# Mathematical Literacy Grade 11 P2 2025 Memo (Eng) > Grade 11 Mathematical Literacy Paper 2 memorandum from the Eastern Cape November Exam 2025 (English), 10 pages. Read online or download the free PDF. - Page: https://www.hlayiso.com/library/maths-lit-p2-grade-11-nov-2025-memo-eng-watermark/00c7d846-499c-4c72-87d9-0b9055358bc5 - Updated: 2026-09-27 - Subject: Mathematical Literacy - Grade: Grade 11 - Document type: Memorandum - Year: 2025 - Exam period: Eastern Cape November Exam - Paper: 2 - Curriculum: CAPS - Pages: 10 Breadcrumbs: [Home](https://www.hlayiso.com/) › [Library](https://www.hlayiso.com/library) › [Grade 11](https://www.hlayiso.com/library/grade-11) › [Mathematical Literacy](https://www.hlayiso.com/library/grade-11/mathematical-literacy) › [Mathematical Literacy Grade 11 P2 2025 Memo (Eng)](https://www.hlayiso.com/library/maths-lit-p2-grade-11-nov-2025-memo-eng-watermark/00c7d846-499c-4c72-87d9-0b9055358bc5) ## About this document Mathematical Literacy · Grade 11 · Eastern Cape November Exam · 2025. Memorandum, 10 pages. Read online or download the PDF. 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Layout, diagrams and tables may not survive extraction. ### Page 1 NATIONAL SENIOR CERTIFICATE GRADE 11 NOVEMBER 2025 MATHEMATICAL LITERACY P2 MARKING GUIDELINES MARKS: 100 Symbol Explanation M Method MA Method with accuracy CA Consistent accuracy A Accuracy C Conversion S Simplification RT Reading from a table/graph/diagram SF Correct substitution in a formula O Opinion/Explanation/Reasoning P Penalty, e.g. for no units, incorrect rounding off, etc. R Rounding Off/Reason NPR No penalty for correct rounding minimum two decimal places AO Answer only MCA Method with consistent accuracy RCA Rounding with consistent accuracy This marking guidelines consist of 10 pages. ### Page 2 2 MATHEMATICAL LITERACY P2 (EC/NOVEMBER 2025) MARKING GUIDELINES NOTE: • If a candidate answers a question TWICE, only mark the FIRST attempt. • If a candidate has crossed out (cancelled) an attempt to a question and NOT redone the solution, mark the crossed out (cancelled) version. • Consistent Accuracy (CA) applies in ALL aspects of the marking guidelines; however, it stops at the second calculation error. • If the candidate presents any extra solution when reading from a graph, table, layout plan and map, then penalize for every extra incorrect item presented. Copyright reserved Please turn over ### Page 3 (EC/NOVEMBER 2025) MATHEMATICAL LITERACY P2 3 KEY TO TOPIC SYMBOL: F = Finance; M = Measurement; MP = Maps, plans and other representations; P = Probability QUESTION 1 [24 MARKS] ANSWER ONLY FULL MARKS Ques. Solution Explanation Level 1.1.1 Total time = 1,5 minutes + 3 minutes + 15 minutes M 1M adding time M = 19,5 minutes A 1A total time L1 (2) 1.1.2 Cream cheese = 10 ounces 1C dividing with M C 35,274 35,274 L1 = 0,28349… 1A cream cheese in kg ≈ 0,28 kg A NPR (2) 1.1.3 Salt = 1½ × 5 ml M 1M multiplying M = 7,5 ml A 1A correct answer L1 (2) 1.1.4 5 ℃ = 9 × (℉ - 32) M 5 1SF substitution L1 = 9 × (356⁰ - 32) SF 1A temperature in ℃ = 180 ℃ A (2) 1.2.1 Capacity refers to the maximum amount of liquid a 2A correct definition M container can hold. ✓A (2) L1 1.2.2 Capacity = 500 ml ✓RT 2RT correct capacity M (2) L1 1.3.1 Circumference of a circle = π × diameter 1SF substitution M = 3,142 × 13SF 1A circumference L1 = 40,846 m A NPR (2) 1.3.2 Z:X 1A correct ratio M 16 : 8A If ratio swopped = 1 mark 1S simplification L1 2 : 1 S (2) 1.4.1 Oribi Animal Clinic✓RT 2RT correct clinic MP (2) L1 1.4.2 Southeast ✓A OR SE ✓A 2A correct direction MP (2) L1 Copyright reserved Please turn over ### Page 4 4 MATHEMATICAL LITERACY P2 (EC/NOVEMBER 2025) 1.4.3 Travelling distance = 21,1 km × 1 000 C 1C multiply by 1 000 MP = 21 100 m A 1A distance in m L1 (2) 1.4.4 Arrival time = 10:15 1M adding time MP + :26 M 1A correct time L1 = 10:41 A (2) [24] Copyright reserved Please turn over ### Page 5 (EC/NOVEMBER 2025) MATHEMATICAL LITERACY P2 5 QUESTION 2 [27 MARKS] Ques. Solution Explanation Level 2.1.1 Rober’s Grave ✓RT 2RT correct attraction MP (2) L2 2.1.2 Probability = 0 ✓A OR None ✓A 2A correct answer P (2) L2 2.1.3 Distance = 6,4 cm ✓A 2A correct distance MP (Accept 6,2 cm – 6,6 cm) (2) L1 A CA from 2.1.3 MP 2.1.4 Scale line = 2,6cm (Accept 2,5 – 2,7 cm) 1A scale line in cm L3 2,6 cm 600 m 1M dividing correct Scale = = M 2,6 2,6 values = 1 cm : 230,7692308 m CA 1CA scale Actual distance = 6,4 cm × 230,7692308 MCA 1 476,923077 m 1MCA multiplication = 1 000 = 1,48 km CA 1CA distance in km OR OR Scale line = 2,6 cm A 1A scale line in cm Scale = 2,6 cm = 600 m 2,6 60 000 1M dividing correct = : M 2,6 2,6 values = 1 : 23 076,92308 CA 1CA scale Actual distance = 6,4 × 23 076,92308 MCA = 147 692,3077 cm 1MCA multiplication 147 692,3077 = 100 000 = 1,48 km CA 1CA distance in km NPR (5) 2.1.5 No of people = 1 721 M 1M dividing correct MP 25,40 values L1 = 67,7559… 1R number of people ≈ 68 people R (Accept 67 people) (2) 2.2.1 Mozambique ✓RT OR Swaziland ✓RT 2RT any correct MP country L1 (2) Copyright reserved Please turn over ### Page 6 6 MATHEMATICAL LITERACY P2 (EC/NOVEMBER 2025) 2.2.2 6 national roads ✓RT 2RT no of national MP roads L2 (2) 2.2.3 Scale = 8,3 cm : 276 km MP = 276 km × 100 000 C 1C multiplying by L2 = 27 600 000 cm 100 000 Scale = 8,3 : 27 600 000 M 1M dividing distances 8,3 8,3 1CA scale = 1 : 3 325 301,205 CA NPR (3) 2.2.4 Speed = Distance MP Time L4 276 km 1SF substitution 80 km/h = SF Time Time = 276 𝑘𝑚 1M changing subject M 80 𝑘𝑚/ℎ of formula = 3,45 hoursCA 1CA time = 0,45 × 60 = 27 minutes C 1C converting hrs to Travel time = 3h27min min Arrival time = 12:45 + 03:27 M 1M adding time = 16:12 CA ⸫ Siphokhazi’s claim is not validO 1CA arrival time 1O opinion (7) [27] Copyright reserved Please turn over ### Page 7 (EC/NOVEMBER 2025) MATHEMATICAL LITERACY P2 7 QUESTION 3 [23 MARKS] Ques. Solution Explanation Level 3.1.1 50 Radius = = 5 cm C 1C radius in cm M 10 L2 1SF substitution Volume = 3,142 × 52 × 12 SF 1CA volume in cm3 = 942,6 cm3CA (3) 3.1.2 Width = 0,08 × 1 000 C 1C multiply by 1 000 M = 80 mm A 1A width in mm L3 1C height in mm Height = 14,5 × 10 1SF substitution = 145 mm C 1S simplification TSA = 2 (150 × 80) + 2 (150 × 145) + 2 (145 × 80)SF 1R rounding = 24 000 mm2 + 43 500 mm2 + 23 200 mm2 = 90 700 mm2S ≈ 91 000 mm2R (6) CA from 3.1.2 M 3.1.3 Amount of plastic needed = 91 000 C 1C divide by L3 1 000 000 1 000 000 = 0,091 m2 × 50 M 1M multiply by 50 = 4,55 m2 ≈ 5 m2 1M multiply area with Cost of plastic = 5 m2 × R27,55 M cost = R137,75 CA 1CA total cost (4) 3.1.4 1M calculating 7% of M 7 12 L2 Height = 100 × 12 cm = M 1CA answer 0,84 cm CA 1M subtracting 7% ⸫ 12cm – 0,84 cm M from container height = 11,16 ≈ 11,2 cm OR OR 1M subtracting 7% Height = 100% - 7% M 1CA beans height in = 93%  CA % 93 1M calculating 93% ⸫ 100 × 12 cm M of 12 = 11,16 cm ≈ 11,2 cm (3) Copyright reserved Please turn over ### Page 8 8 MATHEMATICAL LITERACY P2 (EC/NOVEMBER 2025) 3.1.5 Volume of cylindrical-shaped container = 942,6 cm3 M L4 Rectangular shaped container: Length = 15 cm C 1C length in cm Width = 8 cmC 1C width in cm Height = 14,5 cm Volume = L × W × H = 15 cm × 8 cm × 14,5 cm SF 1SF substitution = 1 740 cm3 CA 1CA volume in cm3 Her statement is incorrect / not valid O 1O opinion (5) 3.1.6 To keep the coffee beans fresh ✓O 2O reason M OR L4 To protect container against breakage ✓O (Accept any other relevant explanation) (2) [23] Copyright reserved Please turn over ### Page 9 (EC/NOVEMBER 2025) MATHEMATICAL LITERACY P2 9 QUESTION 4 [26 MARKS] Ques. Solution Explanation Level 4.1.1 7 1A correct fraction P Probability = A × 100% M 11 1M multiply by 100% L2 1CA probability as a = 63,64% CA % (3) 4.1.2 Travelling time = 10:15 MP - 08:30 M 1M subtracting time L4 = 01:45 ⸫ 0,45 ÷ 60 = 0,75 h C 1C minutes to hours Time = 1 h + 0,75 h = 1,75 hoursCA 1CA traveling time in hours Distance = Speed × Time = 1,4 miles/h × 1,75 h SF 1SF substitution = 2,45 miles 1C multiply with ⸫ 2,45 miles × 1,60934C conversion factor = 3,942883 kmCA 1CA distance in km Her statement is invalid O 1O opinion OR OR Travelling time = 10:15 1M subtracting time - 08:30 M = 01:45 1C minutes to hours ⸫ 0,45 ÷ 60 = 0,75 h C 1CA traveling time in Time = 1 h + 0,75 h = 1,75 hoursCA hours Speed = 1,4 miles/h × 1,60934 C 1C convert speed to = 2,253076km/h km/h Distance = Speed × Time 1SF substitution = 2,253076km/h × 1,75 h SF 1CA distance in km = 3,942883 kmCA 1O opinion Her statement is invalid O NPR (7) 4.2.1 Area of square = side × side 1SF substitution M = 45 cm × 45 cm SF 1A area of box L2 = 2 025 cm2A ≈ 2 030 cm2 R 1R rounding (3) 4.2.2 Value of D: 1M subtraction M 2D = 45 cm – 42 cm M 1M divide by 2 L2 = 3 cm 1CA value of D 3 𝑐𝑚 M D= 2 = 1,5 cm CA (3) Copyright reserved Please turn over ### Page 10 10 MATHEMATICAL LITERACY P2 (EC/NOVEMBER 2025) 4.2.3 Area of pizza (circle) = 3,142 × 212 A SF 1A radius M 2 = 1 385,622 cm 1SF substitution L3 Area of one slice = 1 385,622 M 1M dividing area by 8 8 = 173,20 cm2CA 1CA area of one slice (4) 4.3.1 Diameter = 160 cm + 35 cm + 35 cm M 1M adding correct M = 230 cm values L2 230 Radius = M 2 1M divide diameter = 115 cm CA by 2 1CA radius (3) 4.3.2 Height of support pole = 78 cmM – (2,8 cm + 0,7 cm) M 1M subtraction M = 74,5 cm CA 1M adding base and L2 thickness 1CA height in cm (3) [26] TOTAL: 100 Copyright reserved Please turn over ## Related documents - [MATHS LIT P2 GR11 NOV25 ADDENDUM ENGLISH FINAL (1) watermark](https://www.hlayiso.com/library/maths-lit-p2-gr11-nov25-addendum-english-final-1-watermark/6d3d1a99-ee4e-4b35-9dfc-765595836d35) — Mathematical Literacy · Addendum · 2025 · Eng - [MATHS LIT AFR GRADE 11 NOV 2025 ADDENDUM (3) watermark](https://www.hlayiso.com/library/maths-lit-afr-grade-11-nov-2025-addendum-3-watermark/e7865fd3-d528-472d-a551-0585ea50cee1) — Mathematical Literacy · Addendum · 2025 · Afr - [MATHS LIT P2 ADD GR11 NOV 2024 ENG D watermark](https://www.hlayiso.com/library/maths-lit-p2-add-gr11-nov-2024-eng-d-watermark/b7a64733-ebf8-4fbf-9554-c5949755df14) — Mathematical Literacy · QP · 2024 · Eng - [MATHS LIT P2 QP GR11 NOV 2023 English](https://www.hlayiso.com/library/maths-lit-p2-qp-gr11-nov-2023-english/84506bee-de17-47de-8b37-7901b6b5c5e8) — Mathematical Literacy · QP · 2023 · Eng - [MATHS LIT GR11 P2 MEMO NOV2022 Afrikaans](https://www.hlayiso.com/library/maths-lit-gr11-p2-memo-nov2022-afrikaans/8c7033a8-caf2-4285-a7e0-5e3c22a2f68a) — Mathematical Literacy · Memo · 2022 · Afr - [MATHS LIT GR11 P2 MEMO NOV2022 English](https://www.hlayiso.com/library/maths-lit-gr11-p2-memo-nov2022-english/198f7c60-04c9-40cc-bf70-665e026b06f1) — Mathematical Literacy · Memo · 2022 · Eng ## More from Grade 11 Mathematical Literacy - [Grade 11 Mathematical Literacy P2 November 2026 Mock 2](https://www.hlayiso.com/library/grade-11-mathematical-literacy-2026-november-mock-exam-2-question-paper-paper-2/9e28596c-b065-4744-84e1-a7995223ca68) — QP · 2026 · Eng - [Gr 11 Maths Lit ATP 2023-24](https://www.hlayiso.com/library/gr-11-maths-lit-atp-2023-24/729b7b1d-095d-46f4-8082-c0c019b4c6c7) — ATP - [LP Maths Literacy Grade 11 June 2025 P1 only](https://www.hlayiso.com/library/lp-maths-literacy-grade-11-june-2025-p1-only/010db24d-7d07-4b57-b916-5b4856296406) — QP · 2025 - [FS Maths Literacy Grade 11 June 2025 P1 and Memo](https://www.hlayiso.com/library/fs-maths-literacy-grade-11-june-2025-p1-and-memo/913740d3-d3f7-470f-ad0e-289f4f74f68b) — QP + Memo · 2025 - [GP JW Maths Literacy Grade 11 June 2025 P1 and Memo](https://www.hlayiso.com/library/gp-jw-maths-literacy-grade-11-june-2025-p1-and-memo/4157e22a-6e42-4d3f-8ce9-579e85217581) — QP + Memo · 2025 - [NW 11 MATHS LIT P2 QP AFR JUNIE 2024](https://www.hlayiso.com/library/nw-11-maths-lit-p2-qp-afr-junie-2024/2710368d-cef2-403f-aee4-50c45585c1ef) — QP · 2024 · Afr ## Collection - [Grade 11 past papers](https://www.hlayiso.com/grade-11/past-papers) --- Hlayiso: free CAPS and IEB past papers, memos, notes and study guides for South African learners. 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