# Mathematical Literacy Grade 11 P1 North West June 2018 Memo > Grade 11 Mathematical Literacy Paper 1 memorandum from the North West June 2018, 5 pages. Read online or download the free PDF. - Page: https://www.hlayiso.com/library/mathematical-literacy-gr-11-memo-p1-1/5c834dd2-84c0-4f9b-bdc0-a222276ebad9 - Updated: 2026-09-27 - Subject: Mathematical Literacy - Grade: Grade 11 - Document type: Memorandum - Year: 2018 - Exam period: North West June - Paper: 1 - Curriculum: CAPS - Pages: 5 Breadcrumbs: [Home](https://www.hlayiso.com/) › [Library](https://www.hlayiso.com/library) › [Grade 11](https://www.hlayiso.com/library/grade-11) › [Mathematical Literacy](https://www.hlayiso.com/library/grade-11/mathematical-literacy) › [Mathematical Literacy Grade 11 P1 North West June 2018 Memo](https://www.hlayiso.com/library/mathematical-literacy-gr-11-memo-p1-1/5c834dd2-84c0-4f9b-bdc0-a222276ebad9) ## About this document Mathematical Literacy · Grade 11 · North West June · 2018. Memorandum, 5 pages. Read online or download the PDF. Read it free online on the page above; download the PDF from there. ## Document text Text extracted from the PDF. Layout, diagrams and tables may not survive extraction. ### Page 1 Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE GRADE 11 MATHEMATICAL LITERACY PAPER 1 JUNE EXAMINATION 2018 MARKING GUIDELINE MARKS: 75 Symbol Explanation M Method CA Continuous accuracy A Accuracy C Conversion S Simplification RT/RG/RM Read from Table / Read from graph/ 2018Read from Map SF Substitution in formula O Opinion/Example / Deduction/conclusion P Penalise for example no units / incorrect rounding etc R Rounding J Justification/ Motivation/ Supply a Reason F Formula NPR No penalty for rounding OR ommiting units AO Answer only Demo NW/JUNE/MATLIT/ EMIS/6******* 1 ### Page 2 Downloaded from hlayiso.com QUESTION 1 [13] TL 1.1.1 1M division 500 1 Answer 1 Mass = 1000 ü = 0,5kgü (2) 1.1.2 2 1Mmultiplying 1 𝑂𝑖𝑙 𝑛𝑒𝑒𝑑𝑒𝑑 = 3 × 250ü 1Answer = 166,67 ü 1Rounding = 167 ml oil neededü (3) 1.1.3 1Multipying 1 Total muffins =12×2ü 1Answer = 24ü (2) 1.2.1 0 to 1 hourü 2 Answer Sundays and public holidaysü 1 (2) 1.2.2 Total time = 13: 25 – 08: 45 ü 1Subtraction = 4 hours 40 minutesü 1Answer 1 (2) 1.2.3 Amount paid =R6,00 üü 2Anwser 1 (2) QUESTION 2 [16] 2.1 2 Answer 2 Total Cost = R 2 400 × R 50, 00 + n, where n is the number of people attending the conference. üü (2) 2.2 A= R2 400 + 50 × 20 ü 1Substitution = R2 400 +R 1000 1Answer 2 = R3 400 ü (2) 2.3 I = 130× n 1Substitution 2 10 400 = 130× n 1Answer n = 80 (2) Demo NW/JUNE/MATLIT/ EMIS/6******* 2 ### Page 3 Downloaded from hlayiso.com Income and Cost 14000 12000 Amouunt in Rands 10000 8000 6000 Cost Income 4000 2000 0 0 20 40 60 80 100 120 Number of People 1M heading 1M (0, 2 400) 1M labelling both axis 1M(100,7 400) 1M (0,0) 2M joining the points 1M(100, 13 000) 1M labelling both graphs (8) 2.5 30 Tickets üü 2A answer 2 (2) QUESTION 3 [23] 3.1.1 R1 000, 61üü 2RT 1 (2) 3.12 R2 00,00 üü 2RT 1 (2) 3.1.3 Life style magazine feeüü 2A Answer 1 (2) 3.1.4 1substitution 𝑅23,73 1A 2 𝑖𝑛𝑡𝑒𝑟𝑒𝑠𝑡 𝑟𝑎𝑡𝑒 = 𝑅1 000,61×100ü NPR = 2,371553352% =2,38%ü (2) 3.2 12% 1Conversion = 1% Per monthü 12% 1Substitution 1 1A answer 𝑓𝑖𝑟𝑠𝑡 𝑚𝑜𝑛𝑡ℎ = (100 × R13500) + ,R13500, 00ü 1A answer Demo NW/JUNE/MATLIT/ EMIS/6******* 3 ### Page 4 Downloaded from hlayiso.com = R13 635,00 ü 1A answer 3 1 𝑠𝑒𝑐𝑜𝑛𝑑 𝑚𝑜𝑛𝑡ℎ = (100 × R13 635 ) + R13 635, 00 = R13 771,35 ü (5) 1 Third month = (100 × R13 771,35) + R13 771, 35 = R13 909,02 ü OR First month = 1,01 × R13 500ü = R13 635 ü Second month = 1,01 × R13 635 = R13 771,35ü Third month = 1,01 × R13 771,35 = R13 909,02 ü ü 3.3.1 6kl = 0ü 1A answer 6kl = R8,04× 6 = R48,24ü 1Method 2 6kl = R10,55× 6 = R63, 30 1A answer 6kl = R12,21× 6 = R73, 26 1A answer 3kl = R13,95× 3 = R41, 85ü 1A answer Total paid = R48,24+ R63,30 + R73,26 + R41,85ü = R226,65ü (5) 3.3.2 17 1Method New charges = × R44,82 + R44,82ü 1Answer 2 100 = R52,44ü (2) 3.4 R 25000 1 numerator Earning in other country = üü 1denominator 1 16,93 = £1476,67ü 1A answer (3) QUESTION 4 [23] 4.1.1 150 1Dividing Radius = ü 2 1A answer 2 = 75cmü (2) 4.1.2 Volume = 𝜋𝑟 2 h 1Conversion V = 3,142 × (75𝑐𝑚)2 ü × 250ü𝑐𝑚 1Substitution 3 V = 4418437,5 c𝑚3 ü 1A answer 1A answer 1000c𝑚3 = 1litre 1Rounding 4418437,5 V = 1000 V = 4418,4375ü (5) V = 4418,43litresü Demo NW/JUNE/MATLIT/ EMIS/6******* 4 ### Page 5 Downloaded from hlayiso.com 4.1.3 H = 2,5m 1Radius 75 1Substitution Radius = 100 1A answer 3 = 0,75mü 1units Surface area = 2πr(r + h) = 2 × 3,142 × 0,75( 0,75 + 2,5) 𝑚2 ü (4) = 2 × 3,142 × 0,75(3,25) 𝑚2 = 15,31725 𝑚2 ü =15,32𝑚2 ü 4.2.1 8 Medical stations üü 2A answer 1 23 Refreshment stationsüü 2A answer (4) 4.2.2 44 kilometres üü 2A answer 1 (2) 4.2.3 University of Cape townüü 2A answer 1 (2) 4.2.4 1Substitution 3 𝑑𝑖𝑠𝑡𝑎𝑛𝑒 1 Conversion Speed = 𝑡𝑖𝑚𝑒 1A answer 56 1Unit Speed = 3,25ü ü (4) Speed = 17,23ü km/hü Demo NW/JUNE/MATLIT/ EMIS/6******* 5 ## Related documents - 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