# Mathematics Grade 10 Paper 1 KwaZulu Natal June 2019 Memo

> Grade 10 Mathematics Paper 1 memorandum from the KwaZulu Natal June 2019, 8 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/maths-p1-and-memo-june-2019-gr-10/556edfb5-794a-42b2-8090-01ddf36031da
- Updated: 2026-09-27
- Subject: Mathematics
- Grade: Grade 10
- Document type: Memorandum
- Year: 2019
- Exam period: KwaZulu Natal June
- Paper: 1
- Curriculum: CAPS
- Pages: 8

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## About this document

Mathematics · Grade 10 · KwaZulu Natal June · 2019. Memorandum, 8 pages. Read online or download the PDF.

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## Document text

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                                 NATIONAL
                            SENIOR CERTIFICATE

                                     GRADE 10

                               MATHEMATICS P1

                                 COMMON TEST

                                     JUNE 2019

                            MARKING GUIDELINE

MARKS: 50

                       This marking guideline consists of 4 pages.

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Mathematics/P1                 2                                             Common Test June 2019
                                                Grade 10 Marking Guideline

QUESTION 1
1.1.1       3x3  2 x 2 ( x  5)
             3x3  2 x3  10 x 2
                                                                                    2 x3  10 x2
             x  10 x
                 3            2
                                                                                    x3  10 x2          (2)
1.1.2       (2 x  1)(2 x  1)
             4 x2  2 x  2 x  1
                                                                                    4x 2  1          (2)
             4 x2  1
              x  4 x 1  8 x 
1.1.3       1
            4
             1  2 x2                                                              1  2x 2          (2)
1.2         y 2 ( y  2)  x 2 (2  y )
             y 2 ( y  2)  x 2 ( y  2)                                           (y – 2)
             ( y  2)( y 2  x 2 )                                                 ( y 2  x2 )
             ( y  2)( y  x)( y  x)                                              ( y  x)( y  x)   (3)
1.3.1       x = 12                                                                 a                   (1)
1.3.2       x = 11                                                                 a                    (1)
1.3.3                     1                                                        a                    (1)
            x = 12
                          4
                                                                                                        [12]

QUESTION 2

2.1.1       2 x2  5x  3  0
            (2 x  3)( x  1)  0                                                       factors
                   3                                                               
            x        or x 1
                   2                                                                                     (3)
2.1.2       x 1 x  2
                           20
              3        5
            5( x  1)  3( x  2)  2(15)
                                          0                                        LCD = 15
                          15
            5 x  5  3 x  6  30  0                                             
            2 x 19
                     19
            x                                                                                          (3)
                      2
2.2                               2x  3y  3   (1)
                                  2x  y  7    (2)
            (1)  (2)               4 y  4                                      
                                       y 1                                         y-value
            sub y  1 into (2): 2 x  1  7                                         substitution
                                              x3                                   x-value

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Mathematics/P1                 3                                        Common Test June 2019
                                           Grade 10 Marking Guideline

                                                   OR

                          2x  3y  3      (1)
                          2x  y  7       (2)
                                                                              
            (2)  3 :     6 x  3 y  21
                 (1) :    2x  3y  3
            (2)  (1) : 8 x        24
                                                                               x-value
                                 x 3                                          substitution
            sub x  3 into (2): 2(3)  y  7
                                                                               y-value
                                          y 1

                                                   OR
                          2x  3y  3      (1)
                          2x  y  7       (2)
            (2)  (3) :         y   2x  7                                  
            sub (3) into (1) : 2 x  3( 2 x  7)  3
                                   2 x  6 x  21  3
                                                 8 x  24
                                                  x 3                         x-value
            sub x  3 into (3): y  2(3)  7                                  substitution
                                                                               y-value
                                  y 1
                                                                                                 (4)
2.3               5( F  32)                                                  
            C                                                                                   (2)
                       9
                                                                                                [12]

QUESTION 3

3.1        p  14                                                           a
           q  27                                                           a
                                                                                                 (2)
3.2        k 2                                                             a
                                                                                                 (1)
3.3        Rn  7n  1                                                       7n
                                                                            –1                  (2)
3.4        B6  3(6)  2  20
                                         200
           enough bolts to make              10 6m fences                 
                                          20
           R6  7(6)  1  41
                                        400
           enough rods to make              9.8 6m fences                 
                                         41

           There is enough to make 9 complete 6m fences.                    
                                                                                                 (3)
                                                                                                 [8]
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Mathematics/P1                 4                                                 Common Test June 2019
                                            Grade 10 Marking Guideline

QUESTION 4
4.1         y-intercept: (0 ; – 16)                                                                        (1)
4.2         g ( x)  3x  3
            0  3x  3
                                                                                      0  3x  3
            3 3
             x

            x 1
            x-intercept: (1 ; 0)                                  Answer only: 2/2                         (2)
4.3
                                                                                     f(x):    x-intercepts
                                                                                              y-intercept
                                                                                              shape

                                                                                     g(x):    intercepts
                                                                                              asymptote

                                                                                                            (5)

4.4         x  (2; )        OR     x2                                                                   (1)
4.5         x-axis reflection                                                                              (1)
                                                                                                         [10]
QUESTION 5
5.1         y  2                                                                                         (1)
                               1                a
5.2          Sub point (4 ;  2 ) into f ( x)     2:
                               2                 x
                1 a
             2         2
                2     4                                                               substitution
               1 a
              
               2    4
                    1
             a  4
                    2
             a2
                                                                                                           (2)

5.3         y  x  c
            sub (0;  2) :  2  (0)  c
                                                                                      c=–2
                              c2
             y  x  2                                                                                   (2)
5.4         x  R; x  0       or x  (; ); x  0                                                      (2)
5.5          f decreases for NO values of x.                                                               (1)
                                                                                                            [8]

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