# Mechanical Technology Grade 12 NSC November 2021 Memo (Eng)

> Grade 12 Mechanical Technology memorandum from the NSC November Exam 2021 (English), 24 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/mechanical-technology-nov-2021-fitting-machining-mg-eng/63764b76-df00-4fda-836f-57e7cb123ef9
- Updated: 2026-10-29
- Subject: Mechanical Technology
- Grade: Grade 12
- Document type: Memorandum
- Year: 2021
- Exam period: NSC November Exam
- Curriculum: CAPS
- Pages: 24

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Mechanical Technology · Grade 12 · NSC November Exam · 2021. Memorandum. Read online or download the PDF.

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                                  NATIONAL SENIOR
                                    CERTIFICATE

                                       GRADE 12

             MECHANICAL TECHNOLOGY: FITTING AND MACHINING

                                     NOVEMBER 2021

                                 MARKING GUIDELINES

MARKS: 200

                      These marking guidelines consist of 24 pages.

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                                      NSC – Marking Guidelines

QUESTION 1: MULTIPLE-CHOICE QUESTIONS (GENERIC)

1.1       B                                                                                (1)

1.2       A                                                                                (1)

1.3       D                                                                                (1)

1.4       A/C                                                                              (1)

1.5       A                                                                                (1)

1.6       C                                                                                (1)
                                                                                            [6]

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QUESTION 2: SAFETY (GENERIC)

2.1       First-aid applications to an open wound:
               Use surgical gloves. 
               Do not remove anything that is stuck to the wound. 
               Never use sticky plaster on the wound. 
               Cover the wound with a clean, lint-free cloth. 
               Avoid using any oily substances or lotions on wounds. 
               If necessary, cool wounds with cold water. 
               Apply pressure to prevent blood loss if necessary. 
               Avoid contact with blood from patient. 
               If the wound is on your arm, raise the arm above your head to stop
                  the bleeding. 
                                                                        (Any 2 x 1)             (2)

2.2       Surface grinder: (Already switched on)
              Never leave the grinder unattended. 
              Switch off the machine when leaving. 
              Don’t try to stop revolving emery wheel with your hand. 
              Don’t adjust the machine while working. 
              Don’t open any guard while the machine is on. 
              Do not force the grinding wheel on to the work piece. 
              Approach the work piece slowly and evenly. 
              Don’t clean the machine while working. 
              Do not put hands near the work piece when grinder is in motion. 
              Don’t clean or adjust the machine while working.
              Check for oil on the floor while working (spilling of cutting fluid on
                floor while working) 
              Check that he grinding wheel is running evenly. 
                                                                         (Any 2 x 1)            (2)

2.3       Gauges calibrated:
             To ensure accurate readings. 
             To prevent overloading. 
                                                                         (Any 1 x 1)            (1)

2.4       Finger protectors’ hazards on power driven guillotines:
              The finger protector prevents the hazards of getting the fingers cut
                by the blades. 
              To be crushed by the hold-downs.                                                (2)

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2.5       Welding or flame cutting operation safety:
             An operator has been instructed on how to use the equipment
                safely. 
             A workplace is effectively partitioned off. 
             An operator uses protective equipment. 
             Ensure that all equipment is in safe working condition. 
             Ensure that here are no flammable materials around the welding
                area. 
             Weld area must be well ventilated. 
             Fire extinguisher must be in close proximity. 
                                                                        (Any 2 x 1)           (2)

2.6       Workshop layout:
          Product layout.                                                                 (1)
                                                                                          [10]

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QUESTION 3: MATERIALS (GENERIC)

3.1       File test:

          3.1.1        Difficult                                                            (1)

          3.1.2        Easy                                                                 (1)

          3.1.3        Difficult                                                            (1)

3.2       Heat treatment:
           A. – Grain growth. 
           B. – Recrystallisation. 
           C. – Recovery.                                                                   (3)

3.3       Bending test:
             Bend the test piece through a specific angle or around a mandrel or
               bar,  having a defined radius,  until a rupture in the metal
               occurs.
             Place the material in a vice and bend it  then observe  the
               ductility of the material. 
                                                                      (Any 1 x 3)            (3)

3.4       Purpose of case hardening:
          Creates a hard surface  with a tough core.                                       (2)

3.5       Quenching media:
             Water 
             Brine (saltwater) 
             Oil 
             Soluble oil and water 
             Nitrogen air-infused air 
                                                                      (Any 3 x 1)        (3)
                                                                                        [14]

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QUESTION 4: MULTIPLE-CHOICE QUESTIONS (SPECIFIC)

4.1       C                                                                             (1)

4.2       B                                                                             (1)

4.3       A                                                                             (1)

4.4       A                                                                             (1)

4.5       D                                                                             (1)

4.6       D                                                                             (1)

4.7       C                                                                             (1)

4.8       C                                                                             (1)

4.9       B/D                                                                           (1)

4.10      D                                                                             (1)

4.11      A                                                                             (1)

4.12      A                                                                             (1)

4.13      B                                                                             (1)

4.14      D                                                                          (1)
                                                                                     [14]

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QUESTION 5: TERMINOLOGY (LATHE AND MILLING MACHINE) (SPECIFIC)

5.1       Advantages of compound slide method:

                 Tapers with large angles can be cut. 
                 External and internal tapers can be cut. 
                 The set-up is simple. 
                                                                  (Any 2 x 1)            (2)

5.2       Taper cutting:

          5.2.1       Length of taper:

                            θ Dd
                      Tan     
                            2   2 
                                 Dd 
                        2 
                                     θ
                                 tan
                                     2
                                 92  50
                          2            
                                  tan4
                                      42
                          2 
                                 0,069926811 
                                 600,6279909
                                           
                                      2
                              300,31 mm 
                                                                                         (5)

          5.2.2       Tailstock set-over:

                                      LD  d
                      Set  over 
                                        2l
                                      425,3192  50 
                                  
                                        2  300,31 
                                   29,74 mm 
                                                                                         (3)

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5.3       Key ways:

          5.3.1       Width:
                                D
                      Width =
                                4

                                75
                      Width =      
                                 4

                             = 18,75 mm 
                                                                                               (2)

          5.3.2       Thickness:
                                      D
                      Thickness =
                                      6

                                      75
                      Thickness =        
                                      6

                                    = 12,50 mm 
                                                                                               (2)

          5.3.3       Length:
                      Length = 1,5  diameter of shaft
                             = 1,5  75 
                               = 112,50 mm 
                                                                                               (2)

5.4       Disadvantages of down-cut milling:
              Vibration in the arbor is unavoidable. 
              A fine feed must be used. 
              When milling material with hard scale, the cutter teeth come directly
               in contact with the scale, which can damage the cutter. 
              The process is time consuming. 
                                                                         (Any 2 x 1)        (2)
                                                                                           [18]

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QUESTION 6: TERMINOLOGY (INDEXING) (SPECIFIC)

6.1       Gear terminology:

          6.1.1       Pitch-circle diameter:
                      PCD = m  T                         CP = m  π
                            = 1,5  200 
                                                                 = 1,5  π
                            = 300 mm
                                                                 = 4,71 mm 
                                                 OR
                                                                     CP  T
                                                        PCD 
                                                                       π
                                                                     4,71 200
                                                                 
                                                                         π
                                                                  299,85 mm                               (2)

          6.1.2       Dedendum:

                      Dedendum= 1,157  m                            Dedendum= 1,25  m
                              = 1,157  1,5             OR                  = 1,25  1,5 
                              = 1,74 mm                                     = 1,88 mm                     (2)

          6.1.3       Outside diameter:

                      OD = PCD + 2  m                                   OD = mT + 2
                         = 300 + 2(1,5)                  OR                = 1,5(200 + 2) 
                         = 303 mm                                         = 303 mm                        (2)

          6.1.4       Working depth:

                      WD = 2  m                                        WD = 2  a
                         = 2  1,5                    OR                  = 2  1,5 
                         = 3 mm                                           = 3 mm                          (2)

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6.2       Dovetails:

          W = 210 + 2(DE)
          m = W – 2(AC) – 2(R)

          6.2.1       Maximum width distance of dove tail: (W)

                      Calculate DE or y:

                                DE
                       tanθ 
                                AD
                       DE = tanθ  AD 
                          = tan30°  45 
                          = 25,98 mm 

                       W = 210 + 2(DE) 
                         = 210 + 2(25,98) 
                         = 210 + 51,96
                         = 261,96 mm 
                                                                                         (6)

          6.2.2       Distance between the rollers: (m)

                      Calculate AC or x:

                                BC
                       Tanθ 
                                AC

                                 BC
                         AC           
                                Tanθ

                                  17
                         AC           
                                Tan30

                             29,44 mm 

                       m = W - 2(AC) - 2(R) 
                         = 261,96 - 2(29,44) - 2(17)     
                         = 261,96 - 58,88 - 34
                         = 169,08 mm 
                                                                                         (6)

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6.3       Milling of spur gear:
          6.3.1      Indexing:
                                       40 40
                      Indexing          
                                       N 137

                                       40 40
                                                
                                       A 140

                                        4 2
                                        
                                       14 2

                                  8
                                     
                                 28
                      Indexing : 8 holes on a 28 - hole circle 
                                                       OR
                                 12 holes on a 42 - hole circle 
                                                          OR
                                       14 holes on a 49-hole circle. 
                                                                                                 (3)
          6.3.2       Change gears: (Markers to note alternative answers and
                      calculations to award full marks if the answer is correct)
                      Dr              40
                           A  n 
                      Dn              A

                      Dr                  40
                          140  137 
                      Dn                 140 

                                    40
                           3
                                   140

                              120
                          
                              140 

                              12
                          
                              14

                              12 2
                               
                              14 2 

                      Dr 24                    48 
                                        OR
                      Dn 28                    56 
                                                                                              (5)
                                                                                             [28]

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                                      NSC – Marking Guidelines

QUESTION 7: TOOLS AND EQUIPMENT (SPECIFIC)

7.1       Functions of a moment and force tester:
             To determine the reaction on either side of a simple loaded
               beam. 
             To illustrate the concept of the triangle of force.                              (2)

7.2       TWO hardness testers:
             Brinell 
             Rockwell 
             Vickers 
                                                                         (Any 2 x 1)            (2)

7.3       Precision measuring instrument:
              Depth micrometer 
              Vernier caliper 
                                                                         (Any 1 x 1)            (1)

7.4       Identify tester:
          Tensile tester                                                                       (1)

7.5       There are THREE ways that hardness is measured:
              Resistance to penetration. 
              Elastic hardness. 
              Resistance to abrasion / scratching / file test.
              Sound test (dropping it on the floor and listen to the sound).
                                                                          (Any 3 x 1)           (3)

7.6       Screw thread height:

                           
                           
                                                                                                (2)

7.7       Measuring instrument:
          Vernier caliper                                                                      (1)

7.8       Interchangeable extension:
          To measure depths greater than 25 mm.                                             (1)
                                                                                            [13]

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QUESTION 8: FORCES (SPECIFIC)

8.1       Calculate resultant:

         VERTICAL COMPONENT:

                                                                           

                                                                 

         HORIZONTAL COMPONENT:

                                                                       

                                                                 

                                                                                         OR
              VC/y = Fsinɵ                                                                    HC/x = Fcosɵ
        -45sin90° OR 45sin270°                                               -45 N  120cos0°                        120 N 
        -70sin30° OR 70sin210°                                               -35 N     -70cos30° OR 70cos210°       -60,62 N 
        185sin45° OR 185sin135°                                              130,82 N  -185cos45° OR 185cos135°     -130,82 N 
                                                                     Y = 50,82 N                            X = -71,44 N 

                                                                                                                
                VC  45sin9070sin30185sin45

                VC  4535130,82

                                                                                                                     
                VC  50,82N

                                                                                                             

                                                             

                                                                                 

                                                                                                             R
                                                                                 

                                                                                                                                      (15)

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8.2       Moments:

        9,5 kN                80 kN            4,5 kN
                     2,5 m            2,5 m

                                                   10,25 m

          A                                                                               B

          8.2.1        Point load for UDL:
                                         
                                  
                                                                                                     (2)

          8.2.2        Take moments about B:

                      (A  10,25) (4,5  5,25) (80  7,75) (9,5  10,25)   

                             10,25A  23,625  620  97,375

                                        741
                                  A           
                                       10,25

                                  A  72,29 kN                                                      (3)

          8.2.3        Take moments about A:

                      (B  10,25) (9,5  0) (80  2,5) (4,5  5)   

                             10,25B  0  200  22,5

                                       222,5
                                  B         
                                       10,25

                                  B  21,71 kN                                                      (3)

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8.3.1     The stress in the material in MPa:

                                               

                                               
                                                                                                            (2)

8.3.2     The diameter of the mild steel shaft:

                F                                                 πd 2
             σ                                             A
                A                                                  4

                     F                                  A  4  πd 2
             A           
                     σ
                                                                  A 4
             2                    3                        d2         
          πd    90  10                                             π
                          
           4   14,59  106
                                                                    A 4
                              3                             d
                     90  10  4                                      π
           πd2 
                     14,59  106                   OR

                                                            d
                                                                    6,17  10   4 
                                                                               3

           πd2  0,0247                                                    π

                         0,0247                             d      0,007855887 
            d2 
                            π
                                                            d  0,088633441 m 
             d  7,85  10            3   
                                                            d  88,63 mm 
             d  0,08863 m 

             d  88,63 mm 
                                                                                                            (5)

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8.3.3     Original length:

                                

                                        

                                       
                                                                                      (3)
                                                                                     [33]

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QUESTION 9: MAINTENANCE (SPECIFIC)

9.1       Preventative maintenance:
              Planned or scheduled maintenance. 
              Condition-based maintenance.                                                   (2)

9.2       Preventative maintenance of gear drive systems:
              Checking and replenishment of lubrication levels. 
              Ensuring that gears are properly secured to shafts. 
              Cleaning and replacement oil filters. 
              Reporting excessive noise, wear, vibration and overheating for
                expert attention. 
                                                                     (Any 3 x 1)               (3)

9.3       Purpose of jockey pulley:
              The jockey pulley helps setting the tension on the system. 
              To increase the angle of contact in an open belt drive. 
                                                                         (Any 1 x 1)           (1)

9.4       Properties of materials:
          9.4.1     Teflon:
                        Water resistant. 
                        Resistant to grease. 
                        Resistant to heat. 
                        Resistant to corrosion. 
                        Can withstand high temperatures. 
                        Need no lubricants. 
                        Electrical insulator 
                        Thermoplastic /Easy to be reshaped / recycled.
                                                                      (Any 2 x 1)              (2)

          9.4.2       Nylon:
                          Tough. 
                          Hard-wearing. 
                          Cheap. 
                          Needs no or little maintenance. 
                          Can withstand high temperatures. 
                          Need no or little lubricants. 
                          Is light. 
                          Can absorb shock. 
                          Resistant to chemicals. 
                          Non-toxic. 
                          Thermoplastic /Easy to be reshaped.
                          Has high load-bearing strength 
                                                                        (Any 2 x 1)            (2)

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          9.4.3       Vesconite:
                         Wear resistant. 
                         Low friction. 
                         Operate with little or no lubrication. 
                         Easy to machine. 
                         Load carry higher than white metal. 
                         Cost effective material. 
                         Gives long life span. 
                         Performs well, in unhygienic, dirty and un-lubricated
                           environments. 
                         Low maintenance. 
                         Low or no water absorption 
                         High chemical resistance 
                         Versatile 
                         Can handle high temperatures 
                         Thermoplastic /Easy to be reshaped 
                                                                         (Any 2 x 1)            (2)
9.5       Use of material:
          9.5.1    Polyvinyl chloride (PVC): (Due to the large number of alternatives,
                   marker discretion must be used - discuss with IM).
                        Electrical cable isolation.
                        Electrical pipes. 
                        Water pipes. 
                        Artificial leather. 
                        Cling wrap. 
                        Credit / bank / phone cards.
                        Window frames. 
                        Fences. 
                        Furniture. 
                                                                    (Any 1 x 1)        (1)

          9.5.2       Glass fibre: (Due to the large number of alternatives, marker
                      discretion must be used - discuss with IM).
                          Boats.
                          Motor vehicles bodies. 
                          Transparent roof sheeting. 
                          Petrol tanks. 
                          Swimming pools. 
                          Furniture. 
                          Fruit and salad bowls. 
                          Ornaments. 
                          Fishing equipment. 
                                                                         (Any 1 x 1)            (1)
9.6       Difference between thermoplastic and thermo-hardened composites:
          Thermoplastic can be re-heated  and reshaped again  where a thermo-
          hardened plastic cannot be re-heated,  to be softened, shaped  and
          moulded again.
                                                                                             (4)
                                                                                            [18]
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QUESTION 10: JOINING METHODS (SPECIFIC)

10.1      Screw thread:
              Square thread 
              Acme thread 
              V-screw thread 
              Trapezium thread / Buttress thread 
                                                                          (Any 3 x 1 )            (3)

10.2      Square Thread:

          10.2.1      Pitch diameter:

                                 Lead
                      Pitch 
                             Numberof starts
                             36
                                 
                              2
                            18 mm 

                                   P
                        PD  OD 
                                    2
                                  18 
                            80 
                                   2
                            71 mm                                                               (4)

          10.2.2      Helix angle of the thread:

                             Lead
                      Tanθ 
                             π  PD
                              36    
                      Tanθ 
                             π  71 
                          θ  tan 10,161396562        
                             9,17                                                              (4)

          10.2.3      Leading angle:

                      Leading angle = 90° - (helix angle + clearance angle)
                                          = 90° - (9,17° + 3°) 
                                          = 77,83° 
                                                                                                  (2)

          10.2.4      Following angle:

                      Following angle = 90° + (helix angle - clearance)
                                           = 90° + (9,17° - 3°) 
                                          = 96,17°                                               (2)

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                                      NSC – Marking Guidelines

10.3      Multiple screw threads:
             They provide more bearing surface than single start screw thread /
                does not strip easily. 
             To provide faster linear movement. 
             They are more efficient as they lose less power to friction compared
                to single start screw threads.                                           (3)
                                                                                         [18]

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Mechanical Technology: Fitting and Machining     21              DBE/November 2021
                                      NSC – Marking Guidelines

QUESTION 11: SYSTEMS AND CONTROL (DRIVE SYSTEMS) (SPECIFIC)

11.1      Hydraulics:

          11.1.1             The fluid pressure:

                                                                    

                                                                         

                                            
                                                                                         (4)

          11.1.2             Force at ram:

                                                                            

                                                                                 

                                                        

                                                    

                                                

                                           OR
                     F           f
                         2
                             
                     D           d2

                         F            25
                             2
                                           
                     120             352

                      25  1202 
                     F
                          352 

                     F  293,88kN                                                       (5)

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                                      NSC – Marking Guidelines

11.2      Functions hydraulic reservoir:
             A fluid storage tank. 
             Promotes air separation from the fluid. 
             Support for the pump and electric motor. 
             Promotes heat dispersion. 
             Acts as a base plate for mounting control equipment.
             Permits contaminants to settle at the bottom in order to be
                drained. 
                                                                   (Any 1 x 1)                  (1)

11.3      Efficiency of pneumatic systems:
               Pneumatic tools are environmentally friendly. 
               Last long. 
               It is robust (powerful / less force required) 
               Easy to use. 
               It is compact. 
               Easy to maintain as there are so few working parts. 
                                                                        (Any 2 x 1)             (2)

11.4      Applications for pneumatic systems: (Due to the large number of
          alternatives, marker discretion must be used - discuss with IM).
               Drills. 
               Brake systems. 
               Jackhammers 
               Nail guns 
               Missiles 
               Doors 
               Spray guns 
               Air blow guns 
               Air socket wrench 
               Grinders 
                                                                     (Any 2 x 1)                (2)

11.5      Belt drives:

          11.5.1      Rotation frequency:

                                                             

                                                             

                                                                                               (3)

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                                      NSC – Marking Guidelines

          11.5.2       Power transmitted:

                                T1                   (T  T )π DN
                     Ratio                        Ρ 1 2
                                T2                        60

                                 T1
                       T2                         Ρ (300  120 )π  0,8  5,4 
                                Ratio 
                                300
                       T2                         P  2442,90 Watt
                                2,5
                       T2  120 N                 P  2,44 kW                                        (4)

11.6      Gear drives:
          11.6.1    Rotation frequency:

                   Ninput       Product of teeth on driven gears
                            
                 Noutput        Product of teeth on driver gears

                                TA  TC  NA
          N(D)OUTPUT                        
                                  TB  TD
                                30  20  2300 
          N(D)OUTPUT        
                                    40  60    

          N(D)OUTPUT         575 r/min                                                               (4)

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                                      NSC – Marking Guidelines

          11.6.2      Gear ratio:

                         Product of teeth on driven gears
          Gear ratio 
                         Product of teeth on driver gears

                         40  60 
          Gear ratio 
                         30  20 

          Gear ratio  4 : 1 

                             OR

                             NA
          Speed ratio 
                             ND

                             2300 
                         
                             575 

                          4 :1 
                                                                                      (3)
                                                                                     [28]

                                                                     TOTAL:          200

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