# Mathematics Grade 11 Paper 2 Eastern Cape November 2015 Memo

> Grade 11 Mathematics Paper 2 memorandum from the Eastern Cape November 2015, 8 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/maths-p2-memo-gr11-nov-15-a-e/91b8beda-d541-48bf-bea6-00c4d81bfce3
- Updated: 2026-09-27
- Subject: Mathematics
- Grade: Grade 11
- Document type: Memorandum
- Year: 2015
- Exam period: Eastern Cape November
- Paper: 2
- Curriculum: CAPS
- Pages: 8

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## About this document

Mathematics · Grade 11 · Eastern Cape November · 2015. Memorandum, 8 pages. Read online or download the PDF.

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## Document text

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### Page 1

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                          NATIONAL
                     SENIOR CERTIFICATE

                            GRADE 11

                      NOVEMBER 2015

         MATHEMATICS P2/WISKUNDE V2
               MEMORANDUM

MARKS/PUNTE:   150

                       This memorandum consists of 8 pages.
                     Hierdie memorandum bestaan uit 8 bladsye.

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2                                                     MATHEMATICS P2/WISKUNDE V2                (EC/NOVEMBER 2015)

NOTE:
•  If a candidate answers a question TWICE, only mark the FIRST attempt.
•  If a candidate has crossed out an attempt of a question and not redone the question, mark the
   crossed out version.
•  Consistent accuracy applies in ALL aspects of the marking memorandum.
•  Assuming answers/values in order to solve a problem is NOT acceptable.

LET WEL:
•   Indien ŉ kandidaat ŉ vraag twee keer beantwoord, merk slegs die eerste poging.
•   Indien ŉ kandidaat ŉ antwoord doodgetrek het, maar nie oorgedoen het nie, merk die
    doodgetrekte antwoord.
•   Volgehoue akkuraatheid geld in ALLE aspekte van die memorandum.
•   Aanname van antwoorde/waardes om ŉ probleem op te los, is Onaanvaarbaar.

QUESTION/VRAAG 1: [12]
1.1
        Height (cm)    Frequency                                         Cumulative
        Hoogte (cm)    Frekwensie                                         frequency
                                                                         Kumulatiewe
                                                                          frekwensie   26
                    150                         55           4                  4
                    155                        160          22                 26
                    160                        165          56                 82      120
                    165                        170          32                114                                (2)
                                                             6                120

1.2                                                                                    grounding at(150;0)/anker
                                                                                       by (150;0)
                                                Ogive/Ogief
                                                                                        plotting (155;4)/plot van
                                   150                                                 (155;4)

           Cumlative Frequency /
                                   100                                                 plotting with upper
                                                                                       limits/plot by boonste
                                   50                                                  limiete
                                    0                                                   joining the points to form

          Kumulatiewe Frekwensie
                                         140    150      160      170    180              a smooth curve/verbind
                                                Heights/Hoogte (in cm)                   punte om glade kurwe te
                                                                                                    vorm
                                                                                                                 (4)
1.3    (150, 160,5, 163, 166, 175)                                                      150
                    OR/OF                                                              160,5
       Min = 150                                                                        163
       Q1 = 160,5                                                                      166
       Q2 = 163                                                                        175
       Q3 = 166
       Max = 175                                                                                                (5)
1.4    Skewed to the left / Skeefgetrek na links.                                       answer/antwoord        (1)
                                                                                                               [12]

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(EC/NOVEMBER 2015)                           MATHEMATICS P2/WISKUNDE V2                                      3

QUESTION/VRAAG 2 [7]
2.1  ̅                                                                            

        ̅                                              ANSWER ONLY : FULL MARKS
            = R3 555                                 SLEGS ANTWOORD : VOLPUNTE     answer/antwoord         (2)
2.2                                                                                answer/antwoord         (1)
2.3    (3555 – 900,12 ; 3555 + 900,12) = (2654,88 ; 4455,12)                       interval
                                                                                  7
             werkers lê binne een standaardafwyking                                answer/antwoord
                     of workers lie within one standard deviation.                                           (4)
                    van die werkers lê binne een standaardafwyking.
                                                                                                             [7]
QUESTION/VRAAG 3 [13]
3.1 mAB = mBC = mAC                                                                mAB = mBC = mAC

                                                                                   substitute into
                                                                                  equation/vervang in vgl

                 (               )
             (                   )                                                 substituting into
                                                                                  mAC/vervang in vgl mAC

                                                                                   answer/antw            (4)
3.2                          (           )                                         equation/vgl
                                                                                   subst of m and(-5;5) into
                                 (       )                                        form/vervang van m en (4;-1)
                                                                                  in formule
                                                                                   equation/vgl           (3)
3.3
                                                                                   subst into correct
                         [                       ]
                                                                                  formula/vervang in korrekte
                                                                                  formule
                     [                       ]
                                                                                   coordinates/coordinate
                     =[              ]                                                                       (3)
3.4    mCD = 0                                                                     correct m = 0
                                                                                   substitution into
                                                                                  eqn/vervang in vgl
                                                                                   answer/antw
            OR/OF                                                                  equating/
       p – 7 = -1                                                                  answer
       p=6                                                                                                   (3)
                                                                                                            [13]

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4                                           MATHEMATICS P2/WISKUNDE V2               (EC/NOVEMBER 2015)

QUESTION/VRAAG 4: [13]
4.1
                                                                          answer/antw
             =2                                                                                      (1)
4.2      MNQ × MMP = -1 [NQ ┴ MP]                                         answer/antw

                                                                                                     (1)
4.3                                                                      
                                                                         
                                                                         value of /waarde van
                                                                                                     (3)

4.4                     (           )                                     equation/vgl
                        (           )                                     subst of m =         and
                                                                         (0;6) into eqn/vervang
                                                                         m=        en (0;6) in vgl
                                                                         answer/antw              (4)
4.5                                                                      
                                                                                 
                                                                          subst into eqn/vervang in
                                                                         vgl

         P (2;5)                                                          P (2;5)                   (4)
4.6      MR = NR
         R=[                            ]
                                                                          Substitution/vervang.

         R=[                    ]                                         x value/waarde
                                                                          y value/waarde
         R = [-3;-3]                                                                                 (3)
                                                                                                    [16]
QUESTION/VRAAG 5: [23]
5.1.1                                                                    tan θ
                                                                         answer/antwoord            (2)
5.1.2             ( )       ( )                                          OP2
                 √                                                       answer/antwoord            (2)
5.1.3a                                                                   answer/antwoord
                   √                                                                                 (1)
5.1.3b       (              )                                             -cosθ

                                                                          answer/antwoord
                                        √
                                             ANSWER ONLY FULL MARKS/                                 (2)
                                             SLEGS ANTWOORD:VOLPUNTE

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(EC/NOVEMBER 2015)                                  MATHEMATICS P2/WISKUNDE V2                               5

5.2
                                                                                  standard form/st vorm
            (                       )                                             1 – sin2 x

        (                       )(                      )= 0

                                                                                 sin x = ½ or
                                                                                  no soln (sin x = 2)
                                                                                  30° ; 150°
                                                                                  k.360,
                                                                                                             (6)
5.3                                                                               sin x
                                                                                  -sin x
                                                                                  cos2 x
        =                                                                        
        = -tan x                                                                  tan x
                                                                                                             (5)
5.4                         (                   )                                 numerator / teller
                        (                   )                                     denominator / noemer

                                                                                  expansion / uitbreiding
                                (                   )
                                                                                  simplification /
                                                                                 vereenvoudiging
                    (                   )
                                                                                  factorisation /
                (                   )                                            faktorisering             (5)
                    (                   )

                                                                                                         [23]
QUESTION/VRAAG 6: [11]
6.1  b2 = a2 + c2 – 2acCos B                                                      a2 + c 2
                                                                                  2acCos B                (2)
6.2.1                           ̂
                                                                                  Ratio for tan/verhou. vir
                                                                                 tan
                                                                                  substitution 65°/verv van
                                                                                 65°
        PS = 338,83                                                               answer/antwoord        (3)
6.2.2   In ∆PQS
                                                                                 use of cos
           =                                                   (   )(   )        formula/gebruik van cos
           = 1484499,606                                                         formule
        SQ = 1218,40 m2                                                          Substitution/vervang
                                                                                  SQ                    (3)

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6                             MATHEMATICS P2/WISKUNDE V2             (EC/NOVEMBER 2015)

6.2.3   In ∆RSQ:
                                                           

                                                           

                                                            value of /waarde van
                                                                                    (3)
6.2.4   Area of ΔSPQ = ½ SP.PQ.sin̂                         correct formula / korrekte
                    = ½ (338,83)(1 500)sin 30°             formule
                                                           substitute / vervang
                      =127061,25 m2                        (338,83), (1500)
                                                            Sin 300
                                                           answer / antwoord       (4)
                                                                                   [15]
QUESTION/VRAAG 7: [12]
7.1                                                                  f
                                                                      asymtotes /
                                                                     asimptote
                                                                     min value / min
                                                                     waarde
                                                                      max value /
                                                                     maks waarde

                                                                     g
                                                                      (-45°; -1)
                                                                      (45°; 1)
                                                                     (135° ; -1)

                                                                                     (6)
7.2           (      )   (     )   (      )                          -45
                                                                     45
                                                                     0
                                                                     90
                                                                     135
                                                                     180
                                                                                     (6)
7.3     90°                                                           answer /
                                                                     antwoord
                                                                                     (1)
                                                                                    [13]
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(EC/NOVEMBER 2015)             MATHEMATICS P2/WISKUNDE V2                                        7

QUESTION/VRAAG 8: [8]
8.1  bisects the chord.                                                  answer/antwoord
                                                                                                 (1)
8.2.1                                     (Pythagoras)                  
                                          (substitution/vervang)         method/metode

                                                                         answer/antwoord
                                                                                                 (3)
8.2.2                                     (Pythagoras)                  
                                         (substitution/vervang)         method/metode

                 cm                                                              cm

        But AB = 2AE        (OE ┴ AB)
            AB = 2(3)                                                    S/R
               = 6 cm
                                                                         answer/antwoord        (4)
                                                                                                 [8]
QUESTION/VRAAG 9: [13]
9.1                                                                      construction/konstr
                                                   C

                                                                         S/R

                                                  .O
                                                                         S/R
                                                                         S/R
                                                                         S/R

                                                                         conclusion /
                                                                        gevolgtrekking
                                                                    B                            (6)
                                     A             D

        CONSTR: Join CO, extend to D

        PROOF: In ∆AOC
        i) ̂      ̂        ̂         (ext  of ∆/buitehoek van ∆)
        ii)  ̂    ̂       ̂         (ext  of ∆/buitehoek van ∆)
        iii) ̂      ̂               (AO = OC)
        iv) ̂        ̂              (BO = OC)
              ̂    ̂         ̂      ̂
                ̂ = 2( ̂        ̂ )
                           ̂
9.2.1   ̂              ( radii equal/radiusse gelyk)                     S R
                                                                                                 (2)
9.2.2   ̂             (ext  of ∆/buitehoek van ∆)                       S R
                                                                                                 (2)
9.2.3   ̂             (angles in same segment/                           S R
                       hoeke in dieselfde segment)                                               (2)
9.2.4    ̂            (opp angles of cyclic quad/                        S R
                       teenoorstaande hoeke van ŉ koordevierhoek)                                (2)
                                                                                                [14]

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8                                 MATHEMATICS P2/WISKUNDE V2                         (EC/NOVEMBER 2015)

QUESTION/VRAAG 10: [6]

10.1      ̂       ̂ =x                (angles in the same segment/           S R
                                      hoeke in dieselfde segment)

          ̂       ̂ =x                (tan chord/tan koord)                  S R
                                                                                                      (4)
10.2      ̂       ̂                   (both equal to x/albei gelyk aan x)   S/R
                                       ̂                                     conclusion /
                                                                            gevolgtrekking
                                                                                                      (2)
                                                                                                      [6]
QUESTION/VRAAG 11 [11]
11.1 Are supplementary OR add to 180°.                                       answer/antwoord
                                                                                                      (1)
11.2.1 ̂          ̂                 (Ext  of cyclic quad/buitehoek         S  R
                                     van koordevhk)
          ̂=̂                      (corresponding angles, AB ║ DC/          S  R
                                   Ooreenkomstige hoeke AB ║ DC)
                                   (base angles of ∆ equal/basis hoeke      R
                                    van ∆ gelyk)                                                      (5)
11.2.2    ̂                        (angles of ∆/hoeke van ∆)                S
                                                                            R
                                                                                                      (2)
11.2.3 ̂                           (  at centre = 2  at circumference/    S  R
                                     by middle = 2  by omtreks)
           ̂     ̂                                                          S

                                                                                                      (3)
                                                                                                     [11]
QUESTION/VRAAG 12 [11]
12.1 Sh2 =              (Pythagoras)                                        S
       2
     Sh = 64 + 9       (substitution/vervang)                                method/metode
     Sh = √                                                                  answer/antwoord
         = 8,54 cm                                                                                    (3)
12.2 Area of ∆ face =                                                        formula/formule
                                                                             substitution/vervang
                       = ( )(√ )                                            answer/antwoord
                      = 25,63 cm2                                                                     (3)
12.3     TSA = area of slanted faces + area of right prism                   TSA
         TBO = oppervlakte van skuinsvlakke + oppervlakte van reghoekige     substitute/vervang
               prisma                                                        answer/antwoord
                = 3(25,63) + 62 + 4(6 x 12)                                                           (5)
               = 76,89 + 36 + 288
               = 400,89 cm2
                                                                                             [11]
                                                                               TOTAL/TOTAAL: 150

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