# Mathematics Grade 11 Paper 2 North West June 2018 Memo

> Grade 11 Mathematics Paper 2 memorandum from the North West June 2018, 10 pages. Read online or get the free PDF download, question paper linked when available.

- Page: https://www.hlayiso.com/library/mathematics-gr-11-memo-eng-afr-p2-v2/d83957f1-ef33-43d2-87b1-a1d8cd69f64d
- Updated: 2026-09-27
- Subject: Mathematics
- Grade: Grade 11
- Document type: Memorandum
- Year: 2018
- Exam period: North West June
- Paper: 2
- Curriculum: CAPS
- Pages: 10

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## About this document

Mathematics · Grade 11 · North West June · 2018. Memorandum, 10 pages. Read online or download the PDF.

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## Document text

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### Page 1

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                                  NATIONAL
                             SENIOR CERTIFICATE

                                GRADE/GRAAD 11

                         MATHEMATICS P2 (MEMO)/
                                WISKUNDE V2 (MEMO)
                           MID YEAR EXAMINATION/
                          HALF-JAAR EKSAMEN 2018

MARKS/PUNTE: 100

                                JUNE EXAMINATION 2012
This markingguidelines consists of 10 pages./Die merkriglyne bestaan uit 10 bladsye.

                         Demo
                                 NW/JUNE/MATH/ EMIS/6*******

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Mathematics/ P2/WISKUNDE/V2Half-jaar EksamenMid-Year Examination                                    NW/ Jun 2018
                                  NSC- Grade 11

QUESTION/VRAAG 1

1.1.1                                                          (2)
        mAB  mBC
        0 1 p  0
             
        2 1 5  2
        1 p
                                                                            1 p
                                                                               
        3 3
                                                                            3 3
        p 1                                                                answer/antw
1.1.2   mAB  mBC  1                                         (3)          setting an equation/vergelyking
        1  0 p  0
                     1
        1  2 5  2                                                         simplification/vereendiging
        1 p
            1
        3 3
        p                                                                    answer/antw
            1
        9
        p  9
1.1.3    x2  x1    y2  y1   d 2                        (3)
                 2              2

                                                                            substitution/substitusie
         5  2    p  0   52
                 2           2

                                                                            simplification/vereenvoudig
        9  p 2  25
        p   25  9                                                        both answers/beide antw
          4
1.2
                                                                         S  x; y
                                                      y

                        P  4;5

                                                          M  2; 2 
                                                                     Q  4;1           x
                                                  O

                                      R  1;  4 

                               Demo
                                          NW/JUNE/MATH/ EMIS/6*******            2

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Mathematics/ P2/WISKUNDE/V2Half-jaar EksamenMid-Year Examination                                NW/ Jun 2018
                                  NSC- Grade 11

1.2.1          5 1                                                  (2)
        mPQ                                                                 substitution/substitusie
              4  4
               1
                                                                           answer/antw
               2
1.2.2         4  2                                                 (3)
        mRM 
              1  2                                                         2
           2
                                                                               1
                      1
      mPQ  mRM    2                                                        2
                      2                                                       2
                  1                                                        1
       PM  RS
1.2.3  x1  x2 y1  y2                                            (3)
              ;        
       2          2 
         1  x 4  y 
               ;        
         2         2 
      1  x           4  y
              2               2                                            setting equations/verg
         2                 2
      1  x  4        4 y  4
                                                                             x5
      x5                   y 8                                             y 8
1.2.4                                                               (3)
                                                                             Substitution/substitusie
                   1  4    4  1
                               2                2
         RQ 
                50
               5 2                                                          RQ  50 or 5 2

                   5  4   8  1
                           2              2
         SQ 
                50
                                                                             SQ  50 or 5 2
           5 2
         QRS is isosceles
1.2.5                                                               (5)
                 4  4    5  1
                           2              2
        PM 
           4 5                                                              PM  4 5
                 5  1  8  4 
                       2              2
        RS 
          6 5                                                               RS  6 5
                    1
        Area PRS   base  height                                          Formula/form
                    2
                    1                                                        Substitution/substitusie
                   6 54 5
                    2                                                        Answer/antw
                  60 unit 2
                                                                    [24]

                                   Demo
                                              NW/JUNE/MATH/ EMIS/6*******   3

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   Mathematics/ P2/WISKUNDE/V2Half-jaar EksamenMid-Year Examination                             NW/ Jun 2018
                                     NSC- Grade 11

   QUESTION/VRAAG 2

                                                                        (3)
         17 sin   15  0
                 15
         sin  
                 17

                                     17
                          15
                                                                                  correct
                                                                                    sketch/korrekte
                                                                                    sket

         x2  y 2  r 2
         x 2  152  17 2
         x   17 2  152
           8
         Ans : x  8                                                              8

                     15
         tan   
                      8                                                            Answer/antw
2.1.2                                                                   (2)
         cos   180    cos                                                   cos 
                                  8 
                              
                                  17 
                               8                                                   Answer/antw
                            
                              17
2.2.1                                                                   (2)
         tan 70  p

         tan110  tan 180  70 
                    tan 70                                                       tan 70
                                                                                   Answer/antw
                   p

                                   Demo
                                          NW/JUNE/MATH/ EMIS/6*******         4

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Mathematics/ P2/WISKUNDE/V2Half-jaar EksamenMid-Year Examination                                        NW/ Jun 2018
                                  NSC- Grade 11

2.2.2                                                                        (3)
          r x y
           2        2      2

          r 2  p 2  12
          r  1  p2                                                                         1  p2
                                                                                        
          sin 290  sin  360  70 
                          sin 70                                                       sin 70
                                p                                                        Answer/antw
                        
                              1  p2
2.3                                                                          (6)
           sin150.tan 225
          sin  30  .sin 420
               sin 180  30  .tan 180  45                                          sin30
                                                                                       
                    sin 30.sin  360  60                                             tan 45
                                                                                             sin 30
          
                 sin 30  tan 45                                                   
                                                                                            sin 60
                                                                                        
                 sin 30  sin 60 
              1
                1                                                                    correct
            
               2
                                                                                          substitution/korrek
            1  3                                                                      te subs
                  
            2  2 
                  2
          
                   3                                                                     answer/antw
                                                                             [16]
QUESTION /VRAAG3

3.                                                                      (8
1        cos 390                                                       )              cos30
                       tan  360  x  .cos 180  x  .cos  x  90                tan x
        cos(30)                                                                   
                                                                                        cos x
          cos 30
                      tan x   cos x  sin x                                 sin x
          cos 30                                                                     cos30
                                                                                    
               sin x 
                            cos x  sin x 
         1                                                                          sin x
                                                                                      
               cos x                                                                 cos x
         1  sin 2 x                                                                Simplification/vereenv..
                                                                                     Answer/antw
         cos 2 x

                                       Demo
                                              NW/JUNE/MATH/ EMIS/6*******           5

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Mathematics/ P2/WISKUNDE/V2Half-jaar EksamenMid-Year Examination                               NW/ Jun 2018
                                  NSC- Grade 11

3.2                                                             (6)
                          2
                cos x.tan x
      LHS                       cos x
                     1
                          1
                  cos x
                 sin 2 x 
        cos x                                                            sin 2 x
                 cos 2 x                                                     2
                             cos x                                      cos x
            1  cos x
              cos x                                                        1  cos x
         sin x  cos x
              2
                                                                            cos x
                               cos x
         cos   x     1  cos  x
          sin 2 x                                                         Simplification/vereenv..
                   cos x
        1  cos x
        1  cos 2 x                                                       1  cos x
                                                                                  2
                     cos x
         1  cos x

      
        1  cos x 1  cos x   cos x                                  Factoring/fakt..
                1  cos x
       1  cos x  cos x                                                 Simplification/vereenv...
      1
       LHS=RHS
3.3                                                             (6)
                      4
      6 cos x  5 
                    cos x
                                                                          std form/std vorm
      6 cos x  5cos x  4  0
           2
                                                                          factors/faktore
       3cos x  4  2 cos x  1  0
                4                      1                                  values of cos x /waarde van
      cos x        or cos x  
                3                      2
               1                                                          selection of answer/antw
      cos x  
                2                                                         answer/antw
      x  120  360.k ; k 
      OR                                                                  k Z
      x  120  360.k    or 240  360.k
                                                                [20]

                                Demo
                                           NW/JUNE/MATH/ EMIS/6*******    6

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Mathematics/ P2/WISKUNDE/V2Half-jaar EksamenMid-Year Examination                 NW/ Jun 2018
                                  NSC- Grade 11

QUESTION/VRAAG 4

        Statement (S)               Reason (R)
4.2.1                                                            (2)
         ˆ  DEC
        BCA   ˆ  26               equal chords; equal s               S
                                                                         R
4.2.2                                                            (2)
        Â1  53                    at centre  2   at               S
                                    circumference
                                                                         R
4.2.3        ˆ  180
        D̂  A                      opp s quad supp             (6)     S
              1
                                                                         R
        D̂  180  53  127
                                                                         127
        Ĉ4  26  127  180
                                    sum of s in                        S/ R
        Ĉ4  27
        2Cˆ  180  106
           3
                                     s opp equal sides                  S/ R
        Ĉ3  37
        OCDˆ  37  27                                                 Answer/antw
                                    construction
         64
                                                                 [10]

                            Demo
                                   NW/JUNE/MATH/ EMIS/6*******     7

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Mathematics/ P2/WISKUNDE/V2Half-jaar EksamenMid-Year Examination                  NW/ Jun 2018
                                  NSC- Grade 11

QUESTION/VRAAG 5

5.1                                                              (1)    Answer/antw
       90 or right 

5.2

Complete the proof:

                           ˆ  PBM
      Required to proof : MPT   ˆ

        Construction: Draw diameter PA and join AM

       Statement (S)                Reason (R)
5.2                                                              (5)
         ˆ  90
       PMA                            in semi-circle                     S/ R
       ˆ  Pˆ  180  90  90     s in                               S/ R
       A     1                                                            S/ R
         ˆ  ˆP  90
       MPT                          tangent  diameter/ radius            S
                1
          ˆ A
        MPT   ˆ
                                                                        S/ R
        ˆ    ˆ
       PBM  A                       s in same segment
          ˆ  PBM
        MPT    ˆ

                           Demo
                                   NW/JUNE/MATH/ EMIS/6*******     8

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Mathematics/ P2/WISKUNDE/V2Half-jaar EksamenMid-Year Examination                                         NW/ Jun 2018
                                  NSC- Grade 11

OR

        Statement (S)                                       Reason (R)
5.2       ˆ  90
        APT                                                 chord  tan                 (5)
                                                                                                 S/ R
        MPT  90  Pˆ1
           ˆ
        PMA  90                                                                                S
                                                            diameter subtends right 
        ˆ
        A  90  ˆP1                                                                            S/ R
          ˆ
        PBM  A ˆ
                                                            s in same segment                   S
           ˆ  PBM
         MPT   ˆ
                                                                                                 S/ R
5.3

                                            M
         A
                      1
              2
              x                                         1           B
                              1
                                                        2       4
                          C       2                         3

                                       1
                                  S4        2
                                       3
                                                                                                         Q
                                                    2
                                                            3
              1                                 1
                      2
                                                    R
          P

        Statement (S)                                       Reason (R)
5.3.1                                                                                   (8)      S R
              ˆ x
        B̂1  A                                             tan chord theorem
                2
                                                                                                 SR
         ˆ    ˆ
        A B x                                             s opp equal sides
          1       1

        Qˆ B
            ˆ x                                            corresp s; BC // PQ                 S R
             1

        B̂  ˆ
          2  A x 1
                                                            tan chord theorem
                                                                                                 S R
        Pˆ2  B
              ˆ x                                          alt s; BC // PQ                   S R
                2

                                           Demo
                                                        NW/JUNE/MATH/ EMIS/6*******       9

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Mathematics/ P2/WISKUNDE/V2Half-jaar EksamenMid-Year Examination                           NW/ Jun 2018
                                  NSC- Grade 11

5.3.2         ˆ
        P̂2  A                                                    (2)
                1
                                      both  x                              S/ R
         ABRP is a cyclic quad       BR subtends equal s                  conclusion/konk..
5.3.3                                                              (3)
        AP = BP                       sides opp equal s                    S/ R
        BQ = BP                       sides opp equal s                   S/ R
        AP = BQ                       both = BP                             S/ R
                                                                   [19]
QUESTION/VRAAG 6

        Statement (S)                 Reason (R)
6.1     K̂1  90                     diameter subtends right     (5)
                                                                           S R
        Uˆ K ˆ  90                 s in the same seg.
          1          1
        or
        Û1  90                                                           S/ R
                                      diameter subtends right 
                                                                           S/ R
          ˆ  180  90  90
        NUP                           PUS is straight                     R
         PUNK is a cyclic quad       ext   int opp 
                                      opp s supp
6.2     Sˆ 1  Pˆ1                    alt s; OS // PN             (6)
                                                                           S R
        Kˆ  Pˆ                       s in the same seg.
          2      1

        K̂ 2  ˆS1                    converse tan chord theorem           S R
                                                                           S R
         SO is a tangent
                                                                   [11]
                                TOTAL:                             [100]

                             Demo
                                    NW/JUNE/MATH/ EMIS/6*******      10

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