# Physical Sciences Grade 12 Paper 2 Mpumalanga Mock 2022 Memo

> Grade 12 Physical Sciences Paper 2 memorandum from the Mpumalanga Mock Exam 2022, 33 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/mp-physical-science-grade-12-sept-2022-p2-and-memo/c2bff70f-f555-44e8-8cbe-9efda09b925a
- Updated: 2026-09-27
- Subject: Physical Sciences
- Grade: Grade 12
- Document type: Memorandum
- Year: 2022
- Exam period: Mpumalanga Mock Exam
- Paper: 2
- Curriculum: CAPS
- Pages: 33

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## About this document

Physical Sciences · Grade 12 · Mpumalanga Mock Exam · 2022. Memorandum, 33 pages. Read online or download the PDF.

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                                  NATIONAL
                           SENIOR CERTIFICATE

                                  GRADE 12

               PHYSICAL SCIENCES: CHEMISTRY P2

                              SEPTEMBER 2022

                           MARKING GUIDELINES

MARKS/PUNTE: 150

                     This memorandum consists of 14 pages.

                   Hierdie memorandum bestaan uit 14 bladsye.

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Physical Sciences P2/Fisiese Wetenskappe V2     2                             September 2022
                                      NSC/NSS- Marking Guidelines

QUESTION 1 / VRAAG 1

1.1      C ✓✓

1.2      D ✓✓

1.3      A ✓✓

1.4      B ✓✓

1.5      D ✓✓

1.6      B ✓✓

1.7      D ✓✓

1.8      C ✓✓

1.9      B ✓✓

1.10     A ✓✓
                                                                                            [20]

QUESTION 2 / VRAAG 2

2.1      A bond or an atom or a group of atoms that determine(s) the physical and
         chemical properties of a group of organic compounds.✓✓ (2 or 0)

         ‘n Binding of 'n atoom of 'n groep atome wat die fisiese en chemiese eienskappe
         van 'n groep organiese verbindings bepaal. ✓✓ (2 or 0)                              (2)

2.2.1         H      O    H
                               
         H    C      C    C        H

              H           H                                                                  (1)
2.2.2 F                                                                                     (1)

2.2.3 5-bromo-2-chloro-2-methylhexane
      5-bromo-2-chloro-2-methylhexane

         Marking criteria/Nasienriglyne:
        • Correct stem i.e. hexane./Korrekte stam d.i. heksaan. 
        • All substituents (bromo, chloro and methyl) correctly identified./Alle
           substituente (bromo, chloro en metiel) korrek geïdentifiseer. 
        • IUPAC name completely correct including numbering, sequence, hyphens and
           commas./IUPAC-naam heeltemal korrek insluitende volgorde, koppeltekens en
           kommas .                                                                         (3)

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Physical Sciences P2/Fisiese Wetenskappe V2     3                                September 2022
                                      NSC/NSS- Marking Guidelines

2.2.4 Propanone / Propanoon                                                                   (1)

2.2.5 Ketones/Ketone                                                                          (1)

2.2.6                H                         Marking criteria / Nasienriglyne
                                               • Only functional group correct / Slegs
             H       C    H                      funksionele groep korrek 
                                               • Two methyl groups / Twee metielgroepe
             H            H       H   H
                                                 ✓
                                               • Whole structure correct / Hele struktuur
         H   C       C    C       C   C   H
                                                 korrek 
             H            O       H   H
                              H
             H       C    H
                     H                                                                         (3)

2.2.7 Secondary/Sekondêr                                                                      (1)

2.3.1 Unsaturated/Onversadig ✓
         It is a compound with one or more multiple bonds between C atoms in their
         hydrocarbon chains. ✓
         Verbindings waarin een of meer meervoudige bindings tussen C-atome in hul
         koolwaterstofkettings voorkom.                                                        (2)

2.3.2 Bromine water / Br2 (Accept KMnO4) 
      Broom water / Br2 (Aanvaar KMnO4)                                                        (1)

2.3.3 CnH2n+2                                                                                 (1)
                                                                                              [17]

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Physical Sciences P2/Fisiese Wetenskappe V2     4                              September 2022
                                      NSC/NSS- Marking Guidelines

QUESTION 3 / VRAAG 3

3.1    Propane / Propaan ✓                                                                  (1)

3.2.1 Organic molecules with the same molecular formula, ✓ but different structural
      formulae.✓
      Organiese molekule met dieselfde molekulêre formule, maar verskillende
      struktuurformules.                                                                    (2)

3.2.2 Chain isomer / Kettingisomeer✓                                                        (1)

3.2.3 •    Structure:
           Compound B has a larger surface area than compound C. ✓
      •    Intermolecular forces:
           The intermolecular forces in B is stronger than in C. ✓
      •    Energy
           More energy required to overcome/break intermolecular forces in B than
           in C . ✓

      •    Struktuur:
           Verbinding B het ‘n groter kontak oppervlak as verbinding C.
      •    Intermolekulêre kragte:
           Intermolekulêre kragte in verbinding B is sterker as in verbinding C.
      •    Energie:
           Meer energie benodig om intermolekulêre kragte te oorkom/breek in B as in
           C.

       OR

      •    Structure:
           Compound C is more compact or spherical as B, the surface area is
           smaller.✓
      •    Intermolecular forces:
           The intermolecular forces in C is weaker than in B.✓
      •    Energy
           Less energy needed to overcome/break intermolecular forces in C. ✓

       •    Struktuur:
            Verbinding C is meer kompak of series as B, die kontak oppervlak is Kleiner
       •    Intermolekulêre kragte:
            Die intermolekulêre kragte in C is swakker as in B
       •    Energie
            Minder energie benodig om intermolekulêre kragte te oorkom/breek in C

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Physical Sciences P2/Fisiese Wetenskappe V2     5                            September 2022
                                      NSC/NSS- Marking Guidelines

3.3.1 Marking criteria/Nasienriglyne
      If any one of the underlined key phrases in the correct context is omitted,
      deduct 1 mark./Indien enige van die onderstreepte frases in die korrekte
      konteks uitgelaat is, trek 1 punt af,

       The pressure exerted by a vapour at equilibrium with its liquid in a closed
       system.
       Die druk uitgeoefen deur 'n damp in ewewig met sy vloeistof in 'n geslote
       sisteem.                                                                            (1)

3.3.2 D                                                                                    (1)

3.3.3 •   Both compounds/D and E have (in addition to London forces and dipole-
          dipole forces) hydrogen bonding. 
          Beide verbindings/D en E het waterstofbindings (behalwe Londonkragte en
          dipool-dipoolkragte).

      •   Compound D/pentan-1-ol/alcohol has one site for hydrogen bonding and
          compound E/butanoic acid/carboxylic acid has two/more sites for hydrogen
          bonding. OR D/butanoic acid/carboxylic acid has two/more sites for hydrogen
          bonding.
          Verbinding D/pentan-1-ol/alkohol het een punt vir waterstofbindings en
          verbinding B/buurutanoës/karboksielsuur het twee/meer punte vir
          waterstofbindings OF B/butanoësuur/karboksielsuur het twee/meer punte
          waterstofbindings.

      •   Intermolecular forces in compound E/butanoic acid/carboxylic acid are
          stronger than intermolecular forces in compound D/ butan-1-ol/alcohol.
          Intermolekulêre kragte in verbinding E/butanoësuur/karboksielsuur is sterker
          as die intermolekulêre kragte in verbinding D/ pentan-1-ol/alkohol.
          OR/OF
          Intermolecular forces in compound D/pentan-1-ol/alcohol are weaker than
          intermolecular forces in compound E/butanoic acid/carboxylic acid.
          Intermolekulêre kragte in verbinding E/pentan-1-ol/alkohol is swakker as
          intermolekulêre kragte in verbinding D/butanoësuur/karboksielsuur.

      •   More energy is needed to overcome/break intermolecular forces in compound
          E/butanoic acid/carboxylic acid than in compound D/ pentan-1-ol/alcohol. 
          Meer energie word benodig om intermolekulêre kragte in verbinding
          E/butanoësuur as in verbinding D/ pentan-1-ol/alkohol te oorkom/breek.
          OR/OF
          Less energy is needed to overcome/break intermolecular forces in compound
          D/pentan-1-ol/alcohol than in compound E/butanoic acid/carboxylic acid.
          Minder energie word benodig om intermolekulêre kragte in verbinding D/
          pentan-1-ol/alkohol     te      oorkom/breek       as       in    verbinding
          E/butanoësuur/karboksielsuur.                                                     (4)
                                                                                           [14]

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Physical Sciences P2/Fisiese Wetenskappe V2     6                                September 2022
                                      NSC/NSS- Marking Guidelines

QUESTION 4/ VRAAG 4

4.1.1    I: Addition/ hydrohalogenation/hydrobromination
           Addisie/Hidrohalogenering/Hidrobrominasie

         II: Elimination/Dehydrohalogenation
            Eliminasie/Dehidrohalogenering

         III: Addition/Hydration
              Addisie/Hidrasie/Hidratering

         IV: Elimination/Cracking
             Eliminasie / Kraking                                                              (4)

4.1.2    2-bromopentaan / 2-bromopentaan                                                     (2)

4.1.3    Alkene / Alkeen                                                                      (1)

4.1.4    H2O/water                                                                            (1)

4.1.5            H✓                            Marking criteria / Nasienriglyne
                                               • Only functional group correct / Slegs
             H O H H H               ✓           funksionele groep korrek 
         H C C C C C H                         • Whole structure correct / Hele struktuur
             H H H H H                           korrek                                       (2)

4.1.6    C2H6  Ethane/Etaan✓                                                                  (2)

4.2.1    Methyl ethanoate / Metieletanoaat                                                   (2)

4.2.2    A dehydrating agent/catalyst ✓
         Dehidreermiddel/katalisator                                                           (1)

4.2.3     Marking criteria:
         • Substitute 74 g·mol-1 into the correct formula 
         • Use ratio: n(CH4O) = n(C3H6O2) 
         • Substitute 32 g·mol-1 into the correct formula 
         • 60% of mass of CH4O 
         • Final answer: 49,64 g 

          Nasienkriteria:
          • Vervang 74 g·mol-1 in korrekte formule 
          • Gebruik verhouding: n(CH4O) = n(C3H6O2) 
          • Vervang 32 g·mol-1 in korrekte formule 
          • 60% of mass of CH4O
          • Finale antwoord: 49,64 g 

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Physical Sciences P2/Fisiese Wetenskappe V2     7                            September 2022
                                      NSC/NSS- Marking Guidelines

              m
          n=
              M
            68,88
          =
             74✓
          = 0,9308 mol

          n(CH4 O) = n(C3 H6 O2 )✓
                   = 0,09308 mol

          m(CH4 O)pure/suiwer = nM
                              = (0,09308)(32)
          =29,79 g

                           (29,79)(100)
          Impure(CH4 O) =               
                                60
                         = 49,69 g                                                         (5)
                                                                                           [20]

QUESTION 5/ VRAAG 5

5.1    NOTE/LET WEL
       Give the mark for per unit time only if in context of reaction rate.
       Gee die punt vir per eenheidtyd slegs indien in konteks met reaksietempo.

       ANY ONE/ENIGE EEN
      • Change in concentration  of products/reactants per (unit) time. 
         Verandering in konsentrasie van produkte/reaktanse per (eenheid) tyd.

      •    Change in amount/number of moles/volume/mass of products or reactants
           per (unit) time.
           Verandering in hoeveelheid/getal mol/volume/massa van produkte of
           reaktanse per (eenheid) tyd.

      •    Amount/number of moles/volume/mass of products formed/reactants used
           per (unit) time.
      •    Hoeveelheid/getal mol/volume/massa van produkte gevorm/reaktanse
           gebruik per (eenheid) tyd.

      •    Rate of change in concentration/amount/number of moles/volume/mass.
           Tempo van verandering in konsentrasie/ hoeveelheid/getal mol/
           volume/massa. ✓✓ (2 or/of 0)                                                    (2)

5.2    Volume ACCEPT: Rate of reaction/Tempo van reaksie                                  (1)

5.3.1 (Decreasing gradient indicates) rate of reaction is decreasing. ✓
      (Afnemende gradiënt dui aan dat) reaksietempo afneem.                                (1)

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Physical Sciences P2/Fisiese Wetenskappe V2     8                                            September 2022
                                      NSC/NSS- Marking Guidelines

5.3.2 (Gradient is zero, indicates) reaction rate is zero ✓
      (Gradiënt is nul, wat aandui dat) reaksietempo nul is.                                               (1)

5.4                                                   ∆V
       Ave rate /Gem. tempo =
                                                      ∆t
                                                       ∆V
                                               10 =          
                                                      20 − 0
                               V(O2 )produced/berei = 200 cm3

                                              V
       n(O2 )produced/berei =
                                             Vm
                                               200
                                           =
                                             24000
                                           = 0,0083 mol

       n(H2 O2 ) = 2n(O2 )✓
                 = (2)(0,0083)
                 = 0,017 mol

                                              n
       c(H2 O2 )used/gebruik =
                                              V
                                              0,017
                                            =
                                              0,04
                                            = 0,42 mol∙dm-3                                               (5)

5.5    Marking criteria / Nasienkriteria:
      • Graph of Experiment 2 is steeper than gradient of Experiment 2/ Grafiek van
         Eksperiment 2 het ‘n styler gradient as Eksperiment 2✓
          Both graphs ends at the same place/ Beide grafieke eindig op dieselfde
          plek ✓

                                                                              Experiment 1

          Volume of O2 (cm3)
                                        Experiment 2

                                                 10                20            30
                                                             Time (minutes)
                                                                                                           (2)

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Physical Sciences P2/Fisiese Wetenskappe V2     9                             September 2022
                                      NSC/NSS- Marking Guidelines

5.6.1 Catalyst  OR Increases reaction rate
      Katalisator OF Toename in reaksie-tempo                                               (1)

5.6.2 •    Catalyst lowers activation energy/provides an alternative path of lower
           activation energy 
           Katalisator verlaag die aktiveringsenergie/ bied ŉ alternatiewe pad van laer
           aktiveringsenergie
      •    More particles have sufficient EK OR more particles have EK  EA 
           Meer deeltjies het genoegsame EK OF meer deeltjie het EK  EA
      •    More effective collisions per unit time/Frequency of effective collisions
           increase
           Meer effektiewe botsings per eenheidstyd/ Frekwensie van die effektiewe
           botsings neem toe                                                                 (3)
                                                                                            [16]

QUESTION 6 / VRAAG 6

6.1    ++Marking criteria:
       +*
        • Calculate number of moles of H2 and Cℓ2 
        • Use mole ratio 1:1:2 
        • Moles at equilibrium
        • Divide equilibrium moles by Volume (0,5) 
        • Correct Kc expression (formulae in square brackets) 
        • Substitute 64 as Kc value 
        • Substitution of equilibrium concentrations into Kc expression. 
        • Substitute moles of Cℓ2 and in correct formula.
        • Final answer: 71 g 

          Nasienkriteria:

          •   Bereken die aantal mol van H2 en Cℓ2 
          •   Gebruik verhouding 1:1:2 
          •   Mol by ewewig 
          •   Deel mol by ewewig met volume (0,5) ✓
          •   Korrekte Kc - uitdrukking (formules in vierkanthakies) 
          •   Vervang 64 as Kc-waarde 
          •   Vervanging van ewewigskonsentrasies in Kc -uitdrukking. 
          •   Vervang mol van Cℓ2 en 71 g·mol-1 in korrekte formule 
          •   Finale antwoord: 71 g

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Physical Sciences P2/Fisiese Wetenskappe V2     10                                   September 2022
                                      NSC/NSS- Marking Guidelines
               m                m
            n=              n=
               M                M
               10               355
             =                =
               2                 71
             = 5 mol H2       = 5 mol Cl2

                                                      H2(g)       Cℓ2 (g)   HCℓ(g)
        Initial quantity (mol)                                ✓
                                                        5            5        0
        Aanvangshoeveelheid (mol)
        Change (mol)
        Verandering (mol)
                                                        x            x       2x        Ratio 

                                                                             2x ✓
        Quantity at equilibrium (mol)/                5–x           5–x
        Hoeveelheid by ewewig (mol)
        Equilibrium concentration (mol∙dm-3)          5−x           5−x      2x
        Ewewigskonsentrasie (mol∙dm-3)                 0,5           0,5     0,5

               [HCl]2
            Kc =         ✓                 No Kc expression, correct substitution/Geen Kc-
             [H2 ][Cl2 ]                   uitdrukking, korrekte substitusie: Max./Maks. 8/9
                    2x 2
                  (     )
                    0,5
       64 =                   ✓           Wrong Kc expres[sion/Verkeerde Kc uitdrukking:
               5−x 5−x
             (       )(      )             Max./Maks. 6/9
                0,5      0,5
         x=4

       n(Cl2 )equilibrium/ewewig = 5 − 4
                                 = 1
       mCl2 = nM
            = (1)(71)
            = 71 g 
                                                                                                   (9)

6.2    Negative/Negatief 

        •    Decrease in temperature favours the exothermic reaction. 
             Afname in temperatuur bevoordeel die eksotermiese reaksie.
        •    The forward reaction is favoured.
             Die voorwaartse reaksie word bevoordeel.
        •    Reaction is endothermic. 
             Die reaksie is eksotermies.                                                           (4)

6.3.1 Remains the same/Bly dieselfde                                                              (1)

6.3.2 Remains the same/Bly dieselfde                                                               (1)
                                                                                                   [15]

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Physical Sciences P2/Fisiese Wetenskappe V2     11                           September 2022
                                      NSC/NSS- Marking Guidelines

QUESTION 7 / VRAAG 7

7.1.1 Dilute acids contain a small amount (number of moles) of acid in proportion to
      the volume of water.  (2 or 0)
      Verdunde sure bevat 'n klein hoeveelheid (getal mol) suur in verhouding met die
      volume water.                                                                        (2)

7.1.2 Strong acids ionise completely in water to form a high concentration of H3O+
      ions. 
      Sterk sure ioniseer volledig in water om 'n hoë konsentrasie H3O+ -ione te vorm.     (2)

7.1.3 HSO−
         4                                                                                (1)

7.1.4 [H3 O+ ] = 2[H2 SO4 ]
               = 2(0,2)
               = 0,4 mol∙dm−3
                        +
       pH = −log[H3 O ]✓
          = −log[0,4]
          = 0,398                                                                         (3)

7.2.1 Basic/Alkalies                                                                      (1)

7.2.2 CO2−           −     −
        3 + H2O → OH + HCO3                     Balancing 
         Marking criteria / Nasienkriteria:
        •    Reactants        Products     Balancing 
             Reaktanse        Produkte      Balansering
        •    Ignore phases / Ignoreer fases.
                                                                                           (3)

7.3      Marking criteria:
                                 n     c V        n
        •    Use of formula c = V or caVa = na 
                                           b b     b

        •    Substitute 0,1 mol∙dm-3 and 0,0248 dm3 in correct formula
        •    Use ratio: n(NaOH) = 2n(Na2CO3) 
        •    Substitute 0,5 dm3 in correct formula 
                                     m
        •    Use 286 g·mol-1 in n = M 
        •    Final answer: 7,09 g 

         Nasienkriteria:
                                       n         𝐶𝑎𝑉𝑎   𝑛𝑎
         • Gebruik van formule c = v or 𝐶𝑏𝑉𝑏 = 𝑛𝑏 
         •   Vervang 0,1 mol∙dm-3 en 0,0248 dm3 in korrekte formule
         •   Gebruik ratio: n(NaOH) = 2n(Na2CO3) 
         •   Vervang 0,5 dm3 in korrekte formule 
                                        m
         •   Gebruik 286 g·mol-1 in n = M 
        • Finale1/OPSIE
       OPTION            1 7,09 g 
                  antwoord:
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Physical Sciences P2/Fisiese Wetenskappe V2     12                  September 2022
                                      NSC/NSS- Marking Guidelines

       n(HCl) = cV✓
              = (0,1)(0,0248)✓
              = 2,48 × 10−3 mol

       n(Na2 CO3 ) = 2n(HCl)
       n(Na2 CO3 ) = 1,24 × 10−3 mol ✓

       1,24 × 10−3 mol (Na2 CO3 ) in 0,025 dm3
       ∴ in 0,5 dm3 n(Na2 CO3 ) = 0,0248 mol 

                    m
                n=
                    M
                      m
         0,0248 =
                    286
       m(Na2 CO3) = 7,09 g 

       OPTION 2 / OPSIE 2
       ca Va na
              = ✓
       cb Vb nb
       (0,1)(24,8)✓ 2
                    = ✓
          (cb )(25)  1
       ca = 0,0496 mol∙dm3

       n(Na2 CO3 ) = cV
               n = (0,0496)(0,5)
                   = 0,0248 mol

                    m
                n=
                    M
                      m
         0,0248 =
                    286
       m(Na2 CO3) = 7,09 g                                                        (6)
                                                                                  [18]

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### Page 32

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Physical Sciences P2/Fisiese Wetenskappe V2     13                                   September 2022
                                      NSC/NSS- Marking Guidelines

QUESTION 8 / VRAAG 8

8.1    Concentration/Konsentrasie: 1 mol·dm-3 
       Temperature/Temperatuur: 25 °C                                                             (2)

8.2   •       To ensure electrical neutrality / Verseker elektriese neutraliteit 
      •       To separate the two electrolytes/Om die elektroliete te skei                        (2)

8.3    Ni to Ag                                                                                   (1)

8.4    Ni(s) + 2Ag+(aq) → Ni2+(aq) + 2Ag(s)  balancing 

          Marking criteria / Nasienkriteria:
          •    Reactants        Products     Balancing 
               Reaktanse        Produkte      Balansering
          •    Ignore double arrows/Ignoreer dubbel pyltjie
          •    Ignore phases / Ignoreer fases.                                                     (3)

8.5    n(anode) = ½n(cathode)
       n(anode) = ½(0,4)
                = 0,2 mol

                          m
                         n=
                          M
                           m
                    0,2 =
                          59
       mdecrease/afname = 11,8 g                                                                  (3)

8.6    B
       Mg is a stronger reducing agent than Ni. Mg will be oxidized to Mg2+
       Mg is ‘n sterker reduseermiddel as Ni en Mg sal dus geoksideer word tot Mg 2+                (4)
                                                                                                   [15]

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### Page 33

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Physical Sciences P2/Fisiese Wetenskappe V2     14                                 September 2022
                                      NSC/NSS- Marking Guidelines

QUESTION 9 / VRAAG 9

9.1    ANY ONE/ENIGE EEN
       • The chemical process in which electrical energy is converted to chemical
         energy. 
       • The use of electrical energy to produce a chemical change
       • The process during which an electric current passes through a solution/ionic
         liquid/molten ionic compound.
       • Decomposition of an ionic compound by means of electrical energy.
       •   Die chemiese proses waarin elektriese energie gebruik word om 'n chemiese
           verandering te weeg te bring. 
       •   Die chemiese proses waarin elektriese energie omgeskakel word na
           chemiese energie
       •   Die proses waardeur ‘n elektriese stroom deur ‘n opplossing/ioniese
           vloeistof/gesmelte ioniese verbinding beweeg.
       •   Ontbinding van ‘n ioniese verbinding met behulp van elektriese energie.
                                                                                                 (2)

9.2    A                                                                                        (1)

9.3    B                                                                                        (1)

9.4    Cu2+ + 2e- Cu 

       Marking criteria/Nasienriglyne
       Cu  Cu2+ + 2e- ( 3⁄3 )                       Cu2+ + 2e- ⇌ Cu    ( 1⁄3 )

       Cu ⇌ Cu2+ + 2e-      ( 0⁄3 )                 Cu2+ + 2e-  Cu     ( 0⁄3 )                  (3)

9.5    True/Waar 
       Rate of oxidation is equal to the rate of reduction
       Tempo van oksidasie is gelyk aan die tempo van reduksie                                   (2)

9.6    Carbon is unreactive and can conduct electricity 
       Koolstof is onreaktief en kan elektrisiteit gelei.                                        (2)

9.7    A
       2Cℓ- → Cℓ2 + 2e- 

       Marking criteria/Nasienriglyne
       Cℓ2 + 2e-  2Cℓ-   ( 2⁄2 )                    2Cℓ-  Cℓ2 + 2e-    ( 1⁄2 )

       Cℓ2 + 2e- ⇌ 2Cℓ-      ( 0⁄2 )                 2Cℓ-  Cℓ2 + 2e-   ( 0⁄2 )
                                                                                                 (3)

9.8    Decrease/Afneem                                                                           (1)
                                                                                                 [15]
                                                                                   TOTAL:        150

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