# Mathematical Literacy Grade 12 Paper 1 NSC June 2021 Memo

> Grade 12 Mathematical Literacy Paper 1 memorandum from the NSC June Exam 2021, 15 pages. Read online or download the free PDF.

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- Updated: 2026-10-29
- Subject: Mathematical Literacy
- Grade: Grade 12
- Document type: Memorandum
- Year: 2021
- Exam period: NSC June Exam
- Paper: 1
- Curriculum: CAPS
- Pages: 15

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### Page 1

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              SENIOR CERTIFICATE EXAMINATION/
          NATIONAL SENIOR CERTIFICATE EXAMINATION
            SENIORSERTIFIKAAT-EKSAMEN/NASIONALE
                 SENIORSERTIFIKAAT-EKSAMEN

     MATHEMATICAL LITERACY P1/WISKUNDIGE GELETTERDHEID V1

                                              MAY-JUNE 2021

                         MARKING GUIDELINES/NASIENRIGLYNE

                                                                                        MARKS/PUNTE: 150
      Symbol/Kode     Explanation/Verduideliking
          M           Method/Metode
         MA           Method with accuracy/Metode met akkuraatheid
         CA           Consistent accuracy/Volgehoue akkuraatheid
          A           Accuracy/Akkuraatheid
          C           Conversion/Herleiding
           S          Simplification/Vereenvoudiging
         RT           Reading from a table/graph/document/diagram/Lees vanaf tabel/grafiek/dokument/diagram
          SF          Correct substitution in a formula/Korrekte vervanging in 'n formule
          O           Opinion/Explanation/Opinie/Verduideliking
           P          Penalty, e.g. for no units, incorrect rounding off, etc./Penalisasie, bv. vir geen eenhede,
                      verkeerde afronding, ens.
           R          Rounding off/Afronding
          NPR         No penalty for rounding/Geen penalisasie vir afronding nie
          AO          Answer only/Slegs antwoord
          MCA         Method with consistent accuracy/Metode met volgehoue akkuraatheid

                             This marking guideline consists of 15 pages
                             Hierdie nasienriglyne bestaan uit 15 bladsye.

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        Mathematical Literacy/P1/Wiskundige Geletterdheid/V1   2                                        DBE/2021
                                      SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne

        NOTE:
        •  If a candidate answers a question TWICE, only mark the FIRST attempt.
        •  If a candidate has crossed out (cancelled) an attempt to a question and NOT redone the solution,
           mark the crossed out (cancelled) version.
        •  Consistent accuracy (CA) applies in ALL aspects of the marking guidelines; however, it stops at the
           second calculation error.
        •  If the candidate presents any extra solution when reading from a graph, table, layout plan and map,
           then penalise for every extra item presented.
        •  General principle of marking, if the candidate makes one mistake he loses one mark.
        LET WEL:
        •  As 'n kandidaat 'n vraag TWEE KEER beantwoord, sien slegs die EERSTE poging na.
        •  As 'n kandidaat 'n antwoord van 'n vraag doodtrek (kanselleer) en nie oordoen nie, sien die
           doodgetrekte (gekanselleerde) poging na.
        •  Volgehoue akkuraatheid (CA) word in ALLE aspekte van die nasienriglyne toegepas, dit hou op by die
           tweede berekeningsfout.
        •  Wanneer 'n kandidaat aflesings vanaf 'n grafiek, tabel, uitlegplan en kaart geneem en ekstra antwoorde
           gee, penaliseer vir elke ekstra item.
        •  Die algemene beginsel van merk as 'n leerder een fout maak verloor hy een punt.

QUESTION/VRAAG 1 [32 MARKS/PUNTE]                       ANSWER ONLY FULL MARKS
Q/V Solution/Oplossing                                            Explanation/Verduideliking                       T&L
                                                                                                                   M
1.1.1 Radius/Radius = 300 mm ÷ 2 MA                                       1MA dividing by 2                       L1

                            = 150 mm OR/OF 15 cm A                        1A simplify
                                                                                                           (2)
                       RT                                                 1RT reading all the values              F
1.1.2     R330,00; R275,00; R220,00; R110,00 CA                           1CA correct order                       L1
                                                                                                           (2)
                                                                                                                   F
1.1.3 VAT/BTW = R275,00 × 15% MA                                          1MA multiplying by 15%                  L1

                      = R41,25 A                                          1A simplify

                                     OR/OF                                               OR/OF

          Price including VAT/Prys BTW ingesluit
          = R275     1,15
          = R316,25 MA                                                    1MA calculating VAT
          VAT = R316,25 – R275
                = R41,25 A                                                1A simplify
                                                                                                           (2)
                                                                                                                   M
1.1.4       150 ÷ 60 A                                                    1A divide by 60                         L1

          = 2,5 OR/OF 2         hours/uur A                               1A 2,5 hours
                                                                                                           (2)

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Q/V       Solution/Oplossing                                               Explanation/Verduideliking               T&L
                                                                                                                    F
1.1.5 Total cost/Totale Koste                                                                                       L1
                                 MA                                       1MA adding all correct values
          = R330,00 + R275,00 + R220,00 + R220,00 + R165,00
            + R110,00

          = R1 320 MCA                                                    1MCA simplify (at least 5
                                                                                correct values)
                                                                                                              (2)
                                                                                                                    F
1.1.6 Discount/ Afslag = R330,00 × 7,5% MA                                1MA multiplying by 7,5%                  L1

                             = R24,75 A                                   1A simplification
                                                                                                              (2)
                                                                                                                    M
1.2.1     1 250 g                                                          1MA dividing by 1 000                    L1
                  MA
           1 000
                                                                           1A simplification
          = 1,25 kg A                                                                                        (2)
                                                                                                                    F
1.2.2 Cost Price/Kosprys                                                                                            L1
                                                                           1MA subtracting correct
          = R55,00 – R30,30 MA                                                values in the correct order

          = R24,70 A                                                      1A simplification
                                                                                                              (2)
                                                                                                                    M
1.2.3 1 250 : 500 MA                                                      1MA values in correct order              L1
          5 : 2 OR/OF 2,5 : 1 OR/OF 1: 0,4 CA                             1CA simplified form
                                                                                                              (2)
                                                                                                                    M
1.2.4 Number of packets/Aantal pakkies                                                                              L1
          4 000 g                                                          1A number of 500g packs
                   8 A
           500 g

          Mass/Massa
          100 g                                                            1MA dividing 100 g by 8
                MA
            8                                                              1CA simplification
          = 12,5 g CA

                                     OR/OF                                               OR/OF

          Mass/Massa
           MA                                                             1MA number of 500g packs
          500 g  100 g                                                    1A dividing 4 000 g
                         12,5 g CA
            4 000 g A                                                     1CA simplification

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Q/V     Solution/Oplossing                                               Explanation/Verduideliking               T&L
                                   OR/OF                                            OR/OF

        4000 g : 100 g             MA                                   1MA correct ratio concept
        500 g : mass of raisins/massa van rosyntjies
                            50 000 g
        Mass of raisins 
                             4 000 A                                    1A dividing 4 000 g
        Mass of raisins/Massa van rosyntjies                             1CA simplification
        = 12,5 g CA                                                                                        (3)
                                                                                                                  M
1.2.5 Number of cups/aantal koppies                                                                               L1
        MA
      =2×5                                                               1MA multiply by 2 and 5
      = 10 A                                                            1A simplification

                                   OR/OF                                               OR/OF

        4 000 : 5 MA
                                                                         1MA correct ratio
        8 000 : 10
          The number of cups = 10 A                                     1A simplification
                                                                                                            (2)
                                                                                                                  F
1.3.1 Money earned on an investment/                                                                              L1
      Geld verdien op 'n belegging.  A                                 2A definition
                                                                                                            (2)
                                                                                                                  M
1.3.2 25 months/maande A                                               2A correct number of months              L1
                                                                                                            (2)
                                                                                                                  F
1.3.3 Bank A A                                                         2A correct bank                          L1
                                                                                                            (2)
                                                                                                                  F
1.3.4 Difference/Verskil                                                                                          L1
      RT RT                                                            1RT correct value from tables
      7,50% 6,7%                                                         1RT correct value from tables
      = 0,8% CA                                                         1CA simplification (one value
                                                                              must be correct)
                                                                                                           (3)
                                                                                                          [32]

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QUESTION/VRAAG 2 [37 MARKS/PUNTE]
Q/V Solution/Oplossing                                                     Explanation/Verduideliking T&L
                                                                                                       F
2.1.1 Dr. JJ Ndlovu A                                                    2A correct name             L1
                                                                                                   (2)
                                                                                                       F
2.1.2 Year of birth/Geboortejaar                                                                       L1

                                                                           2RT reading from table
       1982 / '82 RT
                                                                                                          (2)
                                                                                                                F
2.1.3 R0,00/nothing/niks       A                                         2A correct amount                    L1
                                                                                                         (2)
                                                                                                                F
2.1.4 Amount excluding VAT/Bedrag BTW uitgesluit                                                                L2
                                                                               115
                                                                           1A       OR 100
                   115         100                                             100     115
       R1 744,75 ÷     OR/OF ×
                   100         115 A                                      1M ÷
                                                                                115
                                                                                    OR ×
                                                                                          100
       R1 744,75 ÷ 1,15 M                                                      100       115

       = R1 517,17 CA                                                     1CA simplification

                                   OR/OF                                               OR/OF

       VAT amount/BTW bedrag
                      15
       R1 744,75 
                     115
      = R227,58 A                                                         1A amount VAT
      Amount excluding VAT/Bedrag BTW uitgesluit
      = R1 744,75 – R227,58 M                                             1M subtracting VAT
                                                                           1CA simplification
      = R 1 517,17 CA
                                                                                                          (3)
                                                                                                                F
2.1.5 One infection control /Een infeksiebeheer                                                                 L1
      =R40,55 ÷ 2 MA                                                      1MA divide by 2
      = R20,28 A                                                          1A simplification
                                                                           NPR
                                                                           AO
                                                                                                          (2)
                                                                                                                F
2.2.1 Total fixed cost/Totale vaste koste                                                                       L1

       = R140,00 + R60,00 RT                                              1RT correct values
       = R200,00 CA                                                       1CA simplification (one
                                                                                value must be correct)
                                                                                                    (2)

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Q/V     Solution/Oplossing                                                  Explanation/Verduideliking T&L
                                                                                                       F
2.2.2 Expenses/Uitgawes                                                                                L2

        Expenses (A) = R200,00 + R12,50 × number of packets

        A = R200,00 + R12,50 × 10 SF                                       1SF correct substitution

        A = R200,00 + R125,00

          = R325,00 A                                                      1A simplification
                   SF             SF
        B = 400 ÷ 25   OR/OF B = (400 – 200 ) ÷ 12,5                        1SF correct substitution
         = 16 A            = 16 A                                         1A simplification
                                                                            AO
                                                                                                         (4)

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Q/V       Solution/Oplossing                                      Explanation/Verduideliking T&L
                                                                                             F
2.2.3                    INCOME AND EXPENDITURE OF 1 kg OF MIXED VEGETABLE PACKS             L2
(a)                             INKOMSTE EN UITGAWES VAN I kg GEMENGDEGROENTE-PAKKE

                              1300

                                                                                Income      A
                              1200                                              Inkomste

                              1100

                              1000

                              900

                                                                                                Expenses
                              800                                                               Uitgawes

             Amount in rand
                              700
                                                                      A

                              600

             Bedrag in rand   500

                              400

                              300

                              200

                              100

                                0        A
                                     0        5   10   15   20   25   30   35    40   45   50

                                                       Number of 1 kg vegetable packs
                                                       Aantal 1 kg groentepakke

          1A starting point (0; 0)
          1A endpoint (50; 1 250)
          1A straight line (must be joining at least 3 points stated in the table; CA for using B)

                                                                                                                  (3)

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Q/V     Solution/Oplossing                                         Explanation/Verduideliking T&L
                                                                                                   F
2.2.3 Where the cost price of mixed vegetable packs equals the                                     L1
(b)   selling price of the packs/Waar die kosprys van 'n pak
      groente gelyk is aan die verkoopprys van die pak groente.    2A explanation
                                                                                               (2)
                                                                   CA from Q2.2.2 / 2.2.3 (a)      F
2.2.3 16 packs/pakke A                                           2A correct number of            L1
(c)                                                                   packs
                                                                                               (2)
                                                                                                   F
2.3.1 Deposit/Deposito                                                                             L1
(a)   R1 799,00 ×
                      20
                     100 MA                                       1MA calculating 20%
      = R359,80 A                                                 1A simplification
                                                                                               (2)
                                                                   CA from Question 2.3.1(a) F
2.3.1 Total amount/Totale bedrag                                                                   L2
(b)                  MA                                           1MA multiplying by 24
      = R359,80 + (24 × R95,00)
      = R359,80 + R2 280,00 MCA                                   1MCA adding the deposit
      = R2 639,80 CA                                              1CA simplification
      = R2 640,00 R                                               1R to the nearest rand
                                                                                               (4)
                 A                                  A                                            F
2.3.2 The  value  of one currency relative to the value of another 1A value  of one currency       L1
(a)   currency/Die waarde van een geldeenheid relatief tot die     1A relative to the value of
      waarde van 'n ander geldeenheid.                                another currency
                                                                                               (2)
       A                                  A                                                    F
2.3.2 yen / jen / Ұ OR/OF Japanese yen / Japanese jen              2A correct currency             L1
(b)                                                                                            (2)
                                                                                                   F
2.3.2 1 ZAR = 0,067251 dollar ($) RT                              1RT exchange rate               L2
(c)
          $130
                   R1 C                                                   1C conversion
        $0,067251
        = R1 933,056758                                                     1R correct rounding
        = R1 933,00 R
        OR/OF                                                                          OR/OF

                                                                            1RT exchange rate
        Dollar ($) = ZAR14,86966737 RT
        $130                                                                1C conversion
              R14,86966737 C
         $1
        = R1 933,056758
        = R1 933,00 R                                                      1R correct rounding
                                                                                                         (3)
                                                                                                        [37]
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QUESTION/VRAAG 3 [22 MARKS/PUNTE]
Q/V  Solution/Oplossing                                                Explanation/Verduideliking                 T&L
                                                                                                                  M
3.1.1     Width/breedte = 3 × 10,4 cm MA                              1MA for multiplying diameter by 3          L1
                        = 31,2 cm A                                   1A simplification

          Length/Lengte = 4 × 10,4 cm MA                              1MA for multiplying diameter by 4
                        = 41,6 cm A                                   1A simplification
                                                                                                      (4)
                                                                                                                  M
3.1.2     Ribbon needed for one candle (cm)                                                                       L3
          Lint benodig vir een kers (cm)
          = 2 × 3,142 × radius + 3 cm
          = 2 × 3,142 × 5,2 cm + 3 cm SF                              1SF correct substitution (radius)
          = 35,6768 cm A                                              1A length for 1 candle

          20 × 100
          = 2 000 cm C
                                                                       1C conversion
          Number of candles/Aantal kerse
          2 000 cm ÷ 35,6768 cm MCA
          = 56, 05883936                                               1MCA dividing by length of
          = 56 candles/kerse R                                                ribbon
                                                                       1R correct number of candles

                                                                         Accept 55 candles if
                                                                         rounded earlier
                                                                                                            (5)
                                                                       CA from Question 3.1.2                     M
3.1.3     Volume = 3,142 × (5,2cm)2 × 11,4cm SF                       1SF substituting correct                   L2
                                                                           values
                    = 968,54 cm3 CA                                   1CA answer in cm3

          Volume of horsehead/Volume van kers met perd

               2 968,54
                        cm3                                            1MCA multiply by 2 and dividing
           =                     MCA
               3   1                                                        by 3

           = 645,69 cm3 CA                                            1CA simplification

                                   OR/OF                                                 OR/OF
           CA
           968,54                                                      2CA answer in cm3
                  = 322,84666 × 2 MCA                                 1MCA multiply by 2 and dividing
             3
                                                                             by 3
                    = 645,69 cm3 CA                                   1CA simplification

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Q/V       Solution/Oplossing                                                   Explanation/Verduideliking          T&L
                                            OR/OF                                       OR/OF
3.1.3
          Volume = 3,142 × (5,2)2 × 11,4 cm SF                                1SF substituting correct
                                                                                   values
                    = 968,54 cm3 CA
                                                                               1CA answer in cm3
          Volume of horsehead = 968,54 cm3 - (968,54 cm3)

                                      = 968,54 – 322,85 MCA                   1MCA subtracting
                                      = 645,69cm3 CA
                                                                               1CA simplification
                                                                                                             (4)
                                                                                                                   P
3.2.1     Ribbon/Lint OR/OF R/L A                                            2A ribbon                           L1
(a)                             A                                                                            (2)
                                                                                                                   P
3.2.1     HBN /PSG A                                                         2A HBN/PSG                          L1
(b)                                                                                                          (2)
                                                                                                                   P
3.2.2                                       A                       A   M                                       L2
                                                     M
(a)       P[candle with ribbon/ kers met lint ] = 1  100 % OR/OF    4 100     1A fraction
                                                                          %
                                                  2 1                8   1     1M concept of percentage

                                          = 50% CA                 = 50%CA 1CA for percentage
                                                A                        A   AO
                                                                                                             (3)
                                                                                                                   P
3.2.2                                                                                                              L2
(b)       P/W P[Gold horsehead candle / Goue perdekop kers ] = 0   A
                                                                   A
                                            OR/OF
                                                                               2A correct probability
                                    0
           Impossible / Onmoontlik / / 0% / 0,0 A
                                    8
                                                            A                                                (2)
                                                                                                            [22]

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QUESTION/VRAAG 4 [21 MARKS/PUNTE]
Q/V Solution/Oplossing                                       Explanation/Verduideliking                             T&L
                                                                                                                    MP
4.1.1      North West / NW                                                                                          L1
           Noord-wes/ NW RT                                2RT reading from map
                                                                                                              (2)
                                                                                                                    MP
4.1.2      N8 RT                                           2RT N8                                                 L1
                                                                                                              (2)
                                                                                                                    MP
4.1.3      Campbell RT                                     2RT town                                               L1
                                                                                                              (2)
                                                                                                                    MP
4.1.4      04:00 – 09:30                                                                                            L2
           = 5 hours 30 min / 5,5 hours/ure A               1A calculating 5,5 hours

           Average Speed /Gemiddelde spoed

               496,9 MCA                                    1MCA dividing correct values in correct
           =                                                      order
                5,5

           = 90,3454545 km/h CA                             1CA simplification
           = 90 km/h R                                      1R rounding
                                                                                                              (4)

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Q/V        Solution/Oplossing                                                Explanation/Verduideliking             T&L
                                                                                                                    MP
4.2.1      1 unit on the plan represents 380 units in real life./                                                   L1
           1 eenheid op die plan verteenwoordig 380 eenhede in
           werklikheid.                                     A              2A explanation
                                                                                                              (2)
                                                                                                                    MP
4.2.2      Lifts/Hysbakke A                                                                                       L1

           OR/OF

           Ground Floor/Grondvloer A                                       2A lifts

           OR/OF

           Stairs/Trappe A
                                                                                                              (2)
                                                                                                                    MP
4.2.3      4 A                                                             2A correct value                       L1
                                                                              Accept 2
                                                                                                              (2)
                                                                                                                    MP
4.2.4      Bloed street entrance/Bloedstraat-ingang RT                                                            L1

                                      OR/OF                                  2RT correct entrance

           South entrance/Suidelike ingang RT
                                                                                                              (2)
                                                                                                                    MP
4.2.5      27 mm A                                                        2A for correct measurement             L1
                                                                             1A correct wall
                                                                             (Accept 26 – 28 mm)
                                                                                                             (3)
                                                                                                            [21]

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        Mathematical Literacy/P1/Wiskundige Geletterdheid/V1   13                                        DBE/2021
                                      SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne

QUESTION/VRAAG 5 [38 MARKS/PUNTE]
Q/V  Solution/Oplossing                                                        Explanation/Verduideliking           T&L
                                                                                                                    D
5.1.1      Range is the difference between the highest/maximum value                                                L1
           and the lowest/minimum value in a data set. A                     2A correct definition
           Omvang is die verskil tussen die hoogste/maksimum waarde
           en die kleinste/minumum waarde in 'n dataversameling.
                                                                                                              (2)
                                                                                                                    D
5.1.2      Line graph/Lyngrafiek                                                                                    L1

           OR/OF                          A                                  2A correct graph

           Broken line graph/Gebrokelyn grafiek
                                                                                                              (2)
                                                                                                                    D
5.1.3      Discrete data/Diskrete data A                                     2A discrete                          L1
                                                                                                              (2)
                                   M                                                                               D
5.1.4      1 749 + 2 239 + 1 618 + 903 + 429 +150 + 16 RT                     1RT correct values                   L1
           = 7 104 CA                                                         1M adding ALL values
                                                                               1CA simplification (at least
                                                                                   6 values correct)

                                                                                Accept 7 136 = full marks
                                                                               AO
                                                                                                        (3)
                                                                                                                    D
5.1.5      L2 RT                                                            3RT correct level                    L1
                                                                                                              (3)
                                                                               CA from Question 5.1.4               D
5.1.6      Median level descriptor/Mediaanvlakbeskrywer                        1MCA arranging in order              L3
                          CA
           = 62; 223; 551; 935 1 231; 1 357; 1 990 MCA                        1CA correct median

           L4 CA                                                              1CA level descriptor

                                      OR/OF                                                OR/OF
                          MCA
           L2 : L3 ; L1 ; L4 ; L5 ; L6 , L7 CA                                1MCA arranging
                                                                               1CA correct order
           Median level/Mediaanvlak
           = L4 CA
                                                                               1CA level descriptor
                                                                               AO
                                                                                                              (3)

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        Mathematical Literacy/P1/Wiskundige Geletterdheid/V1   14                                        DBE/2021
                                      SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne

Q/V        Solution/Oplossing                                                  Explanation/Verduideliking           T&L
                                                                                                                    D
5.2.1       IIII I A                                                         2A correct tally                     L1
                                                                                                              (2)
                                                                               CA from Question 5.2.1               D
5.2.2      6 CA                                                              2CA correct frequency                L1
                                                                                                              (2)
            RT                                                                1RT correct values                   D
5.2.3      43 + 17 = 60                                                        1MA simplification                   L1
            MA
                                        OR/OF                                            OR/OF
            RT         MA                                                    1RT correct values
           0 + 3 + 6 + 12 + 7 + 15 + 17 = 60                                   1MA simplification
                                                                                                              (2)
            A A                                                              1A stacked                           D
5.3.1      Stacked bar graph/Stapel staafgrafiek                               1A bar graph                         L1
                                                                                                              (2)
                               A                       A                                    D
5.3.2      Two hundered and ninety four thousand two hundred and 1A first part of wording     L1
           two/
           Twee honderd vier en negentig duisend twee honderd en 1A second part of wording
           twee.                                                                          (2)

                     RT                                                       1RT correct values                   D
5.3.3      298 607 – 222 034       9 670 M                                    1M subtracting                       L2
           = 66 903 CA                                                        1CA simplification (two
                                                                                    values must be correct)
                                                                               AO
                                                                                                        (3)
                                                                                                                    D
5.3.4      Mean/Gemiddelde                                                                                          L2
                                         RT                                   1RT correct values
            225458 + 263903 + 265810 + 245103 + 233858 + 222034
                                     6                          M 1M concept of mean
           = 242 694,33 CA
                                                                               1CA simplification
                                                                               NPR
                                                                                                              (3)
                                                                                                                    D
5.3.5      Range/Omvang                                                                                             L2

           388 845 – 294 202 MA                                               1MA concept of range

           = 94 643 CA                                                        1CA simplification (one
                                                                                  value must be correct)
                                                                                                       (2)

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        Mathematical Literacy/P1/Wiskundige Geletterdheid/V1   15                                   DBE/2021
                                      SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne

                                                                                                               D
5.3.6      % for Mathematics/% vir Wiskunde                                                                    L2
            RT                                                                1RT correct values
             222034 100                                                        1MA percentage calculation
           =           MA
             530311   1

           41,8686% CA                                                        1CA simplification

           % for Mathematical Literacy/% vir Wiskundige
           Geletterdheid

            298607 100
                   
            530311   1

           56,3079% CA
                                                                               1CA simplification
           56,3079% 41,8686%
           = 14,4 % CA                                                        1CA simplification with
                                                                                  correct rounding
                                        OR/OF
             RT        M                                                               OR/OF
            298 607 - 222 034
                              × 100 MA                                        1RT correct values
                 530 311 CA
                                                                               1M subtracting values
           = 14,4% CA                                                         1CA correct denominator
                                                                               1MA percentage calculation
                                                                               1CA simplification with
                                                                                   correct rounding
                                                                                                        (5)
                                                                                                       [38]
                                                                                  TOTAL/TOTAAL: 150

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