# Mathematics Grade 9 Paper 1 GEC Test 2023 Memo (Afrikaans) > Grade 9 Mathematics Paper 1 memorandum from the GEC Test 2023 (Afrikaans), 11 pages. Read online or download the free PDF. - Page: https://www.hlayiso.com/library/maths-afrikaans-p1-marking-guideline/d0a376c6-1303-4cb4-9808-8f297ba32397 - Updated: 2026-09-27 - Subject: Mathematics - Grade: Grade 9 - Language: Afrikaans - Document type: Memorandum - Year: 2023 - Exam period: GEC Test - Paper: 1 - Curriculum: CAPS - Pages: 11 Breadcrumbs: [Home](https://www.hlayiso.com/) › [Library](https://www.hlayiso.com/library) › [Grade 9](https://www.hlayiso.com/library/grade-9) › [Mathematics](https://www.hlayiso.com/library/grade-9/mathematics) › [Mathematics Grade 9 Paper 1 GEC Test 2023 Memo (Afrikaans)](https://www.hlayiso.com/library/maths-afrikaans-p1-marking-guideline/d0a376c6-1303-4cb4-9808-8f297ba32397) ## About this document Mathematics · Grade 9 · GEC Test · 2023 · Afrikaans. Memorandum, 11 pages. Read online or download the PDF. Read it free online on the page above; download the PDF from there. ## Matching paper and memo - [Maths Afrikaans P1 Test](https://www.hlayiso.com/library/maths-afrikaans-p1-test/b788b5a3-4b9d-4309-b3d7-aa577730d883) — QP · 2023 · Afr ## Document text Text extracted from the PDF. Layout, diagrams and tables may not survive extraction. ### Page 1 Downloaded from hlayiso.com AOS PROEFSTUDIE NASIENRIGLYNE 2023 WISKUNDE VRAESTEL 1 GRAAD 9 AFDELING A  Een punt per antwoord.  Geen halfpunte word toegeken nie. Nr. Verwagte antwoorde Verduideliking 1. B Irrasionaal  2. B 108  12 = 2 × 2 × 3 18 = 2 × 3 × 3 27 = 3 × 3 × 3 2 × 2 × 3 × 3 × 3 = 108 3. A 2  Tellers 3 8 = 23 12 = 22 × 3 GGF= 2 × 2 = 4 Noemers 30 = 2 × 3 × 5 36 = 22 × 32 GGF= 2 × 3 = 6 4 2 GGF = = 6 3 4. C  Graad 9 Wiskunde V1 Nasienriglyn 1 ### Page 2 Downloaded from hlayiso.com Nr. Verwagte antwoorde Verduideliking 5. A 103,13 km/h  𝑑 𝑠= 𝑡 𝑑 120 = 2,75 𝑑 = 120 × 2,75 𝑑 = 330 km 330 𝑠= 3,2 𝑠 = 103,13 km/h 6. D R1 339,42  𝐴 = 𝑃(1 + 𝑖)𝑛 12 2 𝐴 = 𝑅5 265 (1 + ) 100 𝐴 = 𝑅5 265(1 + 0,12)2 𝐴 = 𝑅5 265(1,12)2 𝐴 = 𝑅5 265(1,2544) 𝐴 = 𝑅6 604,42 𝑆𝑅 = 𝑅6 604,42 − 𝑅5 265 𝑆𝑅 = 𝑅1 339,42 7. C −7 × (11 × 4)  8. B 8  3(4) − 2(2) = 12 − 4 =8 9. D 1  2 en − 2 10. C 14  2( − 3) − (5) − 4(6 ÷ 8) 5−6 3 −6 − 5 − 4 ( ) = 4 −1 −14 = −1 = 14 11. A 1  3 √49 − 23 + √216 ÷ 3 =7−8+6÷3 =7−8+2 =1 12. C 1  3 +5 −4 + 5 5 √ √−64 =√ 2 4 +3 2 16 + 9 1 =√ 25 1 = 5 13. A 𝑎5 𝑐  3 2 5 𝑎 ×𝑎 𝑐 =𝑎 𝑐 Graad 9 Wiskunde V1 Nasienriglyn 2 ### Page 3 Downloaded from hlayiso.com Nr. Verwagte antwoorde Verduideliking 14. C 2𝑥+2  4𝑥+1 2𝑥 (22 )𝑥+1 = 2𝑥 2𝑥+2 2 = 2𝑥 2𝑥+2−𝑥 = 2 = 2𝑥+2 15. B 𝑏+𝑎  𝑎−1 + 𝑏 −1 𝑎𝑏 1 1 = + 𝑎 𝑏 𝑏+𝑎 = 𝑎𝑏 16. B 1  (2 )3 × (23 )−2 2 = 26 × 2−6 = 20 =1 17. A 8𝑥 3  𝑥 −3 𝑦 −3 − ( ) 𝑦3 −2𝑥 −2 3 −2𝑥 −2 = ( −3 ) 𝑥 𝑦 3 −2𝑥 3 =( 2 ) 𝑥 𝑦 2𝑥 3 = (− ) 𝑦 8𝑥 3 = − 3 𝑦 18. D 7  3(𝑥 + 𝑦)0 (𝑥 −1 𝑦)3 + 5𝑦 −1 − −3 4 𝑦 𝑦 𝑥 𝑦 −3 3 3×1 1 𝑥 𝑦 = + 5 × − −3 4 𝑦 𝑦 𝑥 𝑦 3 5 1 = + − 𝑦 𝑦 𝑦 7 = 𝑦 19. B 35  3 + 5 ; 8 + 7 ; 15 + 9 ; 24 + 11 = 35 OF Volkome vierkante −1 22 − 1 = 3 32 − 1 = 8 42 − 1 = 15 20. C 83  3 + 6 + 10 + 15 + 21 + 28 = 83 Graad 9 Wiskunde V1 Nasienriglyn 3 ### Page 4 Downloaded from hlayiso.com Nr. Verwagte antwoorde Verduideliking 21. A ʼn Konstante verhouding van  drie was gebruik. 22. C 𝑇𝑛 = −2𝑛 + 7  1; 3; 5; 7; … is nie opeenvolgende term posisies nie 5; 𝑎; 1; 𝑏; −3; 𝑐; … 𝑎−5=1−𝑎 2𝑎 = 6 2𝑎 6 = 2 2 𝑎=3 5; 3; 1; … is opeenvolgende terme 3−5=1−3 𝑑 = −2 𝑇1 = −2(1) + ___ = 5 𝑇2 = −2(2) + ___ = 3 𝑇3 = −2(3) + ___ = 1 𝑇𝑛 = −2𝑛 + 7 23. A 3𝑥 3 en 3𝑥(𝑥 2 )  24. D −8 en 6de  (−2𝑥 2 )3 = (−2)3 (𝑥 2 )3 = −8𝑥 6 Koёffisiёnt is −8 en die graad is 6de. 25. C 𝑥 + 3𝑥 2 + 2 − 4𝑥  26. A −4𝑥 3 − 2𝑥 2 + 𝑥  −𝑥(4𝑥 2 + 2𝑥 − 1) = −4𝑥 3 − 2𝑥 2 + 𝑥 27. A 3𝑥 2 − 10𝑥 + 1  4𝑥 + 2 3𝑥(𝑥 − 4) + 2 4𝑥 2 = 3𝑥(𝑥 − 4) + 2 + 2 = 3𝑥 2 − 12𝑥 + 2𝑥 + 1 = 3𝑥 2 − 10𝑥 + 1 OF 2 × 3𝑥(𝑥 − 4) + 4𝑥 + 2 = 2 6𝑥 2 − 24𝑥 + 4𝑥 + 2 = 2 2 6𝑥 20𝑥 2 = − + 2 2 2 2 = 3𝑥 − 10𝑥 + 1 Graad 9 Wiskunde V1 Nasienriglyn 4 ### Page 5 Downloaded from hlayiso.com Nr. Verwagte antwoorde Verduideliking 28. A 𝑥  3 √0,125𝑥 3 2 3 1 = √ 𝑥3 8 3 1 = √ 3 𝑥3 2 1 1 3 = ( 3 𝑥3) 2 1 1 3 1 = ( 3 ) (𝑥 3 )3 2 1 = 𝑥 2 𝑥 = 2 29. C 17𝑥  1 2𝑥 2 + −1 (𝑥 + 3)(2𝑥 − ) 3 3 𝑥 3 = 2𝑥 2 − + 6𝑥 − 3 3 𝑥 + 18𝑥 = 2𝑥 2 − −1 3 17𝑥 = 2𝑥 2 + −1 3 30. D 16  1 2 −8 (− ) + 10(2) − 2 2 1 = −8 ( ) + 20 − 2 4 = −2 + 20 − 2 = 16 31. A (2𝑥 − 3)(2𝑥 + 3)  32. B (𝑥 − 8)(𝑥 + 3)  33. A 6(𝑦 − 3)(𝑦 + 1)  34. B 𝑥+2  2𝑥 2 − 2𝑥 − 12 2𝑥 − 6 2(𝑥 2 − 𝑥 − 6) = 2(𝑥 − 3) 2(𝑥 + 2)(𝑥 − 3) = 2(𝑥 − 3) =𝑥+2 Graad 9 Wiskunde V1 Nasienriglyn 5 ### Page 6 Downloaded from hlayiso.com Nr. Verwagte antwoorde Verduideliking 35. A 𝑥+𝑦+1  (𝑥 + 𝑦)2 − 1 𝑥+𝑦−1 (𝑥 + 𝑦 − 1)(𝑥 + 𝑦 + 1) = 𝑥+𝑦−1 =𝑥+𝑦+1 36. A 2  37. B 2  2𝑝 4 = 2 2 𝑝=2 38. D 𝑥 = 0 of 𝑥 = 1  39. D 𝑏 = 3 of 𝑏 = −2  40. B 2𝑥 − 8 = 18  41. C 4  𝑦 = 16 − 12 𝑦=4 42. C −2  3𝑚 = 9−1 3𝑚 = (32 )−1 3𝑚 = 3−2 𝑚 = −2 43. D 𝑝 = 17 en 𝑡 = 6  𝑦 = 𝑥2 + 1 𝑝 = (−4)2 + 1 𝑝 = 16 + 1 𝑝 = 17 en 𝑦 = 𝑥2 + 1 37 = 𝑡 2 + 1 𝑡 2 = 36 𝑡 = ±6 ∴𝑡=6 44. D 𝑥 = −6 of 𝑥 = 1  𝑥 2 + 3𝑥 + 2𝑥 − 6 = 0 𝑥 2 + 5𝑥 − 6 = 0 (𝑥 + 6)(𝑥 − 1) = 0 𝑥 = −6 of 𝑥 = 1 Graad 9 Wiskunde V1 Nasienriglyn 6 ### Page 7 Downloaded from hlayiso.com Nr. Verwagte antwoorde Verduideliking 45. B 𝑎 = 0 of 𝑎 = 4  1 1 ( 𝑎 − 1) ( 𝑎 − 1) = 1 2 2 1 2 𝑎 −𝑎+1=1 4 1 2 𝑎 −𝑎 =0 4 𝑎2 − 4𝑎 = 0 𝑎(𝑎 − 4) = 0 𝑎 = 0 of 𝑎 − 4 = 0 𝑎 = 0 of 𝑎=4 OF 1 𝑎 − 1 = ±1 2 1 1 2 𝑎 − 1 = 1 of 2 𝑎 − 1 = −1 1 1 2 𝑎 = 2 of 2 𝑎 = 0 𝑎 = 4 of 𝑎 = 0 46. B 2m  𝐴 = (𝑥 − 18)(𝑥) 40 = 𝑥 2 − 18𝑥 0 = 𝑥 2 − 18𝑥 − 40 0 = (𝑥 − 20)(𝑥 + 2) 𝑥 = 20 of 𝑥 = −2 ∴ 𝑥 = 20 breedte = 20 − 18 breedte = 2 m 47. A 𝑏 = 33  𝑦 = 4𝑥 − 3 𝑏 = 4(9) − 3 𝑏 = 33 48. C  𝒙 −2 0 2 𝒚 −8 −2 4 49. B 𝑚 = (𝑛 + 1)2  𝑚 = (Ewe + 1)2 𝑚 = (Onewe)2 𝑚 = Onewe 50. D 1  1 𝑦 =− 𝑥+1 𝑚=− 2 2 𝑦-afsnit by (0; 1) en 𝑐 = 1 1 𝑦 =− 𝑥+1 2 51. D 𝑉 = 4𝑡 + 6  Gemene verskil = 4 𝑉 = 4𝑡 + 𝑐 Deur inspeksie: 𝑉 = 4𝑡 + 6 Graad 9 Wiskunde V1 Nasienriglyn 7 ### Page 8 Downloaded from hlayiso.com Nr. Verwagte antwoorde Verduideliking 52. A  𝑐 = 40𝑡 + 500 𝑦-afsnit =R500 en die gradiёnt =40 53. B (0; −5)  54. D 1  𝑦 = 2𝑥 − 2 2𝑥 − 2 = 0 2𝑥 = 2 𝑥=1 55. C 3  − 4 56. B  𝒙 −4 −2 2 𝒚 −1 −2 −4 57. C  Konstante verskil van 8 𝒙 1 2 3 4 𝒚 12 20 28 36 58. D −2𝑥 + 𝑦 − 2 = 0  −2𝑥 + 𝑦 − 2 = 0 𝑦 = 2𝑥 + 2 59. B (−1; −3)  𝑦 = 2𝑥 − 1 −3 = 2(−1) − 1 −3 = −3 60. A 𝑦 = −3𝑥 + 5  𝑚𝐴𝐵 = 𝑚𝐶𝐷 …Ewewydige lyne 𝑦 = −3𝑥 + 𝑐 ∴ 2 = −3(1) + 𝑐 𝑐=5 Afdeling A totaal 60 Graad 9 Wiskunde V1 Nasienriglyn 8 ### Page 9 Downloaded from hlayiso.com AFDELING B  Moet nie die leerder vir dieselfde fout twee keer penaliseer nie.  Geen halfpunte word toegeken nie. NASIENKODES M Metodepunt A Akkuraatheidspunt KA Konsekwente/ deurlopende akkuraatheidspunt Punt Nr. Verwagte antwoord Verduideliking 61. 𝑦 = 3𝑥 − 5 𝐌 Algemene term: 1 punt 3 Substitisie: 1 punt 46 = 3𝑞 − 5 𝐌 Antwoord: 1 punt 51 𝑞= 3 Aanvaar 𝑥 = 17 Antwoord alleenlik volpunte 𝑞 = 17 KA 62. −5𝑦 3 (6𝑦 − 1) − 3𝑦 2 (5 − 10𝑦 2 ) Vereenvoudiging:1 punt 3 5𝑦 2 (𝑦−3) 5𝑦 2 :1 punt 5𝑦 2 −30𝑦 4 + 5𝑦 3 − 15𝑦 2 +30𝑦 4 Antwoord:1 punt = 𝐌 5𝑦 2 5𝑦 3 − 15𝑦 2 = 5𝑦 2 5𝑦 2 (𝑦 − 3) = 𝐌 5𝑦 2 = 𝑦 − 3KA OF 𝑦 2 (6𝑦 − 1) 3𝑦 2 (5 − 10𝑦 2 ) − Vereenvoudiging:1 punt −𝑦 5𝑦 2 −6𝑦 2 + 𝑦 − 3 + 6𝑦 2 :1 punt 6𝑦 3 − 𝑦 2 15𝑦 2 − 30𝑦 4 Anwoord:1 punt = − 𝐌 −𝑦 5𝑦 2 6𝑦 3 𝑦 2 15𝑦 2 30𝑦 4 = − − + −𝑦 −𝑦 5𝑦 2 5𝑦 2 = −6𝑦 2 + 𝑦 − 3 + 6𝑦 2 M = 𝑦 − 3 KA Graad 9 Wiskunde V1 Nasienriglyn 9 ### Page 10 Downloaded from hlayiso.com Punt Nr. Verwagte antwoord Verduideliking 63. Laat 𝑥 die massa van die voertuig Vergelyking: 1 punt 4 Vereenvoudiging: 1 punt voorstel. 𝑥 = 1275 kg: 1 punt 𝑥 Antwoord: 1 punt 900 + 120 + = 𝑥 𝐌 5 4500 + 600 + 𝑥 = 5𝑥 𝐌 4𝑥 = 5100 𝑥 = 1275 kg KA 𝑥 ∴ Enjinmassa = 5 =255 kg KA OR Laat 𝑥 die massa van die voertuig Vergelyking: 1 punt voorstel Vereenvoudiging: 1 punt 𝑥 = 1275 kg: 1 punt 𝑥 900 + 120 + = 𝑥 𝐌 Antwoord: 1 punt 5 4 900 + 120 = 𝑥 𝐌 5 4𝑥 = 5100 𝑥 = 1275 kg KA 𝑥 ∴ Die voertuig se enjin = 5 = 255 kg KA 64.     Graad 9 Wiskunde V1 Nasienriglyn 10 ### Page 11 Downloaded from hlayiso.com Punt Nr. Verwagte antwoord Verduideliking 64.1 Op die grafiek A Korrekte stip van enige 2 punte:1 punt (3) Korrekte 𝑦-afsnit:1 punt Vorm van die grafiek:1 punt 64.2 Op die grafiek A Korrekte teken van die grafiek: 1 punt (1) 64.3 Afstand tussen 𝑥-afsnit = 6 Antwoord: 1 punt (1) eenhede KA Afdeling B totaal 15 Graad 9 Wiskunde V1 Nasienriglyn 11 ## Related documents - [Maths P2 Afrikaans Marking guideline](https://www.hlayiso.com/library/maths-p2-afrikaans-marking-guideline/c5298565-1253-45f9-bd19-82899801ab15) — Mathematics · Memo · 2023 · Afr - [Maths P2 Afrikaans Test](https://www.hlayiso.com/library/maths-p2-afrikaans-test/469906bd-339b-433f-8f1b-f55c896fcb71) — Mathematics · QP · 2023 · Afr - [Gr 9 Mathematics P1 (Afrikaans) 2023 Question Paper](https://www.hlayiso.com/library/gr-9-mathematics-p1-afrikaans-2023-question-paper/3bb2171c-2597-4455-beda-80e4db341aec) — Mathematics · QP · 2023 · Afr - [Grade 9 Maths Afrikaans Memo](https://www.hlayiso.com/library/grade-9-maths-afrikaans-memo/8c2c466d-8c22-4425-9370-4ea02b22065c) — Mathematics · Memo · 2022 · Afr - [Gr 9 Math (Afrikaans) June 2023 Question Paper](https://www.hlayiso.com/library/gr-9-math-afrikaans-june-2023-question-paper/135ff87d-7467-4a76-ad0b-5d9d4f8b5bce) — Mathematics · QP · 2023 · Afr - [Gr 9 Mathematics P2 (Afrikaans) 2023 Question Paper](https://www.hlayiso.com/library/gr-9-mathematics-p2-afrikaans-2023-question-paper/573efe48-5a3e-4262-b948-fe2c092ef322) — Mathematics · QP · 2023 · Afr ## More from Grade 9 Mathematics - [FS Maths Grade 9 MOCK November 2025 P2 and Memo](https://www.hlayiso.com/library/fs-maths-grade-9-mock-november-2025-p2-and-memo/411ff601-2320-4073-a074-74427663bad7) — QP + Memo · 2025 - [KZN Zululand Maths Grade 9 March 2025 QP and Memo](https://www.hlayiso.com/library/kzn-zululand-maths-grade-9-march-2025-qp-and-memo/a5d0e368-52a3-4816-b3aa-3597ee4f5a9f) — QP + Memo · 2025 - [Maths Grade 9 June 2025 QP and Memo](https://www.hlayiso.com/library/maths-grade-9-june-2025-qp-and-memo/1c92dc3a-8522-46ea-9bc2-251685906fd8) — QP + Memo · 2025 - [2024 G9 Mock June Test Free State](https://www.hlayiso.com/library/grade-9-mathematics-2024-free-state-june-exam-question-paper/3628eaa4-69bb-4e63-a6b9-8c072d118cdb) — QP · 2024 - [2024 G9 Mock June Test Free State.docx](https://www.hlayiso.com/library/grade-9-mathematics-2024-free-state-june-exam-question-paper/7d033d41-fed7-4c04-a7cc-78d6c025aa9b) — QP · 2024 - [Gr 9 Mathematics P1 (Afrikaans) June 2024 Question Paper](https://www.hlayiso.com/library/gr-9-mathematics-p1-afrikaans-june-2024-question-paper/83b4d57e-57a4-48aa-b3fd-51eb6041a3ba) — QP · 2024 · Afr ## Collection - [Grade 9 past papers](https://www.hlayiso.com/grade-9/past-papers) --- Hlayiso: free CAPS and IEB past papers, memos, notes and study guides for South African learners. 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