# Mathematical Literacy Grade 12 P1 NSC November 2023 Memo > Grade 12 Mathematical Literacy Paper 1 memorandum from the NSC November Exam 2023, 16 pages. Read online or download the free PDF. - Page: https://www.hlayiso.com/library/mathematical-literacy-p1-nov-2023-mg-afr-eng/5fe319d9-da46-407f-8935-2cfcb6062c31 - Updated: 2026-10-29 - Subject: Mathematical Literacy - Grade: Grade 12 - Document type: Memorandum - Year: 2023 - Exam period: NSC November Exam - Paper: 1 - Curriculum: CAPS - Pages: 16 Breadcrumbs: [Home](https://www.hlayiso.com/) › [Library](https://www.hlayiso.com/library) › [Grade 12](https://www.hlayiso.com/library/grade-12) › [Mathematical Literacy](https://www.hlayiso.com/library/grade-12/mathematical-literacy) › [Mathematical Literacy Grade 12 P1 NSC November 2023 Memo](https://www.hlayiso.com/library/mathematical-literacy-p1-nov-2023-mg-afr-eng/5fe319d9-da46-407f-8935-2cfcb6062c31) ## About this document Mathematical Literacy · Grade 12 · NSC November Exam · 2023. 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Layout, diagrams and tables may not survive extraction. ### Page 1 Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE/ NASIONALE SENIOR SERTIFIKAAT GRADE/GRAAD 12 MATHEMATICAL LITERACY P1/ WISKUNDIGE GELETTERDHEID V1 NOVEMBER 2023 MARKING GUIDELINES/NASIENRIGLYNE MARKS/PUNTE: 150 Symbol/Kode Explanation/Verduideliking MA Method with accuracy/Metode met akkuraatheid MCA Method with consistent accuracy/Metode met volgehoue akkuraatheid CA Consistent accuracy/Volgehoue akkuraatheid A Accuracy/Akkuraatheid C Conversion/Herleiding S Simplification/Vereenvoudiging RT Reading from a table/graph/document/diagram/Lees vanaf tabel/grafiek/dokument/diagram SF Correct substitution in a formula/Korrekte vervanging in 'n formule O Opinion/Explanation/Opinie/Verduideliking P Penalty, e.g. for no units, incorrect rounding off, etc./Penalisering, bv. vir geen eenhede, verkeerde afronding, ens. NPR No penalty for correct rounding/Geen penalisering vir korrekte afronding nie NPU No penalty for omitting unit, but wrong unit is penalised/Geen penaliseringe indien die eenheid uitgelos is nie, maar wel indien 'n verkeerde eenheid gebruik word. AO Answer only/Slegs antwoord These marking guidelines consist of 16 pages and 3 pages of notes. Hierdie nasienriglyne bestaan uit 16 bladsye en 3 bladsye met notas. . Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 2 Downloaded from hlayiso.com Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 2 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne NOTE: • If a candidate answers a question TWICE, only mark the FIRST attempt. • If a candidate has crossed out (cancelled) an attempt to a question and NOT redone the solution, mark the crossed out (cancelled) version. • Consistent accuracy (CA) applies in ALL aspects of the marking guidelines; however it stops at the second calculation error. • If the candidate presents any extra solution when reading from a graph, table, layout plan and map, then penalise for every extra item presented. • Rounding is an independent mark. • General principle of marking, if the candidate makes one mistake one mark is deducted. • A conclusion mark can only be given if relevant calculations precedes it. • No penalty for rounding (NPR) if the first decimal is correct. LET WEL: • As 'n kandidaat 'n vraag TWEE KEER beantwoord, sien slegs die EERSTE poging na. • As 'n kandidaat 'n antwoord van 'n vraag doodtrek (kanselleer) en nie oordoen nie, sien die doodgetrekte (gekanselleerde) poging na. • Volgehoue akkuraatheid (CA) word in ALLE aspekte van die nasienriglyne toegepas; dit hou egter op by die tweede berekeningsfout. • Wanneer 'n kandidaat aflesings vanaf 'n grafiek, tabel, uitlegplan en kaart geneem en ekstra antwoorde gee, penaliseer vir elke ekstra item. • Afronding tel as 'n afsonderlike punt. • Die algemene beginsel van merk as 'n leerder een fout maak, word een punt afgetrek. • 'n Gevolgtrekkingspunt kan slegs gegee word indien relevante berekeninge dit voorgaan. • Geen penalisering vir ronding (NPR) as die eerste desimaal korrek is nie. QUESTION/VRAAG 1 [29 MARKS/PUNTE] ANSWER ONLY FULL MARKS Q/V Solution/Oplossing Explanation/Verduideliking T&L D 1.1.1 Discrete / Diskreet A 2A correct classification L1 (2) E D 1.1.2 Twelve million nine hundred and twenty nine thousand nine L1 hundred and thirty nine / Twaalf miljoen negehonderd nege en E twintig duisend negehonderd nege en dertig A 2A correct wording (2) * D 1.1.3 B RT 2RT correct session L1 (2) E D 1.1.4 Increase / Verhoging L1 E = 704 344 RT 1RT correct values = 1 797 A 1A number of tracks OR / OF OR / OF (88 705 985 – 88 704 344) + (88 706 141 – 88 705 985) RT = 1 641 + 156 1RT correct values = 1 797 A 1A number of tracks (2) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 3 Downloaded from hlayiso.com Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 3 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L * RT 1RT correct values D 1.1.5 690 160 : 8 120 031 A 1A values in correct order L1 = 1 : 11,77 A 1A simplification E Accept: 11,765 / 11,8 / 12 (3) F 1.2.1 VAT / BTW A 2A correct acronym L1 (2) E * F 1.2.2 Total price / Totale prys L1 RT 1RT all values E = R18,05 + R41,84 + R12,16 + R8,33 + R0,11 + R6,98 + R11,53 MA 1MA adding all values = R99,00 A 1A simplification (3) * RT 1RT correct value F 1.2.3 R8,33 L1 % amount   100% M R41,84 RT 1RT correct value 1A simplification = 19,91% A NPR (3) F 1.2.4 Amount / Bedrag L1 E = 210 000 × R8,33 MA 1MA multiplying correct values = R1 749 300 A 1A simplification (2) * F 1.2.5 Number of CD's / Aantal CD's L1 E R16,50  MA 1MA dividing by R0,11 R0,11 1A simplification = 150 A (2) * F 1.3.1 Gross monthly income is the monthly income L1 before deductions / Bruto maandelikse inkomste is E die maandelikse inkomste voor aftrekkings. A 2A explanation (2) * F 1.3.2 Price of a vehicle / Prys van voertuig L1 RT 2RT correct price E = R1 000 000,00 / R1 million / 1 million rand = R1 000 000,00 / R1 miljoen / 1 miljoen rand (2) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 4 Downloaded from hlayiso.com Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 4 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L F 1.3.3 Monthly repayment / Maandelikse terugbetaling L1 M = R41 610,78 RT RT correct value = R42 000 R 1R rounding (2) [29] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 5 Downloaded from hlayiso.com Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 5 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne QUESTION/VRAAG 2 [40 MARKS/PUNTE] Q/V Solution/Oplossing Explanation/Verduideliking T&L F 2.1.1 Elite cheque account / Elite Tjekrekening RT 2RT correct account L1 Accept: E Cheque account (2) * F 2.1.2 Total fees / Totale fooie L1 RT 1RT two correct values E R1,60 + R69,00 + R110,00 RT 1RT third correct value 1CA simplification = R180,60 CA AO (3) * F 2.1.3 Net salary (A) / Netto salaris (A) L4 RT 1RT both correct values M = R10 078,41 – R2 100,35 MA 1MA subtracting values = R7 978,06 CA 1CA simplification Portion of Net salary / Gedeelte van Netto salaris 1  R7 978,06  4 /  0,25 /  4 MCA 1MCA dividing by 4 = R1 994,52 CA 1CA simplification Total insurance / Totale versekering R940,39 + R940,39 = R1 880,78 A 1A total monthly insurance R 99 ,52 ˃ R , His statement is INCORRECT / Sy bewering is VERKEERD. O 1O conclusion OR / OF OR / OF Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 6 Downloaded from hlayiso.com Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 6 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L * 2.1.3 Net salary (A) / Netto salaris (A) RT 1RT both correct values = R10 078,41 – R2 100,35 MA 1MA subtracting values = R7 978,06 CA 1CA simplification Total insurance / Totale versekering A 1A numerator R1 880,78   100% R7 978,06 MCA 1MCA denominator = 23,57% CA 1CA simplification 23,57% < 25% His statement is INCORRECT / Sy bewering is O 1O conclusion VERKEERD. OR / OF OR / OF Net salary (A) / Netto salaris (A) 1RT both correct values 1MA subtracting values RT = R10 078,41 – R2 100,35 MA 1CA simplification = R7 978,06 CA Total insurance / Totale versekering R940,39 + R940,39 = R1 880,78 A 1A total monthly insurance R1 880,78 × 4 MCA 1MCA multiplying by 4 = R7 523,12 CA 1CA simplification R7 9 , ˃ R 523,12 His statement is INCORRECT / Sy bewering is VERKEERD. O 1O conclusion (7) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 7 Downloaded from hlayiso.com Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 7 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L * F 2.1.4 Amount excluding VAT / Bedrag BTW uitgesluit L3 A 1A correct VAT calculation D = 100  R110,00MA 115 1 1MA multiplying by = R95,65217391 A 1A simplification Amount including VAT / Bedrag BTW ingesluit 114  R 95,65217391  MA 1MA multiplying by 100 = R109,04 CA 1CA simplification OR/OF OR/OF Amount excluding VAT / Bedrag BTW uitgesluit R110,00 A 1A correct VAT calculation  1MA dividing by 1,15 1,15 MA = R95,65217391 A 1A VAT excluded amount Amount including VAT / Bedrag BTW ingesluit  R95,65217391  1,14 MA 1MA multiplying by 1,14 = R109,04 CA 1CA simplification (5) * F 2.2.1 Annual taxable income / Jaarlikse belasbare inkomste L2 = R8 978,00 × 12 M = R107 736,00 A 1A annual taxable income Tax bracket / Belasting hakkie =A OR / OF = 1 – 226 000 RT 2RT tax bracket OR / OF AO = 18% of taxable income (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 8 Downloaded from hlayiso.com Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 8 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L CA from Question 2.2.1 F 2.2.2 Income Tax / Inkomstebelasting L4 M 18% of taxable income 18  R107 736,00  1MCA calculating 18% 100 MCA = R19 392,48 CA 1CA simplification MA 1MA subtracting rebate R 9 92, R 425,00 + R9 000,00) MA 1MA subtracting rebate R 9 92, R25 25 R 2,52 OR / OF R19 392,48 < R25 425 CA 1CA simplification His statement is VALID / Sy bewering is GELDIG. O 1O conclusion OR / OF OR / OF Annual Taxable Income / Jaarlikse belasbare inkomste = R107 736,00 Rebates / Kortings 1MA adding rebate = R16 425 + R9 000 MA 1CA simplification = R25 425 CA Tax Threshold / Belastingdrempel 1MCA dividing by 18% = R25 425 ÷ 18% MCA 1CA simplification = R141 250 CA 1O reason R141 250 is greater than / is meer as R107 736. O 1O conclusion His statement is VALID / Sy bewering is GELDIG. O (6) F 2.3.1 Grants / Toelae RT 2RT correct item L1 (2) E * F 2.3.2 Amount in thousands / Bedrag in duisende L2 RT 1RT correct values E R340 688 – (R111 769 + R48 152) MA 1MA adding and subtracting = R180 767 CA 1CA simplification (3) * F 2.3.3 The amount is a deficit / Die bedrag is ‘n tekort. O L4 E OR/OF 2O opinion Indicates the amount is negative / Dui aan dat die bedrag negatief is. O (2) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 9 Downloaded from hlayiso.com Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 9 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L F 2.3.4 Net deficit / Netto verlies 1RT correct value L2 RT RT 1RT correct value E R313 792 – R322 891 A 1A subtraction in correct − R9 99 order (3) F 2.3.5 Net surplus/Netto surplus: L3 RT 1RT correct value M 2,53 317 582 Y  MA 100 1 1MA calculating surplus = R8 034,825 OR / OF R8 035 A 1A simplification Expenditure/Uitgawes: Z = R317 582 – R8 035 MA 1MA subtracting correct = R309 547 values OR/OF OR/OF 100% – 2,53% MA 1MA subtracting percentages = 97,47% A 1A simplification Expenditure / Uitgawes RT 1RT correct value 97,47 317 582 MA 1MA correct substitution  100 1 = R309 547,18  R309 547 (4) [40] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 10 Downloaded from hlayiso.com Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 10 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne QUESTION/VRAAG 3 [27 MARKS/PUNTE] Q/V Solution/Oplossing Explanation/Verduideliking T&L D 3.1.1 Male / Manlik RT 2RT correct option L1 (2) E * D 3.1.2 Difference / Verskil 1RT correct values L2 RT 1MA subtracting values E 2 ,5% − 11,1% MA 1CA simplification = 10,4% CA NPU (3) * D 3.1.3 The percentage of children in the under 5 year-category is L4 almost the same. / Die persentasie van kinders in die onder D 5 kategorie is amper dieselfde. O 2O comparison There is a greater increase in urban than in rural for the over 5 years to 17-category / Daar is 'n groter toename in stedelike as in landelike vir die bo 5 tot 17 jaar kategorie. O OR / OF Healthy food vs Junk food / Gesonde kos vs gemorskos. 1O comparison / comment More active vs Less active / Meer aktief vs Minder aktief. Walking long distances to school vs Driving to school / Stap lang afstande skool toe vs ry skool toe. Manual labour vs Playing video games / Handearbeid vs om videospeletjies te speel. O (3) Number of learners / Aantal leerders D 3.1.4 L2 16,3 795 M  100 1 MA 1MA percentage calculation = 130 learners / leerders A 1A simplification Accept: 129 Learners not overweight or obese / Leerders nie oorgewig of baie oorgewig nie = 795 – 130 = 665 learners/leerders CA 1CA simplification Accept: 666 OR/OF OR/OF Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 11 Downloaded from hlayiso.com Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 11 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L 3.1.4 Percentage / Persentasie 100% −16,3% = 83,7% A 1A finding the percentage Number of learners / Aantal leerders 83,7 795 1MA percentage calculation  MA 100 1 = 665 learners / leerders CA 1CA simplification (3) * P 3.1.5 Probability / Waarskynlikheid L3 M Overweight/Obese / Oorgewig/Baie oorgewig = 11,1% MA %− , % 1MA calculating percentage = 88,9% A 1A simplification 889 = 1 000 CA 1CA correct fraction (3) * D 3.2.1 17,9 inches / duim RT 2RT reading from chart L2 , 18 M (2) RT RT D 3.2.2 One month and 18 months 1RT correct age L2 Een maand en 18 maande 1RT correct age M (2) D 3.2.3 The other child fell in a higher percentile / Die ander kind L4 val onder ‘n hoër persentiel. A 2A correct conclusion M (2) D 3.3.1 75% RT 2RT correct interpretation L2 (2) M * MA 1MA calculating 50% D 3.3.2 5 29 RT 1RT finding 129 L3 D = 64,5 A 64 children, because the 65th child will fall on the median / 1A simplification 64 kinders ,want die 65ste kind val op die mediaan. (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 12 Downloaded from hlayiso.com Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 12 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L * D 3.3.3 Unfair sampling - Having sample population of 13 L4 malnourished and 129 normal was biased from the D beginning / Onregverdige steekproefneming - Die steekproefpopulasie van 13 ondervoede en 129 normaal was van die begin af bevooroordeeld. OR / OF O 2O correct explanation The sample was skewed towards the normal nutritional status. The representation might have been based on the prevalence of malnourished to normal status. Die steekproef neig meer na die normale voedingswaarde status. Die steekproef mag verteenwoordigend gewees het van wanvoeding tot normale status. (2) [27] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 13 Downloaded from hlayiso.com Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 13 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne QUESTION/VRAAG 4 [33 MARKS/PUNTE] Q/V Solution/Oplossing Explanation/Verduideliking T&L * D 4.1.1 No mode / Geen modus OR / OF None / Geen A 2A no mode L2 (2) E * D 4.1.2 7 A 2A number of items L1 (2) E * F 4.1.3 Amount for on-line / Bedrag vir aanlyn L2 E MA 1MA multiply by 2 = R 208,74 + (R15 × 2) 1A simplification = R238,74 A Amount saved / Bedrag gespaar RT RT correct value (R261,80) = R261,80 – R238,74 = R23,06 CA 1CA simplification OR / OF OR / OF Amount saved / Bedrag gespaar RT MA RT correct value (R261,80) = (R261,80 – R208,74) – (R15,00 × 2) 1MA multiply by 2 1A simplification A = R53,06 – R30 1CA simplification = R23,06 CA (4) * D 4.1.4 Median / Mediaan L2 M 11,95 12,99 13,95 14,99 15,95 15,95 18,95 20,99 22,95 23,99 27,95 29,95 A 1A arranging values RT 15,95  18,95 1RT two middle values  MA 2 1MA concept of median 34,90  2 = 17,45 CA 1CA simplification (4) P 4.1.5 Probability / Waarskynlikheid L3 E = 6 A OR / OF 1 OR / OF 0,5 OR / OF 50% 2A numerator 12 A 2 1A denominator AO (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 14 Downloaded from hlayiso.com Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 14 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L * F 4.2.1 Third lowest / Derde laagste L1 E = P&P store / winkel A 2A correct store (2) * F 4.2.2 Number of doughnuts / Aantal oliebolle L3 = 50 × 4 MA 1MA multiplying by 4 D = 200 A 1A number of doughnuts Cost of packets of doughnuts / Koste van pakkies oliebolle = R701 – R201 = R500 A 1A cost of packs of doughnuts Cost per doughnut / Koste per oliebol = R500 ÷ 200 MA 1MA dividing by 200 = R2,50 CA 1CA simplification FLM store / winkel A 1A correct store (6) A 1A disagree F 4.2.3 Disagree. The expenses is higher than the income / L4 O Stem nie saam nie. Die uitgawes is hoër as die inkomste. 2O reason M (3) * F 4.2.4 Lower / Laer A 1A lower L4 M Income higher, therefore the break-even point will be reached sooner / Inkomste verhoog, daarom sal die gelykbreekpunt vroeër bereik word. O 2O reason Cost will be covered sooner / Koste sal vroëer gedek word. (3) F 4.2.5 Percentage profit / Persentasie wins 1RT correct value from L2 RT RT graph M R2 000 - R1 201 RT correct value from % Profit / Wins   100% graph R1 201 SF 1SF correct substitution 1CA simplification = 66,53% CA NPR NPU AO (4) [33] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 15 Downloaded from hlayiso.com Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 15 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne QUESTION/VRAAG 5 [21 MARKS/PUNTE] Q/V Solution/Oplossing Explanation/Verduideliking T&L * D 5.1.1 Wizz Air Group / Groep RT 2RT correct aircraft group L2 (2) E * D 5.1.2 Percentage decrease / Persentasie vermindering L3 RT 1RT correct value (3 763) D 3 763  4 290 1A correct denominator A  100% 4 290 A 1A simplification 2,2 22 % A 1R correct rounding 2% R OR / OF OR / OF RT 3 763 % operated = 100% 1RT correct value (3 763) 4 290 1MA calculating % = 87,71561772% MA A = 87,71561772% 100% = 12,28438228% A 1A simplification = 12% R 1R correct rounding (4) D 5.1.3 Range / Omvang L2 RT RT 1RT correct value D % 5% 1RT correct value = 48% A 1A simplification (3) D 5.1.4 Value of B / Waarde van B L3 D 2 566 1 347  ....  B  547  536 1MA concept of mean 1 028,2  MA 10 MA 9 640  B 1MA adding values 1028,2  10 B = 1 028,2 × 10 – 9 640 MA 1MA changing the subject of B = 642 CA the formula 1CA simplification (4) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 16 Downloaded from hlayiso.com Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 16 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking P 5.1.5 Probability / Waarskynlikheid L3 E = 2 A 1A numerator 10 A 1A denominator = 0,2 CA 1CA simplification AO (3) * F 5.2.1 Stronger / Sterker A 2A stronger L1 (2) M F 5.2.2 $1 = NIS 3,66061 A 1A identifying correct L2 exchange rate M Amount / Bedrag 2 580 1MA multiplying with   3,66061 MA 1 exchange rate = NIS 9 444,37 A 1A simplification OR / OF OR / OF NIS 1 = $0,27317867 A 1A identifying correct exchange rate Amount / Bedrag 2 580   1 MA 1MA dividing with 0,27317867 exchange rate = NIS 9 444,37 A 1A simplification NPR AO (3) [21] TOTAL/TOTAAL: 150 Copyright reserved/Kopiereg voorbehou ## Related documents - [Mathematical Literacy P1 Nov 2022 MG Afr Eng](https://www.hlayiso.com/library/mathematical-literacy-p1-nov-2022-mg-afr-eng/50ffcd59-e73a-428f-8797-2b851fe7b383) — Mathematical Literacy · Memo · 2022 · Eng - [Mathematical Literacy P1 Nov 2020 Memo Afr Eng](https://www.hlayiso.com/library/mathematical-literacy-p1-nov-2020-memo-afr-eng/dc38c4a0-3539-4e44-96e2-8ed41da024dc) — Mathematical Literacy · Memo · 2020 · Eng - [Mathematical Literacy P1 Nov 2012 Memo Afr](https://www.hlayiso.com/library/mathematical-literacy-p1-nov-2012-memo-afr/120d5e75-0697-4f67-8d57-288ce36007ca) — Mathematical Literacy · Memo · 2012 · Afr - [MATHS LIT P1 GR12 QP JUNE 2023 Afrikaans](https://www.hlayiso.com/library/maths-lit-p1-gr12-qp-june-2023-afrikaans/2d599711-ccd3-42d3-862f-4c1b72b92e44) — Mathematical Literacy · QP · 2023 · Afr - [Mathematical Literacy P1 Nov 2022 Eng](https://www.hlayiso.com/library/mathematical-literacy-p1-nov-2022-eng/f60c7f64-6e7b-4ec5-bb87-d57373a691f5) — Mathematical Literacy · QP · 2022 · Eng - [Mathematical Literacy P1 Nov 2021 Addendum Afr](https://www.hlayiso.com/library/mathematical-literacy-p1-nov-2021-addendum-afr/7df99ec8-a07d-4bbf-8050-b43332aafdea) — Mathematical Literacy · Addendum · 2021 · Afr ## More from Grade 12 Mathematical Literacy - [MATHS LIT P2 GR 12 SEPT 2025 ADDENDUM AFR watermark](https://www.hlayiso.com/library/maths-lit-p2-gr-12-sept-2025-addendum-afr-watermark/813c6e54-f134-474a-b01a-1260e38b4c8f) — Addendum · 2025 · Afr - [Maths LIT Grade 12 NSC P1 QP September 2025 Free State](https://www.hlayiso.com/library/maths-lit-grade-12-nsc-p1-qp-september-2025-free-state/45f0ab2a-afdd-46df-bf98-5505c4021e64) — QP · 2025 - [Maths LIT Grade 12 NSC P1 ANSWER BOOK September 2025 KZN](https://www.hlayiso.com/library/maths-lit-grade-12-nsc-p1-answer-book-september-2025-kzn/b0b358eb-c897-437a-8694-910fe61dfcbc) — Addendum · 2025 - [Maths LIT Grade 12 NSC P1 QP September 2025 Limpopo](https://www.hlayiso.com/library/maths-lit-grade-12-nsc-p1-qp-september-2025-limpopo/c5d7a167-2d27-4e33-80ef-fad9cde4ebd2) — QP · 2025 - [Maths LIT Grade 12 NSC P2 QP September 2025 Limpopo](https://www.hlayiso.com/library/maths-lit-grade-12-nsc-p2-qp-september-2025-limpopo/f22349c1-8dbf-420e-ae8d-13d53bcb300b) — QP · 2025 - [Maths LIT Grade 12 NSC P2 QP September 2025 North West](https://www.hlayiso.com/library/maths-lit-grade-12-nsc-p2-qp-september-2025-north-west/7ce5b7fe-941b-4148-80dc-d9cde7bdbfd7) — QP · 2025 ## Collection - [Grade 12 past papers](https://www.hlayiso.com/grade-12/past-papers) --- Hlayiso: free CAPS and IEB past papers, memos, notes and study guides for South African learners. 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