# Mathematics Grade 11 Paper 2 Eastern Cape November 2012 Memo

> Grade 11 Mathematics Paper 2 memorandum from the Eastern Cape November 2012, 8 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/math-p2-n12-memo-a-e/68ca412a-9f54-4fef-b85f-55a1f49207a4
- Updated: 2026-09-27
- Subject: Mathematics
- Grade: Grade 11
- Document type: Memorandum
- Year: 2012
- Exam period: Eastern Cape November
- Paper: 2
- Curriculum: CAPS
- Pages: 8

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## About this document

Mathematics · Grade 11 · Eastern Cape November · 2012. Memorandum, 8 pages. Read online or download the PDF.

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## Document text

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### Page 1

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                  Province of the
                  EASTERN CAPE
                  EDUCATION

                          NATIONAL
                     SENIOR CERTIFICATE

                             GRADE 11
                             GRAAD 11

                        NOVEMBER 2012

           MATHEMATICS P2/WISKUNDE V2
                MEMORANDUM

MARKS:
         150
PUNTE:

                        This memo randum consists of 8 pages.
                       Hierdie memorandum bestaan uit 8 bladsye.

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2                                          MATHEMATICS P2/WISKUNDE V2 (Memo)                                                    (NOVEMBER 2012)

QUESTION/VRAAG 1
1.1 Quadratic / Kwadraties                                                                                      answer/antwoord          (1)
1.2 Yes. The shape of the graph shows it./                                                                          Yes/Ja
    Ja. Die vorm van die grafiek toon dit                                                                           reason/rede          (2)
1.3 Drivers should drive at a speed between 80 km/h and                                                         answer/antwoord
    120 km/h.
    Bestuurders behoort teen ’n spoed tussen 80 km/h en 120
    km/h te bestuur.                                                                                                                      (2)
                                                                                                                                          [5]
QUESTION/VRAAG 2
2.1.1 11;18;22;25;31;35;36;42;44;49                                                                             Method/Metode
      Median/Mediaan =        = 33                                                                               Answer/Antwoord
                                                                                                                Answer only: 2/2
                                                                                                                Slegs antwoord :2/2       (2)
2.1.2 Q1 = 22                                                                                                         Q1
      Q3 = 42                                                                                                         Q3
      Semi IQR=       = 10                                                                                      answer/antwoord
                                                                                                                                          (3)
2.2   Min=11, Q1=22, Q2=33, Q3= 42, Max/Maks =49                                                                     min
                                                                                                                     Q1 and/en Q3
                                                                                                                     Q2
                                                                                                                     max/maks
                                                                                                           x
       10   12   14   16   18   20   22   24   26   28   30   32   34   36   38   40   42   44   46   48   50

                                     22                       33                       42             49
                                                                                                                                          (4)
2.3   Data is skewed to the left./Data is skeef na links OR/OF      answer/
      Data is more widely distributed below the median./        antwoord
      Data is wyer verspreid onder die mediaan                                                                                            (1)
                                                                                                                                         [10]

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(NOVEMBER 2012)         MATHEMATICS P2/WISKUNDE V2 (Memo)                                      3

QUESTION/VRAAG 3
3.1 20+32+25+14+x+38+22+30+19+28+34+40+25 = 27            method/metode
                        13                                answer/antwoord
    x = 24                                                                               (2)
3.2      X          x–x        (x – x)2                   sum/som
        20     20 – 27 = – 7   49
                                                         
        32     32 – 27 = 5     25
        25     25 – 27 = –2    4                          Answer/antwoord
        14     14 – 27 = –13   169                       Answer only: 3/3
        24     24 – 27 = –3    9                         Slegs antwoord: 3/3
        38     38 – 27 = 11    121
        22     22 – 27 = –5    25
        30     30 – 27 = 3     9
        19     19 – 27 = –8    64
        28     28 – 27 = 1     1
        34     34 – 27 = 7     49
        40     40 – 27 = 13    169
                                         SD =
        25     25 – 27 = –2    4
               Sum/Som         698       SD = 7,33                                       (3)
3.3 One standard deviation from the mean/Een
    standaardafwyking vanaf die gemiddelde:               interval
    19,67 to/tot 34,33 9 spectators/toeskouers            answer/antwoord               (2)
                                                                                         [7]
QUESTION/VRAAG 4
4.1   Interval Frequency          Cumulative frequency
               Frekwensie            Kumulatiewe             First 4 correct/eerste 4
                                      frekwensie              korrek
       5          10     5                 5                 Last 3 correct/laaste 3
      10          15     9                14                  korrek
      15          20    14                28
      20          25    17                45
      25          30    11                56
      30          35     7                63
      35          40     2                65                                               (2)
4.2   70
                                                              (5 ; 0)
      60                                                      All points correct/Alle
      50                                                       punte korrek
                                                              Shape/vorm
      40

      30

      20

      10

       0
           0       10     20       30       40      50
                                                                                           (3)
4.3 80% of/van 40 = 32                                        method/metode
    Approximately 5 learners/Ongeveer 5 leerders             answer/antwoord
    (Accept 4, 5 or 6/Aanvaar 4, 5 of 6)                                                   (3)
                                                                                           [8]

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4                                  MATHEMATICS P2/WISKUNDE V2 (Memo)                   (NOVEMBER 2012)

QUESTION/VRAAG 5
5.1 S(–6 ; 4), T(–1 ; 3), R(–7 ; –1)
    ST          1 6         3 4                       Substitution/instelling
    ST     √26                                         ST     √26
    SR          7 6           1 4
                                                      SR        √26
    SR     √26
    ST = SR.                                          Conclusion/gevolgtrekking
      ΔSTR is isosceles/gelykbenig.                                                              (4)
5.2 B(       ;                                        Substitution/instelling
                                                       –4 1
      B(– 4 ; 1)                                                                                 (3)
5.3   S(–6 ; 4), B(–4 ; 1)
         SB
                                                       Substitution/instelling

         SB                                            Gradient/gradiënt
                      3
          4                    6
                      2                                Substitution/instelling
                           5
                                                       Answer/antwoord                          (4)
5.4                       5 and/en A(p ; –17)          Substitution of/instelling
                  3                                     van – 17
       17                 5                            Substitution of/instelling
                  2                                     van p
              8
                                                       Answer/antwoord
                                                                                                 (3)
5.5   T(–1 ; 3), R(–7; –1) and/en         AS

                  TR

               TR                                          TR
                           3       2
                           2       3                       TR         AS
                               1
      Hence AS is perpendicular to TR                 AS perpendicular to TR/
      AS is loodreg op TR                             AS is loodreg op TR                        (3)
5.6   STAR is a kite/vlieër                            Kite/vlieër
      Diagonal AS bisects TR at right angles          Reason/rede
      Skuinslyn AS halveer TR en is loodreg op
      TR
      OR/OF
      ΔSTR and ΔRAT are both isosceles.
      ΔSTR en ΔRAT is albei gelykbenig.
                                                                                                 (3)
                                                                                                [20]

QUESTION/VRAAG 6
6.1 x + y + 2 = 0 and/en Q(7;6)                                    m=–1
    y=–x–2                                                         substitution/instelling
    m=–1                                                           answer/antwoord
    y – 6 = – (x – 7)
    y = – x + 13                                                                                 (3)

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(NOVEMBER 2012)                  MATHEMATICS P2/WISKUNDE V2 (Memo)                                                     5

6.2     Q(7 ; 6), R(4; –6)
                   6 6                                                               substitution/instelling
          QR
                  4 7
          QR    4                                                                    answer/antwoord            (2)
6.3     P(– 2; 0)                                                                    –2 0                      (2)
6.4             12                                                                   Method/metode
          QR                                                                        1
                 3
          T(1 ; 12)                                                                  12                        (3)
6.5     tan = 4                                                                      tan = 4
          = 75,96°                                                                       75,96°
          QR              tan         =                                                 PQ
          = 33,69°                                                                      = 33,69°

        PQR = 75,96° – 33,69° = 42,27°                                               Answer/antwoord            (5)
                                                                                                                [15]
QUESTION/VRAAG 7
7.1.1 R/(– 1 ; – 6)                                                                        – 1 – 6             (2)
7.1.2 R/(6 ; 1)                                                                            6 1                 (2)
7.2.1 (x ; y)→ (x ; – y) → (x – 3 ; – y)                                                   x – y
      (x ; y) → (x – 3 ; – y)                                                              x–3 –y              (4)
7.2.2
                                                                                           D//(1 ; – 3)
                                                    y

                                                                                           E//(– 3 ; 1)
                                               5

                                               4
                                                                                           F//(2 ; 2)
                                               3                                           Diagram
                                               2                  F//

                          E//                  1

                                                                                    x
               -5   -4      -3   -2       -1            1     2         3   4   5

                                               -1

                                               -2

                                               -3
                                                        D//
                                               -4

                                               -5

                                                                                                                 (4)
7.2.3   Rigid. The size and shape do not change                                          Rigid/rigied
        Rigied. Die grootte en vorm verander nie                                         reason/rede            (2)
7.3.1   N/( ; 6)                                                                              6                (2)
7.3.2   Perimeter of/omtrek van KLMN = 10 units/eenhede                                 Method/metode
        Perimeter of/omtrek van K/L/M/N/= 3 × 10                                        Answer/antwoord
                                          = 30 units/eenhede                            Answer only/Slegs
                                                                                           antwoord: 2/2         (2)
7.4     Rotation about the origin through 90° anticlockwise                              90°
        Rotasie rondom die oorsprong deur 90° anti-kloksgewys                            anticlockwise/
                                                                                        anti-kloksgewys          (2)
                                                                                                                [20]

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6                           MATHEMATICS P2/WISKUNDE V2 (Memo)                          (NOVEMBER 2012)

QUESTION/VRAAG 8
8.1  V = π r2h and/en V = 4 000 cm3                         Substitution of/instelling van
     π r2 (15) = 4 000                                       15
                                                            Substitution of/instelling van
        r = 9,21 cm                                          4 000
                                                            answer/antwoord                     (3)
8.2     Vcone =   area of base/opp van basis × H
        H = 10          9,21
           = 3,89 cm                                              H = 3,89 [or/of 3,9]
             Vcone/kegel = π (9,21)2 (3,89)                       Substitution/Vervanging
                            = 345,54 cm3                          V = 345,54 [or/of 346,4]
           Vcontainer/houer = 4 000 cm3 + 345,54 cm3
                            = 4 345,54 cm3
        [accept/aanvaar 4 346,4]                                   answer/antwoord              (4)
8.3     SA = π r2 + 2π r h + π r s                          substitution/instelling :
            = π (9,21)2 + 2π (9,21)(15) + π (9,21)(10)       in π r2  in 2π r h  in π r s
            = 1 423,85 cm2                                  answer/antwoord                     (4)
                                                                                                [11]

QUESTION/VRAAG 9
9.1.1 sin 29°
           1                                                       diagram
            1                                 1   61°                    1
                                                        p
                                                                   answer/antwoord
                                         29°
                                              1
        cos 29° = 1

        OR/OF                                                     OR/OF

        sin2 29° + cos2 29° = 1                                    identity/identiteit
        p2 + cos2 29° = 1                                          substitution/instelling
                                                                   answer/antwoord
        cos 29° = 1                                                                               (3)
9.1.2   tan (– 569°) = – tan 29°                                   – tan 29°
                     =                                             answer/antwoord

        OR/OF                                                     OR/OF

        tan (– 569°) = – tan 29°                                   – tan 29°
                                °
                      =
                                   °
                      =                                            answer/antwoord
                                                                                                  (2)
9.1.3   1 – cos 2 61° = 1 – p2                                    answer/antwoord
        OR/OF                                                     OR/OF
        1 – cos 2 61° = sin 261° = cos2 29°
                      =( 1        )2                               sin 261°
                      = 1 – p2                                     answer/antwoord               (2)

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(NOVEMBER 2012)           MATHEMATICS P2/WISKUNDE V2 (Memo)                              7

9.2
       LHS =

             =                                         

             =

             =                                         

             =
             =
                                                        1
             =                                          factors/faktore

             =            = RHS                         division/deel
                                                                                   (5)
                                                                                  [12]

QUESTION/VRAAG 10
10.1 sin      . tan    360° . sin 450°                            
                                            cos     180°            tan x
                     cos 180°
       sin . tan . cos                                              cos x
                             cos
                 1                                                
            sin                                                      –1
     sin . cos . cos
                           cos                                     
               1
     sin       cos                                            
               1                                              answer/antwoord      (8)
10.2 sin x –3cos x = 0
     sin x = 3cos x                                             sin x = 3cos x
     tan x = 3                                                 tan x = 3
     x = 71,57° + 180°k (k )                                   71,57° + 180°k
                                                               k                   (4)
10.3 2. √sin α = 1
      √sin α =
      sin   =                                                  sin   =

        = 180° – 14,48°                                        14,48°
        = 165,52°                                              165,52°             (3)
                                                                                   [15]

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8                                  MATHEMATICS P2/WISKUNDE V2 (Memo)                                                     (NOVEMBER 2012)

QUESTION/VRAAG 11
11.1 3                                                                                                         3                  (1)
11.2
                                                     y                                 f(x)=-sin x
                                                                                       f(x)=cos(x - 30)

                                                                                                           f:
                                                1                                                          x –intercepts/
                                                                                                           x-afsnitte
                                                                                                            turning points/
                                                                                                           draaipunte
                                                                                                           shape/vorm
                                                                                                       x
       -180   -150    -120   -90   -60    -30              30   60   90   120    150                 180

                                                                                                           g:
                                                                                                            y-intercept/
                                                                                                           y-afsnit
                                                                                                            x-intercepts/
                                                                                                           x-afsnitte
                                                -1

                                                                                                           shape/vorm
                                                                                                                                   (6)
11.3   g(x) – f(x) ≤ 0                                                           Values/waardes
       g(x) ≤ f(x)                                                               Notation/notasie
       x [–180° ; –30°] or/of x [150° ; 180°]                                    Values/waardes
       OR/OF                                                                     Notation/notasie
       –180° ≤ x ≤ –30° or/of 150° ≤ x ≤ 180°                                   per interval                                       (4)
11.4.1 g(x) = cos (x –30°)                                                       –90°
       h(x) = cos (x – 30° – 60°) + 1                                            +1
            = cos (x – 90°) + 1                                                                                                    (2)
11.4.2 Maximum value of/maksimum waarde van
       h(x) – f(x) = 3                                                           3                                               (2)
11.5   – sin x = sin (– x)                                                       sin x
                                                                                 sin (–x)                                         (2)
                                                                                                                                  [17]

QUESTION/VRAAG 12
12.1          40
     sin 30°                                                                                          sin 30°
              QS                                                                                                    QS
         QS = 80 m                                                                                    answer/antwoord             (2)
12.2    PSQ    65°    /                  QPS         85°                             PSQ      / QPS
       PQ       80                                                                   sine formula/sinus
     sin 65° sin 85°                                                             formule
         PQ = 72,78 m                                                                answer/antwoord                              (3)
12.3                   1                                                        substitution into area
                           80 72,78              sin 30°                         formula/instelling in area
                       2
                     = 1 455,60 m2                                               formule
                                                                                
                       1                                                        Substitution/instelling
                           40 80 sin 60°
                       2                                                        
                     = 1 385,64 m2

                         2 × 1 455,50 + 1 385,64 m2                             answer/antwoord
                       = 4 296,84 m2                                                                                               (5)
                                                                                                                                  [10]
                                                                                                           TOTAL/TOTAAL:          150

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