# Mathematics Grade 11 March Test 2018 Paper & Memo > Grade 11 Mathematics question paper and memo from the March Test 2018, 10 pages. Read online or get the free PDF download. - Page: https://www.hlayiso.com/library/maths-mar-qp-memo/09635261-ab30-45ef-9f8c-119262258557 - Updated: 2026-09-27 - Subject: Mathematics - Grade: Grade 11 - Document type: Question paper and memo - Year: 2018 - Exam period: March Test - Curriculum: CAPS - Pages: 10 Breadcrumbs: [Home](https://www.hlayiso.com/) › [Library](https://www.hlayiso.com/library) › [Grade 11](https://www.hlayiso.com/library/grade-11) › [Mathematics](https://www.hlayiso.com/library/grade-11/mathematics) › [Mathematics Grade 11 March Test 2018 Paper & Memo](https://www.hlayiso.com/library/maths-mar-qp-memo/09635261-ab30-45ef-9f8c-119262258557) ## About this document Mathematics · Grade 11 · March Test · 2018. Question paper and memorandum, 10 pages. Read online or download the PDF. Read it free online on the page above; download the PDF from there. ## Document text Text extracted from the PDF. Layout, diagrams and tables may not survive extraction. ### Page 1 Downloaded from hlayiso.com testpapers.co.za ### Page 2 Downloaded from hlayiso.com Mathematics March 2018 Common Test INSTRUCTIONS AND INFORMATION Read the following instructions carefully before answering the questions: This question paper consists of 4 questions. 2. Answer ALL the questions. ue Number the answers correctly according to the numbering system used in this question paper. 4, Clearly show ALL calculations, diagrams, graphs, et cetera, which you have used in determining the answers. 6. You may use an approved scientific calculator (non-programmable and non-graphical) unless stated otherwise. 7. If necessary, round off answers to TWO decimal places, unless stated otherwise. 8. Diagrams are NOT necessarily drawn to scale. 9. Write neatly and legibly. Copyright Reserved Please turn over ### Page 3 Downloaded from hlayiso.com Mathematics 3 March 2018 Common Test NSC QUESTION 1 I.1 Solve tory in cach of the following: Lt 3x? 4+10x-5=0 (correct to TWO decimal places) (4) Lio seta (4) 113) Savev4rel (5) 1.2 Solve forx and y if: V4+7=2y and x -yy43y° =15 (6) 130 Given: f(x) =99° - Sy 44 1.3.1 Solve forx if f(x) 50. (3) 1.3.2 Show that /(v) = -3 has no real roots. (4) [26] QUESTION 2 Simplify fully, WITHOUT using a calculator: yl gg 21 ee 8" isl /g§ (5) 2.2 Tf y =8/100.000, WITHOUT USING A CALCULATOR, determine the value of V16 x 4/625 x V0 in terms of ¥. (4) [9] Copyright Reserved Please turn over ### Page 4 Downloaded from hlayiso.com Mathematics 4 March 2018 Common Test NSC QUESTION 3 3.1. Consider the following quadratic number pattern: 64; 42:24)... 3.1.1 Write down the next TWO terms of the number pattern. (2) 3.1.2. Determine an expression for the general term, T,, in the form T,=an +bn+c. (4) 3.1.3 Calculate the value of the 20" term of this number pattern. (2) 3.1.4 Determine the general term of the sequence of first differences of this number pattern. (2) 3.1.5 Between which two consecutive terms of the quadratic number pattern will the difference be equal to 174? (2) If py tl: 20 3 6p forma quadratic number pattern. Calculate the value of p. (4) [16] Copyright Reserved Please turn over ### Page 5 Downloaded from hlayiso.com Mathematics March 2018 Common Test NSC QUESTION 4 4.1 A(psq), B(234), C(3;0) and D(—1; -2) are the vertices of parallelogram ABCD. O is the origin and OE is perpendicular to AB. \ BGA) , (0 CG0) x DE-L-2) 4.1.1 Calculate the length of DC. (leave your answer in surd form) (2) 4.1.2 Hence, write down the length of AB. (1) 4.1.3 Calculate the values of pand g. (2) 4.1.4 Determine the equation of OE. (4) 4.1.5 Calculate the coordinates of E. (4) Copyright Reserved Please turn over ### Page 6 Downloaded from hlayiso.com March 2018 Common Test 6 NSC Mathematics In the diagram P (3 ; 7), Q (-3 ; 4) and R (1: -6) are the vertices ofa triangle. PQ is produced to cut the x-axis at S. PR cuts the x-axis at T. QR cuts the y-axis 4.2 al A. y PGs 7) Q63 34) —_ “@ i a : yo } . S A\ |O {T x R(I 5-6) 4.2.1 Calculate 6 the angle of inclination of the line PS. (3) 4.2.2 Calculate the size of ROS. (4) (4) [24] N is the point (3. ;-11). Are the points N. Rand Q collinear? 4.2.3 Justify your answer by means of calculations. TOTAL MARKS: 75 Copyright Reserved ### Page 7 Downloaded from hlayiso.com L-x7e4 MTSLt4 TI KC) | T= 40 Zp¥x 0=(Z-xXZI-x) O=b0+%PI- I+8p =X +x01-Sz (1+xbp)= {x-s) [ l+XpPhax—¢ ett (r) rex Sm if Beg To BeOS lt ae eT hen he lz = al nk |, st fa a} sIomsue pp LLG“ =x 40 pyQ=x wonmisqns we, a (Sr - AOD) FOI- e{muu0} oneapenb » pee cease | Pb GDS 4 trl TNOILSaNO sonewoyreyy 49A0 WIN] OSBI] ‘soled g Jo sysisuoo aurfopms Supjacwu sip a ANITACIND ONDTAVIN 8107 HOUVI LSaL NOWNOD SOLLVAGHLVIAA VoldsV HLNOS 40 OandaYy uoeonpy Jo juswpedag jeyen-ninzemy uoneonpy paasosaa iymiuxdoy, ### Page 8 Downloaded from hlayiso.com 3 GRADE II -omon Test March 2018 Mathematics QUESTION 2 4 GRADE 11 Marking Guide Common Test March 2018 4-DAY | v "51 Y writing as prime bases ¥ converting surd to exponent Y simplification using laws Y answer (5) 13.1 9x° -15x44>0 (x-4)(3e-) > 0 Y factors 4 1 vst oor x=t 3 3 £ = | 3 3 c= OF plea a y | 3 3 (3) 13.2 | 9 -15x+4=3 >_< Y standard form 9° -15x+7=0 _ ~b#Vb* -4ac = 2a A=b'-4ac Y substituting in A or formula < = _ 2 for roots of quadratic _ 4 ¥C15) -40)7) = (-15Y -4(9(7) equation 2(9) =-27 1stJ-27 is+v—27 = OR Vixe or A=-2 18 Because A< 0, the 18 se V=27 is not real, equation has no Y conclusion both roots are not real real roots. @ [26] Copyright Reserved Please turn over 22 | YiexVo2sxVi0 =V2 x¥5* x10 =(2)' x3) x(10)! =(10) x10)? = (10) 5 =10'x (10) =10y writing with bases of 2 and 5 ¥ surd to exponential form with base 10 Y simplification ¥ answer (4) Copyright Reserved Please turn over ### Page 9 4920 WML aseatg, poarosay iystido 40A0 IN a8eD] qf pomosay 1 @ PLT 8) 8OuDRBSS |] ‘ somsue , oneapenb ayy yo Sy pue z usomjog souaray1p oy osu 00 = 4 PLl=90— Ub | PL = 06- UST + HZ —06F8T—UBT- TH UP + UZ LE = (L~""Z oy Sunmnsgns p | PLI= OG + ¥R2 ~ HZ) —06 + 1+ HI8T= + NZ pli £ uO uo re) @ PL] Sl aauanbos O ADMSUR p oueapenb ayy jo “7 pue "7 usosog aouosayyip aut 4 0g=u fe) 000 = 4b D PLL “y Sunenba p» bLl=9%—4b | ole —_ (2) ; >.) %- A 9-H = "1 ub SOOUALOJ}IP IS1y_ JO 9uaMbas oy} 40} ULI} pLIDUD OY |, is} “Spe t 81>! ee