inbred                            Any          (5)

      3.1.2    Natural selection                        Selective breeding
               The environment or nature is the         Humans represent the selective
               selective force ✓                        force ✓
               Selection is in response to              Selection is in response to
               suitability to the environment ✓/        satisfying human needs ✓/
               Species benefit from organisms           Humans benefit from organisms
               that survive.                            produced
               Occurs within a species ✓                May involve one or more species ✓

               (Mark first TWO only)
                                                        1 mark for table (T ✓) + (Any 2 x 2)    (5)

      3.1.3.   -     Reduced genetic variation ✓/gene pool may increase susceptibility to
                     disease in the population ✓

               -     Reduced wool ✓ on head/legs/abdomen/backside means less wool for
                     farmers to sell ✓/less money for farmers

               -     Exposed skin ✓ on the head/legs/abdomen/backside of sheep is less
                     protected ✓ against damage/injuries/sunburn/insect bites

               -  Increase in genetic disorders due to inbreeding ✓so fewer sheep
                  survive ✓
               (Mark first ONE only)
               (Must be written as a cause-effect statement)                                    (2)
                                                                                               (12)
3.2 3.2.1      (a)    Lamarck ✓                                                                  (1)

               (b)    Acquired characteristics of the sword size cannot be inherited ✓
                      because they are not part of the genotype ✓/not in the genes/only
                      part of the phenotype/ sword size
                      OR
                      The constant use of the sword ✓of a swordfish will not make the
                      sword increase in size ✓
                      OR
                      The swordfish could not chose to grow its sword ✓as it got larger
                      due to environmental pressure ✓                                           (2)
                      Mark FIRST ONE only

                                                   11

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    3.2.2   In a large population of ancestral swordfish:

            -     There was variation in sword length ✓
            -     Some swordfish had a longer sword, and some swordfish had a
                  shorter sword ✓
            -     Due to competition for food ✓*/less prey/less food is available
            -     The swordfish with a longer sword was able to injure/capture prey ✓
            -     and survived ✓
            -     while the swordfish with a shorter sword injured/captured less prey ✓
            -     and many died ✓
            -     Swordfish with longer swords survived and reproduced ✓
            -     and passed the allele for a long sword to their offspring ✓
            -     The next generation will therefore have a higher proportion of
                  individuals with a long sword ✓
                                                            * Compulsory mark + Any 5     (6)
                                                                                          (9)

3.3 3.3.1   Genus names must have a CAPITAL LETTER, and all species names
            MUST be written in LOWERCASE.
            Surnames only of scientists will be accepted.

            (a)    Australopithecus afarensis ✓/A. afarensis                              (1)
            (b)    Lucy ✓                                                                 (1)
            (c)    Donald Johanson ✓                                                      (1)

                   OR

            (a)    Australopithecus prometheus ✓/A. prometheus / Australopithecus         (1)
                   africanus ✓/A. africanus
            (b)    Little Foot ✓                                                          (1)
            (c)    Ron Clarke ✓/Stephen Motsumi/Nkwane Molefe                             (1)

                   OR

            (a)    Australopithecus africanus ✓/A. africanus                              (1)
            (b)    Taung child ✓                                                          (1)
            (c)    Raymond Dart ✓                                                         (1)

                   OR

            (a)    Australopithecus africanus ✓/A. africanus                              (1)
            (b)    Mrs Ples ✓/ Mr Ples                                                    (1)
            (c)    Raymond Dart ✓/Robert Broom/Ron Clarke                                 (1)

                   OR

            (a)    Australopithecus sediba ✓/A. sediba                                    (1)
            (b)    Karabo ✓                                                               (1)
            (c)    Lee Berger ✓                                                           (1)

                                                12

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3.3.2   - Allows for a bigger brain ✓
        - Development of speech ✓/communication
        - Higher intelligence ✓
        - Complex behaviour ✓
        - Quick processing of information ✓
        - Process large amounts of information ✓
        (Mark first TWO only)                                                                                                                       (2)

3.3.3                                                   Bar graph showing the average cranium capacity
                                                                   of different Homo species

            Average capacity of the cranium/ml
                                                 1600
                                                                                                                           1350
                                                 1400
                                                 1200
                                                                                                       1030
                                                                                  930
                                                 1000
                                                  800
                                                            640
                                                  600
                                                  400

                                                  200

                                                    0
                                                         Homo hablis    Homo erectus (Javanese)   Homo erectus (Chinese)   Homo sapiens
                                                                                     Homo species

        Criteria for the assessment of the graph:

            CRITERIA                                                         ELABORATION                               SYMBOL             MARKS
        Correct type of                                                Bar graph drawn                                   (T)                1
        graph
        Caption of graph                                               Both variables included                              (C)             1
                                                                       (average cranium capacity
                                                                       and different Homo species)
        Axes labels                                                    Correct label and unit for x-                        (L)             1
                                                                       and y-axes
        Scale of x- and                                                Equal spacing and correct                            (S)             1
        y- axes                                                        scaling on x- and y-axes
                                                                       and equal width of bars
        Plotting of points                                             (If Australopithecus and/or                          (P)
                                                                       Paranthropus are plotted –
                                                                       no marks are awarded for
                                                                       these bars)
                                                                       1 to 3 required (Homo)
                                                                       bars plotted correctly                                               1
                                                                       Only 4 (Homo) required                                               2
                                                                       bars plotted correctly                                                       (6)

        NOTE:                                       If the wrong type of graph is drawn, marks will be lost for
                                                    “correct type of graph”.

                                                                                         13

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      3.3.4   -   Analysis of mutations ✓
              -   in mitochondrial DNA ✓/mtDNA in mitochondria
              -   is inherited only from the female ✓/maternal line
              -   Shows that the oldest female ancestors ✓
              -   of humans/Homo erectus are from Africa ✓
              -   Chinese and African Homo erectus fossils ✓share similar mutations in
                  mitochondrial DNA/mtDNA ✓
                                                                                   Any      (3)
                                                                                           (14)

3.4   3.4.1   Question removed

      3.4.2   Homologous ✓ structure                                                        (1)

      3.4.3   -   A population of smaller flighted birds species flew long distances to
                  different continents* ✓ / became separated by the sea
              -   causing the population to split into two. ✓
              -   There is no gene flow between the two populations. ✓
              -   Since each population may be exposed to different environmental
                  conditions ✓/the selection pressure may be different/DNA mutations
              -   natural selection occurs independently in each of the two
                  populations ✓
              -   such that the individuals of the two populations become very different
                  from each other ✓
              -   genotypically and phenotypically. ✓
              -   Even if the two populations were to mix again ✓
              -   they will not be able to interbreed. ✓
                                                         ONE compulsory mark* + Any 6       (7)
                                                                                            (8)

3.5 3.5.1     Punctuated equilibrium ✓                                                      (1)

      3.5.2   - Evolution involves longer periods time where species do not
                change /or change gradually (known as equilibrium) through natural
                selection ✓✓
              - This alternates with (is punctuated by) short periods of time where
                rapid changes occur through natural selection ✓✓                            (4)
                                                                                            (5)

                                                                                           [48]

                                                                  TOTAL SECTION B:          98

                                                                               TOTAL:      148

                                                14

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