# Mathematical Literacy Grade 11 P1 2022 Memo (Eng) > Grade 11 Mathematical Literacy Paper 1 memorandum from the Eastern Cape November 2022 (English), 7 pages. Read online or download the free PDF. - Page: https://www.hlayiso.com/library/mats-lit-p1-gr11-memo-nov2022-english/cfc9d5d5-d9d8-402b-b492-f4546d1204ee - Updated: 2026-09-27 - Subject: Mathematical Literacy - Grade: Grade 11 - Language: English - Document type: Memorandum - Year: 2022 - Exam period: Eastern Cape November - Paper: 1 - Curriculum: CAPS - Pages: 7 Breadcrumbs: [Home](https://www.hlayiso.com/) › [Library](https://www.hlayiso.com/library) › [Grade 11](https://www.hlayiso.com/library/grade-11) › [Mathematical Literacy](https://www.hlayiso.com/library/grade-11/mathematical-literacy) › [Mathematical Literacy Grade 11 P1 2022 Memo (Eng)](https://www.hlayiso.com/library/mats-lit-p1-gr11-memo-nov2022-english/cfc9d5d5-d9d8-402b-b492-f4546d1204ee) ## About this document Mathematical Literacy · Grade 11 · Eastern Cape November · 2022 · English. Memorandum, 7 pages. Read online or download the PDF. Read it free online on the page above; download the PDF from there. ## Matching paper and memo - [MATHS LIT P1 GR11 QP NOV2022 English](https://www.hlayiso.com/library/maths-lit-p1-gr11-qp-nov2022-english/cff66dff-d8c3-4e1b-adf0-692ec2e1a58b) — QP · 2022 · Eng ## Document text Text extracted from the PDF. Layout, diagrams and tables may not survive extraction. ### Page 1 Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE GRADE 11 NOVEMBER 2022 MATHEMATICAL LITERACY P1 MARKING GUIDELINE MARKS: 100 Symbol Explanation M Method MA Method with accuracy CA Consistent accuracy MCA Method with consistent accuracy A Accuracy C Conversion S Simplification RT/RG/RM Reading from a table/Reading from a graph/Read from a map F Choosing the correct formula SF Substitution in a formula J Justification P Penalty, e.g. for no units, incorrect rounding off etc. R Rounding Off/Reason AO Answer only NPR No penalty for rounding This marking guideline consists of 7 pages. ### Page 2 Downloaded from hlayiso.com 2 MATHEMATICAL LITERACY P1 (EC/NOVEMBER 2022) QUESTION 1: FINANCE AND DATA HANDLING [19] Ques Solution Explanation T&L 1.1.1 Clerk/Cashier ✓✓ RT 2RT correct occupation F (2) L1 1.1.2 Total deductions =✓ A + R774 + R61,25 ✓ M R650 1M adding the F = R1 485,25 ✓A deductions L1 1A answer OR Total deductions = R6 125–R4 639,75 ✓ M 1M subtracting = R1 485,25 ✓A 1A answer (2) 1.1.3 Overtime = R25 × 45 ✓ RG ✓ M 1RG values R25 and 45 F = R1 125 1M multiplication (2) L1 1.1.4 Net pay is the amount received by employee after 2J explanation F subtracting total deductions ✓ from gross income ✓J (2) L1 1.1.5 Increase = 7,5 × 5 000 ✓ MA ✓M 1MA percentage of 7,5% F 100 1M multiplication with L1 R5 000 = R375 ✓A 1A answer (3) 1.2.1 Histogram ✓✓ RT 2RT correct answer D (2) L1 ✓M D 1.2.2 Total = 30 + 25 + 40 + 35 + 25 + 20 + 15 + 10 + 10 + 5 1M addition L1 = 215 ✓CA 1CA answer (2) 1.2.3 40 ✓✓ RG 2RG answer (2) 1.2.4 68 × 50 = 34 marks ✓M✓ A 1M multiplication with D 100 % with 50 L1 1A answer (2) [19] Copyright reserved Please turn over ### Page 3 Downloaded from hlayiso.com (EC/NOVEMBER 2022) MATHEMATICAL LITERACY P1 3 QUESTION 2: FINANCE [33] Ques. Solution Explanation T&L 2.1.1 R2 470 783 ✓✓ RT 2RT correct lump sum F payable to beneficiaries L1 (2) ✓RT 1RT correct value for F 2.1.2 R2 836 836 – R166 417 ✓ M 2022 L1 = R2 670 419 ✓CA 1M subtraction R166 417 from the value of 2022 1CA correct answer (3) 2.1.3 2022 ✓M F Annual amount = R26 383 × 12 1M multiplying the L2 correct value by 12 = R316 596 ✓ S 1S simplification = R316 600 ✓ R 1R correct rounding (3) 2.1.4 Difference in lump sums for 2022 and 2021 1RT and subtracting F = R919 363 – R884 198✓ RT correct values R919 363 L4 = R35 165 ✓ CA and R884 198 R35 165 is not more than R35 615 statement is invalid. ✓ J 1CA simplification 1J justification. (3) 2.1.5 Advantage: 2J any correct reason F It is a saving for the future ✓✓ J given L4 One gets income after retiring Beneficiaries get some income when the breadwinner has passed on. Choose ONE or ANY relevant answer. (2) 2.2.1 Selling price for Samsung Galaxy A72 F = R7 499,25 + R2 497,75 ✓M 1M addition L1 = R9 999,00 ✓A 1A answer (2) 2.2.2 Total profit = R1 099,75 + R2 499,75 + R3 699,75 + 1M adding the total costs F R7 249,75 ✓M L3 = R14 549,00 Total income = (3 299,25 + 1099,75 + 7499,25 + 2499,75 + 1M adding the profits 11099,25 + 3699,75 + 21749,25+7249,75) = R58 196,00 ✓M 1M forming ratio Ratio of total profit : total income 1CA reduced to simplest = R14 549,00 : R58 196,00 ✓M ratio form = 1 : 4 ✓CA (4) 2 2.2.3 A31 cellphones ordered = × 15 = 10 ✓A 1A for number of A31 F 3 1 phone ordered L4 A72 cellphones ordered = 3 ×15 = 5 ✓A 1A for number of A72 Cost price of A31: 10 × R3 299,25 = R32 992,50 ✓MCA phone ordered. Cost price of A72: 5 × R7 499,25 = R37 496,25 ✓MCA 1MCA cost price for A31 ✓MCA Total cost price of the order = R32 992,50 + R37 496,25 1MCA cost price for A72 = R70 488,75 1MCA addition (5) Copyright reserved Please turn over ### Page 4 Downloaded from hlayiso.com 4 MATHEMATICAL LITERACY P1 (EC/NOVEMBER 2022) Ques Solution Explanation T&L 2.2.4 Percentage decrease = R3 299,25 – R3 399,75 1SF substituting the F × 100% ✓SF ✓SF R3 399,75 numerator values L3 1SF substituting = -2,96% ✓S denominator value 1S simplification = 3,0% ✓R 1R rounding (NPR for negative answer) (4) F 2.3 Amount charged : 6,110 × R16,992900 = 103,826619 } 1M multiplying by the : 4,073 × R17,326130 = 70,56932749 ✓M rate : 2,817 × R24,06370 = 67,7874429 L4 Total: R242,18 ✓ S 1S simplification Amount charged including VAT: R242,18 × 1,15 ✓ M 1M VAT calculation = R278,51 ✓CA 1CA simplification INVALID statement ✓ J 1J justification (5) [33] QUESTION 3: DATA HANDLING AND PROBABILITY [19] Ques. Solution Explanation T&L 3.1 April 2018 ✓✓ RT 1RT for the month D 1RT for the year L1 correct (2) ✓ RT D 3.2 Range = R59 960 – R52 361 ✓ M 1RT identifying the L2 = R7 599 million ✓CA values 1M subtraction 1CA answer (3) ✓A D 3.3 Six hundred and sixty-six billion, four hundred and twenty- 1A value of billions L1 four million ✓ A 1A value of millions (2) D 3.4 666 424 000 ✓ RT 1RT value of the L2 Mean sales in millions = 12 ✓M numerator 1M dividing by 12 = R55 535 333,33 ✓A 1A correct answer (3) 3.5 Descending order: 1M arranging in D 59 960; 59 270; 58 435; 57 915; 56 846; 55 646; 54 981; descending/ascending L3 54 467; 54 249; 53 844; 52 718; 52 361 ✓M order 55 646 + 54 981 ✓M 1M concept of median. Median in millions = 2 1CA answer = R55 313,50 ✓CA (3) Copyright reserved Please turn over ### Page 5 Downloaded from hlayiso.com (EC/NOVEMBER 2022) MATHEMATICAL LITERACY P1 5 3.6 Annual % increase rate on monthly premium 1RT correct values D ✓RT 1M calculation of 60 406 percentage. L2 = 666 424 × 100% ✓ M 1CA answer = 9,06 % ✓ CA (NPR) (3) 3.7 2A identifying the number 5 ✓✓A of 5 months P (month with decline from 2018 to 2019) = ✓A 12 1A answer denominator P (3) L3 [19] QUESTION 4: DATA HANDLING [29 MARKS] Ques. Solution Explanation T&L 4.1.1 R650 ✓✓ RT 2RT value from expenses formula OR OR F Fixed cost = R250 + 400 ✓ RT 1RT for adding both L1 values = R650 ✓ A 1A answer (2) 4.1.2 A = R650 + R25 × 20 1SF substitution in F (a) = R1 150 ✓ A ✓ SF expenses formula L2 1A simplification and answer (2) 4.1.2 Total expenses = R775 + R900 + R1 150 ✓ MCA 1MCA adding the F (b) = R2 825 ✓ S expenses with CA from L4 ✓M 4.1.2 Total Income = R375 + R750 + R1 500 1S simplification = R2 625 ✓ S 1M adding income values 1S simplification Expenses – Income = R2 825 – R2 625 ✓ MCA IMCA subtracting the two = R200 values that give the loss of R200 (5) Copyright reserved Please turn over ### Page 6 Downloaded from hlayiso.com 6 MATHEMATICAL LITERACY P1 (EC/NOVEMBER 2022) 4.1.3 F GRAPH FOR INCOME AND EXPENSES SHOE L2 REPAIR BUSINESS INCOME EXPENSE ✓A Income and Expenses (R) ✓A ✓A Number of pairs of shoes Starting point (0;650) ✓A Any other correctly plotted point ✓ A Joining points with a straight line ✓A (3) 4.1.4 Number of pair of shoes = 13 at break-even point ✓✓RT 2RT value of 13 from F ✓ graph (2) L2 4.2 1 Japanese yen (¥) = R0,1352364 A 2MA multiplication of F (¥) 25 000 = R? the two values L2 Amount received = 25 000 × R0,1352364 ✓✓MA 1A answer = R3 380,91 ✓A (Accept R3 380,90) (3) Copyright reserved Please turn over ### Page 7 Downloaded from hlayiso.com (EC/NOVEMBER 2022) MATHEMATICAL LITERACY P1 7 4.3.1 Weight Female Male 1A tally and frequency D Category Tally Frequency Tally Frequency for each row of males L2 50–59 // 2 / 1 60–69 //// 4 // 2 ✓A 70–79 //// 4 5 ✓A 80–89 / 1 /// 3 ✓A 90–99 / 1 / 1 ✓A (5) 100–109 / 1 0 0 ✓A 4.3.2 60–69 ✓RT 1RT for correct category D 70–70 ✓RT 1RT for correct category L2 (2) 4.3.3 5 + 3 = 8 2RT for the correct ✓✓RT answer of 8 D (2) L3 4.3.4 ✓RT P 16 P(more than 70 kg) = 25 × 100% ✓M 1RT for the correct value L3 of numerator and denominator 1M percentage = 64% ✓A calculation 1A answer (3) [29] TOTAL: 100 Copyright reserved Please turn over ## Related documents - [MATHS LIT P1 GR11 MEMO NOV2020 English](https://www.hlayiso.com/library/maths-lit-p1-gr11-memo-nov2020-english/08e52e8a-ef68-4338-9e8e-a0babd449184) — Mathematical Literacy · Memo · 2020 · Eng - [MATHS LIT P1 GR11 MEMO NOV2018 English final](https://www.hlayiso.com/library/maths-lit-p1-gr11-memo-nov2018-english-final/5944100a-c394-4f99-980a-3bce6f038d91) — Mathematical Literacy · Memo · 2018 · Eng - [MATHS LIT P1 MEMO GR11 NOV2017 English](https://www.hlayiso.com/library/maths-lit-p1-memo-gr11-nov2017-english/645e8d7e-f855-44ed-87e8-91f0005958fd) — Mathematical Literacy · Memo · 2017 · Eng - [MATHS LIT P1 GR11 QP NOV2020 English .docx](https://www.hlayiso.com/library/maths-lit-p1-gr11-qp-nov2020-english-docx/fa0c394f-1138-4ab2-9498-7611a1f9e12f) — Mathematical Literacy · QP · 2020 · Eng - [MATHS LIT P1 GR11 QP NOV 2017 English](https://www.hlayiso.com/library/maths-lit-p1-gr11-qp-nov-2017-english/fec39e1d-6af0-47b5-a096-a661e2066b92) — Mathematical Literacy · QP · 2017 · Eng - [MATHS LIT P2 MEMO GR11 NOV2020 English .docx](https://www.hlayiso.com/library/maths-lit-p2-memo-gr11-nov2020-english-docx/15ce1119-bd4f-4162-8a61-3cae26343f3f) — Mathematical Literacy · Memo · 2020 · Eng ## More from Grade 11 Mathematical Literacy - [Grade 11 Mathematical Literacy P2 November 2026 Mock 2](https://www.hlayiso.com/library/grade-11-mathematical-literacy-2026-november-mock-exam-2-question-paper-paper-2/9e28596c-b065-4744-84e1-a7995223ca68) — QP · 2026 · Eng - [Gr 11 Maths Lit ATP 2023-24](https://www.hlayiso.com/library/gr-11-maths-lit-atp-2023-24/729b7b1d-095d-46f4-8082-c0c019b4c6c7) — ATP - [MATHS LIT P2 GR11 NOV25 ADDENDUM ENGLISH FINAL (1) watermark](https://www.hlayiso.com/library/maths-lit-p2-gr11-nov25-addendum-english-final-1-watermark/6d3d1a99-ee4e-4b35-9dfc-765595836d35) — Addendum · 2025 · Eng - [LP Maths Literacy Grade 11 June 2025 P1 only](https://www.hlayiso.com/library/lp-maths-literacy-grade-11-june-2025-p1-only/010db24d-7d07-4b57-b916-5b4856296406) — QP · 2025 - [FS Maths Literacy Grade 11 June 2025 P1 and Memo](https://www.hlayiso.com/library/fs-maths-literacy-grade-11-june-2025-p1-and-memo/913740d3-d3f7-470f-ad0e-289f4f74f68b) — QP + Memo · 2025 - [GP JW Maths Literacy Grade 11 June 2025 P1 and Memo](https://www.hlayiso.com/library/gp-jw-maths-literacy-grade-11-june-2025-p1-and-memo/4157e22a-6e42-4d3f-8ce9-579e85217581) — QP + Memo · 2025 ## Collection - [Grade 11 past papers](https://www.hlayiso.com/grade-11/past-papers) --- Hlayiso: free CAPS and IEB past papers, memos, notes and study guides for South African learners. 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