# Physical Sciences Grade 12 P2 Mpumalanga November 2014 Memo

> Grade 12 Physical Sciences Paper 2 memorandum from the Mpumalanga November 2014, 9 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/mpu-physical-sciences-p2-sept-2014-memo/b6800da7-3221-43f2-ba55-a68d6aaa7dab
- Updated: 2026-09-27
- Subject: Physical Sciences
- Grade: Grade 12
- Document type: Memorandum
- Year: 2014
- Exam period: Mpumalanga November
- Paper: 2
- Curriculum: CAPS
- Pages: 9

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Physical Sciences · Grade 12 · Mpumalanga November · 2014. Memorandum, 9 pages. Read online or download the PDF.

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### Page 1

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NATIONAL SENIOR CERTIFICATE EXAM

          PHYSICAL SCIENCES P2

             SEPTEMBER 2014

                 GRADE 12

               MEMORANDUM

                                         MARKS: 150

                                    TIME: 3 HOURS

  This memorandum consists of 10 pages

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Physical Sciences/P2                       2                       September 2014
                                     NSC-Memorandum

QUESTION 1 : MULTIPLE-CHOICE QUESTIONS

1.1      D                                                                          (2)

1.2      B                                                                          (2)

1.3      B                                                                          (2)

1.4      A                                                                          (2)

1.5      A                                                                          (2)

1.6      D                                                                          (2)

1.7      B                                                                          (2)

1.8      D                                                                          (2)

1.9      C                                                                          (2)

1.10     A                                                                          (2)

                                                                                      [20]

QUESTION 2

2.1      Homologous series: A series of organic compounds that can be described by
         the same general formula with the same functional group and in which one
         member differs from the next with a -CH2- group.                           (2)

2.2.1        H       H   H   H   H   H

         H C         C   C   C   C   C   H
             H               H   H   H

             H       H   H   H   H   H                                                (2)
         H C         C   C   C   C   C   H
             H       H           H   H       any one 

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Physical Sciences/P2                         3                           September 2014
                                       NSC-Memorandum

2.2.2    H
             C       O
         H                aldehydes / alkanals                                              (2)

2.2.3    3-chlorobut-1-ene                                                                  (2)

2.2.4
                 H       H       O                 H    O       H
         H       C       C   O   C H         H     C    C   O   C   H
                 H       H                   H             H                                  (2)
         Any one  (One mark for the functional group, one mark for the whole
         structure)
                                                                                             [10]

QUESTION 3

3.1      What is the relationship between the mass of a haloalkane and the
         boiling point? .                                                                   (2)

3.2      boiling point                                                                      (1)

3.3      mass of the haloalkane / halogen                                                   (1)

3.4      length of the carbon chain  (also accept: atmospheric pressure OR just
         pressure)                                                                           (1)

3.5      So that the investigation may be deemed valid. 
         (also accept: Changes in pressure affect the boiling points of liquids)             (1)

3.6      As the size / mass of the halogen attached to the methane increases,
         the boiling point increases.                                                      (2)

3.7      As the size / mass of the halogen attached to the methane increases, the
         size/mass of the whole compound increases, therefore the surface area
         increases and the strength of the intermolecular forces / Van der Waals
         forces / London forces, increases. More energy is needed to break the
         forces and therefore the boiling point increases.                                 (3)
                                                                                             [11]

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Physical Sciences/P2                               4                                      September 2014
                                             NSC-Memorandum

QUESTION 4

4.1.1    I     =   addition / hydrogenation    
         II    =   addition / halogenation 
         III   =   substitution 
         IV    =   combustion (oxidation) 
         V     =   elimination / dehydrohalogenation                      
         VI    =   polymerisation                                                                           (6)

4.1.2    I = H2          
         IV = O2                                                                                             (2)

4.2.1    Esterification                                                                                     (1)

4.2.2    H2SO4 is a dehydrating agent / catalyst. Will remove water (H2O) during the
         formation of the ester. Makes the reaction faster                                                  (2)

4.2.3     Contents of the test tube must not be exposed to direct flame                    
          Bumping stones reduce the intensity of the boiling action to prevent
            contents from shooting out.                                                                     (2)

4.2.4          H     H   H                            O           H           H
                                     H
         H     C     C   C       O       +                C       C           C   H

               H     H   H                   H       O                           
                                                                  H           H

                                                  O           H       H

                             H       H   H            C   C       C           H
                                                                                      +      H    O
                                                                                                      H
                     H       C       C   C        O       H       H                                          (5)
                                                                                                 
                             H       H   H                            

4.3.1    Ethene / ethylene                                                                                   (1)

4.3.2    Contains a double bond between two carbon atoms                                                    (1)

4.3.3    Prepare a solution of bromine water (brown). Add bromine water to a solution
         of ethane (ethane is a gas at room temperature). If the bromine water
                                                                                                             (2)
         decolourises quickly the presence of a double bond is indicated.

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Physical Sciences/P2                      5                                 September 2014
                                    NSC-Memorandum

4.3.4                H   H    H    H     H    H                                                (2)

             H       C   C    C    C     C    C     H
                                                        
                     H   H    H    H     H    H

4.3.5    Addition                                                                             (1)

                                                                                               [27]

QUESTION 5

5.1      Increase the concentration of sulphuric acid 
                                                                                                (4)
         Increase surface area of phosphate rock 

5.2.1    The minimum kinetic energy of reacting particles  that can result in a reaction (2)

5.2.2    Collision theory                                                                      (1)

5.2.3    The shaded areas in the distribution curves represent the number of molecules
         with sufficient kinetic energy to overcome the activation energy . An increase
         in the temperature of the system results in a greater number of particles with
         sufficient kinetic energy to overcome the activation energy of the reaction .
         This results in more effective collisions per unit time OR a higher chance of an
         effective collision occurring, resulting in a higher reaction rate .
                                                                                                (3)
                                                                                               [10]

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Physical Sciences/P2                      6                               September 2014
                                    NSC-Memorandum

QUESTION 6

6.1.1    Dynamic (Equilibrium) – Refers to the fact that the forward and reverse
         reactions continue to take place simultaneously without stoppingand the
         rate of the forward reaction is equal to the rate of the reverse reaction, when
                                                                                               (2)
         equilibrium is reached . (changes in macroscopic properties cease,
         changes in microscopic properties continue)

6.1.2    (a)       2SO2(g) + O2(g) → 2SO3(g)                                                 (2)

         (b)       2SO3(g) → 2SO2(g) + O2(g)                                                 (2)

6.1.3    There was an increase in pressure .
         This increases the rate of both the forward and reverse reactions due to the
         particles being closer together and effective collisions occurring more
         frequently. However, the forward reaction is favoured & therefore the
         rate of the forward reaction is increased more to turn 3 moles of gas into
         2 moles of gas to relieve the increased pressure 
                                                                                               (3)

6.1.4    The catalyst was removed                                                             (1)

6.2      n(O2) = m
                 M
               = 9,6
                  32
                = 0,3 mol

                                      2H2 (g)       O2(g)       2H2O(g)
         Mol in the beginning           0,5          0,5          0

         Mol reacted                    0,4          0,2          0,4      ratio

         Mol at equilibrium             0,1          0,3         0,4 

         [ ] at equilibrium             0,5          1,5          2,0      divide by V(0,2)

         Kc = [H2O]2    
              [H2]2[O2]
               =    (2,0)2
                   (0,5)2(1,5)                                                                (7)
               = 10,67                                                                        [17]

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Physical Sciences/P2                         7                          September 2014
                                       NSC-Memorandum

QUESTION 7

7.1      pH = - log[H+] 
                 = -log (3,2x10-5) 
                 = 4,5 
         NO, the fish will not survive
                                                                                            (4)

7.2      A substance that donates protons (H+) OR proton donor                            (2)

7.3.1    C        (Na2CO3)                                                                 (1)

7.3.2    A         (HCℓ)                                                                   (1)

7.3.3    D         (CH3COOH)                                                               (1)

                                                                                            [9]

QUESTION 8

8.1.1    A monoprotic acid is an acid that can donate only one proton (H+-ion) per          (2)
         molecule 

8.1.2    H3O+ & CH3COO-                                                                  (2)

8.1.3    HCℓ is a strong acid which ionises almost completely into its ions and yields a
                                                                                            (2)
         high concentration of H3O+ ions in the solution, while ethanoic acid is only
         partially ionised and has less H3O+ ions in solution.

8.2.1    M(NaOH) = 40 g·mol-1
         c = m
             MV
             =     2,5
                 (40)(0,5)
             = 0,125 mol·dm-3                                                              (3)

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Physical Sciences/P2                           8                          September 2014
                                         NSC-Memorandum

8.2.2    caVa = na
         cbVb nb
            ca = nacbVb
                  nbVa
               = (1)(0,125)(20)
                    (1)(24,5)
                = 0,102 mol·dm-3                                                             (3)

8.2.3    The acid, When NaOH is allowed to stand for longer periods, it may evaporate (2)
         leaving solid sodium hydroxide and the tap will eventually not be able to turn.

8.2.4    Phenolphthalein, because a strong base is titrated with a weak acid and will
         form a basic (pH > 7) solution. The equivalence point of the indicator must
                                                                                              (2)
         therefore be basic.

                                                                                              [16]

QUESTION 9

9.1      Ni                                                                                  (1)

9.2      Ag+ + e- →         Ag                                                            (2)

9.3      Eθcell = Eθcathode - Eθanode
         = 0,8 - (-0,27)
                = 1,07 V                                                                     (4)

9.4      It acts as a salt bridge that separates the two electrolytes but enable ions to
         move from one half cell to the other to ensure electrical neutrality of the
         electrolyte solutions OR it completes the circuit                                  (3)

9.5      Mol ratio : Ni :    e-          OR                 𝑛(𝑁𝑖) 1
                                                                   =
                       1   : 2                              𝑛(𝑒 − ) 2
                                                            𝑛(𝑁𝑖) 1
                       0,2 : 0,4                                  =
                                                             0,4     2
                 Therefore        m=nxM                             1
                                                            𝑛(𝑁𝑖) = × 0,4
                                                                     2
                                     = 0,2 x 59                   = 0,2
                                     = 11,8g                   𝑚 = 𝑛𝑀                        (4)
                                                                   = 0,2 × 59
                                                                   = 11,8 𝑔                   [14]

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Physical Sciences/P2                          9                                  September 2014
                                        NSC-Memorandum

QUESTION 10

10.1
                                       battery 

                              e- 

          Anode: Copper
          electrode 

                                                   Medal 

                               Cu 2+    Cu 2+     CuSO4 or any other copper salt 
                                                                                                    (6)

10.2     Cu2++ 2e-        →   Cu                                                                  (2)

10.3     Cathode                                                                                   (1)
                                                                                                    [9]

QUESTION 11

11.1     26 % of 50 kg = 13 kg 
             Mass of N = 3 x 13 
                        10                                                                          (3)
                          = 3,9 kg 

11.2     Ratio of N : K : P carefully controlled according to specific needs.any 1
                                                                                                    (1)
         Nutrients are concentrated \ need less of them.

11.3     A = Nitrogen 
         B = Brine (seawater) 
         C = Haber Process 
         D = Water 
         E = Ostwald Process 
         Question asked for names don’t give formulae                                               (5)

                                                                                                    [9]

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