# Mathematical Literacy Grade 12 KZN March 2023 Paper & Memo

> Grade 12 Mathematical Literacy question paper and memo from the KZN March 2023, 20 pages. Read online or get the free PDF download.

- Page: https://www.hlayiso.com/library/maths-literacy-grade-12-march-2023-qp-and-memo/b0dc60e2-95e0-4283-b39d-368df29a3f4f
- Updated: 2026-09-27
- Subject: Mathematical Literacy
- Grade: Grade 12
- Document type: Question paper and memo
- Year: 2023
- Exam period: KZN March
- Curriculum: CAPS
- Pages: 20

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## About this document

Mathematical Literacy · Grade 12 · KZN March · 2023. Question paper and memorandum, 20 pages. Read online or download the PDF.

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## Document text

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### Page 1

EDUCATION
REPUBLIC OF SOUTH AFRICA

NATIONAL
SENIOR CERTIFICATE

MARKS: 100

TIME: 2 hours

This question paper consists of 10 pages, and an Addendum with 2 Annexures.

—————— a

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Mathemaicowmnloaded from Stanmoreghysics.com arch 2023 Common T=

INSTRUCTIONS AND INFORMATION

1. This question paper consists of FOUR questions. Answer ALL the questions.
2.
3. Number the answers correctly according to the numbering system used in this

question paper.

4, Start EACH question on a NEW page.

5. You may use an approved calculator (non-programmable and non-graphical), unless
stated otherwise.

6. Show ALL calculations clearly.

7. Round off ALL final answers appropriately according to the given context, unless
stated otherwise.

8. Indicate units of measurement, where applicable.

9. Write neatly and legibly.

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Mathematical oad March 2023 Common Test

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QUESTION 1

il Nombuso has an account with Standard Bank. ANNEXURE A shows

an extigppof her bank statement.

Use Al URE A to answer the questions that follow.

1.1.1 “Define the word “debit” according to the given context above. (2)
1.1.2 Determine the number of days covered by the statement. (2)
1.1.3. Write down the statement frequency. (2)
1.1.4 Show how the total VAT amount of R38,09 was determined. (2)

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1.2

March 2023 Common Test

A summary of 2022/2023 government income and expenditure is given below.

Income Expenditure
Sector Amount
(in billion rand)
TAX AT A GLANCE Economic Development R227,1
Projected tax revehue 2022/2023
Learning and Culture R441,5
R439.7bn i
R587.9bn fe Peace and Security R220,7
Personal income tax
ee Health R259,0
R62.5bn General Public Service R 69,2
ust
“hie, { R40-9bn) ws Community R236,3
‘ Development
Debt Service Costs R301,8
Contingency Reserve R 10,0
Social Development R364,4
TOTAL R1 493,5 TOTAL R2 130

(Extract: www.treasury.gov.za]

Use the information above to answer the following questions.

1.2.1 Identify the type of tax which is the biggest source of revenue for the state. (2)

1.2.2. Write the amount received from personal income tax as a number in millions. (2)

1.2.3. Show how the total income was determined. (3)

1.2.4 Calculate the state deficit and write the figure in full. (3)
1.2.5 Ifa sector is chosen at random, determine the probability that the expenditure

amount is greater than R200 billion. (2)

[20]

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Mathematical Liter March 2023 Common Test

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QUESTION 2
21 Prince Mchunu owns a house in Johannesburg built on a stand that is 1 550 m2. Sewer
monthly.ch arge depends on the size of the stand.

TABE Tah ton shows the 2022/2023 water and sewer tariffs for Johannesburg
Munieipality. N.B: Tariff rates exclude 15% VAT.

Residential Water Tariff Sewer Monthly Charge (VAT Incl.)

Kilolitres R/ke Block | Stand Size (m*) Monthly Charge
0-6 - 1. Up to and including

+6 - 10 R22,26 300m? R_ 307,42

+10-15 R23,23 | 2. More than 300m?

+15 - 20 R32,57 to 1000m? R_ 598,44

+20 - 30 R45,01 | 3. More than 1000m?

+30 - 40 R49,23 to 2000m? R_ 905,33

+40 - 50 R62,11

+50 R66,56_ | 4. More than 2000m? R1 304,42

Source: [www.joburg.org.za]

NOTE: Stand is a plot size

Use the given information and TABLE 1 above to answer the following questions.
2.1.1 Determine the sewer monthly charge for Prince Mchunu. (2)

2.1.2 Match the items in Column A with items in Column B. Write the
number and letter ONLY.

A B

(i) VAT X: 90 533 cents

(ii) Amount Excluding VAT | Y: Value Added Tax

(iii) R905,33 Z: (Amount Including VAT) + 1,15 (3)

2.1.3 Calculate the sewer monthly VAT amount charged for Prince Mchunu’s stand
size. (2)

2.1.4 Prince Mchunu’s household used 24 k¢ of water in January 2027
the wedding celebration.

Calculate the total amount Prince Mchunu paid for water a

15% VAT. (6)

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Mathematical Litera March 2023 Common Test

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2.2

Prince Mchunu applied for a loan of R30 000 from Direct Axis. Loan conditions are given
below.

ate. % p.a compounded monthly
Monthly rep ent: R1 891,16 (including monthly service fee)
Loan term: 2 years

N.B: Once-off initiation fee can be paid upfront or be added to the monthly
repayment. Prince paid it upfront.

ANNEXUREB shows the interest incurred, payments made and balance owed over the loan
term until the loan is fully paid.
Source: www.directaxis.co.za

Use the information above and ANNEXURE B to answer the following questions.

2.2.1. Calculate the monthly interest rate as a percentage. Do not round off. (2)
2.2.2 Calculate the real cost of the loan. (3)
2.2.3 Prince claimed that the total interest on the loan was exactly R7 903.

Verify his claim with calculations. (5)

2.3

The annual inflation rate for 2022 was 5,73% and the projected annual inflation
rates for 2023 and 2024 are 4,65% and 4,6% respectively. The price of cooking
oil (50) for 2022 was R229,99 at Pick n Pay.

Source: www.pnp.co.za

Use the given information above to answer the following questions.

2.3.1 Using the 2022 price of cooking oil and the 2022 inflation rate, calculate
what the same 5 litres of cooking oil cost in 2021. (3)

2.3.2 Calculate what the expected price of cooking oil (50) will be in

using the given inflation rates. (4)
[30]

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Mathematical Literacy March 2023 Common Test

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QUESTION 3

3.1
Bongani, a 2, earns a basic salary of R35 700 per month. He is married with 3 children
and belon medical aid scheme.

Use the fio above to answer the questions that follow.

3.1.1

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Determine Bongani’s annual taxable income if he contributes 7.5% of the basic
salary towards his pension fund each month. (4)

Calculate Bongani’s annual tax if he receives a rebate of R16 425 per year anda
medical aid credit of R815 per month for his entire family.

You may use the following formula:
Annual Tax — Rebate — Medical aid credit for the year

= [73 726 + (31% of the taxable income above R353 000)] — Rebate — Medical
aid credit for the year (6)

Now determine Bongani’s monthly tax. (2)

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Mathematical Liter

3.2

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South African Revenue Service reported to the media that R1, 564 trillion tax revenue was
received in 2022. TABLE 2 below shows the tax revenue received by SARS from 2019 to
2022.

TABLE2: TAX

REVENUE RECEIVED BY SARS FROM 2019 TO 2022

million | 2019/20° 2020/21" 2021/22"

Personal income Tax' 529 172 48S 446 555 780
Corporate Income Tax" 214 386 204 399 S23 577
Dividends Tax / STC 27 930 24 845 33 397
Value-added Tax 346 762 B31 297 Boo Go
Domestic VAT 399 288 392 836 348 782
Iraport VAT RTS O87 DOS 54 204 3232
VAT Refunds 232515 228 193 -262 417
Specific Excise Duties* 46 827 32 273 49 SS2
Fuel Levy 80 175 75 503 88 877

Customs Quties™ 55 428

_ | 84. 902

1355 781.

[Adapted source: www.sars.gov.za]

Use the information in TABLE 2 above to answer the questions that follow.

3.2.1 Write R1, 564 trillion as a number in full.

3.2.2 Determine the difference between the reported tax received and the actual tax
received in 2021/2022.

3.2.3 Calculate the percentage change in the tax received from 2019/20 to 2020/21.
3.2.4 Show by calculation how the Value-added Tax of 390 697 was determined.

3.2.5 Write down the ratio of the corporate income tax to personal income tax in 2021/22.

March 2023 Common Test

(2)
(3)

(4)
(2)
(2)

[25]

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QUESTION 4

41 The data in TABLE 3 below is taken from 2019 National Senior Certificate exam report.

TABL NUMBERS OF LEARNERS WHO WERE IN GRADE 2 IN 2009 AND
THE } hit RIC PASS RATE IN 2019.

Eastern Cape | 179,461 | 109,870 | 63,198 | 48,331 | 76.5% ?

Free State 52,781 | 39,755 | 25,572 | 22,602 | 88.4% 1
Gauteng 145,109 | 132,676 | 97,829 | 85,342 | 87.2% 2
KwaZulu Natal {| 222,656 | 218,915 | 116,937 | 95,017 | 81.3% 5
Limpopo 117,786 | 128,755 | 70,847 | 51,855 | 73.2% 9
Mpumalanga 80,631 | 75,563 | 43,559 | 34,995 | 80.3% 6
Northern Cape | 23,417 | 15,623 | 9,138 6,990 | 76.5% 3
North West 68,567 | 45,454 | 26,819 | 23,272 | 86.8% 7.
Western Cape | 81,847 | 61,066 | 50,404 | 41,502 | 82.3% 4
NATIONAL 972,255 | 827,677 | $04,303 | 403,606 | 91.3%

|Adapted source www:groundup.org.za]

Use the information in TABLE 3 above to answer the questions that follow.

4.1.1 Determine the percentage of learners from Grade 2 in 2009 who passed matric in

2019 in South Africa. (4)
4.1.2 Determine the name of the province with the median matric pass rate in 2019. (2)
4.1.3. Calculate the average (mean) number of learners who passed matric in 2019. (4)

4.1.4 | Which measure of central tendency is a better representation of the data:
mean or median? Give a reason for your answer. (3)

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Mathematical Litegac; March 2023 Common Test
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4.2
The box and whisker plot below shows the heights in inches of learners in a class.

Note: 1 inch = 2,54 cm

Height of Girls and Boys (inches)

—{t +
—— fp

60 61 62 63 64 65 66 67 68 69 70 71 2 73
Height

[Source: www.nagwa.com]

Use the information above to answer the following questions.
4.2.1 Determine the difference in the median height of the learners in inches. (3)
4.2.2 Calculate the inter quartile range for the height of the girls in inches.
You may use the formula:
IQR =Q3-Ql G3)
4.2.3 A learner stated that 25% of girls’ height was equal to 50% of the boys’ height.

Verify if this statement is CORRECT. G3)

43 A survey was conducted amongst learners who participate in sport. TABLE 3 below
shows the number of girls and boys who participate in sport.

TABLE 3: LEARNER PARTICIPATION IN SPORT

SWIMMING SOCCER ATHLETICS TOTAL
GIRLS 5 12 17 34
BOYS ul 3 7 21
TOTAL 16 15 24 =~ 55
4.3.1 Determine the probability, as a decimal, of a girl participatin imming.

[25]

TOTAL: [100]

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Mathematical Literacy March 2023 Common Test

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ANNEXURE A
QUESTION 1.1
—
ESHOWE 76 Statement No: 11
MONTHLY Page 5 of 5
Statement Frequency: Monthly
Statement from 08 October 2022 to 08 November 2022
BANK STATEMENT / TAX INVOICE
| ELITE CURRENT ACCOUNT Account Number 1010 919 HHH #
Details Service Debits Credits Date Balance
BALANCE BROUGHT FORWARD 14,779.26
| FEE - PRE-PAID TOP UP - a.50- 1103 14,778.76
| IMMEDIATE PAYMENT 9,200.00- 1103 §,578.76
67982100 R NGWENYA
| FEE IMMEDIATE PAYMENT Co §0.00- 1103 5,528.76
| PRE-PAID PAYMENT TO 15.00- 1103 5,513.76
| MTN PREPAID 0625015755 : |
| FEE - PRE-PAID TOP UP tt 0.50- 1103 5,513.26
| FEE: PAYMENT CONFIRM - SMS +t 1.35- 1103 5511.91
| RAKESH NOOKHAI |
| CHEQUE CARD PURCHASE 57,90- 1104 5454.01.
| ESHOWE 2 4451*4762 02 NOV |
| CHEQUE CARD PURCHASE 29.90- 1104 6,424.11 |
| ESHOWE 2 4451*4762 02 NOV \
| AUTOBANK CASH WITHDRAWAL AT 2,050.00- 1105 3,374.11 |
| QOQODSG7 2022-11-0ST07:39:38 44 i
| 1B PAYMENT FROM 3,800.00 1107 TATAAT |
| BUMISANI |
| 1B PAYMENT TO 3,800,00- 11:07 3,374.11 |
| BIDORBUY LAPTOP |
| CHEQUE CARD PURCHASE 150,00- 1108 3,224.14 |
SASOL ESHOWE 445174762 04 NOV |
## These fees include VAT at 14% up to 31 March 2018 and at 15% from 1 April 2018. |
[VAT Summary
| Total charge amount (exclucling VAT) 253.46-
| Total VAT 38,09- |
| Total charge amount (including VAT) 291.55- |
Account Summary
Details of Agreement
alance at date of statement 3,224.17
[Extract: Nombuso’s bank statement

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Mathematical Literacy 3 March 2023 Common Test
NSC-ADDENDUM

ANNEXURE B

QUESTION 2.2
Month 1 2 3 4 5 6 7 8 9 10 ll 12
Interest 700 672,21 643,76 614,66 584,87 554,39 523,20 491,28 458,62 425,19 390,99 355,98

Payment 1891,16 1891,16 1891,16 1891,16 1891,16 1891,16 1891,16 1891,16 1891,16 1891,16 1891,16 1891,16

Balance 28808,84 | 27589.89 | 26342,49 | 25065,99 | 23759,70 | 22422,93 | 21054,97 | 19655,09 | 18222,55 | 16756,58 | 1525641 | 13721,23

ydasowuezS wo1g papeojumog

Month 13 14 15 16 17 18 19 20 21 22 23 24

Interest 320,16 283,51 245,99 207,61 168,32 128,12 86,99 44,89 1,81 S

Payment 1891,16 1891,16 1891,16 1891,16 1891,16 1891,16 1891,16 1891,16 Cc 5

Balance 12150,23 | 10542,58 8897.41 7213,86 5491,02 3727.98 1923.81 77,54 0 2
[Adapted from Prince’s loan statement] 3

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KWAZULU-NATAL PROVINCE

EDUCATION

MARKS: 100

REPUBLIC OF SOUTH AFRICA

NATIONAL
SENIOR CERTIFICATE

SYMBOL EXPLANATION

M Method

MA Method with accuracy

CA Consistent accuracy
A Accuracy
C Conversion
S Simplification

RT/RG/RD/RM _| Reading froma table/ graph/ diagram/Map

SE Correct substitution in a formula
Oo Opinion/ reason/deduction/example/Explanatign=
J Justification Iona?
R. Rounding off Jonnr
F deriving a formula loony

AO Answer only full marks —
P Penalty e.g. for units, incorrect rounding off etc.

NPR No penalty for rounding / units
D Correct definition

This marking guideline consists of 8 pages.

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MathemayiWA8aded from Sta rephysigsncom March 2023 Common Test
QUESTION 1 [20 MARKS] AO FULL MARKS
QUE | Solution Explanation T&L
1.1.1 | Money deducted from Nombuso’s accountY VA 2A correct definition (2) | F
OR L1
Accept any validsdefinition relating to the context.
1.1.2 | 32 days’ 7 A 2A correct number of F
(2) | Li
1.1.3. | MonthlyY 2A correct frequenc F
y ya quency @ |i
*1.1.4 YRT F
VAT = R291,55 — R253,46YM 1RT for R291,55 Ll
= R38,09 1M for subtraction (2)
1.2.1 | Personal Income Tax¥ VA 2A answer (2) | F
L1
1.2.2 | R587 900 million’ VA 2A answer (2) |F
Li
1.2.3 ¥M YM F
Total = R587,9 bn + R439,7bn + R269,9bn + R92,6b + 62,5bn | 1M first pair Ll
+R40,9YM 1M second pair
= R1493,5 bn 1M third pair (3)
1.2.4 | Deficit = R1 493,5bn — R2 130bnYM 1M subtracting F
= (R636,5bn)VA 1A answer Li
= (R636 500 000 000)“ CA 1CA answer in full
(3)
*1.2.5 P
aye 7VA 1A for numerator Ll
P(greater than R200 billion) = OVA 1A for denominator (2)
[20]

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March 2023 Common Test

QUESTION 2 [30 MARKS]

2.1.1 | R905,33YYRT 2RT answer F
(2) | L1
2.1.2 | (i) YVA 1A for Y F
(ii) ZVA 1A for Z Li
Gi)xva 1A for X (3)
2.1.3. | VAT = R90 (R905,33 + 1,15)“™M 1M dividing 1.15 F
= R905, R787.24 1A answer L2
= R118,09VA
OR OR
VAT = R905.33 x (15 + 115)“~M 1M dividing 115
= R118.09YM 1A answer (2)
2.1.4 | Charge = 4(22,26) + 5(23,23) + 5(32,57) + 4(45,01)V¥YM 2M for adding all F
= R548,08VA correct values L3
v¥M 1A answer
Total Payment = R548,08 x 1,15 + R905,33V“M 1M multiplying by
= R1535,62VCA 1,15
1M adding R905,33
OR 1CA answer
OR
Charge = 4(22,26) + 5(23,23) + 5(32,57) + 4(45,01)”™”M 2M for adding all
correct values
= R548,08VA 1A answer
VAT = 15% x R548,08
= R82,21VM 1M for VAT
Total Payment = R548,08 + R82,21 + R905,33”M 1M for adding
= R1535,62” CA 1CA answer (6)
2.2.1 | Monthly interest rate = 28% + 12V™M 1M dividing by 12 | F
= 2,333333333%VA 1A answer L2
(2)
2.2.2 ¥M 1M multiplying by | F
Real Cost of Loan = 20(R1 891,16) + R79,35 + R1 207,50V“M 20 L2
= R39 110,05VA 1M adding R79,35

a

and R1 207,50
bia answer (3)

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March 2023 Common Test

2.2.3 v¥M vM 1M multiplying F
Interest = 20(R1 891,16) + R79,35 — R30 000YM 1M adding L4
= R7902,55VA 1M subtracting
The claim is NOT validV¥O 1A correct answer
10 conclusion
OR
OR
v v¥M
Interest = (R' ,05 — 1207.50) — R30 000 1M multiplying
= R7905,55VA 1M adding
1M subtracting
The claim is NOT validVvO 1A correct answer
10 conclusion
6)
2.3.1 ¥vM 1M dividing F
2021 Price = R229,99 + 105,73%YM 1M for dividing by L2
= R217,53VA 105,73%
1A answer
OR
OR
. 100YM
2021 Price = R229,99 x 105,737M 1M for multiplying by
= R217,53VA 100
1M for 105,73
1A answer (3)
2.3.2 | Price for 2022 = R229,99 1M multiplying by F
Price for 2023 = R229,99 x 104,65%YM 104.65% L3
= R240,68VA 1A answer
Price for 2024 = R240,68 x 104,6%YM 1M multiplying by
= R251,75YCA 104.6%
1CA answer
OR OR
YM
2023 Increase = 4,65% x R229,99 1M multiplying by
= R10,69 4.65%
Price for 2023: R229,99 + R10,69 = R240,68VA 1A answer
2024 Increase = 4,6% x R240,68
=R11,07YM 1M multiplying by
Price for 2024 = R240,68 + R11,07 4.6%
= R251,75YCA
1CA answer
(4)
[30]

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March 2023 Common Test

QUESTION 3 [25MARKS]
QUE | Solution Explanation T&L
3.1.1 Monthly taxable income = R35 700 — (R35 700 x 7.5%)” MA | 1MA subtracting 7,5%
33 022,50VA 1A correct answer
Annual taxal ome = R33 022,50 x 12 ™MA 1MA_ multiplying by 12
= R396 270VA 1A correct value
(4)
3.1.2. | Annual Tax CA from 3.1.1 F
. L3
VSF YM YMCA VSE YMA 1SF annual taxable income
=[73 726 + (31% (396 270 - R353 000)] — 16 425-—(815 x12) | 1M __ multiplying by 31%
=R60 934,70VCA 1MCA subtracting values
1SF _ rebate
1MA subtracting medical
credit for the year
1CA answer (6)
3.1.3. | Monthly tax = R60 934,70 + 12 ™MCA CA from 3.1.2 F
= R5 077.89 YCA 1MCA dividing by 12 be
1CA _ answer (2)
3.2.1 | 1564 000 000 000V VA 2A correct answer (2) F
L2
*3.2.2 | Difference 2MCA subtracting correct F
=R 1 564 000 000 000 — 1 563 765 000 000V YMCA. values L2
=R235 000 000VCA 1CA answer (3)
3.2.3 YMA 1MA subtracting correct F
1249 753-1 355 781 values L2
% Change = sa * *100 %¥M 1MA. dividing by 1 355 781
7 JO,
=~ 7,82 %YCA 1M __ multiply by 100%
1CA __ answer (4)
3.2.4 ¥MA ¥MA 1MA adding correct values F
L2
Value added tax = (448 782 + 204 332) — 262 417 .
= 390 697 1MA sane 262417 (2)
faYay
*3.2.5 | 323 577: 555 780V YRT 2RT co} values and order F
L2
(2)
[25]

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March 2023 Common Test

QUESTION 4 [25 MARKS]

QUE | Solution Explanation T&L
4.1.1
1RT correct value
v
RT DH
Percentage 606 _ x 100%”M 1RT dividing by correct value | L2
SoVRT 1M multiply by 100%
551 %YCA
1CA answer (4)
4.1.2 | Median DH
1A arranging values L2
= 73.2; 76.5; 76.5; 80.3; 81.3; 82.3; 86.8; 87.2; 88.4VvA 1A correct answer
(2)
= KwaZulu Natal¥A AO
*4.1.3 DH
Mean = (48 331 + 22 602 ee +95 017 + 51 855 + 2M adding correct values L2
34 995 + 6 990 + 23 272 + 41 502)+9vM 1M dividing by 9
= 45 545,1 1CA answer
= 45 545VCA
(4)
4.1.4 | MedianY A 1A Correct answer DH
L4
Data set has an outlier of 6 990. ¥vWO 20 opinion
(3)
4.2.1 | Difference = 67 -66VY RG 2RG subtracting correct values | DH
=1linchYCA 1CA answer L4
GB)
4.2.2 | IQR =69-—66 YRGYSF 1RG correct values DH
L3
=3YCA 1SF substitution
1CA answer (3)

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March 2023 Common Test

1RG correct value DH
4.2.3 | Qi of girls = 66 YRG L2
1RG correct value
Q: of boys = 66“ RG
10 opinion (3)
The statement i CT. YO
4.3.1 5VA 1A for numerator
P(Girl swimniingy = 16 VA 1A for denominator
1CA correct answer
= v (3)
0,3125Y¥ CA NPR
[25]
TOTAL MARKS: 100

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March 2023 Common Test

NOTES:
e If. acandidate answers a question TWICE, only mark the FIRST attempt.
e Ifa candidate has crossed out (cancelled) an attempt to a question and NOT redone the solution,
e mark the crossed out (cancelled) version.
e Consistent accuracy (CA) applies in ALL aspects of the marking guidelines; however, it stops at
the second ation error.
e If the candi resents any extra solution when reading from a graph, table, layout plan and map,
then penali: every extra item presented.
1.1.4 | VAT = R253,46 x 15% Full marks
= R38,02
1.2.5 | Accept 0,778 OR 77,8% Full marks
NPR
3.2.2 | Accept R235 million Full marks
3.2.5 | 323577: 555 780 Full marks
1:1,71
4.1.3 | Mean = 403 606+9 Full marks
= 44 845,11
= 44 845

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