# Mathematics Grade 9 Paper 1 GEC Test 2023 Memo (English)

> Grade 9 Mathematics Paper 1 memorandum from the GEC Test 2023 (English), 11 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/maths-english-p1-marking-guideline/7586fddb-e2d4-46cf-a658-b78fa757ddd7
- Updated: 2026-09-27
- Subject: Mathematics
- Grade: Grade 9
- Language: English
- Document type: Memorandum
- Year: 2023
- Exam period: GEC Test
- Paper: 1
- Curriculum: CAPS
- Pages: 11

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                                            GEC PILOT STUDY
                                         MARKING GUIDELINE 2023
                                         MATHEMATICS PAPER1
                                               GRADE 9

SECTION A

             One mark per answer.
             There are no half marks.

      No.                     Expected answer                            Clarification

 1.       B      Irrational                       
 2.       B      108                                     12 = 2 × 2 × 3
                                                          18 = 2 × 3 × 3
                                                          27 = 3 × 3 × 3
                                                          2 × 2 × 3 × 3 × 3 = 108
 3.       A      2                                       Numerators
                 3                                         8 = 23
                                                          12 = 22 × 3
                                                          HCF= 2 × 2 = 4
                                                          Denominators
                                                          30 = 2 × 3 × 5
                                                          36 = 22 × 32
                                                          HCF = 2 × 3 = 6
                                                                  4 2
                                                          HCF = =
                                                                  6 3

 4.       C                                       

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      No.                 Expected answer                                Clarification

 5.    A    103,13 km/h                                    𝑑
                                                      𝑠=
                                                            𝑡
                                                            𝑑
                                                    120 =
                                                           2,75
                                                      𝑑 = 120 × 2,75
                                                      𝑑 = 330 km
                                                          330
                                                      𝑠=
                                                          3,2
                                                      𝑠 = 103,13 km/h
 6.    D    R1 339,42                               𝐴 = 𝑃(1 + 𝑖)𝑛
                                                                     12 2
                                                     𝐴 = 𝑅5 265 (1 +     )
                                                                     100
                                                     𝐴 = 𝑅5 265(1 + 0,12)2
                                                     𝐴 = 𝑅5 265(1,12)2
                                                     𝐴 = 𝑅5 265(1,2544)
                                                     𝐴 = 𝑅6 604,42
                                                    𝐶𝐼 = 𝑅6 604,42 − 𝑅5 265
                                                    𝐶𝐼 = 𝑅1 339,42
 7.    C    −7 × (11 × 4)                   

 8.    B    8                                      3(4) − 2(2) = 12 − 4
                                                                =8
 9.    D              1                     
            2 and −
                      2
 10. C      14                                     2( − 3) − (5) − 4(6 ÷ 8)
                                                             5−6
                                                                    3
                                                       −6 − 5 − 4 ( )
                                                    =               4
                                                             −1
                                                       −14
                                                    =
                                                        −1
                                                    = 14
 11. A      1                                                   3
                                                    √49 − 23 + √216 ÷ 3
                                                    =7−8+6÷3
                                                    =7−8+2
                                                    =1
 12. C      1                                        3
                                                           +5   −4 + 5
            5                                       √ √−64    =√
                                                        2
                                                       4 +3 2    16 + 9

                                                                   1
                                                                =√
                                                                  25
                                                                     1
                                                                =
                                                                     5
 13. A      𝑎5 𝑐                                   𝑎3 × 𝑎2 𝑐
                                                    = 𝑎5 𝑐

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   No.                 Expected answer                                 Clarification

 14. C     2𝑥+2                                   4𝑥+1
                                                    2𝑥
                                                     (22 )𝑥+1
                                                   =
                                                         2𝑥
                                                        2𝑥+2
                                                      2
                                                   =
                                                        2𝑥
                                                        2𝑥+2−𝑥
                                                   = 2
                                                   = 2𝑥+2
 15. B     𝑏+𝑎                                    𝑎−1 + 𝑏 −1
            𝑎𝑏                                        1 1
                                                   = +
                                                      𝑎 𝑏
                                                      𝑏+𝑎
                                                   =
                                                        𝑎𝑏
 16. B     1                                      (2 )3 × (23 )−2
                                                     2

                                                   = 26 × 2−6
                                                   = 20
                                                   =1
 17. A          8𝑥 3                                  𝑥 −3 𝑦
                                                                  −3
           −                                         (        )
                𝑦3                                     −2𝑥 −2
                                                                  3
                                                      −2𝑥 −2
                                                   = ( −3 )
                                                      𝑥 𝑦
                                                             3
                                                     −2𝑥 3
                                                   =( 2 )
                                                     𝑥 𝑦
                                                         2𝑥 3
                                                   = (−      )
                                                          𝑦
                                                        8𝑥 3
                                                   = − 3
                                                         𝑦
 18. D     7                                      3(𝑥 + 𝑦)0            (𝑥 −1 𝑦)3
                                                               + 5𝑦 −1 − −3 4
           𝑦                                           𝑦                 𝑥 𝑦
                                                                        −3 3
                                                     3×1           1 𝑥 𝑦
                                                   =        + 5 × − −3 4
                                                       𝑦           𝑦 𝑥 𝑦
                                                     3 5 1
                                                   = + −
                                                     𝑦 𝑦 𝑦
                                                     7
                                                   =
                                                     𝑦
 19. B     35                                     3 + 5 ; 8 + 7 ; 15 + 9 ; 24 + 11 = 35
                                                   OR
                                                   Perfect squares −1
                                                   22 − 1 = 3
                                                   32 − 1 = 8
                                                   42 − 1 = 15
 20. C     83                                     3 + 6 + 10 + 15 + 21 + 28 = 83

Grade 9 Mathematics P1 Marking Guideline       3

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   No.                  Expected answer                            Clarification

 21. A     A constant ratio of three was   
           used.
 22. C     𝑇𝑛 = −2𝑛 + 7                           1; 3; 5; 7; … are not consecutive term
                                                   positions
                                                   5; 𝑎; 1; 𝑏; −3; 𝑐; …
                                                   𝑎−5=1−𝑎
                                                       2𝑎 = 6
                                                      2𝑎 6
                                                          =
                                                       2     2
                                                        𝑎=3
                                                   5; 3; 1; … are consecutive terms
                                                   3−5=1−3
                                                        𝑑 = −2
                                                   𝑇1 = −2(1) + ___ = 5
                                                   𝑇2 = −2(2) + ___ = 3
                                                   𝑇3 = −2(3) + ___ = 1
                                                   𝑇𝑛 = −2𝑛 + 7
 23. A     3𝑥 3 and 3𝑥(𝑥 2 )               

 24. D     −8 and 6th                             (−2𝑥 2 )3
                                                   = (−2)3 (𝑥 2 )3
                                                   = −8𝑥 6
                                                   Coefficient is −8 and degree is 6th
 25. C     𝑥 + 3𝑥 2 + 2 − 4𝑥               

 26. A     −4𝑥 3 − 2𝑥 2 + 𝑥                       −𝑥(4𝑥 2 + 2𝑥 − 1)
                                                   = −4𝑥 3 − 2𝑥 2 + 𝑥
 27. A     3𝑥 2 − 10𝑥 + 1                                     4𝑥 + 2
                                                   3𝑥(𝑥 − 4) +
                                                                   2
                                                                  4𝑥    2
                                                   = 3𝑥(𝑥 − 4) + 2 + 2

                                                   = 3𝑥 2 − 12𝑥 + 2𝑥 + 1
                                                   = 3𝑥 2 − 10𝑥 + 1
                                                    OR
                                                     2 × 3𝑥(𝑥 − 4) + 4𝑥 + 2
                                                   =
                                                                 2
                                                     6𝑥 2 − 24𝑥 + 4𝑥 + 2
                                                   =
                                                               2
                                                        2
                                                     6𝑥     20𝑥 2
                                                   =      −      +
                                                      2      2     2
                                                        2
                                                   = 3𝑥 − 10𝑥 + 1

Grade 9 Mathematics P1 Marking Guideline       4

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   No.                 Expected answer                               Clarification

 28. A     𝑥                                      3
                                                   √0,125𝑥 3
           2
                                                     3 1
                                                   = √ 𝑥3
                                                       8

                                                     3 1
                                                   = √ 3 𝑥3
                                                       2
                                                              1
                                                      1     3
                                                   = ( 3 𝑥3)
                                                      2
                                                          1
                                                       1 3       1
                                                   = ( 3 ) (𝑥 3 )3
                                                      2
                                                     1
                                                   = 𝑥
                                                     2
                                                     𝑥
                                                   =
                                                     2
 29. C              17𝑥                                          1
           2𝑥 2 +       −1                         (𝑥 + 3)(2𝑥 − )
                     3                                            3
                                                            𝑥       3
                                                   = 2𝑥 2 − + 6𝑥 −
                                                            3       3
                                                            𝑥 + 18𝑥
                                                   = 2𝑥 2 −         −1
                                                                3
                                                            17𝑥
                                                   = 2𝑥 2 +     −1
                                                              3
 30. D     16                                            1 2
                                                   −8 (− ) + 10(2) − 2
                                                          2
                                                          1
                                                   = −8 ( ) + 20 − 2
                                                          4
                                                   = −2 + 20 − 2
                                                   = 16
 31. A     (2𝑥 − 3)(2𝑥 + 3)                

 32. B     (𝑥 − 8)(𝑥 + 3)                  

 33. A     6(𝑦 − 3)(𝑦 + 1)                 

 34. B     𝑥+2                                    2𝑥 2 − 2𝑥 − 12
                                                       2𝑥 − 6
                                                     2(𝑥 2 − 𝑥 − 6)
                                                   =
                                                        2(𝑥 − 3)
                                                     2(𝑥 + 2)(𝑥 − 3)
                                                   =
                                                         2(𝑥 − 3)
                                                   =𝑥+2

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   No.                Expected answer                              Clarification

 35. A     𝑥+𝑦+1                                  (𝑥 + 𝑦)2 − 1
                                                    𝑥+𝑦−1
                                                     (𝑥 + 𝑦 − 1)(𝑥 + 𝑦 + 1)
                                                   =
                                                            𝑥+𝑦−1
                                                   =𝑥+𝑦+1

 36. A     2                               

 37. B     2                                      2𝑝 4
                                                      =
                                                    2   2
                                                    𝑝=2

 38. D     𝑥 = 0 or 𝑥 = 1                  

 39. D     𝑏 = 3 or 𝑏 = −2                 

 40. B     2𝑥 − 8 = 18                     

 41. C     4                                      𝑦 = 16 − 12
                                                   𝑦=4

 42. C     −2                                     3𝑚 = 9−1
                                                   3𝑚 = (32 )−1
                                                   3𝑚 = 3−2
                                                    𝑚 = −2

 43. D     𝑝 = 17 and 𝑡 = 6                       𝑦 = 𝑥2 + 1
                                                   𝑝 = (−4)2 + 1
                                                   𝑝 = 16 + 1
                                                   𝑝 = 17
                                                   and
                                                    𝑦 = 𝑥2 + 1
                                                   37 = 𝑡 2 + 1
                                                   𝑡 2 = 36
                                                     𝑡 = ±6
                                                   ∴𝑡=6

 44. D     𝑥 = −6 or 𝑥 = 1                        𝑥 2 + 3𝑥 + 2𝑥 − 6 = 0
                                                         𝑥 2 + 5𝑥 − 6 = 0
                                                      (𝑥 + 6)(𝑥 − 1) = 0
                                                   𝑥 = −6 or 𝑥 = 1

Grade 9 Mathematics P1 Marking Guideline       6

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   No.                  Expected answer                             Clarification

 45. B     𝑎 = 0 or 𝑎 = 4                           1        1
                                                   ( 𝑎 − 1) ( 𝑎 − 1) = 1
                                                     2        2
                                                          1 2
                                                            𝑎 −𝑎+1=1
                                                          4
                                                              1 2
                                                                𝑎 −𝑎 =0
                                                              4
                                                              𝑎2 − 4𝑎 = 0
                                                             𝑎(𝑎 − 4) = 0
                                                        𝑎 = 0 or 𝑎 − 4 = 0
                                                        𝑎 = 0 or 𝑎 = 4
                                                   OR
                                                   1
                                                     𝑎 − 1 = ±1
                                                   2
                                                   1               1
                                                   2
                                                     𝑎 − 1 = 1 or 2 𝑎 − 1 = −1
                                                       1               1
                                                       2
                                                         𝑎 = 2 or      2
                                                                         𝑎=0
                                                        𝑎 = 4 or       𝑎=0
 46. B     2m                                      𝐴 = (𝑥 − 18)(𝑥)
                                                   40 = 𝑥 2 − 18𝑥
                                                    0 = 𝑥 2 − 18𝑥 − 40
                                                    0 = (𝑥 − 20)(𝑥 + 2)
                                                   𝑥 = 20 or 𝑥 = −2
                                                   ∴ 𝑥 = 20
                                                   breadth = 20 − 18
                                                   breadth = 2 m
 47. A     𝑏 = 33                                 𝑦 = 4𝑥 − 3
                                                   𝑏 = 4(9) − 3
                                                   𝑏 = 33
 48. C                                     
              𝒙         −2     0      2
              𝒚         −8    −2      4

 49. B     𝑚 = (𝑛 + 1)2                           𝑚 = (𝐸𝑣𝑒𝑛 + 1)2
                                                   𝑚 = (𝑂𝑑𝑑)2
                                                   𝑚 = 𝑂𝑑𝑑
 50. D         1                                        1
           𝑦 =− 𝑥+1                                𝑚=−
               2                                         2
                                                   𝑦-intercept at (0; 1) and 𝑐 = 1
                                                       1
                                                   𝑦 =− 𝑥+1
                                                       2
 51. D     𝑉 = 4𝑡 + 6                             Common difference = 4
                                                                   𝑉 = 4𝑡 + 𝑐
                                                   By inspection: 𝑉 = 4𝑡 + 6

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   No.                   Expected answer                          Clarification

 52. A                                            𝑐 = 40𝑡 + 500
                                                   𝑦-intercept = R500 and the gradient = 40

 53. B     (0; −5)                         

 54. D     1                                           𝑦 = 2𝑥 − 2
                                                   2𝑥 − 2 = 0
                                                       2𝑥 = 2
                                                        𝑥=1
 55. C         3                           
           −
               4
 56. B                                     
                                                       𝒙         −4           −2       2
                                                      𝒚          −1           −2      −4

 57. C                                            Constant difference of 8
               𝒙     1      2    3     4
               𝒚     12     20   28   36
 58. D     −2𝑥 + 𝑦 − 2 = 0                        −2𝑥 + 𝑦 − 2 = 0
                                                             𝑦 = 2𝑥 + 2
 59. B     (−1; −3)                                𝑦 = 2𝑥 − 1
                                                   −3 = 2(−1) − 1
                                                   −3 = −3
 60. A     𝑦 = −3𝑥 + 5                            𝑚𝐴𝐵 = 𝑚𝐶𝐷 …Parallel lines
                                                     𝑦 = −3𝑥 + 𝑐
                                                   ∴ 2 = −3(1) + 𝑐
                                                     𝑐=5
                                                                   Section A total     60

Grade 9 Mathematics P1 Marking Guideline       8

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SECTION B

      Do not penalise the learner for the same mistake twice.
      There are no half marks.

 MARKING CODES
    M     Method mark
    A     Accuracy mark
   CA     Consistent Accuracy mark

 No.                Expected answer                          Clarification                  Mark

 61.      𝑦 = 3𝑥 − 5 𝐌                                           General term: 1 mark 3
                                                                   Substitution: 1 mark
         46 = 3𝑞 − 5 𝐌
                                                                      Answer: 1 mark
               51
          𝑞= 3
                                                                        Accept 𝑥 = 17
          𝑞 = 17 CA                                             Answer only full marks
 62.    −5𝑦 3 (6𝑦 − 1) − 3𝑦 2 (5 − 10𝑦 2 )                        Simplification:1 mark 3
                                                                        5𝑦 2 (𝑦−3)
                      5𝑦 2                                                        :1 mark
                                                                           5𝑦 2
            −30𝑦 4 + 5𝑦 3 − 15𝑦 2 +30𝑦 4                                Answer:1 mark
        =                                𝐌
                       5𝑦 2
            5𝑦 3 − 15𝑦 2
        =
                5𝑦 2
            5𝑦 2 (𝑦 − 3)
        =                𝐌
                5𝑦 2
        = 𝑦 − 3CA
        OR
        𝑦 2 (6𝑦 − 1) 3𝑦 2 (5 − 10𝑦 2 )
                    −                                             Simplification:1 mark
             −𝑦             5𝑦 2                            −6𝑦 2 + 𝑦 − 3 + 6𝑦 2 :1 mark
            6𝑦 3 − 𝑦 2 15𝑦 2 − 30𝑦 4                                    Answer:1 mark
        =             −              𝐌
               −𝑦           5𝑦 2
          6𝑦 3   𝑦 2 15𝑦 2 30𝑦 4
        =      −    −     +
          −𝑦     −𝑦 5𝑦 2    5𝑦 2
        = −6𝑦 2 + 𝑦 − 3 + 6𝑦 2 M
        = 𝑦 − 3 CA

Grade 9 Mathematics P1 Marking Guideline          9

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 No.              Expected answer                          Clarification                Mark

 63.    Let 𝑥 be the mass of the car                               Equation: 1 mark 4
                      𝑥                                        Simplification: 1 mark
         900 + 120 + = 𝑥 𝐌                                     𝑥 = 1275 kg: 1 mark
                      5
                                                                    Answer: 1 mark
        4500 + 600 + 𝑥 = 5𝑥 𝐌
                     4𝑥 = 5100
                      𝑥 = 1275 kg CA
                             𝑥
        ∴ The car’s engine =
                             5
                           = 255 kg CA
        OR
        Let 𝑥 be the mass of the car                               Equation: 1 mark
                       𝑥                                       Simplification: 1 mark
         900 + 120 + = 𝑥 𝐌                                     𝑥 = 1275 kg: 1 mark
                       5
                      4                                             Answer: 1 mark
        900 + 120 = 𝑥 𝐌
                      5
                     4𝑥 = 5100
                      𝑥 = 1275 kg CA
                             𝑥
        ∴ The car’s engine =
                             5
                           = 255 kg CA
 64.

                           

                                                              

                                           
                            

 64.1   On graph A                          Correct plotting of any 2 points:1 mark (3)
                                                           Correct 𝑦-intercept:1 mark
                                                              Shape of graph: 1 mark
 64.2   On graph A                                 Correct drawing of graph: 1 mark (1)

Grade 9 Mathematics P1 Marking Guideline        10

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 No.              Expected answer                 Clarification             Mark

 64.3   Distance between 𝑥- intercepts = 6                  Answer: 1 mark (1)
        units CA
                                                           Section B total 15

Grade 9 Mathematics P1 Marking Guideline     11

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- [2024 G9 Mock June Test Free State.docx](https://www.hlayiso.com/library/grade-9-mathematics-2024-free-state-june-exam-question-paper/7d033d41-fed7-4c04-a7cc-78d6c025aa9b) — QP · 2024

## Collection

- [Grade 9 past papers](https://www.hlayiso.com/grade-9/past-papers)

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Hlayiso: free CAPS and IEB past papers, memos, notes and study guides for South African learners. When citing, link the page URL above, not a PDF or /api/ URL.
