# Physical Sciences Grade 10 2022 QP & Memo

> Grade 10 Physical Sciences question paper and memo from the Mpumalanga September Test 2022, 17 pages. Read online or get the free PDF download.

- Page: https://www.hlayiso.com/library/mpumlanga-physical-science-grade-10-sept-2022-qp-and-memo/1a7dbc7c-791f-4111-9e1e-2f2c68ff2a23
- Updated: 2026-09-27
- Subject: Physical Sciences
- Grade: Grade 10
- Document type: Question paper and memo
- Year: 2022
- Exam period: Mpumalanga September Test
- Curriculum: CAPS
- Pages: 17

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## About this document

Physical Sciences · Grade 10 · Mpumalanga September Test · 2022. Question paper and memorandum, 17 pages. Read online or download the PDF.

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## Document text

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### Page 1

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7, education

DEPARTMENT: EDUCATION
MPUMALANGA PROVINCE

GERT SIBANDE DISTRICT
ERMELO SUB DISTRICT

SHYS ICAL SCIENCES:
‘CONTROLLED TEST
15 SEPTEMBER 2022

MARKS: 100
TIME: 2:00 HOURS

This question paper consists of 11 pages including the data sheets

1

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INSTRUCTIONS AND INFORMATION

10.

11.

This question paper consists of SEVEN questions. Answer ALL the questions
in the ANSWER BOOK.
Start EACH question on a NEW page in the ANSWER BOOK.

Number the answers correctly according to the numbering system used in this

question paper. @
ew

Leave ONE line between two sub questions, for “example between
N
QUESTION 2.1 and QUESTION 2.2. wy’

You may use a non-programmable calculatgt

©

You may use appropriate mathematiea struments

You are advised to use the anach oars SHEETS.

Show ALL formulae osm in ALL calculations.

Round off your Teahpumeta answers to a minimum of TWO decimal places.
Give nga discussions et cetera where required.

wre and legibly.
fe)

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QUESTION 1

Four options are provided as possible answers to the following questions. Each
question has only ONE correct answer. Choose the answer and write only the
letter (A — D) next to the question number (1.1 — 1.8) in the ANSWER BOOK,
for example 1.11 D.

1.1

1.2

1.3

The gravitational potential energy of an object relative to the ground is
dependent on the object's

A _ speed.
B position.

C velocity. Ss

D_ change in velocity. oS: (2)
An object is released from the top of the platform, and S down ward
along a frictionless inclined plane Y- Z as shown int iagram below.

Which one of the following statements regarding the energy of the ball is

correct?

A Total rectarigahony at Y is greater than total mechanical
energy at ie

B Total 5 we, energy at Y is less than total mechanical energy
at 7X

go energy at Y is equal to total mechanical energy at
Oa mechanical energy at Y is not equal to total mechanical
energy at Z. (2)
The number of wave pulses per second is called ....
A Wave length
B Amplitude
Cc Frequency

D Period (2)

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1.4 Which one of the combinations below concerning longitudinal waves is
correct?

Compression Rarefaction
A | Isregion of high pressure | Is region of low pressure

B Is region of low pressure | Is region of high pressure

C | Is minimum displacement | Is maximum displacement of
of particles particles

D_ | Is maximum displacement | Is minimum displacement of
of particles particles (2)

1.5 A mixture of Salt and water can be separated by boiling the mixture.
The change which take place during the separation of this mixture
components is...........

A Chemical change only.

B Physical change and chemical change.
Cc Neither physical change nor chemical change.

D Physical change only. (2)
1.6 Which type ofchanges obey the Law of conservation of mass?

A Only physical change

B Only chemical change

Cc Only phase changes

D physical change and chemical change (2)
1.7 Consider the following incomplete equation for a chemical reaction:
f Na(s) + H2SOx (aq) + NazSO, (aq) + Q

Letter Q represents one of the products and letter f represents a
numerical value which make the chemical equation correctly balanced.

Which one of the combinations below concerning the above chemical

equation is CORRECT?

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Value of f Formula of Q
A 1 H
B 0 H20
Cc 2 Ho
D 1 Ho (2)

1.8 The number of atoms in ONE formula unit of copper(Il)nitrate Cu(NO3)2

is...
A 9
B 3
Cc 8
D 5 (2)
[16]
QUESTION 2
A 5 kg block is released from rest at a height,of 5myandyslides down a frictionless
incline O-P as shown in the diagram below. It then moves along horizontal
portion PQ where it experiences friction and stops at point Q. Point P is 3 m from
point Q.
aN,
|
I
|
5m
I
I
I
Poo SS
P 3m Q
2.1 State the principle of conservation of mechanical energy in words. (2)
2.2 Calculate the:
2.2.1 Gravitational potential energy of the block just before it is
released. (3)
2.2.2 Magnitude of the velocity of the block at point p, use the principle
of conservation of mechanical energy. (4)
2.2.3 Acceleration that the block experiences as it moves from point P
toQ. (4)

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2.3 Write down the energy conversion which takes place as the block moves (1)
from point P to Q. [14]

QUESTION 3

Two pulses are travelling towards each other along a spring, as shown in the
diagram below.The centres of the two pulses meet and cross at point X.

—
cl
t
x 6c
+
3.1 Which wave property do the two pulses illustrate at point X? (1)
3.2 Name and define the principle used to answer QUESTION 3.1 (3)

3.3 When the pulses cross at point X, the resulting amplitude is different from
the amplitudes of the individual pulses

3.3.1 Define the term amplitude. (2)
3.3.2 Calculate the magnitude of the resulting amplitude. (2)
[8]
QUESTION 4

The sketch below shows a transverse wave in a medium.

B. 2m D

Distance z

Position (m)
>

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4.1 Use the diagram above to write down:
4.1.1 The name of the physical quantity represented by the distance of

2m. . (1)

4.1.2 Two points that are in phase. (1)

4.1.3 One point that represents a crest. : (1)

4.1.4 One point that represents the rest position. (1)
4.2 Write down the number of waves represented in the diagram above. (1)
4.3 Determine distance Z in the diagram. (2)
4.4 Define the term frequency of the wave in words. (2)
45 Calculate:

4.5.1 The frequency of the wave. (3)

4.5.2 The speed of the wave. (3)

[15]
QUESTION 5
The diagram below shows a longitudinal wave produced by a musical instrument.
Wave propagation
T U Vv WwW x

5.1 Define the term a longitudinal wave. (2)
5.2 Write down the name of the parts marked:

5.2.1 U (1)

5.2.2 V (1)
513 Describe the motion of the particle at points U, as the wave propagates to

the right. (2)

5.4 Write down the number of wave lengths shown in the diagram. (1)

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5.5 State whether the following points are IN PHASE or OUT OF PHASE.

5.5.1 TandW (1)
5.5.2 Wand X (1)
5.6 Give a reason for the answer in question 5.5.2 (2)

5.7 Wave particles at point U make 410 oscillations in 2 seconds.

Calculate the frequency of the wave. (2)
[13]
QUESTION 6
6.1 Ice melts when there is a change in temperature of the environment
6.1.1 State whether the melting of ice is a PHYSICAL CHANGE or
CHEMICAL CHANGE (1)

6.1.2 Describe the rearrangement of molecules during the melting of
ice. (2)

6.2 The word equation (i) and the unbalanced equation (ii) for two chemical
reactions are shown below.

(i) — Calcium carbonate + hydrochloric acid — Calcium chloride +
carbon dioxide + water

(ii) 2H202 (aq) — 02 (g) + 2H20 (I)

6.2.1 Give areason why both reactions (i) and (ii) above represent a
chemical change. (1)

6.2.2 Write down a balanced chemical equation for the word equation
(i). Show the phases of ALL reactants and products. (4)

6.2.3 Use acalculation to show that the Law of Conservation of Mass is valid
during reaction (ii). (3)

6.3 Which ONE of the above equations (i) or (ii) represents:

6.3.1 Decomposition reaction? (1)
6.3.2 Synthesis reaction? (1)
[13]

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QUESTION 7

Grade 10 learners demonstrated the reaction of a metal with: an acid.by adding
1,4 g of Zinc to excess hydrochloric acid in the conical’ flask. X volume of
hydrogen gas was produced at STP. The reaction which took place is represented
by the balanced chemical equation below.

Zn(s) + 2HCL(aq) > ZnCt,(aq) + H,(9)

7.1 Calculate:

7.1.1 The value of X (in dm), which is the volume of hydrogen gas
produced at STP. (4)

7.1.2 .The mass (in gram) of ZnCé, (theoretical yield) produced. (3)
7.1.3 The percentage yield of ZnCf2, If the actual mass of ZnCt,
formed is 2,69 g. (3)
7.2 The formula of the hydrated sodium carbonate is Na,CO,.xH,O.

The molar mass of hydrated sodium carbonate is found to be 268 gol.
Calculate the number of moles water of crystallisation (x) in the
compound. (3)

7.3 Asample of compound Q contains 24,27% C, 4,07% H and 71,65% Ce.
7.3.1 Define the term empirical formula. (2)

7.3.2 Use acalculation to determine the empirical formula of
compound Q. (6)
[21]
TOTAL: 100

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DATA FOR PHYSICAL SCIENCES GRADE 10

TABLE 1: PHYSICAL CONSTANTS

NAME SYMBOL VALUE
Molar gas volume at STP Vin 22,4 dm?-molt
Electron Mass me 9,11 x 10°" kg
Charge on electron e -1,6x 10°C
Avogadro’s constant Na 6,02 x 102 mol
TABLE 2: MOTION
1.2
Ve = Vj t+ aAt Ax=viAt+ 5 aAt
Ve +Vj
vi? = VP + 2aax Ax (ac

TABLE 3: WEIGHT AND MECHANICAL ENERGY

Fg =mg U=E, =mgh

1 2
K=E.=5mv

TABLE 4: WAVES, LIGHT AND SOUND

v=fXorv = vA T=" or T=

: : c
n, sind; =n, sin 6, bey

TABLE 5: FORMULAE

10

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education

DEPARTMENT: EDUCATION
MPUMALANGA PROVINCE

GERT SIBANDE DISTRICT
ERMELO SUB DISTRICT

| GRADE 10 |

PHYSICAL SCIENCES

SEPTEMBER 2022
MARKING GUIDELINES

MARKS: 100

This marking guidelines consists of 6 pages
1

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QUESTION 1
1.1 BY Y
1.1 CV
1.3 CVY
14 AVY
1.5 DVY
1.6 BY ¥
1.7 CVY
1.8 AVY
QUESTION 2
2.1 The total energy of an isolated system remains constant.v¥ “
[2 or 0 mk]
2.2.1 Ep=mgh¥
= (5)(9,8)(5) ¥
=24,5)V
2.2.2 = EMey=EMe) / (Ep + Ek)O = (Ep + Ek)P
OR: mgh(o) + ¥mv20) = mgh(p) + YamvaP)
(5)(8,8)(5) + 0 =V 0 + 14(5) Vv
V =9,90 m.s*¥
2.2.3 POSITIVE MARKING FROM Q 2.2.2
vi? = vi? + 2aAx¥
(0)? =v (9,90)? + 2a(3)¥
a=-16, 34m-s"
a= 16, 34m:s-2 in opposite to direction of motion”
2.3 Mechanical/kinetic energy converted to heat/sound/internal

energy.”

(2)
(2)
(2)
(2)
(2)
(2)
(2)

(2)
[18]

(2)

(3)

(4)

(4)

(1)
[14]

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QUESTION 3

3.1

(Destructive) interference.“

3.2 Principle of superposition.
The algebraic sum of the amplitudes of two pulses that occupy the
same space at the same time.“ ¥ [2 or 0 mk]
3.3.1 | The maximum disturbance of the particle from its rest (equilibrium)
position.¥ ¥ [2 or 0 mk]
3.3.2 8-6¥ =2cm¥v
QUESTION 4
4.1.1 Wave length.”
4.1.2 A and CY
4.1.3 BY/D
41.4 AVIC/E
4.2 2v
4.3 3,5 mvv
4.4 The number of wave pulses per second.” ”
45.1 ;_1y
wr
fo=-cv
3
f= 0,333 Hz¥
4.5.2 OPTION 1 OPTION 2
V=fiv Ax = VAtY

V = 0.333x2Yv 2=VX3V

V=0,67ms'¥ |V=0,67m.s'¥

(1)

(3)

(2)

(2)
[8]

(1)
(1)
(1)
(1)
(1)
(2)
(2)

(3)

(3)
[15]

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QUESTION 5

5.1 A wave in which the particlessof the medium vibrate parallel to the
direction of motion of the wave. Vv ” (2)

5.2.1 RarefactionY (1)

5.2.2. compression” (1)

5.3 The particle moves to the left and right’ ”
OR; The particle moves backwards and forwards (then return to its

original position). (2)
5.4 av (1)
5.5.1 OUT OF PHASEY (1)
5.5.2 IN PHASEY (1)
5.6 They are separated by a whole number of (complete)

wavelengths.¥ ¥ (2)
5.7 f = number of oscillations per second

f=410+ 2v

f = 205 Hz¥ (2)

[13]

QUESTION 6
6.1.1 PHYSICAL CHANGEY (1)

6.1.2 Molecules become disorderly arranged V due to breaking of
intermolecular forces.” (2)

6.2.1. Newchemical substances are formed.”
OR: Mass and atoms are conserved , but the number of molecules
is not. (1)

6.2.2 CaCOz3(s)+2HCl (aq) - CaCl (aq) + CO2 (g) + H20 (I)

Criteria for marking Q 6.2.2
Correct reactants

Correct product
Balancing
All states are correct

cS ES EES

(4)

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6.2.3.  2H,O2(aq) — On (g) + 2H20 (I)
2(1x2+16x2)¥ (16x2) + 2(1x2 +16)”
68 = 68v (3)

6.3.1 (ii)¥ (1)

6.3.2 (iv (1)
[13]

QUESTION 7

71.1 any = my

1,4
n(Zn) =——¥ = 0,022 mol
65

n(Zn) =nH2= 1:1
nHz = 0,022 mol

Vv
n(H2) = vm

0,022 = ——_-¥
22,4

V(Hz2) = 0,493 dm?¥ (4)

7.1.2 9 n(Zn) =nZnCl,= 1:1
NZnCl = 0,022 mol¥
m(ZnClz) = nM
m(ZnClz) = 0,022 X 136%

m(ZnCl,) = 2,99 g¥ (3)

7.1.3 actual yield

% yield = x 100

theoretical yield
. 2,69
% yield = F55%t00¥

a

% yield = 89,97 %V (3)

7.2 Na,CO,,.xH,O = 268

23x2+12+16x3 + 18x¥ = 268W
106 + 18X = 268
X=9% (3)

7.3.1 The simplest whole-number ratio of atoms in a compound. ¥ ~ (2)

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7.3.2

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Element Cc H cl
m 24,27 4,07 71,65
n=-v — —_ ay
M 12 1 35,5
= 2)0225)).)= 4,07 = 2,0183Y
2,0225 4,07 2,0183
Divide by 2,0185 2,0183 2,0183
smallest =1 =2 =1v
Empirical formula: CH.CIY

TOTAL: 100

(6)
[21]

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