# Mechanical Technology Grade 12 Eastern Cape Mock 2012 Memo

> Grade 12 Mechanical Technology memorandum from the Eastern Cape Mock Exam 2012 (English), 12 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/mcht-s12-memo-eng/e651547d-e534-4759-9d2c-8f007bac7f12
- Updated: 2026-09-27
- Subject: Mechanical Technology
- Grade: Grade 12
- Document type: Memorandum
- Year: 2012
- Exam period: Eastern Cape Mock Exam
- Curriculum: CAPS
- Pages: 12

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## About this document

Mechanical Technology · Grade 12 · Eastern Cape Mock Exam · 2012. Memorandum, 12 pages. Read online or download the PDF.

Read it free online on the page above; download the PDF from there.

## Document text

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### Page 1

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                  Province of the
                  EASTERN CAPE
                  EDUCATION

                           NATIONAL
                      SENIOR CERTIFICATE

                            GRADE 12

                      SEPTEMBER 2012

               MECHANICAL TECHNOLOGY
                   MEMORANDUM

MARKS:   200

                   This memorandum consists of 12 pages.

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2                        MECHANICAL TECHNOLOGY (Memo)           (SEPTEMBER 2012)

QUESTION 1 is to be answered on this answer sheet.

VRAAG 1 moet op hierdie antwoordblad beantwoord word.

NAME/NAAM:

                   ANSWER SHEET/ANTWOORDBLAD
                                    (MULTIPLE CHOICE
    QUESTION/VRAAG    1
                           QUESTIONS)/(MEERVOUDIGEKEUSE-VRAE)

      1.1     A
      1.2                               D
      1.3            B
      1.4     A
      1.5     A
      1.6                      C
      1.7     A
      1.8                               D
      1.9            B
      1.10    A
      1.11                              D
      1.12                     C
      1.13                              D
      1.14    A
      1.15           B
      1.16    A
      1.17                     C
      1.18                     C
      1.19                     C
      1.20                              D

             TOTAL

              Tear off this page and submit with answer book.

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(SEPTEMBER 2012)                MECHANICAL TECHNOLOGY (Memo)              3

 QUESTION 2            FORCES AND SYSTEMS AND CONTROL

 (LEARNING OUTCOME 3: ASSESSMENT STANDARDS 6 AND 8)

 2.1    2.1.1      Area =               √

                                            √

                        = 0,000452389 m2 √

                   Stress       =

                                =                       √

                                = 132629119,2 Pa

                                = 132,63 MPa √                      (5)

        2.1.2      Strain           =                           √

                                    =           √

                                    = 0,001037735 √                 (3)

        2.1.3      Young modules =                          √

                                            =                   √

                                            = 127,81 GPa √          (3)

 2.2    Stress              =               √

        Area                =                   √

                            = 0,000904761 m2 √
        BUT:

        Area                =                           √

        0,000904761 =
                   D =                              √

                            = 0,020571047 m

                   D = 20,57 mm √
        Say diameter of hole is 21 mm                               (6)

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4                          MECHANICAL TECHNOLOGY (Memo)                        (SEPTEMBER 2012)

2.3   Strain is directly proportional to the stress it causes, provided the limit of
      proportionality is not exceeded. √ √                                               (2)

2.4                  force
      Stress      =
                     area
      force       = stress x area √
                                     200       5
                  = (300 x 103) x (               ) √
                                    1000     1000
                  = 300N that is T1 √
      T1   2,5
                √
      T2    1
           300
      T2 =      √
            2,5
      T2 = 120N √
      Te = 300 – 120 = 180 N √
      Torque: T
      T = Te x radius
                   1000
         = 180 x (      )√ = 180 x 0,5 m
                     2
         = 90 N.m √
      Power: P =                      OR       P =
                 =                       √         =
                 = 1884,96 watt                    = 1884,96
                 = 1,88 kW √                       = 1,88 kW                             (11)

2.5   2.5.1     Force on piston A:
                                                        √
                                             F =                 √
                                                = 75 N √                                 (3)

      2.5.2     areaA
                 0,015 x “X”             = 0,16 x 10 √
                               “X”       =        √
                                         = 106,7 mm √                                    (3)

      2.5.3     No effect because the pressure in the system is unchanged √
                Piston A and B area did not change therefor no effect. √                 (2)

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(SEPTEMBER 2012)              MECHANICAL TECHNOLOGY (Memo)                                    5

 2.6    2.6.1      M

                              “F”                         √
                                                 = 392,5 N √                           (2)

        2.6.2      V

                                                             √

                                                = 14 : 1 √                             (2)

 2.7    2.7.1      Consider a three start or even a four start screw thread √
                   A three start will move - 3 x 10 = 30 mm
                   A four start will move - 4 x 10 = 40 mm √
                   COMPARED TO
                   Two start will move - 2 x 10 = 20 mm                                (2)

        2.7.2      Lead      = pitch x number of starts
                            = 10 x 2
                             = 20 mm

                   EFFECTIVE DIA(DE)      = BD – (0,5 X PITCH)
                                   = 55 – (0,5 x 10)
                                   = 50 mm

                   Helix angle      TAN θ           =
                                                20
                                            =
                                                 50
                                    Θ       = 7,26°                                    (3)

 2.8    “P” power                                  OR    T = µWnR

          43,982 x 103 =                    √                = 0,35 x 2,5 x103 x 2 x

                       T                    √                = 140 N.m

                           = 139,999

                    Say= 140 N.m √                                                      (3)
                                                                                       [50]

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6                         MECHANICAL TECHNOLOGY (Memo)                      (SEPTEMBER 2012)

QUESTION 3          TOOLS AND EQUIPMENT

(LEARNING OUTCOME 3: ASSESSMENT STANDARD 2)

3.1   1.   Scale √
      2.   Indicator √
      3.   Upper platform √
      4.   Lower platform √
      5.   Compressing lever √                                                        (5)

3.2   3.2.1    Determines the amount of CO being produced √ OR
               Analyse the exhaust gases                                              (1)

      3.2.2    To measure the pressure created in one cylinder √                      (1)

      3.2.3    To check whether the engine leaks gases from one cylinder
               during the compression stokes √                                        (1)

3.3   1.   Shielding gas cylinder √
      2.   Wire-feed unit√
      3.   Continuous wire reel√
      4.   Welding gun √
      5.   Gas flow meter √
      6.   Power source OR AC transformer √                                           (6)

3.4   1. Check radiator for air bubbles - Air from cylinder is leaking into the
         water jackets√
      2. Listen for air coming out of the carburettor/air cleaner - this indicates
         that inlet valve is leaking√
      3. Air escaping through exhaust pipe - exhaust valve leaking√
      4. Check for air escaping through the oil filler cap - worn or broken rings
      5. Air escaping through adjacent cylinders - cracked or blown head
         gasket                                                             (Any 3)    (3)

3.5        Keep the meter dry √
           Keep it away from dust and dirt √
           Use and store it in normal temperature environments √
           Do not drop it
           Use only charged cells of correct size
           Remove cells when not in use                                    (Any 3)     (3)
                                                                                      [20]

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(SEPTEMBER 2012)            MECHANICAL TECHNOLOGY (Memo)                                         7

 QUESTION 4            MATERIALS

 (LEARNING OUTCOME 3: ASSESSMENT STANDARD 3)

 4.1    1. Create a harder, tougher metal √
        2. Producing a stronger metal √
        3. Increase the resistance to corrosion and rust √
        4. Changing the colour of the metal √
        5. Increase electrical resistance √
        6. Improve ductility and elasticity
        7. Improving casting properties
        8. Strengthening the metal against wear and tear
        9. Lowering the cost of the metal
        10 Lowering the melting point to below the mean of the metal
           components                                                         (Any 5)     (5)

 4.2    4.2.1      Copper + zinc √ √                                                      (2)

        4.2.2          A hard alloy able to resist wear √
                       Very good resistance to corrosion √
                       Easily machined
                       Lead acts as a lubricating agent                       (Any 2)     (2)

 4.3                           Properties                           Uses
        4.3.1      Very light, ductile, malleable,   Transmission lines, electric
                   soft, resist corrosion conduct    cables, electric conductors,
                   electricity and non-magnetic√     cooking utensils, gear crank
                                                     cases, gear boxes, marine,
                                                     aeroplane, motor vehicle,
                                                     roofing, gutters, doors, etc. √
                                             (Any 1)                            (Any 1)   (2)
        4.3.2          Work-hardens, ductility,           Electrical cables,
                       malleability, electrical- and      switchboard parts,
                       heat-conductivity, resist          electrical bolts and nuts,
                       corrosion √                        water supply tubing and
                                                          roofing √
                                             (Any 1)                            (Any 1)   (2)
        4.3.3          Very soft, malleable,              Soft solder, bullets, lead
                       ductile and tough, bends           cables, plumbing, sinkers
                       and stretches easily √             etc. √
                                             (Any 1)                            (Any 1)   (2)

 4.4    Salt and oil √ √                                                                  (2)

 4.5         Water resistant √
             Oil resistant √
             Heat resistant √
             Corrosion resistant
             Needs no lubrication                                             (Any 3)      (3)
                                                                                          [20]

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8                         MECHANICAL TECHNOLOGY (Memo)                     (SEPTEMBER 2012)

QUESTION 5          SAFETY, TERMINOLOGY AND JOINING METHODS

(LEARNING OUTCOME 3: ASSESSMENT STANDARDS 1, 4 AND 5)

5.1   1.  Never use damaged equipment √
      2.  No oil or grease close to oxygen equipment √
      3.  Never use oxygen to blow dirt or dust off clothing √
      4.  Never use matches or gas lighter to ignite the flame √
      5.  Sniff cylinders before assembling the regulators
      6.  Always make sure regulators have their adjusting screws released
          and purge them
      7. Wear proper welding goggles, gloves and clothing
      8. Make sure to have a fire extinguisher handy
      9. Always use the proper regulator for the gas in the cylinder
      10. Always use cylinders in the upright position
      11. Always keep the acetylene cylinder valve wrench on the cylinder
      12. Cylinder valve a maximum of one and a half turns open
      13. Do not carry lighters or matches or other flammable objects in your
          pocket when welding
      14. Take note of the area when welding
      15. Be careful not to let welding hoses come in contact with the torch,
          flame or sparks from cutting                                   (Any 3)     (3)

5.2   1.   Wear safety goggles √
      2.   Make sure that the test piece is properly mounted √
      3.   Do not exert too much stress in the beginning √
      4.   Only use apparatus if in good order
      5.   Make sure that machine stands firm
      6.   Make sure that all bolts and nuts on the apparatus are tight
      7.   Wear the correct personal protective safety wear
      8.   Before testing commences, make sure that the safety shield is in
           place
      9.   Work with care with the dial indicator, it can easily be damaged
                                                                          (Any 3)    (3)

5.3   1.  Test only in well-ventilated area √
      2.  Make certain that the exhaust probe is fitted correctly to the exhaust
          pipe √
      3. Do not run the engine for too long √
      4. Make sure that the inlet hose is not stepped on or restricted √
      5. Make sure that the hose connections are airtight
      6. Check the valve on the condenser and be in the horizontal closed
          position
      7. Check for leaks in the exhaust system, manifold or vacuum system
      8. Clean the condenser and hose by blowing it with an air line
      9. Drain the condenser after each test by means of the valve
      10. Replace filter if it is light grey
      11 Change fuel filter on condenser stand regularly
      12. Make sure that the terminals are clean                           (Any 4)   (4)

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(SEPTEMBER 2012)                 MECHANICAL TECHNOLOGY (Memo)                                       9

 5.4    1.   It keeps the work piece in position during machining √
        2.   It divides the circumference of the work piece in equal divisions √
        3.   It provides a turning action to work piece when doing helical milling √
        4.   It provides movement to the bed when milling a rack              (Any 3)         (3)

 5.5    Angle 16°30’ change (16 x 60’) + 30’ = 990’
        Angle =                              OR                 Angle =
                   =         √                                          =
               =           √                                            =
               = one full turn of the index crank and                   = one full turn of
        20 holes on the 24 hole circle √                        the index crank and 20
                                                                holes on the 24 hole circle   (3)

 5.6         Rapid indexing √
             Differential indexing √
             Normal indexing/Simple indexing√
             Angular indexing                                                                 (3)

 5.7    5.7.1          Addendum = module √
                                = 2,0 mm √                                                    (2)

        5.7.2          Dedendum = 1,157 x m
                                = 1,157 x 2 √
                                = 2,314 mm √                                                  (2)

        5.7.3          Cutting depth = 2,157 x m OR            cutting depth = add + ded
                                     = 2,157 x 2 √                           = 2 + 2,314
                                     = 4,314 mm    √                         = 4,314 mm       (2)

        5.7.4          Circle pitch =
                                    =       √
                                    = 6,28 mm √                                               (2)

        5.7.5          Clearance    = 0,157 x m
                                    = 0,157 x 2√
                                    = 0,314 mm √                                              (2)

        5.7.6          PCD          =                     OR      PCD       =Txm
                                    =                 √                     = 40 x 2
                                    = 80 mm       √                         = 80 mm           (2)

 5.8         Chance of teeth being sheared off is less √
             Less cost √
             Less power is required to drive the cutter √
             Can use high arbour speed
             Less vibration on the arbour                                                     (3)

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10                          MECHANICAL TECHNOLOGY (Memo)                         (SEPTEMBER 2012)

5.9    r/min of cutter: N                       √

                                        =           √

                                        = 137,1181048 r/min √

       Feed speed     (f)           = f1 x T x N √

                                        = 0,06 x 16 x 137,1181048 √

                                        = 131,63 mm/min √                                  (6)

5.10 5.10.1     CAUSES                                  CORRECTION
                Speed too fast √                        Weld slowly √
                Electrode too large √                   Select correct electrode
                Current too low                         Set current up
                                                        Leave enough space at bottom
                                                        of the weld                        (3)

       5.10.2   CAUSES                                  CORRECTION
                Speed too fast √                        Weld slowly √
                Current too low √                       Select correct current
                Faulty electrode                        Change the electrode
                Impaired base metal to a short          Check for impurities in metal
                arc                                     Hold a longer arc                  (3)

5.11      Cut a nick on the length of the joint approximately 6,5 mm deep √
          Place the test piece on two steel supports √
          Use a sledge hammer to break the welded joint √
          Examine the broken surface of the weld for any possible defects √                 (4)
                                                                                           [50]

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(SEPTEMBER 2012)              MECHANICAL TECHNOLOGY (Memo)                                      11

 QUESTION 6              TURBINE AND MAINTENANCE

 (LEARNING OUTCOME 3: ASSESSMENT STANDARD 7 AND 9)

 6.1    1.   Lubricating insufficient √
        2.   Operating temperature too excessive √
        3.   Oil/grease supply has foreign materials √
        4.   Incorrect lubricant √
        5.   Faulty design
        6.   Lubricant contaminated with water
        7.   Misalignment                                                           (Any 4)   (4)

 6.2    6.2.1      1.    V-belts are used over short distances √
                   2.    V-belts come in standard size for immediate replacement √
                   3.    Silent in operation √
                   4.    Requires very little maintenance
                   5.    Is able to absorb shock loads
                   6.    Operate at low bearing pressure
                   7.    A number of v-belts can be used for heavy duty application
                   8.    In a multi v-belt drive if one belt breaks the machine can still
                         run on the remaining belts                             (Any 3)       (3)

        6.2.2      1.    V-belt tension is too slack √
                   2.    Oil on v-belt √
                   3.    Grease on v-belt √
                   4.    V-belt worn out/damaged sides                              (Any 3)   (3)

 6.3    6.3.1      1. Make sure engine is at working temperature
                   2. Place container under sump. Remove oil filler cap.
                   3. Unscrew sump plug and drain oil into container.
                   4. Use a filter spanner and remove oil filter.
                   5. Allow enough time for oil to drain.
                   6. Apply sheen of oil to rubber seal of oil filter and mount with
                      hand
                   7. Screw sump plug fitted with new copper washer to sump.
                   8. Refill engine with oil according to specifications and replace
                      oil filler cap.                                                         (8)

        6.3.2      (a)       SAE “society of automotive engineers” √                          (1)

                   (b)       20 A thinner oil for when the engine is still cold √             (1)

                   (c)       W Indicates winter/colder conditions √                           (1)

                   (d)       `50 A thicker oil for when the engine is at optimal
                             working temperature √                                            (1)

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12                         MECHANICAL TECHNOLOGY (Memo)                     (SEPTEMBER 2012)

6.4   1.   The work piece and cutting tool are kept cool √
      2.   The life of the cutting tool is prolonged √
      3.   A better finish is imparted to the surface √
      4.   Cuttings are washed away √
      5.   The machine is protected because the cutting process is eased √
      6.   The machine operator is protected from metal chips
      7.   Productivity is increased because of the cutting process is faster
      8.   The soluble oil prevents corrosion
      9.   It lubricates the machine                                        (Any 5)   (5)

6.5   6.5.1      Roots-blower √                                                       (1)

      6.5.2      Vane-blower √                                                        (1)

      6.5.3      Centrifugal-blower √                                                 (1)

6.6   1.      Inlet √
      2.      Outlet √
      3.      Rotor √
      4.      Casing √                                                                (4)

6.7   Centrifugal-blower √ OR Figure 6.5.3                                            (1)

6.8   TURBO                                   SUPERCHARGER
      Driven by exhaust gases √               Mechanical driven √                     (2)

6.9   1. Special shutdown procedure is required √
      2. Special exhaust system needed√
      3. Lag because of the exhaust gases to overcome the rotational inertia √         (3)
                                                                                      [40]

                                                                          TOTAL:      200

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