# Mathematical Literacy Grade 11 P1 2017 Memo

> Grade 11 Mathematical Literacy Paper 1 memorandum from the KwaZulu Natal June 2017, 10 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/maths-literacy-june-p1-qp-memo/e6740d96-aaae-420d-8926-848c8f97edd0
- Updated: 2026-09-27
- Subject: Mathematical Literacy
- Grade: Grade 11
- Document type: Memorandum
- Year: 2017
- Exam period: KwaZulu Natal June
- Paper: 1
- Curriculum: CAPS
- Pages: 10

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## About this document

Mathematical Literacy · Grade 11 · KwaZulu Natal June · 2017. Memorandum, 10 pages. Read online or download the PDF.

Read it free online on the page above; download the PDF from there.

## Document text

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### Page 1

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G SHIVIN LED

Education
KwaZulu-Natal Department of
REPUBLIC OF SOUTH AFRICA

SARA AN EERE ERA E ELE AER ERE BS

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MATHEMATICS P1

COMMON TEST

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JUNE 2017

NATIONAL
SENIOR CERTIFICATE |

GRADE of

MARKS: = 100

TIME: 2 hours

This question paper consists of 6 pages.

Copyright Reserved . Please turn over

### Page 2

Mathematics /P1

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NSC — Grade 11

INSTRUCTIONS AND INFORMATION

Read the following instructions carefully before answering the questions.

1.

2,

Copyright Reserved

This question paper consists of 6 questions.
Answer ALL the questions.

Number the answers correctly according to the numbering system used in. this
question paper.

Clearly show ALL calculations, diagrams, graphs, et cetera that you have used in
determining your answers.

Answers only will not necessarily be awarded full marks.

You may use an approved scientific calculator (non-programmable and
non-graphical), unless stated otherwise.

If necessary, round off answers to TWO decimal places, unless stated otherwise.
Diagrams are NOT necessarily drawn to scale.

Write neatly and legibly,

Common Test June 2017

Please turn over

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NSC — Grade 11

Mathematics /P1

QUESTION 1

1a Solve for x:
Lil (x+3\x-5)=9
1.1.2 x-V2x-1=2

113 1<(2x~3)

1.2 Given: 3x? = 3x+5

1.2.1 Solve for x (correct to TWO decimal places).

1.2.2 Hence, or otherwise, solve for y if 3(y +l) =3(y+ 1) +5.

13 Describe the nature of the roots of 3x7 = 3x+ 5

1.4 Solve for x and y in the following simultaneous equations:
Qx+y=l and 2x?~xyey? =4

QUESTION 2

2.1 Solve for x, without the use of a calculator:

24.1 VI-V2 peg
x

3
21.2 553 256 = a)x?

2.2 Simplify without the use of a calculator:

2.2.1 Fraxal

10” 45

Copyright Reserved

Please turn over

Common Test June 2017

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Mathematics /P1 Common Test June 2017
NSC — Grade 11
QUESTION 3
3.1 4; 10; 18; 28; ..... isa quadratic number pattern.
3.14 Write down the next term in the pattern. qd)
3.1.2 Determine an expression for the n'” term of the pattern. (4)
3.1.3 Calculate the value of the first term of the pattern that will be greater than
460, (4)
3.1.4 Determine an expression for the n® term of the sequence of first
differences of this quadratic number pattern. (2)
3.1.5 Between which two terms of the quadratic number pattern will the first
difference be equal to 64? (3)
3.2 The first 4 terms of a quadratic sequence are 133; «; 29; x+24;......
Calculate the value of x. (5)
[19]
QUESTION 4
Given: A(x)=2°* +1
4.1 Determine the y-intercept of A, (2)
4.2 Write down the equation of the asymptote. qd)
43 Draw a sketch graph of fh. Show clearly any intercepts with the axes and the
asymptote. (3)
4.4 Determine the average gradient of i between x=-2 and x=0, (3)
45 Solve for xif h(x)>5. - (2)
[i]

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Mathematics /P1 Common Test June 2017

NSC ~ Grade 11

QUESTION 5

The graphs of f(x) = fg q and the straight line g are sketched below.
x+p

The asymptotes of fintersect at (- 3;- 2).
The points of intersection of fand g are (- 5;0) and (1;- 3).

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5.1 Determine the values of p, g and a. (4)
5.2 Write down the domain of f (2)
5.3 The equation of one of the axes of symmetry of fis y =x + k. (2)

Calculate the value of k.

5.4 Use the graphs to solve for x, if (x) 2 g(x). (3)
5.5 Determine the equation of g. (2)

[13]

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Mathematics /P1

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NSC - Grade 11

QUESTION 6

The sketch below represents the graphs of two parabolas: f and g.
Pa)=-58 ~x+4,

B is the turning point of f

A(- 23 4) is a point of intersection between f and g, and C is the y-intercept of f
D and E are the x-intercepts of f D is also the x-intercept of g.

K isa point on f and La point on g, such that KL is parallel to the y-axis, and three units to
the left of the y-axis.

6.1

6.2
6.3
6.4

6.5

6.6

y

Calculate the coordinates of

6.1.1 B

6.1.2 Cc

Calculate the coordinates of D and E.
Determine the equation of g.

The graph of gis reflected about the y-axis to obtain the graph of 4. Determine the
equation of h,

Determine the value(s) of k such that - * ~x+4=k will have no real roots.

Calculate the length of KL.

TOTAL

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Common Test June 2017

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3
‘Mathematics P1 (Marking Guideline) NSC June 2017 Common Test
122 |y+1=1,88 OR y+1=—0,88
y= 0,88 or yp=-1,88 2CA for answers
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6 _
. oe 1CA for irrational
‘The roots are real, irrational and unequal. 1CA for unequal
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14 ys-2xt1 equation 1 1A for making y the subject of the
wWe-wyty=4 equation 2 formula
Substitute equation 1 into equation 2:
2x? —x{-2e4l)+(C2x41f =4 1CA for substitution
2x? 42x? —x+4x? ~4x+1=4
82° —5x-3=0 ICA for standard form
(x+3)e-1)=0 ICA for factorization
3
macy or eel ICA for both x-values
| 1CA for both y-values
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Copyright Reserved

Mathematics P1 (Marking Guideline) NSC June 2017 Common Test
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7
Mathematics P1 (Marking Guideline) NSC Jane2017 Common Test Mathematics P1 (Marking Guideline) June 2017 Common Test
QUESTION 5 QUESTION 6
SL | p=3 1A for p=3 611 [nb
qa 1A for g=-2 2a
a -(1
y=—-2 = ct
xt3 = 1A for substitution
Substitute (—5;0): OR Substitute (5-3): 1CA for substitution 3
a a =-1 1A for answer (x-coordinate)
ne ae 3377 7 l 1
7 * fC D=-2 C1 -Ciesaas ICA for y-coordinate
qa -1=4 2 2
—2 4 cial
a=-4 a=-4 1CA for answer 2 @)
@) 612 | (4) TA for answer
52 xe RK, but x#-3 e)
OR
(3) oF (35e0) 2A for answer 87) ak eaneano tAfor-Lit-xe4=0
C32) 2 x +2x-8=0
5.3 Substitute (-3;-2) in yox+k: 78s
-2=-3+k 1A for substitution (e+4x-2)=0 1A for factors
k=l 1A for answer @ x=—4 or x=2
34 |—-SSx<-3 or x2]. D-4; 0) EQ; 0) 2CA for answers ©
OR 2A for —S£x<-3 -
[-5;-3) UIt~) 1Afor x21 63 | ymalx+ay 1A for y=ale+4F
3 4ea(-24+4F 1A for substituting (—2; 4)
35 | Gradient 4=aQy
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1+5
1 ya(et4y ICA for answer 6)
“2 64 =(e-
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. TOTAL: 100
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