# Mathematical Literacy Grade 11 P1 2018 Memo (Eng)

> Grade 11 Mathematical Literacy Paper 1 memorandum from the Eastern Cape November 2018 (English), 6 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/maths-lit-p1-gr11-memo-nov2018-english-final/5944100a-c394-4f99-980a-3bce6f038d91
- Updated: 2026-09-27
- Subject: Mathematical Literacy
- Grade: Grade 11
- Language: English
- Document type: Memorandum
- Year: 2018
- Exam period: Eastern Cape November
- Paper: 1
- Curriculum: CAPS
- Pages: 6

Breadcrumbs: [Home](https://www.hlayiso.com/) › [Library](https://www.hlayiso.com/library) › [Grade 11](https://www.hlayiso.com/library/grade-11) › [Mathematical Literacy](https://www.hlayiso.com/library/grade-11/mathematical-literacy) › [Mathematical Literacy Grade 11 P1 2018 Memo (Eng)](https://www.hlayiso.com/library/maths-lit-p1-gr11-memo-nov2018-english-final/5944100a-c394-4f99-980a-3bce6f038d91)

## About this document

Mathematical Literacy · Grade 11 · Eastern Cape November · 2018 · English. Memorandum, 6 pages. Read online or download the PDF.

Read it free online on the page above; download the PDF from there.

## Document text

Text extracted from the PDF. Layout, diagrams and tables may not survive extraction.

### Page 1

Downloaded from hlayiso.com

                        NATIONAL
                   SENIOR CERTIFICATE

                            GRADE 11

                        NOVEMBER 2018

            MATHEMATICAL LITERACY P1
               MARKING GUIDELINE
MARKS: 100

 Symbol      Explanation
 M           Method
 MA          Method with accuracy
 CA          Consistent accuracy
 A           Accuracy
 C           Conversion
 S           Simplification
 RT/RG/RM    Reading from a table/Reading from a graph/Reading from map
 F           Choosing the correct formula
 SF          Substitution in a formula
 J           Justification
 P           Penalty, e.g. for no units, incorrect rounding off etc.
 R           Rounding Off/Reason
 AO          Answer only
 NPR         No penalty for rounding

                        This marking guideline consists of 6 pages.

### Page 2

Downloaded from hlayiso.com
        2                              MATHEMATICAL LITERACY P1              (EC/NOVEMBER 2018)

QUESTION 1 [21]
Ques                             Solutions                               Explanation                 T&L
1.1.1 R2 578 799                                                                                      F
      Two million, five hundred and seventy eight thousand seven                                      L1
      hundred and ninety nine rand A
                                                                   2A Write in words      (2)
                                                                                                     F
                             M
1.1.2                   386 819,85                                 1M Correct values                 L1
            % Deposit =             100 M                        1M Multiply by 100
                         2 578 799

                       = 15%   A                                  1A Answer in %         (3)
                                                                                                     F
1.1.3       R386 819,85                A                          1A Correct value                  L1
                                               386 819,85
            Transaction Cost = R5,75 + R1,10 × 100 M
                                                                   1M Dividing by 100
                             = R5,75 + R4 255,02
                                                                   1CA Transaction cost (3)
                             = R4 260,77 CA
                                                                   NPR
                                                                                                     M
1.2.1       Distance = 82,3 – 26,9 MRT                           1RT Correct distances             L1
                     = 55,4 km  CA                                1M Subtraction
                                                                   1CA Distance          (3)
                                                                                                     M
1.2.2       Time taken = 04:54:45 – 03:05:14 M                    1MA Subtracting correct           L1
                       = 01:49:31 CA                              times
                                                                   1CA Time             (2)
                                                                                                     M
1.2.3       Distance in metres = 68,9 × 1 000 C                   1C Multiply by 1 000              L1
                               = 68 900 m A                       1A Distance in metres (2)
                                                                                                     D
1.3.1       12, 8, 7, 5, 2, RG M                                 1RG Correct values                L1
                                                                   1M Descending order (2)
                                                                                                     D
1.3.2       Bar graph OR Column graph  A                         2A Correct graph    (2)           L1
                                                                   CA from 1.3.1                     D
1.3.3       Total number of houses = 12 + 8 + 7 + 5 + 2 RG        1RG Values from the               L1
                                   = 34 A                         graph
                                                                   1A Number of houses (2)
                                                                                                     [21]

        Copyright reserved                                                        Please turn over

### Page 3

Downloaded from hlayiso.com
        (EC/NOVEMBER 2018)           MATHEMATICAL LITERACY P1                               3

QUESTION 2 [29]
Ques                                    Solution                     Explanation                T&L
                                                                                                 F
2.1.1      R2 250  RT                                           2RT Break-even                 L1
                                                                  amount         (2)
                                                                                                F
2.1.2      Cost of A = R1 500 + R5,00(50) SF                     1SF Substitution              L1
                    = R1 500 + R250  S                           1S Simplification
                    = R1 750 CA                                  1CA Answer
                                                                                      (3)
                                                                                                F
2.1.3      Income = R15,00 × 250                                1RT Correct values            L1
                  = R3 750,00                                     1M Multiplication
                                                                                   (2)
                                                                                                F
2.1.4      Profit = Income – Expenses                             1RT Correct values            L1
                  = R5 250 – R3 250 RT M                        1M Subtraction
                  = R2 000 A                                     1M Profit       (3)
                                                                                                F
2.2.1       1st year = R60 000 × 8,5% M                          1M Multiplication             L2
                     = R5 100   A                                1CA Interest     (2)
                                                                  CA from 2.2.1                 F
2.2.2       st
           1 year total amount     = R5 100 +R60 000 M           1M Adding interest            L2
                                   = R65 100  CA                 1CA Amount
           2nd year total amount = R65 100 × 8,5 %                1CA % calculation
                                   = R5 533,50 CA                1M Adding interest
           Total at the end of 2 years = R65 100 + R5 533,50 M   1CA Total amount
                                       = R70 633,50 CA                             (5)
           Water used = 587-561                                   1M Water used                 F
2.3.1                   = 26 kℓ M                                1RT Free kℓ                   L2
           Cost = (0 × 6 kℓ) A + (20 × R10,02)  M               1M Multiplying by
                = R200,40 CA                                     R10,02
           Total cost = 200,40 + 80,70                            1CA Water cost
                      = R281,10 CA                               1CA Cost including
                                                                  additional charge (5)
                                                                                                F
2.3.2      VAT amount = R80,70 × 15% M                           1M Multiplying                L1
                      = R12,105 S                                1S Simplification
                      = R12,10 R                                 1R Rounding
                                                                  (Accept R 12,11)(3)

        Copyright reserved                                                 Please turn over

### Page 4

Downloaded from hlayiso.com
        4                                MATHEMATICAL LITERACY P1                         (EC/NOVEMBER 2018)

                                                                                                               F
2.4.1       Inflation rate is a measure of inflation expressed in % showing the      2A Explanation            L1
            increase in price of goods and services. A
            OR
            The rate at which price increases over time if there is a decline in the
            purchasing value of money A                                                           (2)
                                                                                                               F
2.4.2       Price of brown bread in 2017                                          1M Multiply                  L1
            = (1 + 6,59 %) × R9,99  M                                            correct values
            = R10,65  A                                                          1A Cost        (2)

                                                                                                               [29]

QUESTION 3 [17]
Ques                                       Solution                                   Explanation           T&L
                                                                                                             M
3.1.1       12 miles  RT                                                         1RT Correct value          L1
            Distance = 12 × 1,609                                                 1A Answer in km
                     = 19,308 km A                                               NPR             (2)
                                                                                                               M
3.1.2                                68                                           1RT Correct value
            Humidity of Cape Town =      RT                                                                   L1
                                    100
                                    17
                                  =
                                    25  A
                                                                                  1A Simplified
                                                                                  fraction          (2)
                                                                                                               M
3.1.3       Time of sunset in Cape Town = 17:27                                                                L1
            12-hour format = 05:27 pm  A                                        2A Correct time (2)
                                                                                                               M
3.1.4          ℉ = (℃ × 1,8) + 32                                                                              L2
                 = (17 × 1,8) + 32  SF                                           1SF Correct value
                 = 62,6  S                                                       1S Simplification
                 = 63 ℉  R                                                       1R Rounding (3)
                                                                                                               M
3.2.1       Volume = Length × Width × Height                                      1SF Substitution             L2
                   = 30 in × 12 in × 7,1 in  SF                                  1S Simplification
                   = 2 556 in3 S A                                              1A Correct unit (3)

        Copyright reserved                                                                     Please turn over

### Page 5

Downloaded from hlayiso.com
        (EC/NOVEMBER 2018)           MATHEMATICAL LITERACY P1                               5

                                                                   CA from 3.2.1                 M
3.2.2      Volume of the tank = 2 556 in × 85% M
                                       3
                                                                   1M Multiply by                L3
                              = 2 172,6 in3 CA                    85%
                                                                   1CA Volume

           Increased volume after stones added = 2556 × 97%
                                               = 2479,32 in3 CA   1CA Volume
           Volume of stones = 2479,32 – 2 172,6 M                 1M subtraction
                            = 306,72 in3 CA                       1CA Volume
                                           OR
           Volume of stones = 97% - 85% M M                      1M Using correct
                            = 12% × 2556 M M                     values
                            = 306,72 in3 CA                       1M Subtraction
                                                                   2M Multiplication
                                                                   by 12% and 2556
                                                                   1CA Volume of
                                                                   stones          (5)
                                                                                                 [17]

QUESTION 4 [13]
Ques                                  Solutions                       Explanation            T&L
                                                                                             M&P
4.1        Hartford RM                                           2RM Correct city           L1
                                                                                      (2)

4.2        Distance on the map = 7,5 cm
                        2,5 cm = 100 miles M                      1M Scale measure          M&P
                            7,5                                    (use the scale as          L2
                                = 3 cm S                          from actual map)
                            2,5
                                                                   1S Division
           3 × 100 = 300 miles CA
                                                                   1CA Multiply by
                                                                   100            (3)
                                                                                             M&P
4.3        84and 87  RG                                          2RG Combination            L1
                                           OR                      of roads
           81,88 and 90 RG                                                      (2)
                                                                                             M&P
4.4        North East A                                          2A Correct direction       L1
                                                                   (2)
                                                                                             M&P
4.5        Road 80  RG                                           2RG Correct road           L1
                                                                                      (2)
                                                                                                 P
4.6                          RG
                             𝟖                                     1A Numerator                  L2
           Probability =     RG
                         𝟏𝟔                                        1A Denominator (2)
                                                                                                 [13]

        Copyright reserved                                                    Please turn over

### Page 6

Downloaded from hlayiso.com
      6                                    MATHEMATICAL LITERACY P1                (EC/NOVEMBER 2018)

QUESTION 5 [20]
Ques                                       Solutions                             Explanation            T&L
                                                                            1M Subtracting correct       D
5.1       Poults not hatched in December = 28 795 – 25 422 M               values                       L1
                                         = 3 373 CA                        1CA Not hatched (2)
                                                                                                            D
5.2       Mean                                                                                              L2
          = 28 927 + 28 409 + 27 179 + 28 795 + 29 961 + 29 906 + 30 030 + 1M Adding
            28 597 + 28 825 + 29 441 + 29 271 + 29 725  M                 1M Dividing by 12
            349 066                                                        1CA Mean
          =         M
              12                                                           NPR               (3)
          = 29 088,93 CA
                                                                                                            D
5.3       No modal value A                                                2A Modal value       (2)        L1
                                                                                                            D
5.4       Range = highest value – lowest value                              1MA Subtracting                 L2
                = 25 719 – 22 782 MA                                       correct values
                = 2 937 CA                                                 1CA Range            (2)
                                                                                                            D
5.5       25 719, 25 422, 25 332, 25 075, 24 786, 24 616, 24 067, 23 645,   1M Arranged
                                                                                                            L2
          23 598, 23 572, 23 179, 22 782 A                                 1MA Median concept
                                                                            with correct values
                     24 616  24 067                                        1CA Median          (3)
          Median =          2        MA
                   = 24 341  CA
5.6       Total hatched during 2016-2107= 291 7893 M                       1M Addition
          Hatched in March= 25 719  RT                                     1RT                     D
          Ratio. 25 719 : 29 1793  CA                                      1CA Express a ratio.
                                                                                                (3) L2
                                                                            CA from 5.1.2             P
5.7                        29 271                                           1M Fraction              L2
          P(July eggs) =             × 100 M M
                           349 066                                          1M Multiplying by 100
                      = 8,39 % CA                                          1CA %               (3)
                                                                            NPR
                                                                                                      D
5.8       Compound bar graph A                                            2A Type of graph         L1
                                             OR
          Bar graph A
                                             OR
          Line graph A                                                                         (2)
                                                                                                            [20]

                                                                                         TOTAL:             100

      Copyright reserved                                                                 Please turn over

## Related documents

- [MATHS LIT P2 GR11 MEMO NOV 2018 English](https://www.hlayiso.com/library/maths-lit-p2-gr11-memo-nov-2018-english/5020ea72-3c78-478c-827a-d722ddc68e8e) — Mathematical Literacy · Memo · 2018 · Eng
- [MATHS LIT P1 GR11 MEMO NOV2020 English](https://www.hlayiso.com/library/maths-lit-p1-gr11-memo-nov2020-english/08e52e8a-ef68-4338-9e8e-a0babd449184) — Mathematical Literacy · Memo · 2020 · Eng
- [MATHS LIT P1 MEMO GR11 NOV2017 English](https://www.hlayiso.com/library/maths-lit-p1-memo-gr11-nov2017-english/645e8d7e-f855-44ed-87e8-91f0005958fd) — Mathematical Literacy · Memo · 2017 · Eng
- [MATHS LIT P1 GR11 QP NOV2022 English](https://www.hlayiso.com/library/maths-lit-p1-gr11-qp-nov2022-english/cff66dff-d8c3-4e1b-adf0-692ec2e1a58b) — Mathematical Literacy · QP · 2022 · Eng
- [MATHS LIT P1 GR11 QP NOV2020 English .docx](https://www.hlayiso.com/library/maths-lit-p1-gr11-qp-nov2020-english-docx/fa0c394f-1138-4ab2-9498-7611a1f9e12f) — Mathematical Literacy · QP · 2020 · Eng
- [MATHS LIT P1 GR11 QP NOV 2017 English](https://www.hlayiso.com/library/maths-lit-p1-gr11-qp-nov-2017-english/fec39e1d-6af0-47b5-a096-a661e2066b92) — Mathematical Literacy · QP · 2017 · Eng

## More from Grade 11 Mathematical Literacy

- [Grade 11 Mathematical Literacy P2 November 2026 Mock 2](https://www.hlayiso.com/library/grade-11-mathematical-literacy-2026-november-mock-exam-2-question-paper-paper-2/9e28596c-b065-4744-84e1-a7995223ca68) — QP · 2026 · Eng
- [Gr 11 Maths Lit ATP 2023-24](https://www.hlayiso.com/library/gr-11-maths-lit-atp-2023-24/729b7b1d-095d-46f4-8082-c0c019b4c6c7) — ATP
- [MATHS LIT P2 GR11 NOV25 ADDENDUM ENGLISH FINAL (1) watermark](https://www.hlayiso.com/library/maths-lit-p2-gr11-nov25-addendum-english-final-1-watermark/6d3d1a99-ee4e-4b35-9dfc-765595836d35) — Addendum · 2025 · Eng
- [LP Maths Literacy Grade 11 June 2025 P1 only](https://www.hlayiso.com/library/lp-maths-literacy-grade-11-june-2025-p1-only/010db24d-7d07-4b57-b916-5b4856296406) — QP · 2025
- [FS Maths Literacy Grade 11 June 2025 P1 and Memo](https://www.hlayiso.com/library/fs-maths-literacy-grade-11-june-2025-p1-and-memo/913740d3-d3f7-470f-ad0e-289f4f74f68b) — QP + Memo · 2025
- [GP JW Maths Literacy Grade 11 June 2025 P1 and Memo](https://www.hlayiso.com/library/gp-jw-maths-literacy-grade-11-june-2025-p1-and-memo/4157e22a-6e42-4d3f-8ce9-579e85217581) — QP + Memo · 2025

## Collection

- [Grade 11 past papers](https://www.hlayiso.com/grade-11/past-papers)

---

Hlayiso: free CAPS and IEB past papers, memos, notes and study guides for South African learners. When citing, link the page URL above, not a PDF or /api/ URL.
