# Mathematical Literacy Grade 11 P1 2020 Memo (Eng)

> Grade 11 Mathematical Literacy Paper 1 memorandum from the Eastern Cape November 2020 (English), 8 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/maths-lit-p1-gr11-memo-nov2020-english/08e52e8a-ef68-4338-9e8e-a0babd449184
- Updated: 2026-09-27
- Subject: Mathematical Literacy
- Grade: Grade 11
- Language: English
- Document type: Memorandum
- Year: 2020
- Exam period: Eastern Cape November
- Paper: 1
- Curriculum: CAPS
- Pages: 8

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## About this document

Mathematical Literacy · Grade 11 · Eastern Cape November · 2020 · English. Memorandum, 8 pages. Read online or download the PDF.

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## Matching paper and memo

- [MATHS LIT P1 GR11 QP NOV2020 English .docx](https://www.hlayiso.com/library/maths-lit-p1-gr11-qp-nov2020-english-docx/fa0c394f-1138-4ab2-9498-7611a1f9e12f) — QP · 2020 · Eng

## Document text

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### Page 1

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                          NATIONAL
                     SENIOR CERTIFICATE

                                GRADE 11

                         NOVEMBER 2020

               MATHEMATICAL LITERACY P1
                  MARKING GUIDELINE
                     EXEMPLAR
MARKS:   100

   Symbol                                   Explanation
   M            Method
   MA           Method with accuracy
   CA           Consistent accuracy
   A            Accuracy
   C            Conversion
   S            Simplification
   RT/RG/RM     Reading from a table/Reading from a graph/Read from map
   F            Choosing the correct formula
   SF           Substitution in a formula
   J            Justification
   P            Penalty, e.g. for no units, incorrect rounding off etc.
   R            Rounding Off/Reason
   AO           Answer only
   NPR          No penalty for rounding

                    This marking guideline consists of 8 pages.

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2                              MATHEMATICAL LITERACY P1                         (EC/NOVEMBER 2020)

 MARKING GUIDELINES

 NOTE:

    If a candidate answers a question TWICE, only mark the FIRST attempt.
    If a candidate has crossed out (cancelled) an attempt to a question and NOT redone
     the solution, mark the crossed out (cancelled version)
    Consistent accuracy (CA) applies in ALL aspects of the marking guidelines,
     however it stops at the second calculation error.
    If the candidate presents any extra solution when reading from a graph, table, layout
     plan and map, then penalise for every extra incorrect item presented.

 LET WEL:

    As ŉ kandidaat ŉ vraag TWEE keer beantwoord, merk slegs die EERSTE poging.
    As ŉ kandidaat ŉ antwoord van ŉ vraag doodtrek (kanselleer) en nie oordoen nie,
     merk die doodgetrekte (gekanselleerde) poging.
    Volgehoue akkuraatheid (CA) word in ALLE aspekte van die nasienriglyn toegepas,
     maar dit hou by die tweede berekeningsfout op.
    Wanneer ŉ kandidaat aflesings vanaf ŉ grafiek, tabel, uitlegplan en kaart geneem
     en ekstra antwoorde gee, penaliseer vir elke ekstra verkeerde item.

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        (EC/NOVEMBER 2020)             MATHEMATICAL LITERACY P1                                            3

QUESTION 1 [23 marks]

Ques.                             Solution                                       Explanation                   T&L
1.1.1    Annual gross salary = R10 500 × 12  M                           1M Multiply by 12                     F
                             = R126 000     A                            1A Gross per annum        (2)         L1

1.1.2    Monthly food expense = R10 500 × 36% M                          1M % Calculation                     F
                              = R3 780        CA                         1CA Amount                 (2)       L1

1.1.3    Housing % : Food %                                                                                    F
         = 21% : 36% M                                                   1M Correct values and order          L1
         = 7 : 12 CA                                                     1CA Simplest form        (2)
                                      M
1.1.4    Savings % = 100% – (21% +36% +10% + 1,9%)                        1M Adding correct values             F
                   = 100% – 68,9%M                                       1M Subtracting from 100              L1
                   = 31,1% CA                                            1CA Percentage           (3)

1.2.1    Primary data A                                                 2A Correct data type                 D
                                                                                                    (2)        L1

1.2.2    41  RT                                                         2RT Highest mark                     D
                                                                                                    (2)        L1

1.2.3    Median is the middle value of a set of data which is arranged    2A Explanation                       D
         from small to big.        A                                                              (2)        L1
                                   A
1.2.4     35  A                                                         2A Correct mark                      D
                                                                                                    (2)        L1

1.2.5    3  RT                                                          2RT No. of learners failed           D
                                                                                                    (2)        L1

1.3.1    Loss is when the cost is more than the income.  A              2A Correct explanation               F
                                      OR                                                                       L1
         Loss incurred when selling price is less than cost price of an
         item.  A                                                                                 (2)

1.3.2              50                                                     1M Fraction multiplied by            F
         % loss = 750 × 100% M
                                                                            100%                               L1
                = 6,67%  CA
                                                                          1CA Percentage
                                                                          NPR                      (2)
                                                                                                  [23]

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        4                                 MATHEMATICAL LITERACY P1                   (EC/NOVEMBER 2020)

QUESTION 2: FINANCE [30 marks]
Ques.                    Solution                                            Explanation                  Topic
                                                                                                          /Level
2.1.1   SmartMAXFocussed Education Plan 1  RT                      2A Correct investment plan             F
                                                                                              (2)           L1

2.1.2                         8266 ,470                              1C Converted to Rands                 F
        Number of units =               C                           1CA Value                             L2
                                  100
                           = R82,6647  CA
                              8038 ,07                               1M Division
                           =            M
                              82 ,6647
                                                                     1CA No. of units
                           = 97,23703104  CA                                                    (4)

2.1.3   % loss = 12 924,75 – 6 995,25  M                            1M Subtraction of values              F
               = R5 929,50  S                                       1S Simplification                     L3
                  5929 ,50  M                                       1M Dividing correct values
               =             100  M                                1M Multiply by 100%
                 12924 ,75
               = 45,88%
                                       OR                                          OR
                           6995 ,25   M
        Percentage loss =            100  M                        1M Dividing correct values
                          12924,75                                   1M Multiply by 100%
                        = 54,12%           S                        1S Simplification
                        = 100% – 54,12% M                           1M Subtraction of %
                        = 45,88%                                                              (4)

2.1.4   B = R8 038,07 – R6 995,25  MA                               1MA Subtraction                       F
          = R1 042,82 C A                                           1CA Correct answer          (2)       L2

2.1.5   R765,57 RT                                                 2RT Correct value                     F
                                                                                                 (2)       L2
                                 RT
2.1.6                     366 ,02  332 ,75                          1RT Correct values
            % increase =                     100  SF               1SF Substitution
                                                                                                           F
                               332 ,75                                                                     L2
                       = 9,998%  S                                  1S Simplification
                       = 10%  R                                     1R Nearest %                (4)

2.2.1   Number of plates  RT                                       2RT Number of plates                  F
                                                                                                 (2)       L2

2.2.2   Fixed expenses = R500  RT                                  2RT Fixed expenses                    F
                                                                                                 (2)       L2

2.2.3   Income = R50 × Number of plates sold  M  A                 1M Multiplication with R50            F
                                                                     1A Correct formula       (2)          L2

2.2.4   R0 OR (No Profit)  RT                                      2RT No profit                         F
                                                                                                 (2)       L2

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        (EC/NOVEMBER 2020)          MATHEMATICAL LITERACY P1                                  5

2.2.5   Loss for 8 plates = Expenses – Income                  1RT R740                           F
                            RT        RT                     1RT R400                           L3
                          = 740 – 400 M                       1M Subtraction
                          = R340 A                            1A Loss
                                     OR                        (From graph allow 340±10)
                                                                           OR
        Expenses = 500 + 8 × 30 = R740 M                      IM for R740
        Income = 50 × 8 = R400 M                              1M for R400
        Loss = 740 – 400 = R340 A                             1M subtraction
                                                               1A for R340 exact answer (4)
                                                                                       [30]

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      6                                     MATHEMATICAL LITERACY P1                (EC/NOVEMBER 2020)

QUESTION 3: DATA HANDLING (18 marks) AND PROBABILITY (3 marks)
Ques.                           Solution                         Explanation                               T/L
3.1   Total number of spas
      = 30 394 + 13 856 + 3 984 + 6 057 + 46 282 + 48 679 1M Adding correct values                         D
      =149 252 M A                                      1A Total                (2)                      L1

3.2           149 252                                                  CA from 3.1                         D
      Mean = 6 M
                                                                       1M Division                         L2
           = 24 875,33
                                                                       1R Whole number
           = 24 875  R
                                                                                                 (2)

3.3                                46 282                              1M Fraction with correct            D
      European spas as a % = 149 252×100 M
                                                                         values and                        L2
                          = 31% CA
                                                                         multiplication by 100
                                                                       1CA Percentage           (2)

3.4   Range = 48 679 – 3 984                                                                               D
            = 44 695 S                                                1S Calculate range                  L3
      Number of regions above range = 2 CA                            1CA Number of regions (2)

3.5                           48 679                                   1M Ratio                            D
      30 394 : 48 679 = 1 : 30 394 M M
                                                                       1M Fraction                         L3
                                                                       1CA Unit ratio
                        =1 : 1,60  CA
                                                                       NPR                       (3)

3.6   Revenue in sub-saharan Africa = 6,6 – 5,0 M                     1M Subtraction                      D
                                      = 1,6 S                         1S Simplification                   L3
      Total revenue for spas                                           1M Addition
      = 22,9 + 6,6 + 1,6 + 2,8 + 33,3 + 26,5 M                        1CA Total revenue
      = $93,7 billion CA                                              Penalise 1 mark if not in
                                                                       billions                (4)

3.7   1,6; 2,8; 6,6; 22,9; 26,5; 33,3 M                               CA the value $1,6 from 3.6          D
                                                                       included in the data                L3
                           6,6 + 22,9                                  1M Arranging in order of
      Median revenue =                  M
                               2                                       descending or ascending
                        = $14,75 billion CA                           1M Concept of median
                                                                       1CA Answer in billions (3)

3.8   P (Regions with more than 40 000 spas)                           1RT Correct numerator and           P
                   RT                                                     denominator                     L2
                  2                                                    1M Multiplication by 100
                = × 100 M
                  6
                                                                       1CA Percentage
                = 33,33% CA                                           NPR                       (3)
                                                                                                [21]

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      (EC/NOVEMBER 2020)            MATHEMATICAL LITERACY P1                                        7

QUESTION 4: FINANCE (12 marks), DATA HANDLING (11 marks) AND
              PROBABILITY (3 marks)
Ques.                       Solution                          Explanation                               T/L
4.1   Cost =
            Kilolitre      Cost
                                                        1M Cost of first 6 kℓ                           F
            6              6 × 0 = 0 M
                                                                                                        L4
             9                   9 × 9,35 = R84,15                   1M Cost for both 9 and 10
                                                  M                    kilolitres
             10                  10 × 11,16 = R111,6
                                                                     1CA Total cost
             Total = 25 litres   84,15 + 111,60 = R195,75 M
                                         M                          1M Multiply by 15%
                                 R195 ×115% = R225,11 CA            1CA Cost including VAT
                                    OR
                M                M
      Cost = (6 × 0) + (9 × 9,35) + (10 × 11,16)
           = R84,15 + R111,60
           = R195,75 CA
      Including VAT = R195,75 × 15% M
                      = R29,3625
                      = R195,75 + R29,3625
                      = R225,11CA

      Increased block rate tariffs to encourage saving of water A
                                       OR                            1A Reason
      Also assist small businesses or families with free water A
      Accept any other sound reason.                                                          (6)

4.2    R0,019 = 1 RWF                                                1M Concept of ratio                F
       R?       = 745 614,04 RWF M                                                                     L4
       R?       = 0,019 × 745 614,04 M                              1M Multiplication
                = R14 166,66676 S                                   1S Simplification value in R
                                    10                               1M Multiplication of 10%
      Bank charges = 14166,66676×100 M
                                                                     1A Value of 10%
                   = R1 416,666676 A
                                                                     1M Subtraction
      Andile received = R14 166,66676 – 1 416,66676  M
                      = R12 750
                                                                     1A Valid
      Statement is valid. A
                                                                                 OR
                                    OR
                       10                                            1M Multiplication of 10%
      Bank charges =      × 745 614,04 RWF M                        1A Value of 10%
                      100
                    = 74 561,404 A                                  1M Subtraction
      Andile received in RWF = 745 614,04 – 74 561,404 M            1S Simplification value
                              = 671 052,636 S
      In Rands: R0,019        = 1 RWF                                1M Concept of ratio
                      R?      = 671 052,636 RWF M                   1M Multiplication
      Andile received = R0,019 × 671 052,636 M
                      = R12 750
      Statement is valid CA                                         1CA Valid               (6)

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        8                                                              MATHEMATICAL LITERACY P1                     (EC/NOVEMBER 2020)

4.3.1   Total absentees = 67  M                                                                       1M Addition to 67                   P
        Absentees on Wednesday =16 A                                                                  1A Absentees on Wed                 L2
                                                        16                                             1CA Fraction
        P(absent on Wed) =                                   CA
                                                        67                                                                       (3)

4.3.2                                                                                                  1A for Monday boys at 5             D
                                             Number of absent learners during the week                 1A for Tuesday girls at 6           L2
                                        12                                                             1A for Thurs for girls at 7
                                                                                                       1A for Thurs for boys at 9
                                        10                                                             1A for Fri for boys at 7

            Number of absent learners
                                                                                        A
                                        8
                                                                                   A             A
                                        6                    A
                                                  A
                                        4

                                        2

                                        0
                                              Monday     Tuesday       Wednesday   Thursday   Friday
                                                                  Days of the week

                                                                   Girls   Boys

                                                                                                                                 (5)

4.4.1   Value of C:                                                                                                                        D
                                         𝐶 + 1 853                                                     1M Addition (1 853) and             L4
        64,2 =          M
                  30                                                                                   division by 30
        64,2 × 30 = C + 1 853
                                                                                                       1M Subtraction
        C = 1 926 – 1 853 M                                                                           1CA Value of C
          = 73 CA
        Answer invalid O                                                                              1A Invalid                (4)

4.4.2   D = 0 A                                                                                       1A Value of D                       D
        No learners scored 30 – 39 marks A                                                            1A Explanation                      L4
                                                                                                       (CA value of D from 4.4.1
                                                                                                       included in the data) (2)
                                                                                                                             [26]

                                                                                                                          TOTAL:           100

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