# Mathematical Literacy Grade 12 P2 EC June 2019 Memo (Eng)

> Grade 12 Mathematical Literacy Paper 2 memorandum from the EC June 2019 (English), 16 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/maths-lit-p2-memo-june-2019-eng/a904f387-f836-457d-bf6f-ca3ee3002ff3
- Updated: 2026-09-27
- Subject: Mathematical Literacy
- Grade: Grade 12
- Document type: Memorandum
- Year: 2019
- Exam period: EC June
- Paper: 2
- Curriculum: CAPS
- Pages: 16

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## About this document

Mathematical Literacy · Grade 12 · EC June · 2019. Memorandum, 16 pages. Read online or download the PDF.

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                              NATIONAL
                         SENIOR CERTIFICATE

                                  GRADE 12

                                  JUNE 2019

               MATHEMATICAL LITERACY P2
                  MARKING GUIDELINE
MARKS:   100

  SYMBOL                                          EXPLANATION
     M         Method
    MA         Method with accuracy
    CA         Consistent accuracy
     A         Accuracy
     C         Conversion
     S         Simplification
 RT/RG/RM      Reading from a table OR reading from a graph OR diagram OR from map a OR a
               plan
    F          Choosing the correct formula
    SF         Substitution in a formula
     J         Justification
    P          Penalty, e.g. for no units, incorrect rounding off etc.
    R          Rounding Off/Reason
   AO          Answer only
   NPR         No penalty for rounding
    O          Opinion
    D          Define

                         This marking guideline consists of 9 pages.

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2                              MATHEMATICAL LITERACY P2                                  (EC/JUNE 2019)

NOTE:
   If a candidate answer a question TWICE, only mark the FIRST attempt.
   If a candidate has crossed out (cancelled) an attempt to a question and NOT redone the
        solution, mark the crossed out (cancelled) version.
       Consistent accuracy (CA) applies in ALL aspects of the marking guidelines; however it stops
        at the second calculation error.
       If the candidate presents any extra solution when reading from a graph, table, layout plan and
        map, then penalise for every extra incorrect item presented.

QUESTION 1 [23 MARKS]
Ques.   Solution                                                             Explanation                   Level
1.1.1   Amount overdue                                                       1 RT Correct values            L2
        = R26 263,55 – M R25 754,61 RT                                     1M Subtracting                  F
        = R508,94                                                                     OR
                                OR                                           1 RT Correct values
        Amount overdue                                                       1M Subtracting
        = R2 696,94 – M R2 188,00 RT
        = R508,94                                                                                   (2)

1.1.2          Probability                                                                                  L2
                                                                            1A Numerator                   P
               =                                                             1A Denominator
                      
               = 0,18  CA                                                   1CA Rounding          (3)

1.1.3          EBUS 2715 fees                                                1 RT All correct values        L4
               = 2 696,94 + (3 715 × 7) + (4 280 × 2) + 3 510                1M Adding values               F
               + 1 020 + 25,21 + 14,40 + 210 – 2 188 RT MM                1M Subtracting 2188
               = 39 853,55                                                   1M Subtracting from
               = 45 198,55 – 39 853,55 M                                    45 198,55
               = R5 345                                                      1 CA Difference
               Difference = 5 345 – 3 715                                    1O Not valid
                         = R1 630 CA
               Statement is not valid O                                                            (6)

1.1.4                                                                       1RT Correct values             L2
               % Registration fee =              x 100 M                    1M Multiplying by 100          F
                                          ,
                                  = 3,96%CA OR 4%                           1CA Percentage
                                                                             NPR                (3)

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(EC/JUNE 2019)                           MATHEMATICAL LITERACY P2                           3

1.2.1                                                              CA from 1.1.3                L3
                 Semester 1 =                                       1M Adding all values         D
                                              
                                                                    1M Dividing by 6
                           = R4 080,83 CA                          1CA Mean

                 Semester 2 =
                                                                    1CA Mean semester 2
                            = R3 787  CA                           1M Subtract
                 Difference = R4 080,83 – R3 787 M                 1CA Difference
                            = R293,83 CA                                             (6)

1.2.2            Amount for 2017 = 4280      MM                   1M Multiplying by 100        L2
                                                                    1M Dividing by 105           F
                                 = R4 076,19 CA
                                                                    1CA Amount
                                                                             OR
                                            OR
                 Amount for 2017 =         MM                     2M Dividing by 1,05
                                     ,
                                 = R4 076,19 CA                    1CA Amount         (3)
                                                                                      [23]

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4                            MATHEMATICAL LITERACY P2                         (EC/JUNE 2019)

QUESTION 2 [29 MARKS]
  Ques. Solution                                             Explanation                Level
2.1.1   Distance from Vanrhynsdorp to Garies                 1 RT Correct values         L4
         = 433 – 289 RT       OR = 258 – 114 RT            1A Distance                M&P
         = 144 km A           OR = 144 km A
        Distance from Kamieskroon to Springbok
        = 547 – 479            OR = 68 – 0                   1A Distance
        = 68 km A             OR = 68 km                    1O Incorrect
        Incorrect O                                         1O Reason
        Strip chart not drawn to scale R                                        (5)

2.1.2         Distance = (289 – 52) + 121 M                 1M Add correct              L2
                      = 358 km CA                           distances                  M&P
                                        OR                   1CA Distance                L3
              Distance = 65 + 44 + 53 + 75 + 121 M                                      M
                      = 358 km CA
              Distance = Speed Time                          1SF Substitution
                 358 = 95 Time SF                           1M Change subject of
                    = Time M                                formula
              Time = 3,76842 hours
                                                             1C Convert to minutes
              Minutes = 0,76842 60
                                                             1M Adding times
                      = 46 minutes C
                                                             1CA Time
              Time of arrival = 7:00 + 0:45 + 3:46 M
                              = 11:31 CA                                        (7)

2.2.1         Area of rectangle = length x width             1C Convert to mm            L3
                               = 150 120 CSF               1SF Substitution            M
                               = 18 000 mm2 A               1A Area of rectangle
                                                             1A Radius
              Area of a circle =              radius         1CA Area of circle
                               = 3,142 40 mm 40 mm A        1M Subtraction of the
                               = 5 027,2 mm2 CA             two areas
                                                             1CA Area without a
              Area without the photo = 18 000 – 5 027,2 M   photo
                                    = 12 972,8 mm2 CA                          (7)

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(EC/JUNE 2019)                     MATHEMATICAL LITERACY P2                               5

2.2.2      Surface area                                                                    L3
           = 2(length width + width height + length height)    1SF Substitution            M
           = 2(390 270 + 270 300 +390 300)SFA                1A Correct values
           = 2(105 300 + 81 000 + 117 000) S                  1S Simplification
           = 606 600 cm2 CA                                   1CA Surface area.
                                                                                    (4)

2.3        Company A                                           1RT Correct values          L3
           IQR = 3 500 – 1 400 RT                             1CA IQR (A)                Data
               = 2 100 CA                                     1A Range (A)
           Range = 5 300 – 800
                 = 4 500 A
           Company C
           IQR = 5 800 – 3 900                                 1CA IQR (C)
               =1 900 CA                                      1CA Range (C)
           Range = 6 300 – 2 800
                  = 3 500 CA
           Both IQR and range are higher for Company A than    1O Finding
           Company C O
                                     OR
           Both IQR and range are smaller for company C than
           Company A O                                                             (6)
                                                                                   [29]

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6                             MATHEMATICAL LITERACY P2                         (EC/JUNE 2019)

QUESTION 3 [18 MARKS]
  Ques.               Solution                             Explanation                   Level
3.1.1   Value of A = 6 3 + 1           6 M     1MA Matches won and drawn                 L2
                  = 18 + 6                      1A Value of A                             D
                  = 24 A                       1M Subtracting and dividing by 3
        Value of B = 19 – 4
                                                1A Value of B
                        =     M
                        = 5 A                                                     (4)

3.1.2                                           CA from 3.1.1                             L2
              Probability =   AA              1A Numerator                              P
                                                1A Denominator
                                                                                   (2)

3.1.3         Points = 2 3 + 1                  CA from 3.1.1                             L4
                     =7 A                      1A Points                                 D
              Total = 21 + 7
                    = 28 MA                    1MA Total points

              Difference = 28 – 24              1MA Difference
                        = 4 MA
              Statement not valid O            1O Not valid                       (4)

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(EC/JUNE 2019)                        MATHEMATICAL LITERACY P2                                  7

   3.2.1         School A = 45 2 3 = 270 M             1M No. of minutes                       L4
                           45 2 = 90                                                            M
                 Total   = 270 + 90
                         = 360 minutes MA              1M Total no. of minutes
                 Hours     =                            1C Convert to hours
                           = 6 h C

                 School B = 30 8 + 30
                         = 240 + 30
                         = 270 minutes                  1CA No of hours for school B
                                                        1O Conclusion
                 Hours     =
                         = 4,5 h CA
                 School B is CAPS compliant O                                         (5)

   3.2.2                                                1MA Concept of ratio                    L3
                 Ratio =       MA                                                              D
                           = 31

                 Grade 10 = 31 4
                          = 124                         1MA Total for Grade 10 and
                                        MA             Grade 11
                 Grade 11
                 = 31 3
                 = 93                                   1CA Total
                 Total books = 62 + 124 + 93
                             = 279 CA                                                (3)
                                                                                     [18]

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8                            MATHEMATICAL LITERACY P2                          (EC/JUNE 2019)

QUESTION 4 [30 MARKS]
 Ques.                      Solution                              Explanation             Level
 4.1.1 There are emergency exit points between row 8                                       L4
       and row 9 A                                         2A Reason              (2)   M&P

    4.1.2     Seats in the economy class                     1MA Seats per row             L2
              = 18 MA 6 MA                                 1MA Total rows               M&P
              = 108 A                                       1A Total no of seats
                                                                                    (3)

    4.1.3     There is more space R                        2R Reason                     L4
                                      OR                                                  M&P
              Service is better R
                                      OR
              It is more relaxing R

              Any other relevant reason.                                            (2)

    4.2.1     Quarter finals = (1 412 2) + (4 249   2) RT   1RT Correct values for         L4
                            = 2 824 + 8 498 MA              both matches 2                 F
                            = $11 322 CA                    1MA Adding
                                                             1CA Total
                                                             1RT Correct values for
              Finals       = (2 186 2) + (5 538     2) MA   both matches 2
                           = 4 372 + 11 076                  1CA Total for final
                           = $15 448 CA                     1M Adding
                                                             1CA Total in dollars
              Total amount = 11 322 +15 448 M               1O Valid
                           = $26 770 CA

              Statement is valid O                                                 (8)

    4.2.2     % change =                   100% RTMM      1RT Correct values             L2
                                                             1M Correct                     F
                                                             denominator
                       = 41,35% CA
                                                             1M Multiplying by 100
                                  OR
                                                             1CA Percentage
              % change =           100% RTMM

                        = 115,29% CA                                               (4)

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(EC/JUNE 2019)                          MATHEMATICAL LITERACY P2                                   9

   4.2.3         Year 1 = 20 000 1,065 M                         1M Increasing by 6,5%          L3
                        = $21 300 CA                             1CA Amount for                 F
                                                                  year 1
                 Year 2 = 21 300 1,065                            1CA Amount for
                       = $22 684,50 CA                           year 2
                                                                  1A Interest rate for
                 Rate for 9 months =     6,5%                     9 months
                                   = 4,875% A

                 Year 3 = 22 684,50 1,04875
                                                                  1CA Final amount
                        = $23 790,37 CA
                                      OR
                 Final amount
                 = 20 000 1,065 M 1,065 M
                 1,04875AA
                 = $23, 79037 CA
                                                                                      (5)

   4.2.4         Men play more vigourously R                    2R Reason                      L4
                                       OR                                                        F
                 Men’s matches attract more spectators R
                                       OR
                 Performance/Skills better R
                 Any other relevant reason
                                                                                      (2)

   4.2.5         Ticket prices increase from day 1 to the final   2O Trend                       L4
                 day O                                                                         D
                                                                  2R Reason for
                 Competition gets tougher and therefore matches   trend
                 become more interesting to watch. R                                (4)
                                                                                     [30]

                                                         TOTAL:                      100

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