# Mathematics Grade 11 Paper 1 North West June 2018 Memo

> Grade 11 Mathematics Paper 1 memorandum from the North West June 2018, 8 pages. Read online or get the free PDF download, question paper linked when available.

- Page: https://www.hlayiso.com/library/mathematics-gr-11-memo-eng-afr-p1-v1/b70b16b3-6725-45d1-b763-0f44c942ad0f
- Updated: 2026-09-27
- Subject: Mathematics
- Grade: Grade 11
- Document type: Memorandum
- Year: 2018
- Exam period: North West June
- Paper: 1
- Curriculum: CAPS
- Pages: 8

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## About this document

Mathematics · Grade 11 · North West June · 2018. Memorandum, 8 pages. Read online or download the PDF.

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### Page 1

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                                        GRADE/GRAAD 11

                 MATHEMATICS P1/WISKUNDE V1 MEMORANDUM

                             MID –YEAR EXAMINATION 2018/
                               HALF-JAAR EKSAMEN 2018

MARKS: 100
PUNTE: 100

                             Demo
                                    NW/JUNE/MATH/ EMIS/6*******

                            This memorandum consists of 8 pages.
                         Hierdie memorandum bestaan uit 8 blabsye.

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### Page 2

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Mathematics/P1/Wiskunde/V1                                   2                                 June/Junie2018
                                                          NSC/NSS

QUESTION/VRAAG 1

1.1.1         ( 3x –1 )( x + 3 ) = 0                                                Equating to 0 /
                                                                                   Gelykstelling aan 0
                       1
                x =           or/of      x = –3
                       3                                                            Both Answers /
                                                                                   Beide antwoorde                     (2)

1.1.2.              ( 3x –1 )( x + 3 ) = – 5
                    3x2 + 8x + 2 = 0                                               3x2 + 8x + 2 = 0

                            b  b 2  4ac                                          formula/formule
                    x
                                 2a                                                sub. into correct formula/
                                                                                   invervanging in korrekte
                            (8)  (8) 2  4(3)(2)
                    x                                                             formule
                                        2(3)
                                                                                             8  40
                          8  40                                                  x 
                      x                                                                        6
                             6
                                                                                   answers/antwoorde                  (5)
                           x = – 0,28 or/of x = – 2,39

1.2.1             x 2  x  4
                      x 2  4  x                                                         1 x  4  x
                    x + 2 = 16 – 8x + x        2

                     x2 – 9x + 14 = 0                                               squaring/kwadrering
                    (x – 7 )( x – 2 ) = 0
                                                                                   standard form/standaard
                    x = 7 N/A/ N.V.T or/of x = 2
                                                                                   vorm

                                                                                   factors/faktore

                                                                                   answer/antwoord                    (5)

1.2.2                                   2
                    4( x 2  x)           7
                                      x x
                                        2

                    Let/Laat             x2 – x = k                                   x2 -x = k
                                         2                                         std form in k /stdvorm in k
                               4k         7
                                         k
                                                                                   factors/faktore
                    4k – 7k – 2
                       2
                                         = 0

                    ( 4k + 1 )(k – 2 ) = 0
                                                                                   vales of k/waardes van k

                                        Demo

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Mathematics/P1/Wiskunde/V1                                  3                                    June/Junie2018
                                                         NSC/NSS

                               1
                     k =              or / of      k =2
                               4

                                   1
                     x2  x =             or / of x 2  x = 2                        2 eqs. in x/2 vgl’s in x
                                   4

                    4x2 – 4x + 1 = 0             or/of     x2 – x – 2 = 0
                                                                                      3 values of x/
                    (2x – 1) (2x – 1) = 0            or/of (x – 2)(x + 1) = 0        3 waardes van x                (7)
                               1
                          x=       or / of x = 2 or / of x =  1
                               2

1.2.3               3x  2  3x 1  28
                                  
                    3x 3 2  31  28                                                 taking CF outside/
                        28                                                         faktorisering van GF
                    3x    28
                        9                                                           simplification/
                    3 9
                      x                                                              vereenvoudiging

                    3x  32                                                          3x = 9
                     x  2                                                            answer/antwoord                    (4)

1.2.4               x 2  4x                                                          x 2  4x  0

                    x 2  4x  0                                                      factors/faktore
                                                                       -             end values/kritieke waardes
                     x ( x  4)  0                             0              4

                    0  x 4                                                         notation/notasie                    (4)

1.3                       x – 3 – y = 0 and/en x y = – 2

                    x = y+3                                                           x = y+3

                    (y + 3) y = – 2                                                  sub. of/inverv van x
                    y2 +3y + 2 = 0                                                   std form/std vorm
                    (y + 2)( y +1) = 0
                                                                                     factors/faktore
                    y = – 2 or/of y = – 1
                                                                                      y values/y-waardes
                    x = – 2 + 3 = 1 or/of x = – 1 + 3 = 2
                                                                                     x values/x-waardes                 (7)

                                        Demo

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Mathematics/P1/Wiskunde/V1                                    4                                   June/Junie2018
                                                           NSC/NSS

QUESTION/VRAAG 2

2.1
               x  3  18  2a 2
                                                                                      0
               For equal roots/Vir gelyke wortels,   0
                                                                                     18  2a 2  0
                             18  2a 2  0
                                   a2  9
                                   a  3                                           a   3                            (3)

2.2.1          ( a + 3 )2 + 12
                                                                                     0
               ( a + 3 )2 is always positive /is altyd positief                      Roots are real/
                                                                                    Wortels is reëel                    (2)
               ( a + 3 )2 + 12 will also positive/sal altyd positief wees

               Roots are real / Wortels is reëel

2.2.3           – 4( a – b )2< 0                                                     – 4( a – b )2< 0
                Roots are non-real / Wortels in nie-reëel                            Roots are non-real /
                                                                                    Wortels is nie-reëel   (2)
                                                                                    NB: Accept Irrational/
                                                                                    Aanvaar Irrasionaal

QUESTION/VRAAG 3

3.1.1          3 a .9 a 1        3a .32( a 1)
           4                 =4                                                            3a .32( a 1)
                27 a  2           33( a  2)                                        4
                                                                                            33( a  2)
                             = 4 33a 2 3a 6
                                                                                     4 33a 2 3a 6
                             = 4 3 4
                                                                                    answer / antwoord                   (3)
                               1
                             =
                               3

3.1.2      2 x 3  3.2 x 1 2 x (8  3.2 1 )                                       taking common factor
                            =
                 2x2            2 x . 2 2                                         outside / faktorisering
                                                                                    gemeensk faktor
                                             3
                                      8                                                      3
                                  =          2                                          8
                                         1                                                   2
                                                                                          1
                                         4
                                                                                          4
                                   = 26
                                                                                    answer/antwoord                     (3)

                                             Demo

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Mathematics/P1/Wiskunde/V1                                 5                                 June/Junie2018
                                                        NSC/NSS

3.2         10 x 3 = 10x . 103                                                   10x .103

                    = 1,7 x 1000

                    = 1700                                                       answer/antwoord                     (2)

3.3          2. 9a  3. 2b = 2.32a  3. 2b                                      32a

                               = 2.(p)2+ 3.(q)-1                                  sub of p and q./
                                                                                 Invervanging van p en q
                                             3
                               = 2 p2                                                       3
                                             q                                    2 p2                             (3)
                                                                                             q

QUESTON/VRAAG 4

4.1       4 ;       9 ;     x ;         37

                                                                                  correct first differences/
            5       x-9         37- x
                                                                                 korrekte eerste verskille

             x - 14        46- 2x                                                 second differences /
                                                                                 tweede verskille

          x – 14 = 46 – 2x
                                                                                 answer / antwoord                  (3)
           x = 20
4.2
                               3a  b  5             abc  4
           2a  6                                                                 value of/waarde van a
                               33  b  5            3  (4)  c  4
           a3                                                                   value of/waarde van b
                               b  4                 c5                        value of/waarde van c

          Tn  an2  bn  c                                                       answer/antwoord                    (4)
               3n  4n  5
4.3        3n – 4n + 5 = 212
             2
                                                                                  equating to 212 /
                                                                                 gelykstelling aan 212
          3n2 – 4n - 207 = 0
                                                                                  standard form/std vorm
                              4 ± 16  4(3)(207)
                          n=
                                         6                                        values of/waardes van n
                                           23
                             = 9 or / of
                                            3
                n = 9                                                             answer/antwoord                   (4)

                                        Demo

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Mathematics/P1/Wiskunde/V1                               6                                 June/Junie2018
                                                      NSC/NSS

QUESTION/VRAAG 5

5.1.1                                        𝑖 𝑚
                                  𝑖𝑒𝑓𝑓 = (1 + ) − 1                             formula/formule
                                             𝑚
                                  12                                           correct sub. into formula/
                   0,075 
                = 1                  1                                     korrekte inverv. in formule
                      12 

                = 0,07763259...

          Rate/Koers = 7,76%                                                   answer /antwoord                   (3)

5.1.2
           A  P(1  i )n                                                      formula/formule
                      0,075  412
              1200001                                                      sub. into the formula/
                          12                                                 inverv. in formule
             = R 161831,90                                                     answer/antwoord                    (3)
5.2
           A  P( 1 i )n                                                      formula/formule

              = 80000(1– 0,12)3
                                                                               sub. into the formula/
             = R54517,76                                                       inverv. in formule
                                                                               answer/antwoord                    (3)
5.3
                   0,12 12    0,14 4                                              0,12 
                                                                                                12
           x(1        ) (1      )  95000                                     1    
                     4          6                                                    4 
                         12               4
             0,12   0,14                                                      0,14 
                                                                                                4
           x1      1        95000                                        1 
                 4        2                                                          
                                                                                     2 
           x1,868881682  95000                                               equating to/gelykstelling
           x  R50832,54                                                       aan 95000
                                                                                1,868881682
                                                                               answer/antwoord           (5)

QUESTION/VRAAG 6
6.1
                a
      g ( x)      6
               x2
                                                                                value of/waarde van p
                   a                                                            value of/waarde van q
           0           6                                                      value of/waarde van a
                5
                  2                                                            equation/vergelyking
                2                                                                                                  (4)
            a  3

                                        Demo

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Mathematics/P1/Wiskunde/V1                               7                                 June/Junie2018
                                                      NSC/NSS

                   3
            g ( x)     6
                  x2
6.2        x R , x  2
                                                                                answer/antwoord                     (1)
6.3
                       5                                                        end points/kritieke waardes
           2 x 
                       2
                                                                                correct notation/korrekte
                                                                               notasie                   (2)

6.4          3                                                               x coordinate/koördinaat
           F  ; 12                                                           y coordinate/koördinaat
             2     
                                                                                                                     (2)
QUESTION/VRAAG 7

7.1.1      y =–4
                                                                                           y =–4

7.1.2
              f ( x)  2 x 1  4
                                                                                           making/maak
                                                                                           y=0
              0  2x 1  4
           2 x 1  22                                                                      22
               x = 3                                                                       x=3

               (3 ; 0)

                                                                                                               (3)
7.1.3    y- intercept /y-afsnit                                                            y-int/y-afsnit
                                        7
         y = y  20  1  4 
                                         2

                                                                                           x-int/x-afsnit

                                                                                            shape(increasing)/
                                                                                           vorm(stygend)

                                                                                            asymptote /
                                                                                           asimptote               (4)

                                        Demo

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Mathematics/P1/Wiskunde/V1                                 8                               June/Junie2018
                                                        NSC/NSS

7.1.4    Range/Waardeversameling is y   4                                                answer/antwoord
                                                                                                         (1)
7.1.5     m  21  1  4   3
                                                                                           answer/antwoord
                                                                                                         (1)

7.2

                                                    y                                      shape(concave up)/
                                                                                           vorm(konkaaf op)

                                                                                            x-intercepts (one
                                                                                           +ve and one –ve)/
                                                                                           x-afsnitte ( een
                                                                                           +tiewe en een -
                                                                      x                    tiewe)

                                                                                            -ve y-intercept/
                                                                                           -tiewe y-afsnit

                                                                                           -ve axis of
                                                                                           symmetry /
                                                                                           -tiewe simmetrie-as
                                                                                                            (4)

                                        Demo

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