# Mathematical Literacy Grade 11 P1 2020 Memo (Eng)

> Grade 11 Mathematical Literacy Paper 1 memorandum from the National Exemplar November Exam 2020 (English), 8 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/maths-lit-p1-gr11-memo-nov2020-eng-d/2ce6aed3-a370-44d9-9f8c-ce84b2c4b34c
- Updated: 2026-09-27
- Subject: Mathematical Literacy
- Grade: Grade 11
- Document type: Memorandum
- Year: 2020
- Exam period: National Exemplar November Exam
- Paper: 1
- Curriculum: CAPS
- Pages: 8

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## About this document

Mathematical Literacy · Grade 11 · National Exemplar November Exam · 2020. Memorandum, 8 pages. Read online or download the PDF.

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## Document text

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### Page 1

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                          NATIONAL
                     SENIOR CERTIFICATE

                                GRADE 11

                         NOVEMBER 2020

               MATHEMATICAL LITERACY P1
                  MARKING GUIDELINE
                     EXEMPLAR
MARKS:   100

   Symbol                                   Explanation
   M            Method
   MA           Method with accuracy
   CA           Consistent accuracy
   A            Accuracy
   C            Conversion
   S            Simplification
   RT/RG/RM     Reading from a table/Reading from a graph/Read from map
   F            Choosing the correct formula
   SF           Substitution in a formula
   J            Justification
   P            Penalty, e.g. for no units, incorrect rounding off etc.
   R            Rounding Off/Reason
   AO           Answer only
   NPR          No penalty for rounding

                    This marking guideline consists of 8 pages.

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2                              MATHEMATICAL LITERACY P1                         (EC/NOVEMBER 2020)

 MARKING GUIDELINES

 NOTE:

 x   If a candidate answers a question TWICE, only mark the FIRST attempt.
 x   If a candidate has crossed out (cancelled) an attempt to a question and NOT redone
     the solution, mark the crossed out (cancelled version)
 x   Consistent accuracy (CA) applies in ALL aspects of the marking guidelines,
     however it stops at the second calculation error.
 x   If the candidate presents any extra solution when reading from a graph, table, layout
     plan and map, then penalise for every extra incorrect item presented.

 LET WEL:

 x   As ŉ kandidaat ŉ vraag TWEE keer beantwoord, merk slegs die EERSTE poging.
 x   As ŉ kandidaat ŉ antwoord van ŉ vraag doodtrek (kanselleer) en nie oordoen nie,
     merk die doodgetrekte (gekanselleerde) poging.
 x   Volgehoue akkuraatheid (CA) word in ALLE aspekte van die nasienriglyn toegepas,
     maar dit hou by die tweede berekeningsfout op.
 x   Wanneer ŉ kandidaat aflesings vanaf ŉ grafiek, tabel, uitlegplan en kaart geneem
     en ekstra antwoorde gee, penaliseer vir elke ekstra verkeerde item.

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        (EC/NOVEMBER 2020)             MATHEMATICAL LITERACY P1                                            3

QUESTION 1 [23 marks]

Ques.                             Solution                                       Explanation                   T&L
1.1.1    Annual gross salary = R10 500 × 12 9 M                           1M Multiply by 12                     F
                             = R126 000     9A                            1A Gross per annum        (2)         L1

1.1.2    Monthly food expense = R10 500 × 36% 9M                          1M % Calculation                     F
                              = R3 780        9CA                         1CA Amount                 (2)       L1

1.1.3    Housing % : Food %                                                                                    F
         = 21% : 36% 9M                                                   1M Correct values and order          L1
         = 7 : 12 9CA                                                     1CA Simplest form        (2)
                                      9M
1.1.4    Savings % = 100% – (21% +36% +10% + 1,9%)                        1M Adding correct values             F
                   = 100% – 68,9%9M                                       1M Subtracting from 100              L1
                   = 31,1% 9CA                                            1CA Percentage           (3)

1.2.1    Primary data 99A                                                 2A Correct data type                 D
                                                                                                    (2)        L1

1.2.2    41 99 RT                                                         2RT Highest mark                     D
                                                                                                    (2)        L1

1.2.3    Median is the middle value of a set of data which is arranged    2A Explanation                       D
         from small to big.        99A                                                              (2)        L1

1.2.4     35 99 A                                                         2A Correct mark                      D
                                                                                                    (2)        L1

1.2.5    3 99 RT                                                          2RT No. of learners failed           D
                                                                                                    (2)        L1

1.3.1    Loss is when the cost is more than the income. 99 A              2A Correct explanation               F
                                      OR                                                                       L1
         Loss incurred when selling price is less than cost price of an
         item. 99 A                                                                                 (2)

1.3.2              ହ଴
         % loss = ଻ହ଴ × 100% 9M                                           1M Fraction multiplied by            F
                                                                            100%                               L1
                = 6,67% 9 CA
                                                                          1CA Percentage
                                                                          NPR                      (2)
                                                                                                  [23]

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        4                                 MATHEMATICAL LITERACY P1                   (EC/NOVEMBER 2020)

QUESTION 2: FINANCE [30 marks]
Ques.                    Solution                                            Explanation                  Topic
                                                                                                          /Level
2.1.1   SmartMAXFocussed Education Plan 1 99 RT                      2A Correct investment plan             F
                                                                                              (2)           L1

2.1.2                         8266 ,470                              1C Converted to Rands                 F
        Number of units =               9C                           1CA Value                             L2
                                  100
                           = R82,6647 9 CA
                              8038 ,07                               1M Division
                           =            9M
                              82 ,6647
                                                                     1CA No. of units
                           = 97,23703104 9 CA                                                    (4)

2.1.3   % loss = 12 924,75 – 6 995,25 9 M                            1M Subtraction of values              F
               = R5 929,50 9 S                                       1S Simplification                     L3
                  5929 ,50 9 M                                       1M Dividing correct values
               =            u 100 9 M                                1M Multiply by 100%
                 12924 ,75
               = 45,88%
                                       OR                                          OR
                           6995 ,25 9  M
        Percentage loss =           u 100 9 M                        1M Dividing correct values
                          12924,75                                   1M Multiply by 100%
                        = 54,12%           9S                        1S Simplification
                        = 100% – 54,12% 9M                           1M Subtraction of %
                        = 45,88%                                                              (4)

2.1.4   B = R8 038,07 – R6 995,25 9 MA                               1MA Subtraction                       F
          = R1 042,82 9C A                                           1CA Correct answer          (2)       L2

2.1.5   R765,57 99RT                                                 2RT Correct value                     F
                                                                                                 (2)       L2
                                 9RT
2.1.6                     366 ,02  332 ,75                          1RT Correct values                    F
            % increase =                    u 100 9 SF               1SF Substitution
                               332 ,75                                                                     L2
                       = 9,998% 9 S                                  1S Simplification
                       = 10% 9 R                                     1R Nearest %                (4)

2.2.1   Number of plates 99 RT                                       2RT Number of plates                  F
                                                                                                 (2)       L2

2.2.2   Fixed expenses = R500 99 RT                                  2RT Fixed expenses                    F
                                                                                                 (2)       L2

2.2.3   Income = R50 × Number of plates sold 9 M 9 A                 1M Multiplication with R50            F
                                                                     1A Correct formula       (2)          L2

2.2.4   R0 OR (No Profit) 99 RT                                      2RT No profit                         F
                                                                                                 (2)       L2

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        (EC/NOVEMBER 2020)          MATHEMATICAL LITERACY P1                                  5

2.2.5   Loss for 8 plates = Expenses – Income                  1RT R740                           F
                            9RT       9 RT                     1RT R400                           L3
                          = 740 – 400 9M                       1M Subtraction
                          = R340 9A                            1A Loss
                                     OR                        (From graph allow 340±10)
                                                                           OR
        Expenses = 500 + 8 × 30 = R740 9M                      IM for R740
        Income = 50 × 8 = R400 9M                              1M for R400
        Loss = 740 – 400 = R340 9A                             1M subtraction
                                                               1A for R340 exact answer (4)
                                                                                       [30]

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      6                                     MATHEMATICAL LITERACY P1                (EC/NOVEMBER 2020)

QUESTION 3: DATA HANDLING (18 marks) AND PROBABILITY (3 marks)
Ques.                           Solution                         Explanation                               T/L
3.1   Total number of spas
      = 30 394 + 13 856 + 3 984 + 6 057 + 46 282 + 48 679 1M Adding correct values                         D
      =149 252 9M 9A                                      1A Total                (2)                      L1

3.2   Mean =
              ଵସଽ ଶହଶ
                   9M                                                  CA from 3.1                         D
               ଺
                                                                       1M Division                         L2
           = 24 875,33
                                                                       1R Whole number
           = 24 875 9 R
                                                                                                 (2)

3.3   European spas as a % =
                                   ସ଺ ଶ଼ଶ
                                    ×100 9M                            1M Fraction with correct            D
                             ଵସଽ ଶହଶ
                                                                         values and                        L2
                          = 31% 9CA
                                                                         multiplication by 100
                                                                       1CA Percentage           (2)

3.4   Range = 48 679 – 3 984                                                                               D
            = 44 695 9S                                                1S Calculate range                  L3
      Number of regions above range = 2 CA9                            1CA Number of regions (2)

3.5                           ସ଼ ଺଻ଽ
      30 394 : 48 679 = 1 : ଷ଴ ଷଽସ 9M 9M                               1M Ratio                            D
                                                                       1M Fraction                         L3
                                                                       1CA Unit ratio
                        =1 : 1,60 9 CA
                                                                       NPR                       (3)

3.6   Revenue in sub-saharan Africa = 6,6 – 5,0 9M                     1M Subtraction                      D
                                      = 1,6 9S                         1S Simplification                   L3
      Total revenue for spas                                           1M Addition
      = 22,9 + 6,6 + 1,6 + 2,8 + 33,3 + 26,5 9M                        1CA Total revenue
      = $93,7 billion 9CA                                              Penalise 1 mark if not in
                                                                       billions                (4)

3.7   1,6; 2,8; 6,6; 22,9; 26,5; 33,3 9M                               CA the value $1,6 from 3.6          D
                                                                       included in the data                L3
      Median revenue =
                           ଺,଺ ା ଶଶ,ଽ
                                        9M                             1M Arranging in order of
                               ଶ                                       descending or ascending
                        = $14,75 billion 9CA                           1M Concept of median
                                                                       1CA Answer in billions (3)

3.8   P (Regions with more than 40 000 spas)                           1RT Correct numerator and           P
                   9RT                                                     denominator                     L2
                  ଶ
                = × 100 9M                                             1M Multiplication by 100
                  ଺
                                                                       1CA Percentage
                = 33,33% 9CA                                           NPR                       (3)
                                                                                                [21]

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      (EC/NOVEMBER 2020)            MATHEMATICAL LITERACY P1                                        7

QUESTION 4: FINANCE (12 marks), DATA HANDLING (11 marks) AND
              PROBABILITY (3 marks)
Ques.                       Solution                          Explanation                               T/L
4.1   Cost =
            Kilolitre      Cost
            6              6 × 0 = 0 9M                 1M Cost of first 6 kℓ                           F
                                                                                                        L4
             9                   9 × 9,35 = R84,15                   1M Cost for both 9 and 10
                                                  9M                    kilolitres
             10                  10 × 11,16 = R111,6
                                                                     1CA Total cost
             Total = 25 litres   84,15 + 111,60 = R195,75 9M
                                         9M                          1M Multiply by 15%
                                 R195 ×115% = R225,11 9CA            1CA Cost including VAT
                                    OR
                9M                9M
      Cost = (6 × 0) + (9 × 9,35) + (10 × 11,16)
           = R84,15 + R111,60
           = R195,75 9CA
      Including VAT = R195,75 × 15% 9M
                      = R29,3625
                      = R195,75 + R29,3625
                      = R225,119CA

      Increased block rate tariffs to encourage saving of water 9A
                                       OR                            1A Reason
      Also assist small businesses or families with free water 9A
      Accept any other sound reason.                                                          (6)

4.2    R0,019 = 1 RWF                                                1M Concept of ratio                F
       R?       = 745 614,04 RWF 9M                                                                     L4
       R?       = 0,019 × 745 614,04 9M                              1M Multiplication
                = R14 166,66676 9S                                   1S Simplification value in R
                                    ଵ଴
      Bank charges = 14166,66676×ଵ଴଴ 9M                              1M Multiplication of 10%
                                                                     1A Value of 10%
                   = R1 416,666676 9A
                                                                     1M Subtraction
      Andile received = R14 166,66676 – 1 416,66676 9 M
                      = R12 750
                                                                     1A Valid
      Statement is valid. 9A
                                                                                 OR
                                    OR
                       ଵ଴                                            1M Multiplication of 10%
      Bank charges =      × 745 614,04 RWF 9M                        1A Value of 10%
                      ଵ଴଴
                    = 74 561,404 9A                                  1M Subtraction
      Andile received in RWF = 745 614,04 – 74 561,404 9M            1S Simplification value
                              = 671 052,636 9S
      In Rands: R0,019        = 1 RWF                                1M Concept of ratio
                     R?       = 671 052,636 RWF 9M                   1M Multiplication
      Andile received = R0,019 × 671 052,636 9M
                      = R12 750
      Statement is valid 9CA                                         1CA Valid               (6)

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        8                                                             MATHEMATICAL LITERACY P1                     (EC/NOVEMBER 2020)

4.3.1   Total absentees = 67 9 M                                                                      1M Addition to 67                   P
        Absentees on Wednesday =16 9A                                                                 1A Absentees on Wed                 L2
        P(absent on Wed) =
                                                       ଵ଺
                                                            9CA                                       1CA Fraction
                                                       ଺଻                                                                       (3)

4.3.2                                                                                                 1A for Monday boys at 5             D
                                             Number of absent learners during the week                1A for Tuesday girls at 6           L2
                                        12                                                            1A for Thurs for girls at 7
                                                                                                      1A for Thurs for boys at 9
                                        10                                                            1A for Fri for boys at 7

            Number of absent learners
                                                                                       9A
                                        8
                                                                                  9A             9A
                                        6                   9A
                                                  9A
                                        4

                                        2

                                        0
                                              Monday    Tuesday       Wednesday   Thursday   Friday
                                                                 Days of the week

                                                                  Girls   Boys

                                                                                                                                (5)

4.4.1   Value of C:                                                                                                                       D
        64,2 =          9M
                                         ஼ ା ଵ ଼ହଷ                                                    1M Addition (1 853) and             L4
                  ଷ଴                                                                                  division by 30
        64,2 × 30 = C + 1 853
                                                                                                      1M Subtraction
        C = 1 926 – 1 853 9M                                                                          1CA Value of C
          = 73 9CA
        Answer invalid 9O                                                                             1A Invalid                (4)

4.4.2   D = 0 9A                                                                                      1A Value of D                       D
        No learners scored 30 – 39 marks 9A                                                           1A Explanation                      L4
                                                                                                      (CA value of D from 4.4.1
                                                                                                      included in the data) (2)
                                                                                                                            [26]

                                                                                                                         TOTAL:           100

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