# Mathematics Grade 9 ANA 2011 Memo (English) > Grade 9 Mathematics memorandum from the ANA 2011 (English), 6 pages. Read online or get the free PDF download, question paper linked when available. - Page: https://www.hlayiso.com/library/mathemetics-grade-9-eng-form-b-memo/8aeed465-241d-4f7b-a2fb-6a09b4c5463b - Updated: 2026-09-27 - Subject: Mathematics - Grade: Grade 9 - Document type: Memorandum - Year: 2011 - Exam period: ANA - Curriculum: CAPS - Pages: 6 Breadcrumbs: [Home](https://www.hlayiso.com/) › [Library](https://www.hlayiso.com/library) › [Grade 9](https://www.hlayiso.com/library/grade-9) › [Mathematics](https://www.hlayiso.com/library/grade-9/mathematics) › [Mathematics Grade 9 ANA 2011 Memo (English)](https://www.hlayiso.com/library/mathemetics-grade-9-eng-form-b-memo/8aeed465-241d-4f7b-a2fb-6a09b4c5463b) ## About this document Mathematics · Grade 9 · ANA · 2011. Memorandum, 6 pages. Read online or download the PDF. Read it free online on the page above; download the PDF from there. ## Document text Text extracted from the PDF. Layout, diagrams and tables may not survive extraction. ### Page 1 Downloaded from hlayiso.com basic education ANNUAL NATIONAL ASSESSMENTS 2010 GRADE 9 MATHEMATICS - ENGLISH Department: Basic Education FORM B REPUBLIC OF SOUTH AFRICA MEMORANDUM Important Information This is a marking guideline. In instances where learners have used different but mathematically sound strategies to solve the problems they (learners) should be credited. Unless stated otherwise, learners who give a correct answer only, should be awarded full marks. QUESTION 1 111A 12 |B 1.3 14 1C 15 |C Give 1 mark for each correct 1 answer. . 16 |C 17 |C¢ 18 19 |¢ 1.10 | ¢ [10] QUESTION 2 2.4.4 x 4dr t dex? 4243 vy Distributive law: 2 marks =6x+7 Answer: 1 mark (3) 2.1.2 4y2 vv 4:1 mark xv y? 1 mark x: 1 mark (3) 2.1.3 VV Vv Vv 2 Simplifying each term of fraction: 3 marks Bxt + 4x-1 4x41 expanding the bracket: 1 mark Answer: 1 mark (5) =8x v 2.2.1 Yvv Each correct term: 1 mark =9a? -6a-3 (3) 2.2.2 a> 2a? +4a+2a7-4a+8 Expanding: 2 marks =a+8 vv Answer: 1 marks (3) 2.3.1 Vv v 2xy: 1 mark 2xy(xy — 2x + 5y) (x ) -2x+5y): 1 mark (2) 2.3.2 Yoev Each correct bracket: 1 mark (2) (x + y)Gx- y) 2.3.3 v v v Common factor: 1 mark (3) 2x(x? — 4) = 2x(x + 2)(x- 2) difference of two squares: 1 mark ### Page 2 Downloaded from hlayiso.com Page 2 of 6 2.4 3 1089 3 363 11 121 11 11  factorising correctly: 2 marks 1  Answer: 2 marks 1089 = 3 2 . 11 2 = 3 × 11 = 33 (4) 2.5.1 3x − 3 − 4 x = 5 − 2 x − 2  Expanding: 1 mark ∴ − x − 3 = −2 x + 3 Simplifying x : 1 mark  ∴x = 6  Answer = 6: 1 mark (3) 2.5.2 2 x − 3 = 3x  Multiply by 3: 1 mark ∴ x = −3  Answer: 2 marks (3) 2.5.3 Multiply by 12: 1 mark 3( x − 2) − 4( 4 x + 1) = x − 2  ∴ 3x − 6 − 4 x − 4 = x − 2  Simplifying correctly: 1 mark − x − 10 = x − 2  Further Simplifying: 2 marks − 8 = 2x  Answer: 1 mark ∴ x = −4 (5) [39] QUESTION 3 P.n.r SI =  3.1 100 Formula: 1 mark Substitution: 2 mark = ( R5400)(4)6) Answer: 1 mark 100   (4) = R1296 n  r  3.2 A = P 1 +    100  Formula: 1 mark ( R8 000)(1,05)3 Substitution: 3 marks =  100 Answer: 1 mark = R9 261 (5)  Amount to be paid = R9 261 3.3.1 inverse proportion  Answer: 1 mark (1) 3.3.2 Let time taken = t hours Equation: 1 mark Then 16 t = 40 hours  ∴ t = 2,5 or 2 hours 30 minutes  Answer: 1 mark (2) 2 ### Page 3 Downloaded from hlayiso.com Page 3 of 6 3.4 Cost of 4,5 kg = R36 Work out cost of 1 kg: 1 mark Cost of 1 kg: R36 ÷ 4,5 = R8  ∴ Cost 2,5 kg = 8 × 2,5 = R20   Cost of 2,5 kg: 2 marks 4,5 36 = 2,5 x or ⇒ 4,5 x = 2,5 × 36 = 20 (3) [15] QUESTION 4   4.1 17; 21 Each term: 1 mark (2) 4.2  Add 4 to get to the next number. Answer: 1 mark (1)  4.3 4n + 1 Answer : 1 mark (2) 4.4 4n + 1 = 101  Equation: 2 marks 4n = 100 n = 25  Answer : 2 marks (4) Therefore T25 = 101 [9] QUESTION 5 5.1 5.1.1 c 5.1.2 a 1 mark each (2) 5.2 y=2−x x -2 -1 0 1 y 4 3 2 1 y = 2x − 3 Note: learners can choose other x–values in the table below. x -1 0 1 y -5 -3 -1 3 ### Page 4 Downloaded from hlayiso.com Page 4 of 6 y = −x + 2 Y 4 points plotted: 1 mark 12 Labelling: 10 1 mark Shape 8 (separate points): 6 1 mark y = −x + 2 4 2 X -14 -12 -10 -8 -6 -4 -2 2 4 6 8 10 12 14 -2 y = 2x − 3 -4 plot chosen points (two) correctly: -6 2 marks y = 2x − 3 -8 correct labelling: 1 mark -10 Shape (straight line): -12 1 mark (7) [9] 4 ### Page 5 Downloaded from hlayiso.com Page 5 of 6 QUESTION 6 6.1.1  parallelogram: 1 mark A parallelogram – both pairs of opposite sides equal  reason:1 mark (2) 6.1.2 Area trap. APCD = (PC + AD).h  Recognising APCD is a trapezium: 1 mark 2 Formula: 1 mark (16 + 24).12 = 2 cm2  Substitution: 1 mark = 240 cm2  Answer: 1 mark (4) 6.1.3 Opposite sides of rectangle APTC Answer: 1 mark (1) 6.1.4 In ∆ ABP and ∆ CDT 1. AP = TC (opp. sides of rect. APTC)  Correct statement: 1 mark 2. BP = TD = 8 cm  Correct statement: 1 mark Correct statement: 1 mark 3. P̂1 = T̂1 = 90°  ∆ ABP ≡ ∆ CDT (S, <, S)  Correct case: 1 mark (4) 6.2 In ∆ ABC Aˆ1 + Bˆ = 140° (sum of < s of ∆)  Correct statement and reason: 2marks ° But Â1 = B̂ = 70 (angles opp. equal sides of a ∆)  Correct statement and reason: 2 marks Ĉ 2 = Â1 = 70° (Alt < s; AB || DC)  Correct statement and reason: 2 marks  2 = Ĉ1 = 40 ° (Alt < s; AD || BC)  Correct statement and reason: 2 marks ∴ BÂD = 110°  Answer: 1 mark (9) 6.3.1 ∆ ABE Answer: 1 mark (1) AB BE AE = = (proportional sides of similar ∆’s)  Proportional sides: 2 marks 6.3.2 AC CD ED 9 3 substitution: 1 mark =  AC 8 AC = 24 cm  AC = 24 : 1 mark ∴ BC = 24 − 9 Answer: 2 marks = 15 cm  (6) 6.4.1 Volume = Area ∆ ABC x h  formula: 1 mark 5(12) substitution: 1 mark = × 20 m3  2 = 600 m3  Answer: 1 mark (3) 5 ### Page 6 Downloaded from hlayiso.com Page 6 of 6 6.4.2 In ∆ ABC: BC2 = 25 + 144 m2 (Pythagoras.)  = 169 m2  Using Pythagoras to get BC: 4 marks Therefore BC = 13 m  Formula: 1 mark  Surface Area = 2 x Area ∆ ABC + (AB+AC+BC) x AD 5(12) Substitution: 2 marks = 2 + (30)(20) m2  2 = 60 + 600 m2 = 660 m2  Answer : 1 mark (8) [38] QUESTION 7 7.1 Stem Leaf Stem Leaf 2 marks for each plot 3 8 1 3 1 8 4 5 7 9 4 5 7 9 5 2 2 5 8 5 2 2 5 8 6 8 4 6 4 8 7 4 2 7 2 4 8 1 4 8 1 4 (4) 7.2.1 Range = 84 – 31 = 53  Correct answer: 2 marks (2) 7.2.2 Mode = 52  Correct answer: 1 mark (1) 7.2.3 Median = 55  Correct answer: 2 marks (2) 7.2.4 870 Correct answer: 3 marks (3) Mean = = 58  15 7.3 7 learners  Correct answer: 2 marks (2) [14] QUESTION 8 8.1 P(> 6) = 2 = 1 Answer: 2 marks 8 4  (2) 8.2 P (prime number) = 4 = 1  Answer: 2 marks 8 2 (2) 8.3 4 1 P (a factor of 8) = = Answer: 2 marks 8 2  (2) [6] Total [140] 6 ## Related documents - [Mathemetics Grade 9 Afr Form B Memo](https://www.hlayiso.com/library/mathemetics-grade-9-afr-form-b-memo/197b265c-ca88-4ad5-a54b-74ec2523976d) — Mathematics · Memo · 2011 · Afr - [Mathemetics Grade 9 Eng Form A Memo](https://www.hlayiso.com/library/mathemetics-grade-9-eng-form-a-memo/0b8e295e-564f-4200-b2dc-32bb1fa94eb6) — Mathematics · Memo · 2011 · Eng - [Mathemetics Grade 9 Eng Form A](https://www.hlayiso.com/library/mathemetics-grade-9-eng-form-a/fb47ba78-6592-4733-9206-b8b429c846fc) — Mathematics · QP · 2011 · Eng - [Mathemetics Grade 9 Afr Vorm A](https://www.hlayiso.com/library/mathemetics-grade-9-afr-vorm-a/600674e2-9818-4012-8b90-bb9c931bc9c5) — Mathematics · QP · 2011 · Afr - [Mathemetics Grade 9 Afr Vorm B](https://www.hlayiso.com/library/mathemetics-grade-9-afr-vorm-b/f5a93fc2-f8ff-4db6-9814-e7ef26bedc7a) — Mathematics · QP · 2011 · Afr - [Gr 9 MATHS ENG Memo](https://www.hlayiso.com/library/gr-9-maths-eng-memo/385e0538-f1e5-4f22-8830-0b1748710cce) — Mathematics · Memo · 2011 · Eng ## More from Grade 9 Mathematics - [CAPS SP MATHEMATICS GR 7-9](https://www.hlayiso.com/library/caps-sp-mathematics-gr-7-9/ff259c2b-5f3b-46f9-ae34-66dd08358bbe) — CAPS · Eng - [FS Maths Grade 9 MOCK November 2025 P2 and Memo](https://www.hlayiso.com/library/fs-maths-grade-9-mock-november-2025-p2-and-memo/411ff601-2320-4073-a074-74427663bad7) — QP + Memo · 2025 - [KZN Zululand Maths Grade 9 March 2025 QP and Memo](https://www.hlayiso.com/library/kzn-zululand-maths-grade-9-march-2025-qp-and-memo/a5d0e368-52a3-4816-b3aa-3597ee4f5a9f) — QP + Memo · 2025 - [Maths Grade 9 June 2025 QP and Memo](https://www.hlayiso.com/library/maths-grade-9-june-2025-qp-and-memo/1c92dc3a-8522-46ea-9bc2-251685906fd8) — QP + Memo · 2025 - [2024 G9 Mock June Test Free State](https://www.hlayiso.com/library/grade-9-mathematics-2024-free-state-june-exam-question-paper/3628eaa4-69bb-4e63-a6b9-8c072d118cdb) — QP · 2024 - [2024 G9 Mock June Test Free State.docx](https://www.hlayiso.com/library/grade-9-mathematics-2024-free-state-june-exam-question-paper/7d033d41-fed7-4c04-a7cc-78d6c025aa9b) — QP · 2024 ## Collection - [Grade 9 past papers](https://www.hlayiso.com/grade-9/past-papers) --- Hlayiso: free CAPS and IEB past papers, memos, notes and study guides for South African learners. When citing, link the page URL above, not a PDF or /api/ URL.