# Mathematics Grade 11 Paper 3 Eastern Cape November 2012 Memo

> Grade 11 Mathematics Paper 3 memorandum from the Eastern Cape November 2012, 6 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/math-p3-n12-memo-eng-afr/31cb255f-b632-41cb-8fe2-0bcddb459ec8
- Updated: 2026-09-27
- Subject: Mathematics
- Grade: Grade 11
- Document type: Memorandum
- Year: 2012
- Exam period: Eastern Cape November
- Paper: 3
- Curriculum: CAPS
- Pages: 6

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## About this document

Mathematics · Grade 11 · Eastern Cape November · 2012. Memorandum, 6 pages. Read online or download the PDF.

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## Document text

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### Page 1

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                  Province of the
                  EASTERN CAPE
                  EDUCATION

                          NATIONAL
                     SENIOR CERTIFICATE

                         GRADE/ GRAAD 11

                        NOVEMBER 2012

               MATHEMATICS P3/ WISKUNDE V3
                    MEMORANDUM

MARKS:
         100
PUNTE:

                     This memorandum consists of 6 pages./
                   Hierdie memorandum bestaan uit 6 bladsye.

### Page 2

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2                                 MATHEMATICS P3 (Memo)                             (NOVEMBER 2012)

QUESTION/ VRAAG 1

1.1   1.1.1      P(A and/en B) = P(A) × P(B)                           √ P(A) × P(B)             (1)

      1.1.2      P(A or/of B) = P (A) + P(B)                           √ P(A) + P(B)             (1)

1.2   1.2.1      (a)    30 √    (b)   150 √      (c)   40 √
                 (d)    150 √   (e)   160 √      (f)   140 √                                     (6)

      1.2.2      P(M passed and S passed./
                                                                       √ 0,40                    (1)
                 (W slaag en S slaag) = = 0,40

      1.2.3      P(M passed and S failed/
                                                                       √ 0,10                    (1)
                 (W slaag en S druip) =   = 0,10

      1.2.4      P(M passed and S passed/
                 (W slaag en S slaag) = = 0,40
                 P(M passed/ W slaag) =       = 0,50
                 P(S passed/ S slaag) =    = 0,53
                  P(M passed/ W slaag) ×                                                        (5)
                                  P(S passed/ S slaag) = 0,50 × 0,53
                                                       = 0,267
                  P(M passed and S passed/W slaag en S slaag)
                       P(M passed/W slaag) × P(S passed/S slaag)
                  Events M and S are dependent/
                   Gebeurtenisse W en S is afhanklik
                                                                                                [15]
QUESTION/ VRAAG 2

2.1   31+10+23+15+x+18 +48+5 = 160                                     √ equation/vergelyking
                                                                                                 (2)
                           x = 10                                      √ answer/antwoord

2.2      =     = 0,03125                                               √ answer/antwoord         (1)

2.3   P(B) =                                                           √ addition/optelling
              =                                                        √ 160                     (3)
                                                                       √ answer/antwoord
              = 0,381

2.4   P(at least TWO candidates/ Ten minste TWEE kandidate)
                                                  =                    √ addition/optelling
                                                       =               √ 160                     (3)
                                                                       √ answer/antwoord
                                                       = 0,331
                                                       = 33%
                                                                                                 [9]

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(NOVEMBER 2012)                          WISKUNDE V3 (Memo)                                      3

 QUESTION/ VRAAG 3

 3.1    The statement is correct as far as the sample is concerned/
        Die stelling is korrek sover dit die steekproef aangaan.

        This does not imply that the total voter population will have the same result/
        Dit impliseer nie dat die totale stemgeregtigde bevolking dieselfde resultaat gaan hê
        nie.

        It is a small sample to consider when you look at a presidential race, as
                 is far less than 10%/                                                          (4)
        Dit is ŉ klein steekproef om in ag te neem as jy kyk na ŉ presidensiële wedloop,
        wetende dat          ver kleiner as 10%.

        This could swing the broader public’s vote unfairly in the actual voting as they
        might believe it is not worthwhile voting for the other candidate(s) in the race./
        Dit kan die breër publiek se stem onregverdig in die werklike stemming swaai, omdat
        hulle mag dink dit sal nie die moeite werd wees om vir die ander kandidaat/kandidate
        in die wedloop te stem nie.

 3.2    3.2.1
                                           2     M        ×7=     =    (MM)
                                           7
                      3         M
                                            5
                      8
                                            7    W        ×7=          (MW)
                                                                                                (7)
                      5                    3     M        ×7=          (WM)
                      8         W          7

                                           4
                                           7
                                                W         ×7=     =    (WW)

        3.2.2     P(W,W) =      = 0,36                                                          (2)

        3.2.3     P(M,W any order/ enige orde) =      +
                                                    =                                           (3)
                                                    = 53,4%
                                                                                                [16]

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4                                  MATHEMATICS P3 (Memo)                                  (NOVEMBER 2012)

QUESTION/ VRAAG 4
4.1   P(HIV+) =       7                                                √ fraction / breuk
              = 0,245                                                                                  (2)
                                                                       √ percentage / persentasie
              = 24,5%
4.2                  7    7
      P(25 – 29) =        7                                            √ fraction / breuk
                  = 0,057                                                                              (2)
                                                                       √ percentage / persentasie
                  = 5,7%
4.3   P(15 – 19, not infected/nie-geïnfekteer nie) =       7           √ fraction / breuk
                                                   = 0,168                                             (2)
                                                                       √ percentage / persentasie
                                                   = 16,8%
4.4   Total population/Totale bevolking (HIV+)=            x100        √ fraction / breuk
                                                          7                                            (2)
                                                    = 24,5%            √ percentage / persentasie

4.5   Age group/Ouderdomsgroep: 25 – 29 = 35,4%                        √ age group / ouderdom
                                                                       √ comparing / vergelyking       (3)
                                                                       √ percentage / persentasie
4.6   More education on HIV/Aids issues, knowing your
      status, single partner, faithful to partner, use of              √√√ Any THREE logical
      condoms, etc./                                                   reasons/                        (3)
      Meer opvoeding oor HIV/Vigs, ken jou status, enkel genoot,       Enige DRIE logiese redes
      getrou aan genoot, gebruik van kondome, ens.
                                                                                                       [14]
QUESTION/ VRAAG 5
5.1   GRAPH A. The scale on the vertical axis is causing the             GRAPH A /
      effect./                                                            GRAFIEK A
                                                                                                       (2)
      GRAFIEK A. Die skaal op die vertikale as veroorsaak die            reason / rede
      effek.

5.2   GRAPH B. It is clear from the graph that the illegal              GRAPH B /
      immigrant influx shows a slight increase for a three               GRAFIEK B
      month period, which show that the minister is in control
      of the problem./                                                   reason / rede                (2)
      GRAFIEK B. Dit is duidelik vanaf die grafiek dat die
      instroming van onwettige immigrante ŉ matige toename wys
      vir ŉ drie-maande periode, wat toon dat die minister in beheer
      van die probleem is

5.3   GRAPH A. It is clear from the graph that the illegal               GRAPH A /
      immigrant influx shows a steep increase for the three               GRAFIEK A
      month period, which the opposition could use to show the           reason / rede
      lack of control by government over the problem./                                                 (2)
      GRAFIEK A. Dit is duidelik vanaf die grafiek dat die
      instroming van onwettige immigrante ŉ skerp toename wys vir
      die drie–maande periode, wat die opposisie kan gebruik om te
      wys dat die regering in gebreke bly om die probleem te beheer.
                                                                                                       [6]

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(NOVEMBER 2012)                                 WISKUNDE V3 (Memo)                                            5

                  * FOR QUESTIONS 6 TO 9 FOLLOW CANDIDATES REASONING */
                   * VANAF VRAAG 6 TOT VRAAG 9 VOLG KANDIDATE SE REDENERING*
 QUESTION/ VRAAG 6
 6.1    6.1.1      P(8;14)                                                                                  (1)
        6.1.2      Q(8;1)                                                                                   (1)
        6.1.3      R(2; 9)                                                                                  (1)
 6.2    6.2.1               7
                   P(2; )                                                                                  (1)
        6.2.2      Q(2; )                                                                                  (1)
        6.2.3      R( ; )                                                                                  (1)
 6.3    Yes, the corresponding sides are equal in proportion/
        Ja, die ooreenstemmende sye is eweredig gelyk.                                                       (2)
                                                                        = 2 or/of
 6.4    Area ∆PQR = (2)2(16x) = 64x units2/                                                               (2)
        Oppervlakte ∆P’Q’R’ = (2)2(16x) = 64x eenhede2
                                                                                                             [10]
 QUESTION/ VRAAG 7
 7.1    7.1.1                   7
                           =                                                        answer / antwoord      (2)
        7.1.2        PM = 2PV (V is the midpoint of PM) = 22
                     PM = 2PV (V is die middelpunt van PM) = 22
                           =                                                        answer / antwoord      (2)
                            =
        7.1.3              =                                                        answer / antwoord      (2)
 7.2    7.2.1        Q ̂ R = y (alternate angles, // lines/
                                                                                     statement / stelling   (1)
                                        verwisselende hoeke, // lyne)
        7.2.2        P ̂ T = 90° – y (angles on a straight line/
                                                                                     statement / stelling   (1)
                                    hoeke op ŉ reguitlyn)
        7.2.3        In ∆PSQ and/ en ∆STP
                      ̂ 1 = ̂ 1 = 90° – y (alternate angles/
                                    verwisselende hoeke : PQ // TR)  statement / stelling
                       ̂      ̂
                            = = 90°                                  statement / stelling                   (3)
                     ̂ 2 = ̂2    (3rd angle of ∆/3rde hoek van ∆)    statement / stelling

                      ∆PSQ /// ∆STP (AAA)/(HHH)/(, ,)
        7.2.4           =           =     (similar triangles/
                                         gelyksoortige driehoeke)
                      PS = ST × PQ
                                2                                      statement / stelling
                           = ST × (RS + ST)                            statement / stelling                 (3)
                      (PQ = RT                                         answer / antwoord
                          = RS + ST, opp. sides of rectangle equal/
                                    teenoorst. sye van reghoek gelyk)
                                                                                                             [14]

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6                                  MATHEMATICS P3 (Memo)                              (NOVEMBER 2012)

QUESTION/ VRAAG 8
8.1   In ∆STP and/ en ∆SQT:
      ̂ is common/ is gemeen                                           statement / stelling
      S ̂ P = T ̂ S (given/ gegee)                                     statement / stelling       (3)
      3rd angle/3rde hoek                                              statement / stelling
       ∆STP /// ∆SQT (AAA)
8.2     =     (similar triangles/ gelyksoortige driehoeke)
                                                                       statement / stelling
        =                                                              substitution /
                                                                                                   (3)
                                                                        substitusie
      SQ =                                                             answer / antwoord
         = 79,79 mm
8.3      =
         =
      QT =                                                             statement / stelling
        = 45,37 mm                                                     substitution /
                                  OR/OF                                                            (3)
                                                                        substitusie
                                                                       answer / antwoord

             79 79    29
                 5
             45 37
                                                                                                   [9]
QUESTION/ VRAAG 9
9.1      =      (similar triangles/ gelyksoortige driehoeke)
         =                                                             statement / stelling
                                                                       substitution/
      EC =                                                                                         (3)
                                                                        substitusie
          = 2p units/ eenhede                                          answer / antwoord
       OB = EC = 2p (opposite sides of a rectangle equal/
                           teenoorstaande sye van reghoek is gelyk)
9.2   OC = (10 – p) units/ eenhede                                     answer / antwoord          (1)
9.3                           /                    =      =
                                                                       statement/ stelling
                                                   =                   substitution/
                                                                                                   (3)
                                                   =                    substitusie
                                                                       answer/ antwoord
                                                   =
                                                                                                   [7]
                                                                           TOTAL/TOTAAL:          100

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