# Mathematics Grade 10 KwaZulu Natal June 2017 Memo

> Grade 10 Mathematics memorandum from the KwaZulu Natal June 2017, 18 pages. Read online or get the free PDF download, question paper linked when available.

- Page: https://www.hlayiso.com/library/maths-2017-june-qp-memo/9870ea69-cc9c-4703-af3f-2068ef62f444
- Updated: 2026-09-27
- Subject: Mathematics
- Grade: Grade 10
- Document type: Memorandum
- Year: 2017
- Exam period: KwaZulu Natal June
- Curriculum: CAPS
- Pages: 18

Breadcrumbs: [Home](https://www.hlayiso.com/) › [Library](https://www.hlayiso.com/library) › [Grade 10](https://www.hlayiso.com/library/grade-10) › [Mathematics](https://www.hlayiso.com/library/grade-10/mathematics) › [Mathematics Grade 10 KwaZulu Natal June 2017 Memo](https://www.hlayiso.com/library/maths-2017-june-qp-memo/9870ea69-cc9c-4703-af3f-2068ef62f444)

## About this document

Mathematics · Grade 10 · KwaZulu Natal June · 2017. Memorandum, 18 pages. Read online or download the PDF.

Read it free online on the page above; download the PDF from there.

## Document text

Text extracted from the PDF. Layout, diagrams and tables may not survive extraction.

### Page 1

____-hownloaded from hlayiso.com

Education

KwaZulu-Natal Department of Education
REPUBLIC OF SOUTH AFRICA

Gen RGR R RR SRR RT Re

* MATHEMATICS =
nm COMMONTEST = 8

NATIONAL
SENIOR CERTIFICATE

MARKS: 100

TIME: 2 hours

This question paper consists of 10 pages and 2 DIAGRAM SHEETS.

### Page 2

Mathematics

Downloaded from hlayiso.com

June 2017 Common Test
NSC

INSTRUCTIONS AND INFORMATION

Read the following instructions carefully before answering the questions:

L.

2.

10.

This question paper consists of 8 questions. -
Answer ALL the questions.

Clearly show ALL calculations, diagrams, graphs, et cetera, which you have used in
determining the answers.

Answers only will NOT necessarily be awarded full marks.

You may use an approved scientific calculator (non-programmable and
non-graphical), unless stated otherwise.

If necessary, round off answers to TWO decimal places, unless stated otherwise,
TWO diagram sheets for answering QUESTION 7.1, QUESTION 7.2,

QUESTION 7.3, QUESTION 8.1 and QUESTION 8.2 are attached at the end of this
question paper. Write your name on these sheets in the spaces provided and insert the
sheets inside the back cover of your ANSWER BOOK.

Diagrams are NOT necessarily drawn to scale.

Number the answers correctly according to the numbering system used in this
question paper.

Write neatly and legibly.

Copyright Reserved Please turn over

### Page 3

Downloaded from hlayiso.com

Mathematics 3 June 2017 Common Test
NSC
QUESTION 1
1.1 Factorise the following expressions fully:
y LLL 7414 ve (1)
1.1.2 2x? +2ax—3bx-3ab (3)
1.2 Determine the product of the following expression:
~2(x+D00? ~x +1) (3)
1.3 Calculate the value of the following expression without using a calculator:
(0,072)? ~ (0,028)? Lo (2)
14 — Simplify the following expression fully:
5x? + 14x —3 ;
x? -9 (3)
15 Evaluate the following expression:
get gx?
Gagat . Write your answer as a fraction in its simplest form, 6)
verre (17).

Copyright Reserved

Please turn over

### Page 4

Mathematics

QUESTION 2

Downloaded from hlayiso.Cartr commonest

2.1 Solveform: 4% =1

2.2 Given: a+ Ss

5x

2.2.1 Solve for x.

2.2.2 Write the answer to QUESTION 2.2.1 in interval notation.

2.3 Solve simultaneously for x and y:

x-2y=3

37 where xeR

and = 4x+3y+10=0

(2)

(3)
68)

6)

24  Arectangular garden is made up of a square lawn of side x m and two paths 1,5 m

wide, as shown in the diagram below. The total area of the garden is 88 m_.
Write down an equation in terms of x and solve the equation to find the

dimensions of the lawn.

Copyright Reserved

1,5 m

i
I
I
a
[

I
I
I
[
I
I

+

I

15m

CT

[I

TT NOT
J TO
SCALE
T
I

(5)
[16]

Please turn over

### Page 5

Downloaded from hlayiso.com

Mathematics 5 June 2017 Common Test
NSC

QUESTION 3

3.1 The nth term ofa pattern is given as T, =12n—~7.

3.1.1 Write down the first three terms of this pattern. (2)

3.1.2 Is 356 a term in this pattern? Explain your answer. Q)

3.2 Consider the following sequence of Es:

3.2.1 How many blocks are needed to make the next E? qd)

3.2.2 Write down the general term, T,,, for the number of blocks used in each E. (2)

3.2.3 Calculate how many blocks will be needed to make the 100" E, (2)
3.2.4 Calculate which E can be made from 116 blocks. (3)
[12]
QUESTION 4

The following functions are given: f(x) =x~-2 and g(x)= 4 ~2
x

Sketch the graphs of f and g on the same set of axes, clearly showing all intercepts
with the axes and asymptotes where applicable, [6]

Copyright Reserved Please turn over

### Page 6

Downloaded from hlayiso.com

Mathematics June 2017 Common Test

NSC

QUESTION 5

Sketched below are the graphs of f(x)=-4x° +9 and g(x)=2x+3.

The graph of f intersects the x-axis at A and B. The graph of g intersects f at A and D
and the y-axis at C, DE // y-axis.

ty
g
Cc
A x
A N EB >
5.1 Write down the coordinates of C. qd)
5.2 Calculate the length of AB. Q)
5.3 Calculate the length of DE if AE =2 ; units. (2)
5.4 For which values of x will s(x) > g(x)? (2)
5.5 Calculate the length of AD. (2)
[10]

Copyright Reserved Please turn over

### Page 7

Mathematics
NSC

QUESTION 6

Sketched below are the graphs of g and hf. g(x) =b* +c and A(x) = k :
x

A, the point of intersection of g and A, is (1; 1).

Downloaded from hlayiso.c

Use the graphs and the information above to answer the following :
6.1 Write down the values of k, ¢ and d.

6.2 Write down the equation of the asymptote of g.

6.3. Write down the domain of h.

6.4 Determine the equation of f if f is the reflection of g in the y-axis,

Copyright Reserved

June 2017 Common Test

(4)
G)
(2)

(2)
19]

Please turn over

### Page 8

Mathematics
NSC

QUESTION 7

Downloaded from hlayiso.com

June 2017 Common Test

In this question, you must give a reason to justify each of your statements.

71. Inthe diagram below, the diagonals of parallelogram ABCD intersect in M.

AB = 13cm, ABC=76° and COM=28°.

13cm

28°
D Cc

7.1.1 Write down, giving a reason, the length of DC.

7.1.2 Calculate, giving reasons, the size of ADM

7.2 %n the diagram below, PR is a diagonal of square PORS. Point E lies on SR
and QE is drawn, PR and QE intersect at T. SET =120°.

P Q

1209
E

7.2.1 Giveareason why SPR = 45°,

7.2.2 Calculate, giving reasons, the size of PTE

Copyright Reserved

76°,

(2)
Q)

13)

Q)

Please turn over

”

### Page 9

Downloaded from hlayiso.com

Mathematics June 2017 Common Test

NSC

7.3 Inthe diagram below, ABCD is a kite having diagonals AC and BD intersecting at
O. AO = 8cm, BO = 2x cm and DO = 5x

A
8
Sx 2x
D B
ie)
Cc
cm,
7.3.1 Write down, giving a reason, the length of OC. (2)
7.3.2. Write down the area of ABCD in terms of x. (2)
7.3.3. Ifthe area of ABCD is 168cm’, calculate the value of x (2) -
73.4 Calculate, giving a reason, the length of AB. (3)
[16]
QUESTION 8
In this question, you must give a reason to justify each of your statements.
8.1 In the diagram below, ABCD is a quadrilateral having AB = DC and AB || DC.
A +4 B
D 1
2
mn 1
D or Cc
Use the diagram on the DIAGRAM SHEET to prove that ABCD is a parallelogram. (5)

Copyright Reserved Piease turn over

### Page 10

Downloaded from hlayiso.com

Mathematics June 2017 Common Test

NSC

8.2 In APQR, A is the midpoint of QR and B is the midpoint of PA. C and D are
points on PR such that QBC || AD. G is a point on QB such that GB = BC.

A
8.2.1 Give a reason why PGAC is a parallelogram. qd)
8.2.2 Prove that PC = CD = DR. (4)
8.2.3 Prove that GCDA is a parallelogram (4)

[4]

TOTAL MARKS: 100

Copyright Reserved Please turn over

### Page 11

Downloaded from hlayiso.com

Mathematics June 2017 Common Test
NSC
| NAME:
! DIAGRAM SHEET 1
! QUESTION 7.1
A 13cm B
M
28°
: D i C
%| QUESTION 7.2
Bip —Q
5!
RY
é |
2!
E ' T
Be ' o
s 120' R
: E
! QUESTION 7.3
A
5x 2x
D r) B
C

Copyright Reserved Please turn over

### Page 12

Downloaded from hlayiso.com

Mathematics June 2017 Common Test
NSC
: NAME:
| DIAGRAM SHEET 2
| QUESTION 8.1
A ~ B

No

QUESTION 8.2

PLEASE TEAR ON DOTTED LINES

Copyright Reserved

### Page 13

2A0 TM) 9SROTE panrasoy msEKdo3

taal “soBud 6 Jo sjsisuoo suepms Suppreuw supp,
S
+
uoneoyydunis » Oo =
welt A veel al
bak * i oe WOSPAL 499.1109 YA JUIUISILZS 199.1109 OJ HAVA WSA
= soseq sumd = wl = Woseax 10y Fae Ws
wal Ye pa33TM0 Wosver 10; Asjeusd OU “JuoMMAyEIS J9L109 JO} YEA] SA
8 tl ped NOLLAIIDSIG TORMAS
4 a wa Opel st
fo) samo} :
- Ht 7A
rv) Jomsue ~ o-¥
— I>*¢ :
~ (c+2Y{E-2) » (c+x\e-x) Ook SSRIVIN
S (e+x)1-*9) + F029) ~
—_ 6- x
= o E-XbT+ 2xS Pal
pr000=
= JOMSUB A
000) =
2 Bco-zOSZO +720) 4 G%'0-7ZL0)BZ0'0 +200) = -
2(820°0)— (0°) €1
+ @ =
O somsue toe =
(¥) I+ tap G+ Xe-= BSS RR RS
O o . Gex- 20+X)Z- ral
G
S samsue @e-x¢o+2)=
9 exo +p (GE-2OE A exc + GE-x0)x=
ce GPE ~MOT +I — XT
= wo
fo) ©
a JOMSUB A @e-xOe +2) =
(o+x)96-/ (DEXET A (@4+X)GE-@4+2)RT= rer ere sa
- GPE-MGEME XE |e 7
Joust » @+OL=
- bite | TT
Voidsv HLNOS 40 OMaNnday
TNOLESaNd uoljeonpg jo juewpedsgq jeyen-ninzemy
Suppo Sunepy uo! feonp3
“OL 3avao
as0y, WOUND £19Z UNE z SOMPUITNE,

LIA shit - AGA .

### Page 14

Downloaded from hlayiso.com

Mathematics 3 June 2017 Common Test
GRADE 10
Marking Guideline
QUESTION 2
Zl 4 =]
4 =4 v1=4
x=0 ¥ answer
2
2.2.4 2415 sto
4 3
3x+180 <20x—24 vmultiplying by 12
-17x S-204 Y simplification
x212 v answer
@)
OR
x Sx
4° 15< 3 2
3% 445< 202 5 mom
RB 12” ¥ common denominator
Vix forx
aps Y simplification
x212 ¥ answer
@)
222 | xe [12;<) @
23 x—2y=
x=2yt3 VY x=2y43
A(2y +3) +3y +10 =0 Y substitution
8y+1243y+10=0 ~ multiplying out
lly =-22
yo v y—value
x= 2(-2)+3
ze] ¥ x~value
(5)
24 Area of rectangle = [xb
88 = x(x +3) Y x(x+3) ¥ equating to 88
x? +3x-88=0 Y standard form
(~-8)(x411) =0 Y factors
x=8vx#-11
- The lawn is 8 m by 8 m Y answer 6
[16]
Copyright Reserved Please turn over

Mathematics 4 June 2017 Common Test
GRADE 10
Marking Guideline
QUESTION 3
3.11 ‘The sequence is: 5 ; 17; 29; ... v5 ¥17 and 29
(2)
3.12  )No v answer
12n-7=356
363 is not exactly divisible by 12 ¥ reason
OR
12 is not a multiple of 363 Q)
3.21 17 blocks au
ie)
322 | TL =3n+5 ¥3n
+5
(2)
3.23 | No. of blocks required to make the 100°E: 3(100)+3 j ¥ substitution
=305 Y answer
(2)
N.B. Answer only: full
marks.
3.24 3n+5=116 ¥ 3n+5=116
3n=111 Y simplification
n=37
The 37" E can be made from 116 blocks Y answer
G)
{12}
QUESTION 4

f)=x-2 and g(a)= 4-2

v x-intercepts of f (2; 0)

y-intercept of f: (0 ;-2)

v x-intercept of g: (2 : 0)
Y asymptote of g: y=~2
¥ another point ong eg.

(132), 43-0,
(2; 4), (1; 6), etc.

Please turn over

2;4)
Y shape of g ie.
hyperbola predominately
in quadrants 1 and 3.
[6t
Copyright Reserved

### Page 15

FAO UM oseayy posresoy 1ysnkdoy BAO WAT 9521 paaussoy 1ySukdos

@
yomsue A o8h=
8% .9L = NOY
ws (fenbo ore wued yo soySue ddo) o9L= 8T+ MOK | cry
@
MASA (jenbo oz wired jo sapis ddo) woet=od| Try
fe) a
E 087
fo)
O Ww
° OL
fo)
AY) a MOET v Tor]
vL @ z z
> Jomsue pa 656 10 —— 40 =av
S LNOLLSand sys sch
<= al
(= ) Zz TOFMIBSGHS yaTI09 ~ (se1oSeppAq)
usu pp prea @8 _— - ss
fo) A)
ia Jomsue
uo As
ye
@ zt, (z
©} JOAMSUR pp Tt yee? yo
AY) 24.9=@3| yo © pee Se
me} w soso wes
oO BASIE 4 A {o#x Sy Sx|x} :y Jo uremoq £9 @
{e) @ aa somsue » san ¢=4q
= oasoE p ia a) 3 ow [=x omAsqns » £+We=30 gs
rma ra) i)
> ; t somsue p sun ¢ = qv
5 fea, 174 bari Snx
aD 2°91! Dommsqns » £4 q=1 : :
Th srorey 0= (€4x2KE-XZ}
z z 0=6~ *F
tT A ane 0=f, 6+ %p-=0 J Jo sdeoisqur-r zs
1=4 l= r9 @
— = yomsue (09) 1s
(I! 1) St ‘wonsasioyt yo aod am ‘y Ft 4 Paw O44 = (D3 “E+xT= (23 pur 6+ y= () Sf
. 9 NOLLSaND sNOLiSand
SUapINg Supe aurepmy Supprepy
ol gavas Or gavap
ysoq mou 107 sung Py sonBMOyTEY yso wou) L19Z ony ¢ sopearayyeyy

### Page 16

Mathematics. 7 June 2017 Common Test
GRADE 10
72
P iQ
T
120)
(eo) 5 R
O E
© (721 _ J The diagonals of a square bisects the vertex angles. Y reason
12) @)
—~ 722 ) pfE+45°+90° +120°=360° (gum of angles in quad) vSIR
PTE =360°—255°
io} =i0s° Y answer,
= fp "
7.
A
fo} 8
; a bx on
Qu D ray B
TW
AY) Q
S °
© [734 [0C=8em (diagonals of @ kite) YSYR
t (2)
= 732 |p ceaof ite = (ACNBD)
1 g 120° 1
==(16)(7: R 1
B FOOT) E ¥ 50072)
= Y answer
= 56x
2)
733 | 36x=168 VS
x=3 Y answer
2)
734 [OB=6em VS
AOB =90° (diagonals of a kite) vse
AB’ =67 +8 ‘Theorem of Pytha;
=100 ‘ of Fythagorss) Y answer with
AB=10 reason.
(3)
[16]
Copyright Reserved Please turn over

«

Mathematics 8 June 2017 Common Test
GRADE 10
Marking Guideline

QUESTION 8

8.1

A B
:
(NI
Y 2
D t 4

Constr: Draw diagonal AC

Proof: In AABC and ACDA
@ = ACis common

@  aB=DC (given)
Gi) AC, (alt angles AB {[ DC)
AABC=ACDA (8323S)
oA, =O,
‘These are alternate angles
<-AD || BC

:. ABCD isa parallelogram (both pairs of opp sides are
parallel)

Y constr

Y AABC=ACDA
(S;2;8)
YA, =¢,
“AD || BC

YR

G)

Copyright Resexved

Please tum over

### Page 17

Downloaded from hlayiso.com

ponresay 1ygutdoy

001 -SMAVIA TYLOL
Trul
® (prem
Ww
pur yenbo sapis ddo Jo med ovo) wexBojayjeted 8 st G¥DD~-
(oars) av loome
Sa ay =o0%
av = az
[4
WA Sp (aroorp amodprut) dy 7 = Oa
avav4| cvs
Wd=do =a"
&) (OPIS ps€ OM SJOOSTG “OPIS pyZ BP 0} joyTexed
WAS “opis suo jo modpru op Woy umexp eu) G9=Da
‘avav
WSs PIS px€ OUP SIOOSIQ “OPIS zaZ OP 01 JorTeTEd
“opis euo jo ywiodpra oy woy uMeIp auy) §- Yq = aD.
~AOvA| zwzs
wo
wosear ~ Joy} yoro jasig speuoseiq | 17s
a
suTepmy Sunpreyy
ol davao
39] WOUMMTOD LT OZ sung

6 sonREENRENA,

### Page 18

Downloaded from hlayiso.com

## Related documents

- [Gr10 Math P1 (Afrikaans) June 2017 Possible Answers](https://www.hlayiso.com/library/gr10-math-p1-afrikaans-june-2017-possible-answers/ed628e40-c132-422b-8d08-3f73add812ad) — Mathematics · Memo · 2017 · Afr
- [Gr10 Math P1 (English) June 2017 Possible Answers](https://www.hlayiso.com/library/gr10-math-p1-english-june-2017-possible-answers/f0410453-7885-46f5-8a4d-6521771a981d) — Mathematics · Memo · 2017 · Eng
- [Gr10 Math P2 (Afrikaans) June 2017 Possible Answers](https://www.hlayiso.com/library/gr10-math-p2-afrikaans-june-2017-possible-answers/80ad79a2-f1ee-463d-8abe-4c256f21b7de) — Mathematics · Memo · 2017 · Afr
- [Gr10 Math P2 (English) June 2017 Possible Answers](https://www.hlayiso.com/library/gr10-math-p2-english-june-2017-possible-answers/26dc2a6d-2c76-4c1c-a2b8-614d6e862891) — Mathematics · Memo · 2017 · Eng
- [Gr10 Math P1 (English and Afrikaans) November 2017 Possible Answers](https://www.hlayiso.com/library/gr10-math-p1-english-and-afrikaans-november-2017-possible-answers/c6757aea-7cc5-4e44-a7ce-0ebf13b83f78) — Mathematics · Memo · 2017 · Afr
- [Mathematics GR 10 MEMO Paper 1](https://www.hlayiso.com/library/grade-10-mathematics-2017-north-west-june-memorandum-paper-1/2264f19f-0d16-46f9-a97d-201cadf5ac49) — Mathematics · Memo · 2017

## More from Grade 10 Mathematics

- [Gr 10 Maths ATP 2023-24](https://www.hlayiso.com/library/gr-10-maths-atp-2023-24/80c1c337-e011-4b8b-a37b-d2e0df9daaf6) — ATP
- [KZN Maths Grade 10 June 2025 P1 and Memo](https://www.hlayiso.com/library/kzn-maths-grade-10-june-2025-p1-and-memo/dc5ae33f-46ec-4eae-b577-25a82956eaec) — QP + Memo · 2025
- [KZN Maths Grade 10 March 2025 QP and Memo](https://www.hlayiso.com/library/kzn-maths-grade-10-march-2025-qp-and-memo/bc27cbbf-ec6d-4c60-bf7e-25a154d363e4) — QP + Memo · 2025
- [KZN Maths Grade 10 November 2025 P1 and Memo](https://www.hlayiso.com/library/kzn-maths-grade-10-november-2025-p1-and-memo/ece9abee-2009-4e22-8de3-34ccb229e5cb) — QP + Memo · 2025
- [KZN Maths Grade 10 November 2025 P2 and Memo](https://www.hlayiso.com/library/kzn-maths-grade-10-november-2025-p2-and-memo/417e9b18-c39d-4fb2-9e32-c089e8fbfd22) — QP + Memo · 2025
- [Gr 10 Mathematics P1 (Afrikaans) June 2024 Question Paper](https://www.hlayiso.com/library/gr-10-mathematics-p1-afrikaans-june-2024-question-paper/f7a97f78-e0a1-47a0-9585-d048fbb9a0b0) — QP · 2024 · Afr

## Collection

- [Grade 10 past papers](https://www.hlayiso.com/grade-10/past-papers)

---

Hlayiso: free CAPS and IEB past papers, memos, notes and study guides for South African learners. When citing, link the page URL above, not a PDF or /api/ URL.
