# Mathematical Literacy Grade 10 P1 2012 Memo (Eng)

> Grade 10 Mathematical Literacy Paper 1 memorandum from the National Exemplar Exam 2012 (English), 6 pages. Read online or download the free PDF.

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- Updated: 2026-09-27
- Subject: Mathematical Literacy
- Grade: Grade 10
- Document type: Memorandum
- Year: 2012
- Exam period: National Exemplar Exam
- Paper: 1
- Curriculum: CAPS
- Pages: 6

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## About this document

Mathematical Literacy · Grade 10 · National Exemplar Exam · 2012. Memorandum, 6 pages. Read online or download the PDF.

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## Document text

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### Page 1

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                                     NATIONAL
                                SENIOR CERTIFICATE

                                          GRADE 10

                          MATHEMATICAL LITERACY P1

                                     EXEMPLAR 2012

                                     MEMORANDUM

MARKS: 75

                 Symbol   Explanation
                 M        Method
                 MA       Method with accuracy
                 CA       Consistent accuracy
                 A        Accuracy
                 C        Conversion
                 S        Simplification
                 RT/RG    Reading from a table/Reading from a graph
                 SF       Correct substitution in a formula
                 O        Opinion/Example
                 P        Penalty, e.g. for no units, incorrect rounding off, etc.
                 R        Rounding off/Reason

                           This memorandum consists of 6 pages.
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### Page 2

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      Mathematical Literacy/P1                       2                                             DBE/2012
                                   NSC – Grade 10 Exemplar –Memorandum

QUESTION 1 [15]
Ques   Solution                                                          Explanation                    Topic
                                                                                                        M
                   A       A
1.1          1 × 60 = 20 minutes                                         1 A multiply 60
             3                                                           1 A answer
                                                                                                  (2)

1.2          80 g A                                                     1A reading from the
                                                                         table
                                                                                                  (1)
                                                                                                        M
1.3          1 tablespoon = 12,5 mℓ A                                   1A tablespoon to mℓ
             12,5 mℓ margarine = 12,5 g A A                            2A mℓ to g
             ∴ Lindi added 12,5 g of margarine                                                    (3)
                                                                                                        M
1.4          Amount of water used = 4 cups
                                  = 4 × 250 mℓ M                        1M multiplying
                                  = 1 000 mℓ A                          1A mℓ
                                  = 1 litre C                           1C conversion to litre
                                                                                                  (3)
1.5.1                                                                    1M multiplying                 M
             2,5 kg = 2,5 × 1 000g M                                    1C conversion to grams
                    = 2 500 g C                                                              (2)
                                                                                                        M
1.5.2                                                2 500 g M
             Number of times she can make porridge =                     1M dividing
                                                     312,5 g
                                                                         1CA simplification
                                                     = 8 CA
                                                                                                  (2)
                                                                                                        M
1.6          To simmer turn knob to 1. A A                             2A answer
                                                                         [Accept values below 3
                                                                         but more than 0]
                                                                                               (2)

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Mathematical Literacy/P1                         3                                                 DBE/2012
                                  NSC – Grade 10 Exemplar –Memorandum

QUESTION 2 [15]
Ques     Solution                                                     Explanation                   Topic

                                                                A                                 D
2.1       5     5    6     7    7    7    8     8    8     8     9  2A arranging
          10    15   15    15   15   15   15    20   23    23                           (2)
                                                                                                    D
2.2      Mode is R15 A                                              2A answer
                                                                                             (2)
                                                                                                    F
2.3      R23 A                                                      2A answer         (2)

                                                                                                    D
2.4      Median = R9 AA                                             2A answer
                                                                                             (2)
                                                                                                    D
2.5      Mean =                            M
         5 + 5 + 6 + 7 + 7 + 7 + 8 + 8 + 8 + 8 + 9 + 10 + 15 + 15     1M adding
                                    21 A                             1A number of entries
           15 + 15 + 15 + 15 + 20 + 23 + 23
         +
                           21
                     R 244 CA                                        1CA sum
                 =
                       21
                 = R11,62                                             1CA rounded off
                 ≈ R12 CA                                            answer
                                                                                             (4)
                                                                                                    P
2.6                          number of learners getting R 7           1A numerator
         Probability (R7) =                                           1A denominator
                                total number of learners
                              3 A
                           =
                             21 A                                    1CA simplified answer
                                                                                         (3)
                                1
                            =     CA
                                7

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Mathematical Literacy/P1                         4                                            DBE/2012
                                  NSC – Grade 10 Exemplar –Memorandum

QUESTION 3 [20]
Ques     Solution                                               Explanation                    Topic
                                                                                               F
3.1.1    Total number of items = 26     AA                    2A answer
                                                                                        (2)
                                                                                               F
3.1.2                   R 32,97                                 1M dividing
         Unit price =              M
                           3
                      = R10,99     A                           1A simplification
                                                                                        (2)
                                                                                               F
3.1.3    Total amount = R324,85 A A                           2A answer
                                                                                        (2)
                                                                                               F
3.1.4    Change = R400 – R324,85 M                             1M subtracting from R400
                = R75,15 CA                                    1CA answer
                                                                                      (2)
                                                                                               F
3.1.5    Mangoes A A                                          2A answer
                                                                                        (2)
                                                                                               F
3.1.6    R38,92 A                                              2A answer
                                                                                        (2)
                                                                                               F
3.2.1    Bond repayment OR Rates OR School fees OR
         Car instalment (any one)      A A                    2A answer
                                                                                        (2)
              M       A                                                                      F
3.2.2    A: 12% × R18 350 = R2 202                              1M percentage
                                                                1A correct value used
                                                                                        (2)
                                         M                                                    F
3.2.3    B: R4 100 + R475 + R325 + R580 + R2 750                1M adding
             + R1 650 + R1 800 + R1 300 + R940 + R2 202
           = R16 122 CA                                        1CA answer
                                                                                        (2)
                                                                                               F
3.2.4    R18 350 – R16 122 M                                   1M subtracting
         = R2 228 CA                                           1CA answer
                                                                                        (2)

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Mathematical Literacy/P1                        5                                           DBE/2012
                                 NSC – Grade 10 Exemplar –Memorandum

QUESTION 4 [11]
Ques     Solution                                          Explanation                      Topic
                                                                                            SM
4.1      2    A A                                        2A number of restaurants
                                                                                      (2)
                                                                                            SM
4.2      38                              A A             2A correct number
                                                                                      (2)
           A                                   A                                          SM
4.3.1    1 unit on the map is equivalent to 500 units in   2A correct number
         real life.                                                                   (2)
                                                                                            S
4.3.2    1 mm represents 500 mm on the ground
         180 mm represents 180 mm × 500 A                 1A using the scale
                         = 90 000 mm A                    1A answer in centimetres
                         = 90 m C                         1C answer in metres
                                                                                      (3)
                                                                                            M
4.4      Restaurant AA                                   2A correct shop
                                                                                      (2)

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Mathematical Literacy/P1                       6                                    DBE/2012
                             NSC – Grade 10 Exemplar –Memorandum

QUESTION 5 [14]
Ques     Solution                                        Explanation                 Topic
                                                                                     D
5.1.1    Sprite and Granadilla Twist A A               2A solution
         (any valid cooldrink)
                                                                              (2)
                                          M                                         D
5.1.2    % Fanta Orange sales = 100% – (12+55+9+7)% 1M subtracting from 100
                              = 17% CA              1CA answer
                                                                              (2)
                                                                                     D
5.1.3    Coca-Cola A A                                 2A solution
                                                                              (2)
                                                                                     D
5.1.4                                   A A            2A solution
         55% OR 0,55 OR 55
                        100                                                   (2)

                                                                                     F
5.2.1    Original price = R4 999 + R500 M               1M adding
                        = R5 499 A                      1A answer
                                                                              (2)
                                                                                     F
                                amount saved
5.2.2    Percentage discount =                 × 100%
                                original price
                                 500
                              =       × 100% SF
                                5 499                    1SF substitution

                            = 9,09% A                   1A answer
                                                                              (2)
                                                                                     F
5.2.3    Total amount paid = deposit + monthly
                      payment × number of months

         = R500 + (R263 × 24) SF                        1SF substitution
         = R6 812 A                                     1A answer
                                                                              (2)

                                                                              TOTAL:           75

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