# Mathematics Grade 11 KwaZulu Natal June 2022 Paper & Memo

> Grade 11 Mathematics question paper and memo from the KwaZulu Natal June 2022, 16 pages. Read online or get the free PDF download.

- Page: https://www.hlayiso.com/library/mathsl-gr11-june-2022-qp2-and-memo/e72e4f6b-111b-441c-b5e2-58ba74667ca5
- Updated: 2026-09-27
- Subject: Mathematics
- Grade: Grade 11
- Document type: Question paper and memo
- Year: 2022
- Exam period: KwaZulu Natal June
- Curriculum: CAPS
- Pages: 16

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## About this document

Mathematics · Grade 11 · KwaZulu Natal June · 2022. Question paper and memorandum, 16 pages. Read online or download the PDF.

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                                     NATIONAL
                                SENIOR CERTIFICATE

                                          GRADE 11

                            MATHEMATICAL LITERACY
                                     COMMON TEST
                                         JUNE 2022
                                MARKING GUIDELINE

MARKS: 100

                 SYMBOL       EXPLANATION
                    M         Method
                    MA        Method with accuracy
                    CA        Consistent accuracy
                     A        Accuracy (Answer)
                     C        Conversion
                     S        Simplification
                 RT/RG/RD     Reading from a table/ graph/ diagram
                   NPR        No penalty for units/rounding
                    SF        Correct substitution in a formula
                     O        Opinion/ reason/deduction/example
                     J        Justification
                     R        Rounding off
                     F        deriving a formula
                     E        Explanation
                     U        Units
                    AO        Answer only full marks

                            This marking guideline consists of 5 pages.

Copyright reserved                                                        Please turn over

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          Mathematical Literacy                             2                       Common Test June 2022
          Downloaded f rom St NSC –
                             anmorephysics.
                                    Marking Guideline com
QUESTION 1 [20 MARKS]
QUE SOLUTION                                                      EXPLANATION                               L/T
1.1.1 Rands = 103,42 M                                           1M, Conversion dividing by 100            L1
               100                                                1CA,Answer                                F
            = R1,0342CA                                          Accept R1,03

                                                                  NPR                                (2)
1.1.2                                                                                                       L1
        Cost = R1,0342 ×348,2kwh M                               1M, Multiplying by Rate                   F
             = R360,108
             =R360,11 CA                                         1CA, Answer in rands
                OR                                                Accept R358,65
        Cost = 103,42 ×348,2kwh M                                               OR
             =36 010.844 cents CA                                1M, Multiplying by rate
                                                                  1CA, Answer in cents
                                                                                                      (2)
1.1.3                         M                                                                            L1
        Block 1 tariff = 87,5 ×103,42                             1M, Multiplying rate by percentage        F
                         100
                       =90,4925 centsA                           1A, Answer
                                                                    NPR                               (2)
                                                                  2A, Answer                              L1
1.2.1   Number scaleA
                                                                                                      (2) MP
1.2.2   One unit on the map represents twenty thousand units in   2E, Explanation                         L1
        reality/actual groundE                                                                          MP
                         OR
        The map is 20 000 times smaller than the actual
        ground. E                                                                                   (2)
1.2.3   Meters = 20 000cm                                         1MA, Dividing by 100                      L1
                    100 MA                                                                                 MP
                 = 200 A                                         1A, Answer
                                                                                                      (2)
1.3.1   10 km RT                                                2RT, Answer                               L1
                                                                                                     (2)    M&P
1.3.2   25 km RT                                                2RT, Answer                               L1
                                                                                                     (2)    M&P
1.3.3   Saddle Path RT                                          2RT, Answer                               L1
                                                                                                     (2)    M&P
1.3.4   Woodcutters Trail RT                                     1RT, Answer                               L1
        Block House RT                                           1RT, Answer                               M&P
                                                                                                     (2)
                                                                                                   [20]

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           Mathematical Literacy                                3                        Common Test June 2022
           Downloaded f rom St NSC –
                              anmorephysics.
                                     Marking Guideline com
QUESTION 2[30 MARKS]
QUE    SOLUTION                                                     EXPLANATION                                  L/T
2.1.1  05 March 1998 A                                            2A, Answer                                   L1
                                                                    Accept 980305 OR 05/03/1998            (2)   F
2.1.2        Service Period        = 14 months                                                                   L2
                                     12 M                          1M, Dividing by 12                           M
                                   = 1,166666666
                                     1year 2months A               1A, Correct years and months          (2)
2.1.3                                                               1M, Multiplying R7200 by 1%                  L2
             A=    × R7200M                                                                                     F
                                                                    1A, Answer
              = R72 A
                                                                                                           (2)
2.1.4                                                               CA from 2.1.3                                L2
             B = R22 +R250 +R72 +R680M                             1M, Adding correct values                    F
               = R1024 CA                                          1CA, Answer
                       M
             C =R7200 – R1024                                       1M,Subracting Correct values
               =R6176 CA                                           1CA, Answer
                                                                                                           (4)
2.1.5(a)                                                                                                         L3
             UIF benefit = R86400 × 60% A SF                      1A, Annual gross                             F
                                 365                                1SF, Correct substitution
                        =R142,03 CA                                1CA, Answer
             His statement is incorrect J                          1J,Justification
                                                                                                           (4)
2.1.5(b)      A                                                                                                 L4
             Agree, All UIF claims that are within 5years are       1A, Answer                                   F
             payable irrespective of nature of departure. R       2R, Reason
                                                                                                           (3)
2.2.1        Duration =       M                                    1M, Dividing by 60                           L2
                                                                    1A, Answer                                   M
                      = 1 hourA
                                                                                                           (2)
2.2.2        R120RT                                               2RT, Answer                                L1
                                                                                                           (2) F
2.2.3        Daily cost(0-5days) = R688 M                          1M,Dividing by 5 days                      L3
                                   5 days                                                                      F
                                  =R137,60A                        1A, Daily rate of R137,60
             Difference = R137,60-R54M
                         =R83,60                                    1M, Difference
             Her statement is correctJ                             1J, Justification
                                                                                                           (4)
2.2.4        Step graphA                                          2A, Answer                                 L1
                                                                                                           (2) F
2.2.5                                                                                                          L2
                                   A                               1A, Numerator
             P(above R90) =                                                                                    P
                                   A                               1A, Denominator
                          = CA                                     1CA, Simplification
                         OR                                         OR
             P (above R90) = 1 - MA                               1M, Probability concept
                                                                    1A, Correct fraction
                                                                    1CA, Simplification
                               = CA                                                                       (3)
                                                                                                         [30]

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           Mathematical Literacy                                     4                       Common Test June 2022
           Downloaded f rom St NSC –
                              anmorephysics.
                                     Marking Guideline com
QUESTION 3 [30 MARKS]
QUE    SOLUTION                                                          EXPLANATION                               L/T
3.1.1  Total Distance = 60 + 33 + 27 MA                                 1MA, Adding all correct distances         L2
                      = 120km A                                         1A,Answer                             (2) M&P
3.1.2                                                                                                              L3
       Average speed =         SF                                       1SF, Correct substitution                 M

                                                                         1C, Conversion to hours
                               =      C
                               = 60km/h A U                            1A, Answer
                                                                         1U, Units
                                                                                                               (4)
3.1.3        Distance = 460 – 280 OR 684 – 504                                                                       L3
                       = 180km                                                                                       M
                       M                                                1M, Measuring distance
             Scale = 2.5cm : 180km M                                    1M, Concept of scale
                  = 2.5 : 18 000 000 C                                  1C, Conversion
                  = 1: 7 200 000 CA                                     1CA, Answer
                                                                                                               (4)
3.1.4                                                                    CA from 3.1.3                               L4
             Measured distance = 5cm M                                  1M, Measured distance                       M
             Scale = 1 : 7 200 000
             Actual distance = 5 x 7 200 000 CA                         1CA, Using scale
                             = 36 000 000
                             = 360km  CA                                1CA, Distance
               The distance given is incorrect O                        1O, Deduction
                                                                                                               (4)
3.1.5          High traffic volumes O                                                                             L4
                            OR                                           2O, Opinion                                 M&P
              Poor road condition
                            OR                                                                                 (2)
              Delays caused by traffic officials
                            OR
              Road accidents
                            OR
                Any other valid reason
3.2.1        South East RT                                              2RT,Answer                                L1
                                                                                                               (2) MP
3.2.2(a)                                                                                                           L2
             Ratio =         :     MA                                   1MA, Dividing by 55 both sides            M
                   = 1 mile :1,61kmA
                                                                         1A, Correct answer                    (2)
3.2.2(b)     Duration = 17:30 -05:30 M                                  1M, Subtracting times                       L2
                      = 12hoursA                                        1A, Answer                                  M
                                                                                       AO                      (2)
3.2.3        Because the starting point of the marathon is at the                                                    L4
             highest point above sea levelO                                                                        MP
                            OR                                           2O, Reason
             The finishing point is at the lowest height above sea
             levelO                                                                                          (2)
3.2.4        Male athletes =     × 11 000M                              1M, Percentage concept                      L2
                                                                         1A, Correct answer                          MP
                                                                         AO                                    (2)
                             = 6050A

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         Mathematical Literacy                                5                       Common Test June 2022
         Downloaded f rom St NSC –
                            anmorephysics.
                                   Marking Guideline com
QUE        SOLUTION                                               EXPLANATION                                 L/T
3.2.5      In order to disqualify incompetent athletesO                                                     L4
                      OR                                                                                      MP
           In order to manage broadcasting times for other
           programmes. O                                        2R, Reason
                     OR
           Athletes won’t run for the rest of the day. O
                     OR                                                                                 (2)
           Any other valid reason
3.2.6                                                             1RT, Correct distance difference            L3
           Distance = 74km – 45kmRT                              1CA, Answer                                 MP
                    = 29kmCA                                     Accept 26km to 32km
                                                                                                        (2)
                                                                                                      [30]

QUESTION 4 [20 MARKS]
QUE SOLUTION                                                      EXPLANATION                                 L/T
4.1.1 Compound bar graphA                                        1A, Correct graph                           L1
      Heading A                                                  1A, Answer                                  DH
                                                                                                        (2)
4.1.2   No of hats = 54 – 10MA                                   1MA, Correct values subtracted              L3
                   = 44 hatsA                                    1A,Answer                                   DH
                                                                                                        (2)
4.1.3   Shoes = 29+20+14+10+4+12 M                               1M, Adding values                           L2
             =89CA                                               1CA, Number of shoes                        DH
                                                                                                        (2)
4.2.1   Survey A                                                2A, Answer                                L1
                                                                                                        (2) DH
4.2.2   Mean =        M                                                                                    L2
        350+999+450+280+350+720+192+800+450+220+280               1M,Adding values                          DH
                           11
             =5091                                                1MA,Dividing by 11
               11MA
             =R462,82CA                                          1CA, Answer.
                                                                                                        (3)
4.2.3   R39,R39.20,R49.90;R52;R52;R55,R69,90;R89,90;R92;                                                      L4
        R99;R409 M                                      1M, Arranging prices                                 DH

        VAT (median) = 15% ×R55CAMA                             1CA,Correct median
                        =R8,25                                    1MA, Calculating vat by15%
        Incorrect statement. J                                   1J, Justification
                                                                                                        (4)
4.2.4   Range = R999- R192MA                                     1MA, Range concept                          L2
              =R807 A                                            1A,Answer                                   DH
                                                                  AO                                    (2)
4.2.5       A                                  E               1A,Answer                                   L4
        Mode, mode is not affected by outliers/ the modal price   2E,Explanation                              DH
        will indicate the most favourable item by customers.                                            (3)
                                                                                             [20]
                                                                                 TOTAL MARKS: 100

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