# Mechanical Technology Grade 12 NSC November 2014 Memo (Eng)

> Grade 12 Mechanical Technology memorandum from the NSC November Exam 2014 (English), 18 pages. Read online or download the free PDF.

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- Updated: 2026-09-27
- Subject: Mechanical Technology
- Grade: Grade 12
- Document type: Memorandum
- Year: 2014
- Exam period: NSC November Exam
- Curriculum: CAPS
- Pages: 18

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## About this document

Mechanical Technology · Grade 12 · NSC November Exam · 2014. Memorandum, 18 pages. Read online or download the PDF.

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                                NATIONAL
                           SENIOR CERTIFICATE

                                   GRADE 12

                         MECHANICAL TECHNOLOGY

                                NOVEMBER 2014

                                 MEMORANDUM

MARKS: 200

                       This memorandum consists of 18 pages.

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Mechanical Technology                2          DBE/November 2014
                             NSC – Memorandum

QUESTION 1: MULTIPLE-CHOICE QUESTIONS

1.1       B                                                      (1)

1.2       C                                                      (1)

1.3       D                                                      (1)

1.4       C                                                      (1)

1.5       A                                                      (1)

1.6       A or C                                                 (1)

1.7       D                                                      (1)

1.8       A                                                      (1)

1.9       B                                                      (1)

1.10      C                                                      (1)

1.11      D                                                      (1)

1.12      B                                                      (1)

1.13      B                                                      (1)

1.14      A                                                      (1)

1.15      D                                                      (1)

1.16      A                                                      (1)

1.17      B                                                      (1)

1.18      D                                                       (1)

1.19      C                                                      (1)

1.20      B                                                      (1)
                                                                  [20]

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Mechanical Technology                       3                           DBE/November 2014
                                    NSC – Memorandum

QUESTION 2: SAFETY

2.1      Gas cylinders:
           • Store full cylinders apart from empty cylinders. 
           • Keep in cool place and protect them from sunlight and other sources
              of heat. 
           • Always store and use gas cylinders in an upright position. 
           • Store different gas cylinders separately. 
           • Never stack cylinders on top of one another. 
           • Do not bang or work on the cylinders. 
           • Never allow cylinders to fall. 
           • No oil and grease should come into contact with gas cylinders or
              fittings. 
           • Keep the caps on the cylinders for protection. 
           • Do not store near flammable materials. 
           • Store in a well ventilated area. 
           • Ensure the correct assembly of regulators
             •   Close valves
                                                                           (Any 3x1)            (3)

2.2      Arc welding:
         To protect your skin and eyes against the dangerous ultra-violet rays.                (1)

2.3      Safety before using a machine:
            • Always clamp work pieces and holding devices properly. 
            • Know where the ON/OFF switch is located. 
            • Make sure that all guards are in place. 
            • Make sure that there is no oil or grease on the floor around the
               machine. 
            • Wear all necessary safety equipment. 
            • Do not use machine without proper training. 
            • Do not use machine without permission. 
            • Make sure that the machine is in working order. 
                                                                       (Any 2x1)                (2)

2.4      Safety after using a machine:
         Switch the machine off.                                                               (1)

2.5      Bench grinder:
         The maximum is a 3 mm gap.                                                            (1)

2.6      Gas analyser:
         To ensure a more accurate reading or no readings at all.                           (2)
                                                                                            [10]

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Mechanical Technology                          4                             DBE/November 2014
                                       NSC – Memorandum

QUESTION 3: TOOLS AND EQUIPMENT

3.1      Causes of low compression:
         •    Worn cylinders
         •    Worn inlet valves
         •    Worn outlet valves
         •    Worn compression rings 
         •    Worn piston 
         •    Worn head gasket 
         •    Leaking, cracked, wrong settings of valves and cylinder head
                                                                        (Any 2 x 1)                  (2)

3.2.     MIGS/ MAGS:

          3.2.1       MIGS/ MAGS:PURPOSE OF INERT GAS
                      • Stabilises the arc on the parent metal 
                      •   Shields the arc and weld pool from atmospheric gases like
                          oxygen                                                                    (2)

          3.2.2       Advantages of MIGS/ MAGS:
                      • Can weld in any position 
                      • Less operator skill required 
                      • Long welds can be made without stops and starts 
                      • Causes less deformation 
                      • Faster than arc welding 
                      • Minimal post weld cleaning 
                      • No slag removal is required 
                      • Gives better finish                                                         (2)

3.3       Spring tester:
              • To check for correct tension 
              • To check for elasticity 
               • Check according to manufacturer’s specification                                    (2)

 3.4     Multimeter:
         A.    LCD display screen/Reading screen
         B.    Range selector switch
         C.    10A DC socket
         D.    VΩmA socket                                                                        (4)
                                                                                                 [12]

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Mechanical Technology                         5                             DBE/November 2014
                                      NSC – Memorandum

QUESTION 4: MATERIALS

4.1       Iron-carbon diagram:

          4.1.1         Labelling:
                        A.     Ferrite + Pearlite 
                        B.     Pearlite + Cementite 
                        C.     Ferrite + Austenite 
                        D.     Cementite + Austenite 
                        E.     Austenite                                                           (5)

          4.1.2       AC 1
                         •    It represents the lowest temperature to which steel must be
                              heated to be hardened. 
                          •   It is the temperature where the first change in structure
                              takes place.
                                                                               (Any 1 x 2)          (2)

4.2       Characteristics of:

          4.2.1       Cementite:
                        • Intensely hard 
                        • Brittle                                                                  (2)

          4.2.2       Ferrite:
                         • Soft 
                         • Ductile / malleable                                                     (2)

4.3       Austenite:
          Austenite is a combination  of iron and carbon which is called iron
          carbide.                                                                              (2)
                                                                                                [13]

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Mechanical Technology                          6                           DBE/November 2014
                                       NSC – Memorandum

QUESTION 5: TERMINOLOGY

5.1       Screw thread terminology:
             A. Crest / Outside /Normal / Major / Full / Basic diameter
             B. Effective / Pitch diameter
             C. Root /Core / Inside / Minor diameter
             D. Angle (60°)/Thread angle
             E. Crest
             F. Root
             G. Flank                                                                               (7)

5.2       Milling operations:
          Gang milling                                                                             (2)

5.3       Keyway cutting:

          5.3.1       Side and Face cutter                                                          (1)

          5.3.2          A. Work piece / Shaft
                         B. Keyway
                         C. Ruler / Scale
                         D. Cutter (Side and face) 
                         E. Square                                                                  (5)

          Key calculations:

Unit need to be specified – if omitted = no mark / Wrong unit = no mark

          5.3.3                               Diameter of shaft
                              Width of key =
                                                     4
                                              48                                  
                                            =
                                               4
                                            = 12 mm                                                 (2)

          5.3.4                                   Diameter of shaft
                             Thickness of key =
                                                         6
                                                  48                              
                                                =
                                                  6
                                                = 8 mm                            
                                                                                                     (2)

          5.3.5                  Length of key = 1,5 × Diameter
                                                                                  
                                               = 1,5 × 48
                                               = 72 mm                                              (2)

          5.3.6       Distance        = ½ diameter of shaft – ½ width of cutter        
                                      = 24 – 6                                         
                                      =18 mm                                                        (3)
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Mechanical Technology                          7                             DBE/November 2014
                                       NSC – Memorandum

5.4       Indexing:

                                      40
                        Indexing   =            
                                      n
                                     40
                                   =
                                     14
                                      6×4
                                   =2           
                                      7×4
                                       24
                                   =2           
                                       28

                      2 full turns of the crank and 24 holes in a 28 hole circle
                      2 full turns of the crank and 36 holes in a 42 hole circle       
                      2 full turns of the crank and 42 holes in a 49 hole circle                      (4)

5.5       TWO methods for screw cutting:
          Cross slide  and compound slide                                                        (2)
                                                                                                  [30]

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Mechanical Technology                        8                              DBE/November 2014
                                     NSC – Memorandum

QUESTION 6: JOINING METHODS
6.1       Causes of welding defects:
          6.1.1       Porosity:
                         •      Atmospheric contamination
                         •      Surface contamination / Dirty / Rusted
                         •      Dirty or wet electrodes with arc welding
                         •      Rusted wire with MIGS/MAGS
                         •      Incorrect flame / setting
                         •      Low current                                   (Any 3x1)           (3)
          6.1.2       Slag inclusion:
                         •     Incorrect current settings / Low current setting / Weld
                               temperature is too low 
                         •     Included angle too narrow
                         •     Rapid chilling
                         •     High viscosity of molten metal
                         •     The previous weld slag has not been removed 
                                                                             (Any 3x1)             (3)
6.2       Nick break test:
           • Each edge of the weld is slotted by means of a saw. 
           • Place the specimen on two steel supports / In a bench vice. 
           • Use a hammer to break the specimen by striking it in the zone where
               the cut was made. 
           • The weld metal exposed should be completely fused, free from slag
               inclusions and contain no gas pockets greater than 1,6 mm. 
           • There should not be more than one pore or gas pocket per square
               centimetre.                                                                   (5)
6.3       Dye penetration test:
           • Clean the weld that needs to be tested. 
           • Spray dye onto the surface and leave to penetrate. 
           • Excess dye is cleaned away with a cleaning agent. 
           • Allow surface to dry. 
           • Spray a developer onto the surface to bring out the dye trapped in the
              crack. 
           • The dye will show all the surface defects.                                      (5)
6.4       Advantages of non-destructive tests:
           • The test is done without destroying the usefulness of a finished
              product 
           • It is the fastest and least expensive in terms of the finished product.         (2)

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Mechanical Technology                      9          DBE/November 2014
                                   NSC – Memorandum

6.5       MIGS / MAGS welding process:
              A. Parent metal 
              B. Weld pool
              C. Electrode wire
              D. Gas shroud / Welding pistol
              E. Contact tube / Nozzle
              F. Shielding gas
              G. Earth cable / Clamp / Ground                             (7)
                                                                          [25]

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Mechanical Technology                             10                              DBE/November 2014
                                           NSC – Memorandum

QUESTION 7: FORCES

7.1       Resultant:
                                                   2,5cos60°
                                                            2,5 kN

                                                                 2,5sin60°
                     2,1 kN
                                      2,1cos30°

                         2,1sin30°
                                           30°       60°                       3,6 kN

                                                     3 kN

                     7.1.1            The sum of the horizontal components

          ∑ HC = 3,6 + 2,5cos60° − 2,1cos30°
                                                           
               = 3,6 + 1,25 − 1,82                         
               = 3,03 kN                                   

                     7.1.2            The sum of the vertical components

          ∑ VC = 2,5sin60° + 2,1sin30° − 3             
               = 2,17 + 1,05 − 3                       
                                                       
               = 0,22 kN

                                                    OR

           Horizontal                Magnitudes       Vertical               Magnitudes
           component                                  component
           2,1 cos30 0              -1,82 kN         2,1 sin30 0           1,05 kN
           2,5 cos60 0              1,25 kN         2,5 sin60 0           2,17 kN 
           3,6 kN                   3,6 kN           -3 kN                 -3 kN
           TOTAL                     3,03 kN        TOTAL                  0,22 kN                 (12)

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Mechanical Technology                         11                   DBE/November 2014
                                       NSC – Memorandum

          7.2.1       Stress:
                         π 2
                       A=D                                     
                             4
                         π (0,05 ) 2
                       A=
                               4
                                                               
                       A = 1,963495 × 10 −3 m 2

                              Load
                        Stress =                               
                              Area
                         σ =F
                             A
                         σ = 50 × 10
                                      3

                             1,96 × 10 −3
                         σ = 25,51× 10 6 Pa
                                                               
                        OR
                         σ = 25,51 MPa

                      No / wrong unit – no mark                                       (4)

          7.2.2       Strain:

                                            Change in length
                                   Strain =                    
                                             Original length
                                            0,005
                                   Strain =                    
                                              3
                                         = 1,6667 × 10 −3                                (3)

7.3       Stress/ strain diagram
          A = Limit of proportionality
          B = Limit of elasticity
          C = Yield point
          D = Maximum stress
          E = Break stress / Break point                                                 (5)

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Mechanical Technology                          12                                  DBE/November 2014
                                        NSC – Memorandum

7.4       Moments:

                        1400 N                                    2500 N
                                              100 N/m

                     2m                        6m                             4m

                 A                                                                       B

          Calculate A
          Take moments about B

                          A × 12 = (2500 × 4 ) + (600 × 7 ) + (1400 × 10 ) 
                          A ×12 = 10000 + 4200 + 14 000
                                                                           
                              12A 28200
                                    =
                               12      12
                                A = 2350 N                                 
          Calculate B
          Take moments about A

                          B ×12 = ( 1400 × 2 ) + ( 600 × 5 ) + ( 2500 × 8 )   
                          B ×12 = 2800 + 3000 + 20 000                        
                             12B 25800
                                    =
                             12         12
                                                                              
                              B = 2150 N

                                                                                                        (6)
                                                                                                       [30]

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Mechanical Technology                      13                              DBE/November 2014
                                    NSC – Memorandum

QUESTION 8: MAINTENANCE

8.1       EP – oil:

          Manual Gearbox and differential.                                                       (1)

8.2       Abbreviations:

          8.2.1       SAE: Society of Automotive Engineers                                       (1)

          8.2.2       ATF: Automatic Transmission Fluid                                          (1)

8.3       Properties of grease:
           •   It must be water resistant; it must not mix with water. 
           •   Prevents rust / corrosion. 
           •   Good for load pressures.
           •   High melting point.
           •    Low freezing point.
           •    Prevent gumming 
           •    Be able to lubricate                                        (Any 2x1)            (2)

8.4       Maintenance of V belt drives:
           •    Check the contact surfaces of the pulley to prevent the belt from
                being damaged. 
           •    Check the belt condition and replace if it is worn. 
           •    Correct installation procedure must be followed. 
           •    Belt drives should be well guarded to prevent foreign objects to
                come into contact with the belts and pulleys. 
           •    Keep guard mesh free of papers, rags etc. that can cause
                insufficient air flow. 
           •    Check that belt deflection is according to specification. 
           •    Store replacement belts in a cool, well ventilated place. 
           •    Correct alignment of pulleys                                (Any 2x1)             (2)

8.5       Causes of clutch slip:
           •   Worn friction material 
           •   Oil on friction material 
           •   Over loading 
           •   Lack of pressure on friction surfaces 
           •   Broken clutch plate / pressure plate
           •   Incorrect adjustment (free play) 
           •   Worn flywheel                                                (Any 3x1)            (3)

8.6       Clutch replacement:
           •    Clutch plate 
           •    Pressure plate / Fly wheel 
           •    Thrust bearing / Release bearing / pilot bearing            (Any 3x1)            (3)

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Mechanical Technology                       14                             DBE/November 2014
                                     NSC – Memorandum

8.7       Viscosity of engine oil:

           •     The oil will not stay between the surfaces in contact, it will just flow
                 through. 
           •     The oil will not have enough time to carry away the heat generated
                 by the friction of the moving parts.                                             (2)

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Mechanical Technology                      15                            DBE/November 2014
                                    NSC – Memorandum

QUESTION 9: SYSTEMS AND CONTROL

9.1       Gear drives:

          Rotation frequency of the electric motor:

One mark – magnitude / one mark for the unit

                                         NA TB × TD
                                           =                    
                                         ND TA × TC
                                                TB × TD
                                         NA =           × ND    
                                                TA × TC
                                                56 × 76         
                                         NA =           × 800
                                                40 × 28
                                              = 3040 rpm                                      (5)

9.2       Belt Drives:

          9.2.1       Diameter of the driven pulley:

                                    NDN × D DN = NDR × D DR     
                                                  NDR × D DR
                                          DDN =                 
                                                    NDN
                                                  1440 × 0,16
                                           D DN =
                                                      3840
                                           D DN = 0, 06 m       
                                                = 60 mm                                         (3)

          9.2.2       Power transmitted:

                              T1
                                 = 2,5                               
                              T2
                                  320
                             T2 =
                                   2,5
                                                                     
                             T2 = 128 N

                             P=
                                  (T1 − Tπ
                                         2)
                                         Dn
                                      60                             
                                          π) × 0,16 × 1440
                                 (320 − 128
                             P=
                                            60
                                                                     
                             P = 2316,23 Watt                                                   (4)

          NOTE: If driven diameter and speed is used to calculate power, mark
          correct, i.e. 2 316,23 Watt.

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Mechanical Technology                          16                            DBE/November 2014
                                        NSC – Memorandum

9.3       Hydraulics:

          9.3.1       Fluid pressure:

                                           π 2
                                       AB = D
                                               4
                                           π (0,13 ) 2
                                       AB =
                                                 4
                                       A B = 13,273228 × 10 −3 m 2   
                                             F
                                        P=
                                             A                       
                                                20 × 10 3
                                        P=
                                            13,273228 × 10 −3
                                        P = 1506792,36 Pa            

                                                                                                    (3)

          9.3.2       Force needed on piston A:

                                 π 2
                             AA = D
                                     4
                                 π × (0,03 ) 2
                             AA =
                                       4
                             A A = 0,000706858 m 2
                             A A = 0,706858 × 10 − 3 m2                  

                                  F
                              P=                                         
                                  A
                              F = P× A                                   
                              F = (1506792,36 ) × (0,706858 × 10 − 3 )
                              F = 1065,09 N                              

                             OR

                             FA   F
                                = B                                      
                             AA  AB
                                        FB × A A                         
                             FA    =
                                          AB
                                     2000 ×10 × 0,706858 ×10 − 3         
                                   =
                                          13,273228 ×10 − 3
                                                                         
                                   = 1065,09 N                                                      (4)

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Mechanical Technology                      17                      DBE/November 2014
                                    NSC – Memorandum

9.4       Functioning of vehicle management system:

          •      Electronic systems use sensors to supply ECU with data. 
          •      The sensor data is read and compared with pre-programmed
                 information. 
          •      A response is calculated and actuators are adjusted. 
          •      The results are checked and the process is repeated.                    (4)

9.5       Anti-lock brake system:

          ABS comes into play in poor road surface and weather conditions  and
          also during emergency stops.                                                 (2)
                                                                                       [25]

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Mechanical Technology                        18                             DBE/November 2014
                                      NSC – Memorandum

QUESTION 10: TURBINES

10.1      Turbine:
          A steam turbine is a mechanical device that extracts thermal energy from
          pressurised steam and converts it into mechanical work / rotary motion.               (2)

10.2      Supercharger terminology:

          10.2.1      Boost:
                      This refers to the increase in manifold pressure that is generated
                      by the turbocharger in the intake path or specifically intake
                      manifold which exceeds normal atmospheric pressure.                      (2)

          10.2.2      Density ratio:
                      The density of the inlet air compared to the density of the outlet
                      air in comparison to the inlet manifold.                                 (2)

10.3      Water turbine:

          10.3.1      Reaction turbine / Water turbine / Kaplan turbine                         (1)

          10.3.2      A – Wicket gate 
                      B – Rotor 
                      C – Stator 
                      D – Shaft 
                      E – Water-flow / Inlet port
                      F – Blades / Vanes / Propeller / Fins / Turbine wheel                     (6)

          10.3.3      Advantages of water turbine:
                      •    Water turbines do not emit carbon. 
                      •    No water is consumed in the process of generating
                           electricity. 
                      •    Water turbines are more reliable. 
                      •    Water turbine blades continue to turn on cloudy windless
                           days unlike sun and wind systems. 
                      •    It is environmental friendly with no pollution. 
                      •    More economical than steam turbines
                                                                                (Any 3x1)        (3)

          10.4        Waste gate:
                      A waste gate is a valve that diverts exhaust gases away from the turbine
                      wheel. It regulates the turbine speed, rotating speed of the compressor as well
                      as regulates maximum boost pressure in the turbocharger system.

10.5      Oil cooler:
          To cool the oil that lubricates the turbocharger bearings.  and shaft                (2)
                                                                                                [20]

                                                                                 TOTAL:          200

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- [MT Nov 2020 (Automotive) Memo Afr](https://www.hlayiso.com/library/mt-nov-2020-automotive-memo-afr/3f9a8d78-97b6-4d96-a459-e2cd2e0f4240) — Mechanical Technology · Memo · 2020 · Afr

## More from Grade 12 Mechanical Technology

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## Collection

- [Grade 12 past papers](https://www.hlayiso.com/grade-12/past-papers)

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