# Mathematical Literacy Grade 11 P1 2015 Memo (Afr)

> Grade 11 Mathematical Literacy Paper 1 memorandum from the Eastern Cape November 2015 (Afrikaans), 7 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/maths-lit-p1-memo-gr11-sept-2015-afr-final/0dcd7563-b8f7-46bd-899b-3a12c434d053
- Updated: 2026-09-27
- Subject: Mathematical Literacy
- Grade: Grade 11
- Document type: Memorandum
- Year: 2015
- Exam period: Eastern Cape November
- Paper: 1
- Curriculum: CAPS
- Pages: 7

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## About this document

Mathematical Literacy · Grade 11 · Eastern Cape November · 2015. Memorandum, 7 pages. Read online or download the PDF.

Read it free online on the page above; download the PDF from there.

## Document text

Text extracted from the PDF. Layout, diagrams and tables may not survive extraction.

### Page 1

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                               NASIONALE
                           SENIOR SERTIFIKAAT

                                   GRAAD 11

                             NOVEMBER 2015

           WISKUNDIGE GELETTERDHEID V1
                  MEMORANDUM

PUNTE:   100

Simbool        Verduideliking
M              Metode
A              Akkuraatheid
CA             Deurlopende akkuraatheid
RT/RG/RM       Lees vanaf tabel/Lees vanaf ŉ grafiek/Lees vanaf kaart
RP             Lees vanaf plan
SF             Vervanging in ŉ formule
S              Vereenvoudiging
P              Penaliseer (geen eenhede, inkorrekte afronding, ens.)
O              Opinie
J              Regverdiging
RO             Afronding

                        Hierdie memorandum bestaan uit 7 bladsye.

### Page 2

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2                         WISKUNDIGE GELETTERDHEID V1              (EC/NOVEMBER 2015)

 VRAAG 1

 Vraag         Oplossing                                    Verduideliking      Punte

 1.1   1.1.1   R169 x 24 + R55 x 24                       2M
               R4 056 + R1 320                             1S
               = R5 376                                    1A                          (4)

       1.1.2   R0,79 x 8                                   1M
               R6,32                                       1S                          (2)

       1.1.3   R1 999 + R 1 999 x 4,4% OF R1 999 x 1,044   1M
               =R1 999 + R87,96         = R2 086,96
               = R2 086,96                                 1S                          (2)

 1.2   1.2.1   R0,35 x 25                                  1M
               = R8,75                                     1A                          (2)

       1.2.2   18:15                                       1M
               = 6:5                                       1A                          (2)

       1.2.3   25= 5                                      1M
               35    7                                      1A
               = 0,71 of 71% (Slegs antwoord – volpunte)                                (2)

 1.3   1.3.1   Maand 1:   R1 525 x 20%                      1M
                        = R305,00 
               Maand 2:   R1 830,00 x 20%
               Rente    = R366 + R305 = R671,00            1S                          (2)

       1.3.2   R400 x 11 x 8  + R2 000 x 8 + R671         2M
               = R35 200 + 16 000 + R671                    1CA
               = R51 871,00                                Vermenigvuldig
                                                            met getal anders
                                                            as 11                       (3)

       1.3.3   R400 x 11 + R2 000 + R671  = 400 000        1M
               R4 400 + R2 000 + R671                      1S
               = R7 071,00                                 1S
               OF
                         + R671 = R7 071,00                                             (3)

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(EC/NOVEMBER 2015)            WISKUNDIGE GELETTERDHEID V1                             3

 Vraag           Oplossing                                  Verduideliking     Punte
 1.4 1.4.1       4 760 x 11,82  OF 4,760 x 11,82           1M
                 = R56 263,20        = 56,26               1A                      (2)

       1.4.2     R1 571,05 x 114%  OF R1 571,05 x 14%      1M
                 R1 790,997          R219,95               1S
                 R1 790,997 x 2  R1 571,05 + R219,95      1A
                 = R3 581,99      R1 571,05 + R219,95 
                 OF
                 R1 571,05 x 14%
                 = R219,95 
                 = R1 571,05 + R219,947 
                 = R1 790,997 x 2
                 = R3 581,99 
                 OF
                 R1 571,05 x 2 
                 = R3 142,10 x 114% 
                 = R3 581,99                                                       (3)
                                                                                   [27]

Kopiereg voorbehou                                                     Blaai om asseblief

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4                        WISKUNDIGE GELETTERDHEID V1                      (EC/NOVEMBER 2015)

 VRAAG 2

 Vraag         Oplossing                                 Verduideliking          Punte

 2.1 2.1.1     227                                     RD                            (2)

      2.1.2    7 ÷ 60  = 0,1166666667 h                 2M
               5 ÷ (60 x 60) = 0,00138888888 h          1S
               4 h + 0,1166666667 h + 0,00138888888 h
               = 4,118055556 uur
               = 4 uur                                                                (3)

      2.1.3                                              1S
               Gemiddelde spoed =            
                                                         2S
                                  = 16,5  km/uur       Penaliseer vir
                                                         eenheid                       (3)

 2.2 2.2.1     Aankomstyd – 18:56 
               Vertrektyd – 19:00                       2RT                           (2)

      2.2.2    Bloemfontein                            2RT                           (2)

      2.2.3    Oppervlak van groter sirkel – Oppervlak   1F
               van kleiner sirkel 
               3,142 x (5 m)2  – 3,142 x (2,5 m)2      2F
               = 78,55 m2 – 19,6375 m2                  1S
               = 58,9125 m2 (Aanvaar 58,91 m2)          1A                            (5)

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(EC/NOVEMBER 2015)                          WISKUNDIGE GELETTERDHEID V1                                                5

 VRAAG 3

 Vraag          Oplossing                                                               Verduideliking               Pun
                                                                                                                      te

 3.1 3.1.1      113 341 x 26% 
                = 113 341 x 0,26
                = 29 468,66
                = 29 469                                                                                             (2)

       3.1.2    (i) Kanker 
                (ii) Hartsiektes                                                                                     (2)

       3.1.3                                                                                         Alle ander
                 Tipes Sterftes            Ongelukke   Kanker   Hartsiektes   Selfmoord      Moord
                                                                                                     oorsake
                 Persentasie
                                              26         13         12            11           6          32
                 van sterftes

                                                       Persentasie van sterftes
                                    35
                                    30
                                    25

                     Persentasies
                                    20
                                    15
                                    10
                                    5
                                    0
                                         Ongelukke     Kanker   Hartsiektes   Selfmoord      Moord      Alle ander
                                                                                                         oorsake
                                                                 Oorsake van sterftes

                 1 punt vir voltooiing van die tabel                                               =1
                   p nt vi ve binding van p nte et ŉ eg itlyn                                      =1
                 1 punt vir elke drie punte korrek afgesteek                                       =2
                 2 punte vir korrekte benaming van horisontale- en
                 vertikale asse                                                                    =2
                                                                                                                      (6)
       3.1.4    113 341 – 39 213                                                       1M
                = 74 128                                                               1A                            (2)

       3.1.5         −44 jaar                                                         2GR                           (2)

       3.1.6    Hulle ry onverskillig om vriende van hulle
                ouderdom te beïndruk met hulle
                bestuursvaardighede. Hulle konsentreer nie
                op die paaie nie, want hulle groet hulle vriende
                op straat. 25–44 is meer volwasse en meer
                versigtig as hulle bestuur. 
                Aanvaar enige ander relevante redes.                                    2A                            (2)

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6                           WISKUNDIGE GELETTERDHEID V1                             (EC/NOVEMBER 2015)

 3.2 3.2.1     15+14 x 2 + 13 +12 + 9 x 5 + 10 x 3+7 + 5 x 2               1M
                                  16
               = 160                                                       1S
                 16
               = 10                                                        1S                   (3)

      3.2.2    Modus = 36                                                 2A                   (2)

      3.2.3    Maluti VOO Kollege                                         2A                   (2)
                                                                                                [23]

 VRAAG 4

 Vraag         Oplossing                                                    Verduideliking   Punte

 4.1 4.1.1     35 passasiersitplekke                                      2A                   (2)

      4.1.2    Klim in die bus en draai regs.  Loop reguit in              3
               die gang af  of suidwaarts en by die derde ry
               van agter  langs die venster sal jou sitplek
               wees.
               Aanvaar enige relevante verduideliking.                                           (3)

      4.1.3    A7                                                         2A                   (2)

 4.2 4.2.1     Strookkaart                                                2A                   (2)

      4.2.2    430 – 220  OF 22 + 19 x 2 + 14 x 2 +17 x 2 + 10 + 35 + 43   1M
               = 210 km              = 210 km                              1S                   (2)

      4.2.3    N1 OF Pad 1  en 4 tolhekke                                 2RM                  (2)

      4.2.4    Noordwes                                                   2RM                  (2)
                                                                                                [15]

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(EC/NOVEMBER 2015)             WISKUNDIGE GELETTERDHEID V1                                  7

 VRAAG 5

 Vraag          Oplossing                                          Verduideliking   Punte

 5.1 5.1.1      323 liter 
                323 x 1 000 = 3 3         ℓ                      1RD                  (3)

       5.1.2    Rentekoers is die koers  waarby rente betaal      2A
                of gelas word vir die gebruik van geld. 
                                        OF
                Dit is die persentasie van die totale bedrag wat
                oo ŉ pe iode van tyd betaal word.                                       (2)

       5.1.3    R4 799,00 – R479,90                               1M
                = R4 319,10                                       1S                   (2)

       5.1.4    R4 319,10 x (21,75 ÷ 100 ÷ 12)                    1M
                = R4 319,10 x 0,018125                            1S
                = R78,2836875 x 24                                 1S
                = R1 878,81 
                                      OF
                R4 319,10 x (21,75 ÷ 100)
                = R939,40425 x 2
                = R1 878,81
                                      OF
                R4 319,10 x (21,75 ÷ 100) x 2
                = R1 878,81                                                             (3)

       5.2.1    32;35,36;37;38;42;46;46;46;49;58;62;64;66;67       2A
                Mediaan = 46                                                          (2)

       5.2.2    IKO = 62  – 37                                   2CV
                    = 25                                          1A                   (3)

       5.2.3    10                                                2M
                 15
                =2
                  3                                               1A                   (3)
                                                                                       [18]

                                                                        TOTAAL:      100

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