# Mathematics Grade 10 Paper 2 North West June 2018 Memo

> Grade 10 Mathematics Paper 2 memorandum from the North West June 2018, 7 pages. Read online or get the free PDF download, question paper linked when available.

- Page: https://www.hlayiso.com/library/mathematics-gr-10-memo-paper-2-1/9a4d1e07-7e7a-45c2-af18-f32bab508dd9
- Updated: 2026-09-27
- Subject: Mathematics
- Grade: Grade 10
- Document type: Memorandum
- Year: 2018
- Exam period: North West June
- Paper: 2
- Curriculum: CAPS
- Pages: 7

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## About this document

Mathematics · Grade 10 · North West June · 2018. Memorandum, 7 pages. Read online or download the PDF.

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## Document text

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### Page 1

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                             GRADE 10

                       MATHEMATICS PAPER2

                MID – YEAR EXAMINATION 2018

                            MEMORANDUM

MARKS: 75

                This memorandum consists of 7 pages

                Demo
                       NW/JUNE/MATH/ EMIS/6*******

### Page 2

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Mathematics memo/P2                           2                        NW/June 2018
                                           Grade10
QUESTION 1
1.1     sin  sec 
         sin 47,5  sec 50,3
                                                                            substitution
                           1
         sin 47,5  
                       cos 50,3                                                  1
         2.30                                                             
                                                                               cos50,3
        ANSWER ONLY: Full marks
                                                                            answer
                                                                                               (3)
1.2.1   2 sin x  2
        sin x  1                                                           division by 2
                                                                            answer
        x  90                                                                                (2)
1.2.2   cos ( x  11)  1  1,79
        cos ( x  11)  0,79                                             transposing
        x  11  37,8144                                                  simplification
                                                                            answer
        x  48,81
                                                                                               (3)
1.3.1    24  tan 45
                   2
                                                                           1
         24  1                                                            answer
        5                                                                                     (2)
1.3.2                           
        sin 60 .sec 60 . cot 30
                 sin 45                                                   
                                                                                3
          3                                                                    2
            . 2. 3                                                         2
         2
               2                                                            3
              2                                                               1      2
                                                                                or
         6                                                                     2    2
          3                                                                 answer
                                                                                               (5)

                                                                                              [15]

                                  Demo
                                         NW/JUNE/MATH/ EMIS/6*******

### Page 3

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Mathematics memo/P2                               3                        NW/June 2018
                                               Grade10
QUESTION 2

2.1

                                 13
                        12
                                         θ

                             -5                                                correct quad
                                                                               r = 13

                                                                                  5
                                                                              
                                                                                  13

        cos  sin                                                               12
                                                                              
           5 12                                                                  13
            
          13 13
           17
                                                                             answer
           13
                                                                                                   (5)

2.2                 Q
                                                               P
                                                     36

                             S
                     R
2.2.1                   PS
        cos 36                                                                answer
                        PQ

                                                                                answer
                        PQ
        cos 36                                                                                   (2)
                        PR
2.2.2              QS
        tan 36                                                                ratio
                   PS
                  QS                                                           subs of 9,5
        tan 36 
                  9 .5
                                                                                simplification
        QS  9,5 tan 36
        QS  6,9cm                                                              answer
                                                                                                   (4)
2.2.3               SP                                                          answer
        sin 54                                                                                   (1)
                    QP
                                                                                                  [12]

                                  Demo
                                             NW/JUNE/MATH/ EMIS/6*******

### Page 4

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Mathematics memo/P2                     4                        NW/June 2018
                                     Grade10
QUESTION 3

3.1             opp
        sin                                                         ratio
                hyp
                                                                      Substitution
                 122
        sin  
                1200                                                  Answer
              
         6

        Answer only: full marks                                                        (3)

3.2.1             QT
        cos 15                                                      substitution into
                   72
        Q T  72 cos15                                              the correct ratio
                                                                      simplification
        QT  69,55cm
                                                                      answer
                                                                                       (3)
3.2.2            QT                                                   substitution into
        cos35 
                 TR                                                  the correct ratio
              69,55                                                   simplification
        TR                                                           answer
             cos35
        TR  84,90 cm                                                                  (3)

                                                                                       [9]

                            Demo
                                   NW/JUNE/MATH/ EMIS/6*******

### Page 5

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Mathematics memo/P2                5                        NW/June 2018
                                Grade10

QUESTION 4
4.1

                                                                f
                                                                 y – intercept

                                                                 x – intercept

                                                                 shape

                                                                g

                                                                 y – intercept

                                                                 x – intercept

                                                                 shape

                                                                                    6
4.2   0 0  x  3600                                             notation
                                                                 end points
                                                                                    2
4.3   y  0; 2                                                 notation
                                                                end points
      OR

      0 y  2                                                                      2

                                                                                  [10]

                       Demo
                              NW/JUNE/MATH/ EMIS/6*******

### Page 6

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 Mathematics memo/P2                            6                        NW/June 2018
                                             Grade10
 QUESTION 5

5.1     Lˆ  Mˆ                      (s opp  sides)                       R
                                                                            SR
        Lˆ  Mˆ  2 x  1800        ( of s of a Δ)
        2M  2 x  180  0

        Mˆ  900  x                                                         value of M̂

        6 x  900  x  1800        (co  int s PQ KM )                    SR
        5 x  900
        x  180                                                              answer
                                                                                                  (7)

5.2

5.2.1   EGˆ F  x              (s opp  sides / EF  EG)                    S R
                                                                                                  (2)

5.2.2   GEˆ D  GDˆ E  2 x (Ext  of a ∆ FEˆ G )                             value of FEˆ G
        Fˆ  Dˆ  DGˆ H     (Ext  of a ∆ DGˆ F )                            SR
        x  2 x  75                                                        substitution
        x  25
                                                                              answer (5)       [14]

                                    Demo
                                           NW/JUNE/MATH/ EMIS/6*******

### Page 7

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 Mathematics memo/P2                        7                       NW/June 2018
                                         Grade10
 QUESTION 6

6.1

6.1.1   DOC and BOA
        OC  OA (given)                                                  S/R
                                                                        SR
        DCˆO  BXˆO    (alter...s)                                      S/R
      DOˆ C  BOˆ A      (vert....opp)                                  S/R
       DOC  BOA           ( AAS )                                    conclusion
       AB  DC                                                                               (6)
6.1.2 OD = OB ( DOC  BOA)                                             S R
      Diagonals bisect each other                                                            (2)

7.2     PQ 2  PT 2  QT 2                                                Pythagoras
                                                                          substitution
        10  8  QT
          2    2      2

        QT 2  100  64
        QT  36                                                           QT  6
        QT  6
        TS  21  6                                                       TS  15
        TS  15
        PS 2  TS 2  PT 2
        PS 2  152  82                                                   PS  17
        PS  289                                                         substitution
        PS  17
         Perimeter  2(10)  2(17)
                                                                          answer         (7)
                                                                                             [15]
                     54cm

                               Demo
                                      NW/JUNE/MATH/ EMIS/6*******

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