# Mathematical Literacy Grade 11 P1 2015 Memo (Eng)

> Grade 11 Mathematical Literacy Paper 1 memorandum from the Eastern Cape November 2015 (English), 7 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/maths-lit-p1-memo-gr11-sept-2015-eng-final/4dbb2229-1791-4494-be69-2fc70a30941c
- Updated: 2026-09-27
- Subject: Mathematical Literacy
- Grade: Grade 11
- Document type: Memorandum
- Year: 2015
- Exam period: Eastern Cape November
- Paper: 1
- Curriculum: CAPS
- Pages: 7

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## About this document

Mathematical Literacy · Grade 11 · Eastern Cape November · 2015. Memorandum, 7 pages. Read online or download the PDF.

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## Document text

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### Page 1

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                             NATIONAL
                        SENIOR CERTIFICATE

                              GRADE 11

                          NOVEMBER 2015

                 MATHEMATICAL LITERACY P1
                      MEMORANDUM

MARKS:     100

Symbol       Explanation
M            Method
A            Accuracy
CA           Consistent accuracy
RT/RG/RM     Reading from a table/Reading from a graph/Read from map
RP           Reading from the plan
SF           Substitution in a formula
S            Simplications
P            Penalty (no units, incorrect rounding off etc.)
O            Opinion
J            Justification
RO           Rounding Off

                   This memorandum consists of 7 pages.

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2                               MATHEMATICAL LITERACY P1                 (EC/NOVEMBER 2015)

 QUESTION 1

 Question            Solution                                     Explanation      Mark

 1.1     1.1.1       R169 x 24 + R55 x 24                       2M
                     R4 056 + R1 320                             1S
                     = R5 376                                    1A                  (4)

         1.1.2       R0,79 x 8                                   1M
                     R6,32                                       1S                  (2)

         1.1.3       R1 999 + R1 999 x 4,4%  OR R1 999 x 1,044   1M
                     = R1 999 + R87,96           = R2 086,96
                     = R2 086,96                                 1S
                     OR
                     R1,999 x 0,144
                     R2 086,86                                                        (2)

 1.2     1.2.1       R0,35 x 25                                  1M
                     = R8,75                                     1A                  (2)

         1.2.2       18:15                                       1M
                     = 6:5                                       1A                  (2)

         1.2.3       25 = 5                                     1M
                     35     7                                     1A
                     = 0,71 or 71% (Answer only – full marks)                         (2)

 1.3     1.3.1       Month 1: R1 525 x 20%
                              = R305,00                          1M
                     Month 2: R1 830,00 x 20%
                              = R366,00
                     Interest = R366 + R305 = R671,00            1S                  (2)

         1.3.2       R400 x 11 x 8  + R2 000 x 8 + R671         2M
                     = R35 200 + 16 000 + R671                    1CA
                     = R51 871,00                                Multiplication
                                                                  by different
                                                                  number not 11       (3)

         1.3.3       R400 x 11+ R2000 + R671 = 400 000           1M
                     R4 400 + R2 000 + R671                      1S
                     = R7 071,00                                 1S
                     OR
                               + R671 = R7 071,00                                     (3)

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(EC/NOVEMBER 2015)            MATHEMATICAL LITERACY P1                                 3

 Question        Solution                                  Explanation           Mark
 1.4  1.4.1      R4 760 x 11,82  OR 4,760 x 11,82         1M
                 = R56 263,20      = 56,26                1A                       (2)

        1.4.2    R1 571,05 x 114%  OF R1 571,05 x 14%     1M
                 R1 790,997          R219,95              1S
                 R1 790,997 x 2  R1 571,05 + R219,95     1A
                 = R3 581,99      R1 571,05 + R219,95 
                 OR
                 R1 571,05 x 14%
                 = R 219,95
                 = R1 571,05 + R219,947 
                 = R1 790,997 x 2
                 = R3 581,99 
                 OR
                 R1 571,05 x 2 
                 = R3 142,10 x 114% 
                 = R3 581,99                                                       (3)
                                                                                   [28]

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4                            MATHEMATICAL LITERACY P1                          (EC/NOVEMBER 2015)

 QUESTION 2

 Question       Solution                                               Explanation         Marks

 2.1   2.1.1    227                                                  RD                     (2)

       2.1.2    7 ÷ 60 = 0,1166666667 h                               2M
                5 ÷ (60 x 60) = 0,00138888888 h                       1S
                4 h + 0,1166666667 h + 0,00138888888 h                                        (3)
                = 4,118055556 hours
                = 4 hours 

       2.1.3                                                           1S
                Average speed =                
                                                                       2S
                                   = 16,5  km/hour                   Penalise for unit      (3)

 2.2   2.2.1    Arrival time   – 18:56                                2RT
                Departure time – 19:00                                                       (2)

       2.2.2    Bloemfontein                                         2RT                    (2)

       2.2.3    Area of a bigger circle – Area of a smaller circle    1F
                               2                    2
                3,142 x (5 m) – 3,142 x (2,5 m) 
                = 78,55 m2 – 19,6375 m2                               2SF
                = 58,91 m2      (Accept 58,91 m2)                    1S
                                                                       1A                    (5)
                                                                                            [17]

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(EC/NOVEMBER 2015)                              MATHEMATICAL LITERACY P1                                      5

 QUESTION 3

 Question        Solution                                                             Explanation
 3.1   3.1.1     113 341 x 26% 
                 = 113 341 x 0,26
                 = 29 468,66
                 = 29 469                                                                                 (2)

       3.1.2     (i) Cancer 
                 (ii) Heart disease                                                                       (2)

       3.1.3     Types of                                      Heart                           All other
                                        Accidents   Cancer              Suicide   Homicide
                 death                                        disease                           causes
                 % death                   26           13       12        11         6         32 232

                                                             % death
                                   35

                                   30

                       
                                   25                                                              

                     Percentages
                                   20               
                                                                                      
                                   15

                                   10

                                   5

                                   0
                                        Accidents   Cancer    Heart     Suicide   Homicide   All other
                                                             disease                          causes
                                                              Causes of death 
                 1 mark for completing the table                                          = 1 mark
                 1mark for joining points with a straight line                            = 1 mark
                 1 mark per three correctly plotted points                                = 2 marks
                 2 marks for correctly labelling x-axis and y-axis                         = 2 marks       (6)

       3.1.4     113 341 – 39 213                                                    1M
                 = 74 128                                                            1A                   (2)

       3.1.5     25–44 years                                                        2RG                  (2)

       3.1.6     They drive recklessly trying to impress those
                 people of their age about their driving skills. They
                 do not concentrate on the road trying to greet
                 their friends walking on the street. 25–44 are
                 mature enough and they are careful when
                 driving. 
                 (Accept any acceptable reasons.)                                     2A                   (2)

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6                              MATHEMATICAL LITERACY P1                             (EC/NOVEMBER 2015)

 3.2   3.2.1     15+14 x 2 + 13 +12 + 9 x 5 + 10 x 3+7 + 5 x 2               1M
                                    16
                 = 160                                                       1S
                   16
                 = 10                                                        1S                 (3)

       3.2.2     Mode = 36                                                  2A                 (2)

       3.2.3     Maluti FET College                                         2A                 (2)
                                                                                                [23]

 QUESTION 4

 Question        Solution                                                     Explanatio    Marks
                                                                              n

 4.1    4.1.1    35 passengers                                              2A                 (2)

        4.1.2    Get in and turn right.  Walk straight or                    3
                 southwards and at the third row from the
                 back  next to the window will be your seat.
                 Accept any relevant explanation.                                                (3)

        4.1.3    A7                                                         2A                 (2)

 4.2    4.2.1    Strip Map                                                  2A                 (2)

        4.2.2    430 – 220  OR 22 + 19 x 2 + 14 x 2 +17 x 2 + 10 + 35 + 43   1M
                 = 210 km              = 210 km                              1S                 (2)

        4.2.3    N1 or Road 1 and 4 toll gates                              2RM                (2)

        4.2.4    North west                                                 2RM                (2)
                                                                                                [15]

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(EC/NOVEMBER 2015)               MATHEMATICAL LITERACY P1                                  7

 QUESTION 5

 Question        Solution                                           Explanation    Marks

 5.1    5.1.1    323 litres                                        1RD
                 323 x 1 000 = 3 3         ℓ                      1C                  (3)

        5.1.2    Interest rate is the rate  at which interest is   2A
                 paid or charged for the use of money. 
                                          OR
                 It is percentage of the total amount paid over a
                 period of time.                                                        (2)

        5.1.3    R4 799,00 – R479,90                               1M
                 = R4 319,10                                       1S                  (2)

        5.1.4    R4 319,10 x (21,75 ÷ 100 ÷ 12)                    1M
                 = R4 319,10 x 0,018125                            1S
                 = R78,2836875 x 24
                 = R1 878,81                                       1S
                                      OR
                 R4 319,10 x (21,75 ÷ 100)
                 = R939,40425 x 2
                 = R1 878,81
                                      OR
                 R4 319,10 x (21,71 ÷ 100) x 2
                 = R1 878,81                                                            (3)

        5.2.1    32;35,36;37;38;42;46;46;46;49;58;62;64;66;67       2A
                 Median = 46                                                          (2)

        5.2.2    IQR = 62 – 37                                    2CV
                     = 25                                          1A                  (3)

        5.2.3    10                                                2M
                 15
                 =2
                   3                                               1A                  (3)
                                                                                       [18]

                                                                         TOTAAL:       100

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