# Mathematics Grade 10 Paper 1 North West June 2019 Memo

> Grade 10 Mathematics Paper 1 memorandum from the North West June 2019, 6 pages. Read online or get the free PDF download, question paper linked when available.

- Page: https://www.hlayiso.com/library/mathematics-gr-10-memo-paper-1/739ed530-604f-4de5-a765-e580c6ddf024
- Updated: 2026-09-27
- Subject: Mathematics
- Grade: Grade 10
- Document type: Memorandum
- Year: 2019
- Exam period: North West June
- Paper: 1
- Curriculum: CAPS
- Pages: 6

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## About this document

Mathematics · Grade 10 · North West June · 2019. Memorandum, 6 pages. Read online or download the PDF.

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## Document text

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### Page 1

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                          GRADE 10

                        MATHEMATICS PAPER 1

            MID YEAR EXAMINATION 2019 MEMORANDUM

MARKS: 75

                 This memorandum consists of 6 pages

                 Demo
                        NW/JUNE/MATH/ EMIS/6*******

### Page 2

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Mathematics Memo/P1                                            2                                    NW/June 2019
                                                            Grade 10

QUESTION 1[9]

1.1.1             2E
        v
                  m
                  2  132                                                       substitution
          
                    12
           22                                                                  answer
                                                                                                         (2)
1.1.2   irrational                                                              answer
                                                                                                         (1)
1.1.3     16  22  25
                                                                                 16  22  25
        4  22  5
                                                                                answer
         it lies between integers 4 and 5                                                               (2)

1.2           
        0,5 2  0,5222222222..
                       
        let x  0,5 2
                       
        10x  5, 2                       (1)                            equation 1
                                                                               equation 2
        100x  52, 2        (2)
        equation (2) - (1)
                                                                                 90x  47
        90x  47
              47                                                                answer
        x 
              92                                                                                         (4)

QUESTION 2[18]

2.1.1   a 2  2a  ax  2 x  a(a  2)  x(a  2)                                   a (a  2)
                             (a  2)(a  x)                                         x ( a  2)
                                                                                   answer
                                                                                                          (3)
2.1.2    x  27
              3
                     ( x  3)( x  3 x  9)   2                                    factors
                   
        x  3x  9
          2
                          x 2  3x  9
                                                                                   answer
                    x3
                                                                                                          (3)
2.2.1   (2 y  3)(6 y  4 y  8)
                           2

         2 y (6 y 2  4 y  8)  3(6 y 2  4 y  8)
                                                                                   12 y 3  8 y 2  16 y
         12 y  8 y  16 y  18 y  12 y  24
                  3        2                      2
                                                                                     18 y 2  12 y  24
         12 y 3  10 y 2  28 y  24                                              answer
                                                                                                          (3)

                                       Demo
                                                  NW/JUNE/MATH/ EMIS/6*******

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Mathematics Memo/P1                                      3                          NW/June 2019
                                                      Grade 10

2.2.2   2 2 n  4 n  2 2 2 n 2 2 n .2                                 changing 4 n to 2 2 n
                                                                      changing
              16 n          2 4n
                                                                       16 n to 2 4 n
                         2 4n 2
                        4n
                         2
                       2                                              answer
                                                                                             (3)
2.2.3   3x  7 x  6 x 3x  2 x x(3x  7 x  6) x(3x  2)
           3       2               2              2
                                                                        x(3x  7 x  6)
                                                                              2
                                                 
           x2  9       3x  9    ( x  3)( x  3)   3( x  3)          ( x  3)( x  3)
                                 x(3x  2)( x  3) 3( x  3)            x(3 x  2)
                                                                      3( x  3)
                                  ( x  3)( x  3)   x(3x  2)
                                                                        (3 x  2)( x  3)
                               3
                                                                       answer
                                                                                             (6)

QUESTION 3[17]

3.1.1   9 x  4  5(2 x  3)
        9 x  4  10x  15
                                                                       removing brackets
        9 x  10x  4  15
        18x  18                                                       adding like terms
        x 1                                                          answer
                                                                                                (3)
3.1.2          1
        4x 
              256
               1
        2 2x  8                                                       expressing both 4
               2                                                       and 256 as the base of
        2  2 8
          2x
                                                                       2
         2 x  8
                                                                       answer
         x  4
                                                                                                (2)
3.2     10  x  4  12
        10  4  x  12  4                                            transposing 4
                                                                       critical values
        6 x8                                                         notation
                                                                       graphical
                                                                       representation
                         6                                   8                                  (4)

                                Demo
                                         NW/JUNE/MATH/ EMIS/6*******

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Mathematics Memo/P1                                 4                               NW/June 2019
                                                 Grade 10

3.3     A   R2   r 2                                              r 2 subj. of formula
                                                                      r subj. of formula
        A  R 2  r 2
                                                                     NB: DO NOT
        A  R 2                                                     PANELISE IF WRITE
                  r2
                                                                             A
                                                                      R2 
        r  R 2 
                     A                                                          
                                                                                          (2)
3.4.1   x  9 y  99
          2       2

                                                                     factors
        ( x  3 y )( x  3 y )  99
                          99                                         answer
         x  3y 
                        x  3y                                                             (2)
3.4.2               99
        x  3y 
                  x  3y
                                                                     substituting 3
                  99
        x  3y 
                   3
        x  3 y  33    equation1
        x  3 y  3    equation2
                                                                      2x  36
        2 x  36
         x  18                                                      value of x
        18  3 y  33
        3 y  15
                                                                      value of y
        y 5                                                                              (4)
QUESTION 4[10]

4.1.1    11;  16                                                   each term
                                                                                           (2)
4.1.2   Pattern is linear, Tn  dn  c
        To solve for c , substitute n  1 and T1  4
                                                                     substitution
        4  5(1)  c
        c  9                                                        value of c
         Tn  5n  9                                               answer
                                                                                           (3)
4.1.3    Tn  5n  9
        T27  5(27)  9                                             substitution
                                                                     answer
               126                                                                       (2)
4.1.3          Tn  5n  9
               71  5n  9                                         substitution
               5n  80
                   n  16                                           answer
                                                                                           (2)
4.2     111111X111111                                                answer
                                                                                           (1)

                                Demo
                                       NW/JUNE/MATH/ EMIS/6*******

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Mathematics Memo/P1                              5                      NW/June 2019
                                              Grade 10

QUESTION 5[10]

5.1   y  1                                                       answer
                                                                                   (1)
5.2                                                               Parabola

                                                                  x – intercepts
                                                                  Turning point
                                                                  concave up

                                                                  Exponential

                                                                  intercepts at
                                                                  (0;0)
                                                                  asymptote
                                                                  increasing
                                                                  function
                                                                                   (6)

5.3   y  1
      OR                                                          answer
                                                                                   (1)
      y  (1; )
5.4   reflection about the x axis                                 reflection
                                                                  x axis
                                                                                   (2)

                           Demo
                                    NW/JUNE/MATH/ EMIS/6*******

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Mathematics Memo/P1                              6                           NW/June 2019
                                              Grade 10

QUESTION 6[11]

6.1          y 2  y1
        m                                                        formula
             x 2  x1
          1 4                                                   substitution
        
           3 2
         1                                                      -1
        y  mx  c
        4  1(2)  c
        c  2
         y  x  2                                              equation
         a  1 q  2
                                                                                      (4)
6.2   h( x )  p ( x )
        2                                                         equating
        1  x  2
         x
        2
        x  1
         x
       2  x 2  x
                                                                  standard form
      x2  x  2  0
                                                                  factors
      ( x  2)( x  1)  0
       x  2 or x  1                                           both values of x
                                                                                      (4)
6.3    1  x  0 or     x2                                       end points
                                                                  notation for
                                                                  1 x  0
                                                                  x2
                                                                                      (3)

                             Demo
                                    NW/JUNE/MATH/ EMIS/6*******

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