# Mathematical Literacy Grade 11 P2 2020 Memo (Eng)

> Grade 11 Mathematical Literacy Paper 2 memorandum from the Eastern Cape November 2020 (English), 5 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/maths-lit-p2-memo-gr11-nov2020-eng-d/38ae2913-1e38-41c5-a84b-45817fdcc07c
- Updated: 2026-09-27
- Subject: Mathematical Literacy
- Grade: Grade 11
- Document type: Memorandum
- Year: 2020
- Exam period: Eastern Cape November
- Paper: 2
- Curriculum: CAPS
- Pages: 5

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## About this document

Mathematical Literacy · Grade 11 · Eastern Cape November · 2020. Memorandum, 5 pages. Read online or download the PDF.

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## Document text

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### Page 1

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                                 NATIONAL
                            SENIOR CERTIFICATE

                                      GRADE 11

                               NOVEMBER 2020

                  MATHEMATICAL LITERACY P2
                     MARKING GUIDELINE
                        (EXEMPLAR)

MARKS:      100

   Symbol                                          Explanation
M                 Method
M/A               Method with Accuracy
MCA               Method with Consistent Accuracy
CA                Consistent Accuracy
A                 Accuracy
C                 Conversion
S                 Simplification
RT/RG/RM          Reading from a table OR Reading from a graph OR Read from map
F                 Choosing the correct formula
SF                Substitution in a formula
J                 Justification
P                 Penalty, e.g. for no units, incorrect rounding off etc.
R                 Rounding Off OR Reason
AO                Answer only
NPR               No penalty for rounding

                          This marking guideline consists of 5 pages.

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2                            MATHEMATICAL LITERACY P2              (EC/NOVEMBER 2020)

QUESTION 1 [21 MARKS]
Ques.                                 Solution                      Explanation             Topic
                                                                                             &
                                                                                            Level
1.1.1      Temperature reading = 30 °C 99A                       2A Correct reading          M
                                                                                  (2)        L1

1.1.2      °F = 100 °F 99A                                       2A °F               (2)     M
                                                                                             L1

1.1.3      Minimum °Fahrenheit = minus 42°F OR -42°F 99A         2A Min °F           (2)     M
                                                                                             L1

1.1.4      Thermometer 1 : Thermometer 2                         1RD Both values             M
                        9RD                                      correct                     L1
           =          90 : 20 9M                                 1M Correct order
           =           9 : 2 9CA                                 1CA Simplified
                                                                 ratio            (3)

1.2.1      Number of houses = 18 99A                             2A Correct number           M
                                                                 of houses      (2)          L1

1.2.2      Hospital99A                                           2A Correct building         M
                                                                                  (2)        L1

1.2.3      Café 99A                                              2A Correct business         M
                                                                                 (2)         L1

1.2.4      Length of the bar = 1,5 cm 99A                        2A Correct length           M
                                                                                  (2)        L1

1.2.5      1,5 cm on the map represents 50 yards in reality99A   CA from 1.2.4               M
                                                                 2A Explanation (2)          L1

1.2.6      3 houses 99A                                          2A Number of                M
                                                                 houses more         (2)     L1
                                                                                    [21]

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(EC/NOVEMBER 2020)                     MATHEMATICAL LITERACY P2                          3

QUESTION 2 [26 MARKS]
Ques. Solution                                                       Explanation              Topic
                                                                                               &
                                                                                              Level
2.1.1      Circumference is the distance or length around the lamp   2A Explanation (2)        M
           shade 99A                                                                           L1

2.1.2                 ଶ଴଴
           Radius = ଵ଴ 9C                                            1C mm to cm               M
                      ଶ଴                                                                       L2
                     = ଶ 9M                                          1M Divide by 2
                     = 10 cm 9CA                                     1CA Radius     (3)

2.1.3      Circumference of lamp shade = ߨ × diameter                CA from 2.1.1             M
                                       = 3,142 × 20 cm 9SF           1SF Substitution          L2
                                       = 62,84 cm 9MCA               1MCA
                                                                     Circumference (2)

2.1.4      Height of lamp shade = 20 cm × 1,65 9M                    1M Multiply by            M
                                = 33 cm 9A                           1,65                      L4
           Statement invalid 9O                                      1A Height
                                                                     1O Invalid     (3)

2.1.5      Area of lampshade = ߨ × radius × radius                   CA from 2.1.1             M
                             = 3,142 × 10 cm × 10 cm9SF              1SF Substitution          L3
                             = 314, 2 cm2 9MCA                       1MCA Area of
           Area including wastage = 314, 2 cm2 × 1,0425 9M           lamp shade
                                  = 327,5535 cm2 9CA                 1M Multiply by
                                  ≈ 328 cm2 9R                       1,0425
                                                                     1CA Area including
                                                                     wastage
                                                                     1R Nearest cm2 (5)

2.2.1      Number of parts = 22 parts 99A                            2A Number of parts       M&P
                                                                                   (2)         L2

2.2.2      P(set screw) = 9A                                                                   P
                          ଶ                                          CA from 2.2.1
                          ଶଶ 9MCA
                                                                     1A Number of set          L2
                        = 0,090909….
                                                                     screws
                        ≈ 0,091 9R
                                                                     1MCA
                                                                     1R 3 dec places (3)

2.2.3      To prevent shocking 99R                                   2R Reason         (2)    M&P
                                        OR                                                     L4
           For safety purposes
           Accept any other relevant reasons

2.2.4      Bulbs can break/damage 99R                                2R Explanation (2)       M&P
                                                                                               L4

2.2.5      To connect Stem 2 with Stem 3 99A                         2A Explanation (2)       M&P
                                                                                               L4

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4                                MATHEMATICAL LITERACY P2                        (EC/NOVEMBER 2020)

QUESTION 3 [33 MARKS]
Ques. Solution                                                                 Explanation           Topic
                                                                                                      &
                                                                                                     Level
3.1.1     Southwest 99A                                                        2A Southwest          M&P
          North 99A                                                            1A North          (4)  L2

3.1.2     Scale refers to the relationship (ratio) between distance on a map   2A Definition     (2)    M&P
          and the corresponding distance on the ground (reality)       99A                               L1

3.1.3     Measure bar = 1,8 cm 9A (Accept 1,7 cm to 1,9 cm)                    1A Measure bar           M&P
          1,8 cm = 2 km                                                        1C km to cm               L3
          1,8 cm = 200 000 cm 9C
          ⸫ 1 cm = 111 111, 111 9S                                             1S Simplification
          ⸫ 1 : 111 000 9R                                                     1R Nearest ‘000 (4)

3.1.4     Speed =
                     ࡰ࢏࢙࢚ࢇ࢔ࢉࢋ                                                                           M&P
                       ࢀ࢏࢓ࢋ                                                    1SF Substitution          L3
                       ૚ૡ,૛ ࢑࢓
          65 km/h =              9M                                            1M Changing
                          ࢀ࢏࢓ࢋ
                     ଵ଼,ଶ ௞௠
          Time = ଺ହ ௞௠/௛ 9M                                                    subject of formule
                                                                               1A Time in hours
               = 0,28….h 9A                                                    1CA Time in min
               = 16,8 min 9C                                                   1M Add times
               = 17 minutes                                                    1CA Arrival time
          Time of arrival = 14:53 + 17 minutes 9M                                               (6)
                          = 15:10 9CA

3.1.5     Because of the (Indian) ocean 99R                                    2R Reason         (2)    M&P
                                                                                                         L4

                                                                                                        M
3.2.1     Steak = 0,454 kg 99A                                                 2A Kilogram       (2)    L1

3.2.2     Salt = 0,5 × 5 ml                                                                             M
               = 2,5 ml 9MA                                                    1MA Millilitres          L2
          Black pepper = 0,25 × 5 ml
                        = 1,25 ml 9CA                                          1CA Millilitres
          Total = 2,5 ml + 1,25 ml
                = 3,75 ml 9CA                                                  11CA Total        (3)

3.2.3     1 cup broth = 250 ml 9MA                                             1MA 250 ml               M
          ଷ
            cup whipping cream = 0,75 × 250 ml                                                          L4
          ସ
                                                                               1MA 187,5 ml
                                  = 187,5 ml 9MA
          ଵ
            cup sour cream = 0,25 × 250
          ସ
                            = 62,5 ml 9MA                                      1MA 62,5 ml
          Total = 250 ml + 187,5 ml + 62,5 ml
                = 500 ml = 0,5 litres 9CA                                      1CA Litre
          Statement is valid 9O                                                1O Valid          (5)

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(EC/NOVEMBER 2020)                    MATHEMATICAL LITERACY P2                                   5

3.2.4         Cooking time9M                                 9MCA            1M Multiply by 2          M
              = (3 min × 2) + 8 min + 1 min + 1 min + 2 min + 20 min + 2     1MCA Adding all           L2
              min                                                            times
              = 40 minutes 9CA                                               1CA Total time (3)

                                                                                                       M
3.2.5         Time for preparation should also be considered. 99A            2A Reason         (2)     L4

QUESTION 4 [20 MARKS]
Ques.  Solution                                                              Explanation              Topic
                                                                                                       &
                                                                                                      Level
4.1.1         6 seats      99A                                               2A No of seats           M&P
                                                                                               (2)     L1

4.1.2         Raised Seating Area = 112 seats 9A                             1A Seats in RSA          M&P
              Flat Seating Area = 85 seats 9A                                1A Seats in FSA           L3
              Difference = 112 – 85 9M                                       1M Subtract
                         = 27 seats 9CA                                      1CA Difference (4)

4.1.3                      ଵଶ 9A                                             1A Numerator             M&P
              P(L-row) =
                           ଵଽ଻ 9MCA
                                                                             1MCA                      L2
                                                                             Denominator (CA
                                                                             from 4.1.2)   (2)

4.1.4         Walk to A5, then turn right 9A                                 1A Straight              M&P
              Walk straight pass the Row D 9A                                1A Turn right             L4
              Third Row (G) third seat 9A                                    1A 3rd row, 3rd seat
              Accept any other relevant responses                                             (3)
4.2.1         Volume of drum = ߨ × radius × radius × height                                            M
                                           9C     9A                         1C mm to cm               L3
                               = 3,142 × 29 cm × 29 cm × 93 cm 9SF           1A Radius
                               = 245 745, 246 cm3 9CA                        1SF Substitution
              Litres = 245 745, 246 cm3 ÷ 1 000 cm3                          1CA Volume
                     = 2 45,745 litres 9CA                                   1CA Litres       (5)

4.2.2         x      The volume of advertisement refers to the maximum the   2A 1st Reason             M
                     drum can hold. 99A                                                                L4
              x      The calculated volume refers to the entire drum. 99A    2A 2nd Reason (4)

                                                                                       TOTAL:         100

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