# Physical Sciences Grade 12 Paper 2 Limpopo Mock 2018 Memo

> Grade 12 Physical Sciences Paper 2 memorandum from the Limpopo Mock Exam 2018, 11 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/lp-2018-paper-2-memorandum/bd3e670d-d605-46da-9bd1-48a271587cb2
- Updated: 2026-09-27
- Subject: Physical Sciences
- Grade: Grade 12
- Document type: Memorandum
- Year: 2018
- Exam period: Limpopo Mock Exam
- Paper: 2
- Curriculum: CAPS
- Pages: 11

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Physical Sciences · Grade 12 · Limpopo Mock Exam · 2018. Memorandum, 11 pages. Read online or download the PDF.

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                               NATIONAL
                          SENIOR CERTIFICATE
                              NASIONALE
                          SENIOR SERTIFIKAAT

                               GRADE/GRAAD 12

                      PHYSICAL SCIENCES: CHEMISTRY (P2)
                       FISIESE WETENSKAPPE: CHEMIE (V2)

                                 SEPTEMBER 2018

                                   MEMORANDUM

    MARKS/PUNTE: 150

                        This memorandum consists of 11 pages.
                      Hierdie memorandum bestaan uit 11 bladsye.

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Physical Sciences P2/Fisiese Wetenskappe V2                      Limpopo September 2018
                                          NSC/NSS - Memorandum

QUESTION 1/VRAAG 1

1.1             A                                                     (2)

1.2             A                                                     (2)

1.3             B                                                     (2)

1.4             D                                                     (2)

1.5             B                                                     (2)

1.6             D                                                     (2)

1.7             C                                                     (2)

1.8             A                                                     (2)

1.9             C                                                     (2)

1.10            C                                                     (2)

                                                                        [20]

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                                                     3
Physical Sciences P2/Fisiese Wetenskappe V2                                          Limpopo September 2018
                                          NSC/NSS - Memorandum
QUESTION 2/VRAAG 2

2.1.1       Carboxylic acids //karboksielsure                                                      (1)

2.1.2       Molecules with the same molecular formulae but different structural formula
            // Organiese molekule met dieselfde molekulêre formule, maar verskillende               (2)
            struktuurformules. 

2.1.3                                                Marking criteria/Nasienriglyne:
                  H O         H                       Whole structure correct/Hele struktuur
                  I II         I                         korrek. 2
                H-C – C – O - C-H                                    2
                  I            I                      Functional group correct./Funksionele
                  H           H                          groep korrek. 1
                                                                                 2
                                                                                                     (2)

2.1.4
           H H O                H HH H         H H H H   O H H       
           I I II                I I I I         I I I I    II I I
         H–C–C–C–O–H         + H–C–C–C–C–O-H  H–C–C–C–C–O–C–C–C-H + H-O-H
           I I                   I I I I         I I I I       I I
           H H                   H H H H         H H H H      H H                                    (4)

        Notes/Aantekeninge:
         Condensed or semistructural formula: Max. 3
                                                                 4
            Gekondenseerde of semistruktuurformule: Maks. 3
                                                                             4
         Molecular formula/Molekulêre formule: 1
                                                         4
         Marking rule 3.9/Nasienreël 3.9
         Any additional reactants or products: Max. 3
                                                             4
            Enige addisionele reaktanse of produkte: Maks. 4
                                                                         4
         If arrow in equation omitted: Max. 3
                                                 4
            Indien pyltjie in vergelyking uitgelaat is: Maks. 3
                                                                     4
2.1.5       Butyl propanoate // butielpropanoaat                                                 (2)

2.2         2,4 – dimethyl pent-2-ene (2-pentene) //2,4-dimetielpent-2-een                       (2)
                                                                                                     [13]

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                                                      4
Physical Sciences P2/Fisiese Wetenskappe V2                                        Limpopo September 2018
                                          NSC/NSS - Memorandum

QUESTION 3/VRAAG 3

3.1         Temperature at which the vapour pressure of the substance equals
            atmospheric pressure.
            Die temperatuur waar die dampdruk van die stof gelyk is aan die
            atmosferiese druk.                                                                      (2)

3.2.1       Liquid //vloeistof                                                                     (1)

3.2.2       Boiling points increase(as chain length increases)  //
            Kookpunte neem toe(soos die kettinglengte toeneem)                                      (1)

3.2.3       Lower.  The isomer is branched/ rounder/ molecules further away from each
            other // Laer. Die isomeer is vertak/ ronder/ molekules verder van mekaar             (2)

3.3         Alkanes have London forces between molecules, alcohols have hydrogen
            bonding forces 
            hydrogen bonding forces are stronger than London forces hydrogen bonding
            forces
            more energy is needed to overcome the intermolecular forces between alcohol
            molecules / break the hydrogen bonding forces hydrogen bonding forces and
            therefore the boiling point is higher
            Tussen die alkane kom Londonkragte voor en tussen die alkohole
            waterstofbindings.
            Waterstofbindings is sterker as Londonkragte.
            Dit vereis dus meer energie om die waterstofbindings te breek en daarom is
            die kookpunt hoër.                                                                       (3)

3.4.1       The pressure exerted by a vapour in equilibrium with its liquidin a closed
            system
            Die druk uitgeoefen deur ‘n damp in ewewig met sy vloeistof in ‘n geslote
            sisteem
              Note/aantekening:
              Allocate mark for closed system only if first part of definition is correct.
              Ken punt toe vir geslote sisteem slegs indien eerste deel van definisie
              korrek is.                                                                             (2)

3.4.2       Lower //Laer                                                                           (1)
3.5                                                        H
                                                           I
                                          H      H        -C-   H
                                          I                I                      
                                      H - C       -        C    - O - H           (2 or/of 0)
                                          I                I
                                          H      H        -C-   H
                                                           I
                                                           H                                         (2)
                                                                                                     [14]

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Physical Sciences P2/Fisiese Wetenskappe V2                                  Limpopo September 2018
                                          NSC/NSS - Memorandum

QUESTION 4/VRAAG 4

4.1.1       The solutionldecolourises/ loses its colour //Die broomwater ontkleur           (1)

4.1.2       Halogenation // Halogenering / halogenasie                                      (1)

4.2.1
                         H H H H H
                         ı    ı ı     ı ı
                     H – C = C – C – C – C – H + H- Br  
                                 ı    ı ı
                                 H H H

                       H H H H H
                       ı ı   ı ı ı
                     H–C-C–C–C–C–H 
                        ı ı  ı ı ı
                       H Br H H H
                                                                                              (3)

4.2.2       2-bromopentane // 2-bromo pentaan                                              (2)

4.2.3       Concentrated NaOH/strong base and high temperature/strong heat                 (3)
            Gekonsentreerde  NaOH/KOH/sterk basis, en hoë temperatuur /sterk
            verhit
4.3         H2SO4 / H3PO4                                                                    (1)

4.4.1       Hydrogen  //Waterstof                                                           (1)

4.4.2       2C4H10 + 13O2 8CO2 + 10H2O  (bal )                                           (3)

4.4.3       Exothermic //eksotermies                                                        (1)
                                                                                              [16]

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Physical Sciences P2/Fisiese Wetenskappe V2                                 Limpopo September 2018
                                          NSC/NSS - Memorandum

QUESTION 5/VRAAG 5

5.1.1       Homogeneous (reaction) //Homogene (reaksie)                                   (1)

5.1.2       Heat of reaction / enthalpy difference / energy difference between products and (1)
            reactants/ energy products – energy reactants Reaksiewarmte/energieverandering
            tussen reaktamore particleste en produkte 
5.1.3       Iron/iron oxide /Yster / Ysteroksied                                          (1)

5.2          Increase in concentration of N2 means more particles/molecules per unit
             volume
             More particles have enough kinetic energy/ energy equal or greater than
             activation energy
             Number of effective collisions per unit time increases
             Verhoging in konsentrasie van N2 beteken meer deeltjies per
             eenheidvolume.
             Meer deeltjies het voldoende/genoeg kinetiese energie
             Die aantal effektiewe botsings per tydseenheid neem dus toe/ frekwensie van
             effektiewe botsings neem toe.                                                 (3)

5.3.1       B.
            When temperature is increased, according to Le Chatelier the endothermic
            reaction will be favoured, thus the reverse reaction Yield of ammonia
            decreases
            Die voorwaartse reaksie is eksotermies en volgens Le Chatelier sal ‘n
            temperatuurverhoging teengewerk word deur die endotemiese reaksie
            bevoordeel wat in hierdie geval die terugwaartse reaksie is. Opbrengs         (4)
            ammoniak verminder dus.
5.3.2       A                                                                             (2)

5.3.3       C.                                                                            (2)
                                                                                            [14]

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Physical Sciences P2/Fisiese Wetenskappe V2                                  Limpopo September 2018
                                          NSC/NSS - Memorandum

QUESTION 6/VRAAG 6

6.1.1       A catalyst is a chemical substance which increases the rate of a
            reaction without undergoing a permanent change itself //
            ŉ Katalisator is ŉ chemiese stof wat die tempo van ŉ chemiese reaksie
            verhoog  sonder om self ŉ permanente verandering te ondergaan. 

             OR/OF
            A catalyst increases the rate of a reaction by providing an alternative route
            with lower activation energy. //
            ŉ Katalisator verhoog die tempo van ‘n reaksie deur ‘n alternatiewe roete  van
            laer aktiveringsenergie te verskaf.                                              (2)

6.1.2       The reaction is exothermic and releases energy //Die reaksie is                 (2)
            eksotermies en stel energie vry.
6.1.3       When pressure is increased
            the reaction which produces less moles of gas / smaller volume of gas will be
            favoured 
            Thus forward reaction is favoured and more NO2 is produced/formed 
            //As die druk verhoog
            sal die reaksie wat minder mol gas/kleiner volume gas produseer bevoordeel
            word 
            dus sal die voorwaartse reaksie bevoordeel word.                                 (3)
            Meer NO2 sal dus vorm.

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Physical Sciences P2/Fisiese Wetenskappe V2                                    Limpopo September 2018
                                          NSC/NSS - Memorandum

6.2.1
                                   NO2(g)    +    NO(g)    ⇌ N2O(g) + O2(g)
             Initial mol           0,06          0,29       0,18    0,38 
             aanvanklike mol
             Used/formed           0,12-0,06     0,06        0,06      0,06
             Verbruik/gevorm       =0,06                              
             Equilibrium           0,12          0,35        0,12      0,32
             (mol∙dm-3)
             /Ewewig(mol∙dm-3)
                                         Add// optel            subtract// aftrek      

                     [   ]                   
            Kc =             =              = 0,914 
                     [   ]                   

            Marking criteria/nasienriglyne
            a. initial concentrations/ aanvanklike konsentrasies neer
            b. Calculate concentration of NO2 used (0,06)/Bereken konsentrasie van
               NO2 wat gebruik is(0,06)
            c. Values of other reactants and products used or formed/ Waardes van
               ander reaktante wat verbruik of gevorm is
            d. Equilibrium values for reactants/ Ewewig waardes vir reaktante
            e. Equilibrium values for products/ Ewewig waardes vir produkte
            f. Correct Kc expression/ Korrekte Kc uitdrukking
            g. Substitution of concentration in correct Kc expression/ Vervanging van
               konsentrasies in korrekte Kc-uitdrukking
            h. Correct final answer/Korrekte finale antwoord                                   (9)

6.2.2       Temperature is decreased // Temperatuuris verlaag                                 (2)
                                                                                                [18]

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Physical Sciences P2/Fisiese Wetenskappe V2                                Limpopo September 2018
                                          NSC/NSS - Memorandum

QUESTION 7/VRAAG 7

7.1.1       Basic// basies                                                                (1)

7.1.2       pH = -log[H3O+] 
              = - log 10-8
              = 8  2 marks for only answer / 2 punte vir slegs antwoord                   (2)

7.1.3       CO32- + H2O ⇌ HCO3- + OH-                                                    (2)

7.2.1       n(NaOH) = cV = 0,2 mol∙dm-3 x 0,025 dm3 = 0,005 mol NaOH 

            n(HCl) = cV = 0,15 mol∙dm-3 x 0,04 dm3 = 0,006 mol HCl 

            1 mol NaOH reacts with //reageer met 1 mol HCl 

            ∴ Excess//oormaat HCl = 0,006 – 0,005 = 0,001 mol                            (7)

7.2.2       Positive marking from 7.2.1// positiewe nasien vanaf 7.2.1
                     n
            [H3O+] = =                = 0,0154 mol∙dm-3 

            pH = -log[H3O+] 

                = -log(0,0154) = 1,812                                                    (5)
                                                                                           [17]

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Physical Sciences P2/Fisiese Wetenskappe V2                                             Limpopo September 2018
                                          NSC/NSS - Memorandum

QUESTION 8/VRAAG 8

8.1.1       Temperature 25°C (298 K)  // temperatuur 25°C;  (298 K)
            Pressure 101,3 kPa (1 atm)  // druk 101,3 kPa (1 atm);                                     (3)
            Concentration 1mol∙dm-3 // konsentrasie 1mol∙dm-3 
8.1.2       Fe/Fe2+ or/of Fe-half cell/halfsel or/of Fe(s)                                             (2)

8.1.3       Fe  Fe2+ + 2e-                                                                            (2)

8.1.4       O2 + 4H+ + 4e-  2H2O                                                                      (2)

8.1.5       Fe(s) / Fe2+ (aq) // O2 (g) / H2O (l),Pt(s) ( -1 if // not there)                         (3)

8.1.6       Eθcell/sel = Eθcathode/katode - Eθanode
                                                       Accept any other correct formula from the data
                       = 1,23 - (-0,44)
                       = 1,67 V                        sheet / Aanvaar enige ander korrekte formule
                                                        vanaf gegewensblad.
                                                       Any other formula using unconventional
                                                        abbreviations, e.g. Eθcell = EθOA- EθRA followed by
                                                        correct substitutions:/ Enige ander formule wat
                                                        onkonvensionele afkortings gebruik bv. Eθsel =
                                                        EθOM- EθRM gevolg deur regte vervangings:
                                                        Max/maks 3/4

                                                                                                         (4)

8.2         Mg is a stronger reducing agent than Fe  Therefore Mg is more easily
            oxidised than iron and prevent that Fe is oxidized to Fe2+. 
            Mg is ‘n sterker reduseermiddel as Fe. Mg is daarom makliker geoksideer as
            yster  en verhoed dat Fe na Fe2+ oksideer.                                                 (3)
                                                                                                         [19]

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QUESTION 9/VRAAG 9

9.1       P                                                                                       (1)

9.2       2H2O + 2e-  H2 + 2OH-                                                                 (2)
          Notes/Aantekeninge
            Reactants  Products  Balancing 
               Reaktanse Produkte Balansering
            Ignore double arrows./Ignoreer dubbele pyle.
          Marking  rule 6.3.10./Nasienreël 6.3.10.
          Marking criteria

9.3       Q na P                                                                                  (1)

9.4       Water / hygrogen ion // water/ waterstofioon                                           (1)

9.5       H2  Cl2  NaOH  (any 2 // enige 2)                                                     (2)
                                                                                                   [7]

QUESTION 10/VRAAG 10

10.1.1     Fractional distillation of liquid air // Fraksionele distillasie van vloeibare lug    (1)

10.1.2     Contact process / Kontakproses                                                        (1)

10.1.3     2NH3 + H2SO4  (NH4)2SO4  (for/vir bal)                                              (3)

10.2.1     Ratio of nitrogen to phosphorous to potassium t                                       (2)

10.2.2
           :        x      x 50 = 5 kg
           OR/OF
           % N:          x 30% = 10%
           Mass of nitogen // massa stikstof: 10% van totale massa van 50 kg

           ∴:            x 50 = 5 kg 
                                                                                                   (3)
10.2.3     % filler/ vulsel= 100 – 30 = 70%

               70
                    x 50 = 35 kg
           100
           OR/OF
                                                  30
           Mass of fertilizer/massa kunsmis =          x 50 = 15
                                                 100
                                                                                                   (2)
           Mass of filler/massa vulsel = 50 – 15x = 35 kgx
                                                                                                   [12]

                                                                         TOTAL/TOTAAL:             150

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