# Mathematical Literacy Grade 11 P2 North West June 2019 Memo

> Grade 11 Mathematical Literacy Paper 2 memorandum from the North West June 2019, 7 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/mathematical-literacy-gr-11-memo-paper-2/58096d5e-5c73-4d60-80ab-69b9573b149a
- Updated: 2026-09-27
- Subject: Mathematical Literacy
- Grade: Grade 11
- Document type: Memorandum
- Year: 2019
- Exam period: North West June
- Paper: 2
- Curriculum: CAPS
- Pages: 7

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Mathematical Literacy · Grade 11 · North West June · 2019. Memorandum, 7 pages. Read online or download the PDF.

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### Page 1

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                          NATIONAL
                     SENIOR CERTIFICATE

                            NATIONAL
                       SENIOR CERTIFICATE

                                   GRADE 11

                  MATHEMATICAL LITERACY P2
                           MARKING GUIDELINES

                                 JUNE 2019

         SYMBOL      EXPLANATION
         M           Method
         M/A         Method with accuracy
         CA          Consistent accuracy
         A           Accuracy
         C           Conversion
         S           Simplification
         RT/RG       Reading from a table/Reading from a graph
         F           Choosing the correct formula
         SF          Correct substitution in a formula
         O           Opinion/Example
         P           Penalty, e.g. for no units, incorrect rounding off etc.
         R           Rounding off
         J           Justification/Reason

MARKS:    75

                  This marking guidelines consists of 7 pages.

                    Demo
                            NW/JUNE/MATLIT/ EMIS/6*******

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       MATHEMATICAL LITERACY/P2                                                NSC                                    NW/JUNE 2019
                                                                             GRADE 11

       MARKING GUIDELINES
                                                                                                                             Taxonomy
Ques                                                     Solution                                       Explanation
                                                                                                                               levels
                                QUESTION 1 [21 MARKS]
1.1    Expense (R) = R200 + R5 ×number of passengers                                             1A fixed value            L2
                                                                                                   1MA multiplication
                                                                                                                     (2)
1.2    Expense (R) = R200 + R5 ×7                                                                 1SF substitution          L2
                   = R200 + R35                                                                   1S simplification
                   = R235                                                                         1A answer
                                                                                                                    (3)
1.3    TABLE: Phemelo’s Income                                                                     Table:                    L3
                                                                                                   1A any two correct
        Number of                        0       5      10         15        20     25             points
        passengers                                                                                 1A any two correct
        Income                           0       100    200        300       400    500         points
                                                                                                   1A any two correct
                                     Phemelo's Expenses and Income                                 points
                           500                                                                
                                                                                                  Graph:
                                                                                   Income
                           450
                                                                                                   1CA starting point
                           400                                                                     1CA break-even pint
                           350                                                          Expenses   1CA end point

          Amount in rand
                                                                                                   1A joining the points
                           300
                                                                                                  1A naming graph
                           250
                                                                                                                       (8)
                           200
                                                              
                           150

                           100

                           50
                                 
                            0
                                 0           5           10             15         20         25
                                                 Number of passengers

1.4    No,  because the break-even point is between 13 and 15 passengers.                         1O opinion                L4
       Accept the break-even point is between 12,5 and 15                                          2J justification
       passengers.                                                                                                     (3)

1.5    ˚F = 1,8 × 37˚ + 32˚                                                                       1SF substitution          L4
          = 66,6˚+ 32˚                                                                            1S simplification
                                                                                                   1A answer
          = 98,6˚
                                                                                                   1R rounding
          = 99˚
                                                                                                   1O opinion
       The passenger is correct. 

                                                       Demo
                                                                  NW/JUNE/MATLIT/ EMIS/6*******     2

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        MATHEMATICAL LITERACY/P2                      NSC                                 NW/JUNE 2019
                                                    GRADE 11
        OR
        99˚  = 1,8 ×˚C + 32˚                                              OR
        1,8 ×˚C = 99˚- 32˚                                                 1SF substitution

             ˚C = 67˚÷1,8
                                                                           1S simplification
                = 37,2222˚
                = 37˚                                                     1A answer
        The passenger is correct.                                         1R rounding
                                                                           1O opinion
                                                                                              (5)
                                    QUESTION 2[19 MARKS]
2.1.1   To minimise water that spill out of the pool when people are       2A answer                  L4
        swimming. 
        OR                                                                                      (2)
        When people get into the swimming pool the water will rise to a
        higher level.
        Accept any relevant reason.

2.1.2   Area = side × side                                                                            L2
                                                                           1SF substitution
             = 32,8084 ×32,8084
                                                                           1A answer
             = 1 076,39111
                                                                           1R rounding        (3)
             ≈ 1 077 feet2

2.1.3   radius = 32,8084 ÷2 = 16,4042 feet                                1A radius in feet          L3
        radius = 16,4042÷3,28084 =5 m                                    1C conversion
                                                                           1A radius in metres
        Volume of circular = π × r2 × h
                           = 3,142 × (5)2 × 2 m                           1SF substitution
                             = 157,1 m 
                                       3                                   1S simplification
                                                                           1A volume kilolitres
                              = 157,1 kilolitres                          OR
        OR                                                                 1A height in feet
                                                                           1C conversion
        radius = 32,8084 ÷2 = 16,4042 feet
                                                                           1A height in metres
        height = 2 ×3,28084 =6,56168 m
        Volume of circular = π × r2 × h                                    1SF substitution
                           = 3,142 × (16,4042)2 × 6,56168 m               1S simplification

                             = 5547,934675 feet3 
                                                                           1A volume in
                                                                           kilolitres
                                 5547,934675m3
                             =                                                            (6)
                                   3,280843
                             = 157,1 kilolitres

                                    Demo
                                           NW/JUNE/MATLIT/ EMIS/6*******    3

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        MATHEMATICAL LITERACY/P2                           NSC                                 NW/JUNE 2019
                                                         GRADE 11
2.2            Calc.                                       Cost                  1M multiplication         L3
               R9,54× 6                                   R57,24               1CA answer
               R13,62× 6                                   R81,72
               R17,89× 6                                   R107,34
                                                                                 1A calculation and
               R20,70× 6                                   R124,24               cost
               R23,66× 6                                   R141,96               1A calculation and
               R25,57× 12                                  R306,84               cost
               R27,36× 30                                  R820,80              1A calculation and
               R29,29× 78                                  R2 284,62             cost
               Total cost                                  R3 924,76            1CA total cost

                                                                 115             1M calculating VAT
               Total cost including VAT = R3 924,76 ×                
                                                                 100             1CA cost including
                                                 = R4 513,47                    VAT
               OR
               Total cost including VAT                                          OR
                                    15                                           1CA VAT amount
               = R3 924,76 ×              + R3 924,76
                                    100                                          1CA cost including
               = R588,71 + R3 924,76                                            VAT
               = R4 513,47                                                                       (8)
                                            QUESTION 3[13 MARKS]
3.1.1   The school did not receive the expected number of learners             2Answer                   L4
        OR
        Some learners were transferred to other schools before the end of the
        year. 
        OR
        Less number of learners enrolled                                                        (2)
3.1.2   Water and sanitation                                                   2A any two correct        L4
        Telephones                                                              answer
        Electricity
        Gardening
        Cleaning
        Accept any relevant answer                                                                   (2)
                        420 000
3.1.3   Percentage =
                        993 500
                                  ×100%                                        1RT correct values        L4
                                                                                 1M multiplication
                   = 42%
                                                                                 1A answer
        The claim is valid. 
                                                                                 1O opinion
        OR
                   40
                                                                                 OR
        Amount =         × R993 500                                            1RT correct value
                   100
                = R397 400  ( it is less than R420 000)                         1M multiplication
        The claim is valid                                                      1A answer
                                                                                 1O opinion        (4)
3.2.1   Time = 30 min + 45 minutes + 45 Minutes                                 1M adding                 L2
             = 120 minutes                                                      1A time in minutes
            = 2 hours                                                           1A time in hours
                                                                                                  (3)
                                          Demo
                                                 NW/JUNE/MATLIT/ EMIS/6*******    4

### Page 5

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        MATHEMATICAL LITERACY/P2                        NSC                                  NW/JUNE 2019
                                                      GRADE 11
        To prepare children to sleep.                                       2J reasoning             L4
        OR
        To develop listening skill
        OR
        To improve vocabulary
3.2.2
        OR
        To develop oral communication skills
        OR
        Helps kids to bond with their teachers. 
        Accept any relevant reason                                                               (2)

                                             QUESTION 4[22 MARKS]
4.1.1   The decrease in the general price of goods and services             2A answer                L4
        OR
        It means deflation                                                                     (2)
        OR
        Inflation decline
4.1.2                75                                                       1M dividing              L3
        Amount = 14,2417
                                                                              1S simplification
                 = 5,26622524€
                                                                              1M multiplication
                 = 5,26622524 ×1,15$                                         1A answer
                 = 6,056159026 $                                             NPR
                                                                                                (4)
                                     100
4.1.3   2016 monthly rental fee = 110,61 × 1654 EGP                         1A fraction              L2
(a)                                                                           1M multiplication
                               = 1 495,344001 EGP
                                                                              1A answer
                                                                              NPR
        OR
                                             10,61
                                                                              OR
        2016 monthly rental fee increase = 110,61× 1654 EGP                  1M multiplication
                                        = 158,6559986                        1S simplification
        2016 monthly rental fee = 1 654 – 158,6559986                         1A answer
                                = 1 495,344001EGP                            NPR               (3)
4.1.3   South Africa:                                                                                  L4
(b)                     𝑟𝑒𝑛𝑡𝑎𝑙 (2018)−𝑟𝑒𝑛𝑡𝑎𝑙 (2016)
        % increase =                                   ×100%
                              𝑟𝑒𝑛𝑡𝑎𝑙 𝑖𝑛 2016
                        𝑅7 175− 𝑅6 350                                        1SF substitution
        % increase =                       ×100%
                            𝑅6 350
                    = 13%                                                    1A answer
        Egypt:
                        𝑟𝑒𝑛𝑡𝑎𝑙 (2018)−𝑟𝑒𝑛𝑡𝑎𝑙 (2016)
        % increase =                                   ×100%
                              𝑟𝑒𝑛𝑡𝑎𝑙 𝑖𝑛 2016
                        1654−1495,3
        % increase =                  ×100%
                          1495,3
                    = 10,6%                                                  1CA answer
        The claim is not valid.                                              1Opinion
                                                                              NPR
                                                                                                 (4)

                                      Demo
                                              NW/JUNE/MATLIT/ EMIS/6*******    5

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        MATHEMATICAL LITERACY/P2                         NSC                                    NW/JUNE 2019
                                                       GRADE 11
4.2.1   Up OR above Church Square                                             2A answer                L2
                                                                                                     (2)
4.2.2   Take Rissik street,  turn right into Nelson Mandela drive,  turn left   1A direction and         L3
        into Pretorius Street, destination is on the right.                     street
        OR                                                                        1A direction and
        Go north towards Park street, turn left into Schoeman street             street
        immediately right into Nelson Mandela,  turn left into Pretorius         1A destination
        street,  destination in on the right.                                                      (4)
4.2.3   Actual distance = 6 ×100 000 cm = 600 000 cm                             1C conversion            L3
                            600 000𝑐𝑚                                             1M using scale
        Distance on map =    75 000
                                        
                                                                                  1A answer
                         = 8cm
                                                                                                     (3)
        OR
                          75 000𝑐𝑚
        Actual distance = 100 000 
                         = 0,75 km
                                1 𝑐𝑚
        Distance on map = 6× 0,75 
                         = 8cm

                                                 TOTAL MARK : 75

                                        Demo
                                               NW/JUNE/MATLIT/ EMIS/6*******       6

### Page 7

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MATHEMATICAL LITERACY/P2                   NSC                          NW/JUNE 2019
                                         GRADE 11
PAPER ANALYSIS

QUESTION   L2    L3 L4       FINANCE          MEASUREMENT        MAPS, PLANS AND
                                                                 OTHER
                                                                 REPRESENTATIONS
                                                                 OF THE REAL WORLD
1.1        2                 2
1.2        3                 3
1.3              8           8
1.4                   3      3
1.5                   5                       5
2.1.1                 2                       2
2.1.2      3                                  3
2.1.3            6                            6
2.2              8           8
3.1.1                 2      2
3.1.2                 2      2
3.1.3      4                 4
3.2.1      3                                  3
3.2.2                 2                       2
4.1.1                 2      2
4.1.2            4           4
4.1.3(a)   3                 3
4.1.3(b)              4      4
4.2.1      2                                                     2
4.2.2                 4                                          4
4.2.3            3                                               3
TOTAL      20    29   26     45               21                 9
MARK
EXPECTED   15    30   30
MARK
ATUAL %    25    39   35
EXPECTED   25    35   40
%

                      Demo
                                 NW/JUNE/MATLIT/ EMIS/6*******   7

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